I need to provide a static url to a client, eg. http://domain.com/video.mp4. However this URL needs to provide a random video from a selection of 5 videos each time it is accessed.
Is this possible using PHP and mod_rewrite? Or some other way?
Thanks
You may be able to provide a url to a PHP script (http://domain.com/video.php), which then sets its content-type header to the type of a video and then randomly reads out a file using readfile.
I don't think you need to use mod_rewrite in this case.
header('Content-type: video/mp4'); // I don't know the correct MIME type
$files = array('vid1.mp4', 'vid2.mp4', 'vid3.mp4');
readfile($files[array_rand($files)]);
Does your client require the url to end in .mp4?
If not you could indeed use a mod_rewrite by selecting a random number from, say, 1 to 5
Related
I want to show an img like this:
http://picviewer.umov.me/Pic/GetImage?id=92013681&token=ee103380297bbb2df0d8855949d791df
How should i use php to show the img with dynamic parameters?
You need to set the proper content type headers and then stream the binary data.
$imagepath = '/path/to/file';
header("Content-type: image/jpeg");
echo file_get_contents( $imagepath );
First i'll explain what does that URL do: it's configured to point to a script, or class->function, that manages the searching in the database, for the real path, the path you want to hide for the user, then returns the image to the request.
That said, in two steps, what you have to do is the following.
Check how to customize your url, this could be a start:
How to create friendly URL in php?
create your custom url pointing to a script or class/function like this:
Return a PHP page as an image
Thats, all... Assuming that you already have the images/database covered of course. if not, well you'll have to make the necessary database and tables...
I want to get current URL inside a PNG generated by PHP (header('Content-Type: image/png');)
But when i use http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];,
The URL output is the file's location (http://test.com/png.php) but not the page which get the img with <img> tag.
What can i do to get current URL?
Thanks!
Sounds like you're looking for $_SERVER['HTTP_REFERER'], not REQUEST_URI.
I'm not sure I understood you, but I'll give it a go. If you serve an image via PHP, it's URL will always point to a PHP script. If you want it to look like it's really a .png image, you have 2 choices:
1) Create a rewrite rule which will redirect some .png URL to your PHP script and then serve that URL to users.
2) Stick with the current URL, but also add an (non-standard!) Content-Disposition header:
header('Content-Disposition: attachment; filename="my_image.png"');
This way the URL will still point to a PHP script, but when a user tries to save the image, the suggested name won't be the PHP script, but the name specified in Content-Disposition.
So this is simple to understand what i want to achieve. So i get links like theese:
http://rockdizfile.com/atfmzkm7236t
http://rockdizfile.com/xuj5oincoqmy
http://rockdizfile.com/pg8wg9ej3pou
So theese links are from one cloud storage site I want to make a php script that automates their downloading.
So I can't find which is the script or the thing these links download button starts and how can I start that so i can download it with php on my server?
Basically my idea is to download a lot of files but don't wanna do it manually so need automatic way of doing it. As far as I know I make a request which is the following 2 urls:
http://rockdizfile.com/pg8wg9ej3pou
http://wi32.rockdizfile.com/d/wsli6rbhfp4r2ge4t7cqeeztijrprelfiw4afvqg5iwspmvqabpkmgiz/Desislava%20feat.%20Mandi%20&%20Ustata%20-%20Pusni%20go%20pak%20(CDRIP).mp3
So the first url is executing the next one but here comes the tricky part as far as I tested that last string Desislava%20feat.%20Mandi%20&%20Ustata%20-%20Pusni%20go%20pak%20(CDRIP).mp3 is the file name we get when downloading so if you change it with for example somefile.mp3 it will download somefile.mp3 but with the same file content as http://wi32.rockdizfile.com/d/wsli6rbhfp4r2ge4t7cqeeztijrprelfiw4afvqg5iwspmvqabpkmgiz/Desislava%20feat.%20Mandi%20&%20Ustata%20-%20Pusni%20go%20pak%20(CDRIP).mp3 so the data is hidden in this hash wsli6rbhfp4r2ge4t7cqeeztijrprelfiw4afvqg5iwspmvqabpkmgiz or i think so. And now is the tricky part how to get this hash? we have almost everything we have the code for the url atfmzkm7236t the hash wsli6rbhfp4r2ge4t7cqeeztijrprelfiw4afvqg5iwspmvqabpkmgiz and the filename Desislava%20feat.%20Mandi%20&%20Ustata%20-%20Pusni%20go%20pak%20(CDRIP).mp3 There must be a way to download from this site without clicking so please help me kinda a hack this :)
you can use PHP's header function to force a file to download
header('Content-disposition: attachment; filename=index.php');
readfile('Link');
You should know that this will not give you the ability to download PHP files from external websites.
You can only use this if you got the direct link to a file
It's impossibly to tell you without the source code
e.g. sha1("Test Message") gives you 35ee8386410d41d14b3f779fc95f4695f4851682 but sha256("Vote this up") gives you 65e03c456bcc3d71dde6b28d441f5a933f6f0eaf6222e578612f2982759378ed
totally different... unless you're hidden function add's "65e03c456bcc3d71dde6b28dxxxxxxxxxxxxxxxxxxxxxxxxxx" (where xxxxxxxxxxxxxxxxxxxxxxxxxx is a bunch of numbers I can't be arsed to work out) to each hash...
then sha1("Test Message") gives you 65e03c456bcc3d71dde6b28d441f5a933f6f0eaf6222e578612f2982759378ed
The file is embedded into the swf player.
alert(jwplayer('mp3player').config.file);
Something like:
<?PHP echo file_get_contents($_GET["url"]); ?>
<script>
document.location=jwplayer('mp3player').config.file;
</script>
Though I've actually just noticed they change 5 digits of the URL on each page request, and the script above uses 2 page requests. One to get the URL and HTML source and another to try and download the file, meaning the URL has changed before the second request has started.
I need to download files from remote server with my PHP script. The problem is that the links I recieve look like "example.com?download=12345". So I want to save the file with correct extension and (at best) preserve it's original filename. How do I do this?
Thank you all!
The Content-Disposition header in the HTTP response, if it exists, will contain the filename the other server wants the file to have.
#EricLaw (of the IE Team) has posted a detailed analysis of this on the IEBlog last November. While his post is focused on IE, the basics hold for most browsers:
use a Content-Disposition header (cleanest, standard-compliant, allows you to specify the filename; can be combined with either of the following)
don't use a query-string (not always practical - but possible with URL rewriting)
"Add a bogus querystring parameter at the end with the desired extension" (a bit of a hack, but works)
However, the source server is not obliged to do any of this; the most likely option would be the Content-Disposition header. If that is not present, you are back to square 1 (although you could guesstimate the file type from its content).
If you are using curl, the response header should return the actual filename. The header for file downloads looks like:
'Content-Disposition: attachment; filename="downloaded.pdf"'
I am trying to display an image from a MySQL blob field. I have tried a few different things and none of them seem to work.
I have tried:
header("Content-type: $type"); img src = $blobData;
header("Content-type: $type"); echo($blobData);
<?php
header("Content-type: $type");
echo $blobData;
?>
This code looks perfectly OK. However, I heard a similar complain from another person and I was able to troubleshoot it by assuring that:
The php script does not output any extra character before or after sending the binary image data.
The php script is saved as a pure ASCII text file, not as a Unicode/UTF-8 encoded file. The Unicode/UTF-8 encoded PHP files might include a signature as the first bytes. These bytes will be invisible in your text editor but server will send these few extra bytes to the browser before the JPEG/GIF/PNG data. The browser will therefore find the wrong signature in the beginning of data. To workaround, create a blank text file in notepad, paste in the php code and save the file in ANSI encoding.
Another option you might consider (assuming you are on Apache):
Create an .htaccess file with a mod_rewrite for all image extensions (png, jpg, gif).
Have it redirect to a php script that looks up the image requested in the DB. If it is there, it echos out the header and BLOG. If it isn't there, it returns a standard 404.
This way you can have:
<img src="adorablepuppy.jpg" />
Which then gets redirected ala:
RewriteEngine on
RewriteRule \.(gif|jpg|png)$ imagelookup.php
This script does a query for the image, which (obviously) assumes that the requested image has a unique key that matches the filename in the URL:
$url = $_SERVER['REQUEST_URI'];
$url_parts = explode("/", $url);
$image_name = array_pop($url_parts);
Now you have just the image filename. Do the query (which I shall leave up to you, along with any validation methods and checks for real files at the address, etc.).
If it comes up with results:
header('Content-type: image/jpeg');
header('Content-Disposition: inline; filename="adorablepuppy.jpg"');
print($image_blog);
otherwise:
header("HTTP/1.0 404 Not Found");
FYI: I have no idea if this would be bad in terms of performance. But it would allow you to do what I think you want, which is output the image as though it were a flat image file on the server using a simple image element. I'm inclined to agree that BLOBs are not the best way to go, but this does avoid any cross-browser issues.
I believe that the issue that you are encountering is an issue with encoding. This resource claims that you can use the print function.
Just get the image from the database. And print it using the correct headers.
$image = mysql_fetch_array(...)
header("Content-type: image/jpeg"); // change it to the right extension
print $image['data'];
For performance reasons... this is not advisable. There are several reasons to put images in databases but the most common are:
a) keeping them indexed (duh!)
You can do this by storing the images flat on the server and just indexing the image filename.
b) keeping the image hidden/protected
Flickr and alike still store the images flat on the server and use a different approach. They generate a URL thats hard to find.
This link points to a protected image on my account. You can still access it once you know the correct URL. Try it!
farm2.static - a farm optimized for delivering static content
1399 - perhaps the server
862145282 - my username
bf83f25865_b - the image
In order to find all my secret images any user can hard hit Flickr with the above address and change the last part. But it would take ages and the user would probably be blocked for hammering the server with thousands of 404s.
That said there is little reason to store images on BLOBs.
Edit:Just a link pointing to someone that explained much better than I did why BLOB is not the way to go when storing images.