Ok, So i have a script that reads in a csv file and in there is a time that is formatted in the traditional HH:MM am/pm. I need to convert that into the mysql standard time format (HH:MM:SS).
This is what i have so far and it works
$schedule[$row]["TIME"] = date("H:i:s", strtotime($data[4]))
the problem is, if the input is formatted incorrectly there is no way i can tell. Is there some sort of "or die()" feature i can use or do i have to somehow check with a regex or something?
For example:
12:00 pm should be 12:00:00
but...if theres some issue with the format
12:d00 p.m comes out as 17:00:00
Thanks,
Ian
strtotime returns false if the parsing fails. So you can do:
$t = strtotime($data[4]);
if ($t === false)
//handle error
$schedule[$row]["TIME"] = date("H:i:s", $t);
Related
I'm working with an XML document that is returning variables and for some reason in a xml return the timestamp is formatted like this... 20180606T110000 ... why anyone would format it like that makes no sense to me; however, its what I have to work with. ITs formatted YYYYMMDD , the T is the split between date and time, HHMMSS. ITs set up in a 24 Hour clock that I also need to convert to 12 hr clock with am/pm
I need that formatted like 06/06/2018 11:00:00 AM.
Is there a way to do that via a date format (I know how to use date() but I don't know how to bring in that timestamp the way its formatted) or even separating it out into
$year = xxxx
$month = xx
$day = $xx
$Hour=xx
etc. etc. etc.
if need be.
I've briefly looked at php's date create from format ( date_create_from_format('j-M-Y', '15-Feb-2009') ) but dont fully understand how that works.
I've also thought about a split. I've also looked at chunk_split and wordwrap but its not even amounts of characters so that would be complex to create.
Any ideas?
The format you're working with is "XMLRPC (Compact)" format. This is fully supported by PHP (you can see a list of supported formats here). To get what you want, just use a combination of strtotime() and date().
$timestring = "20180606T110000";
$timestamp = strtotime($timestring);
echo date("m/d/Y h:i:s A", $timestamp);
You can use PHP DateTime to parse a datetime String with any format. Please view the Parameters format in the following link to understand how the "Ymd\THis" part works: http://php.net/manual/en/datetime.createfromformat.php
<?php
$time = "20180606T110000";
$date = DateTime::createFromFormat("Ymd\THis", $time);
// 06/06/2018 11:00:00 AM.
echo $date->format("d/m/Y h:i:s A");
I am new to PHP and I am trying to learn more of php date and time but I seem to get stuck with this.
I have this date format:
ddMMyyHHmmss
And an example is 120813125055 but I am trying to manipulate the string such that it will give me the format of:
yyyy-MM-dd HH:mm:ss (in the example above, 2013-08-12 12:50:55)
I tried to do something like:
date('Y-m-d H:i:s', strtotime('120813125055'));
But it always gives me a result of 1969-12-31 18:00:00.
I assume that I need to do some string manipulation in PHP for this but I was wondering if there is an easier and more efficient way to do it?
I think what you're looking for is in the second response answered here: how to re-format datetime string in php?
To summarize (and apply to your example), you could modify the code like this.
$datetime = "120813125055";
$d = DateTime::createFromFormat("dmyHis", $datetime);
echo $d->format("Y-m-d H:i:s");
Use date_create_from_format:
$ts = date_create_from_format('dmyHis', '120813125055');
$str = date('Y-m-d H:i:s', $ts);
strtotime() only works on EASILY recognizable formats. Your is a ugly mix of garbage, so no surprise that strtotime bails with a boolean FALSE for failure, which then gets typecast to an int 0 when you tried feed it back into date().
And of course, note that your time string is NOT y2k compliant. two digit years should never ever be used anymore, except for display purposes.
You're using your function call and the argument the wrong way around.
In your example, php will try to return you the date for which the time is 'strtotime('120813125055')', and this function returns false (interpreted as 0). So you get returned the date formatted in 'Y-m-d H:i:s' for the Unix epoch.
You will need to get the actual timestamp of your string, so use http://www.php.net/manual/en/datetime.createfromformat.php.
You are mistaken here..
I tried to do something like:
date('Y-m-d H:i:s', strtotime('120813125055'));
You shouldn't use only numbers ( doesnt matter its an integer or a string ), than it will always give you the same thing.
You can use any other valid date and time ( E.G. 6 Jun 2013, 5 may 12...) . Because what strtotime() do is detect a valid date and convert it into timestamp.
I need to convert a specific date format into local time (Europe/Sarajevo), I have the time in this format 2013-02-17T15:00:00Z which I don't really understand and this is why I don't know how to convert it to the Europe/Sarajevo time, who knows maybe it is already Sarajevo time, I don't know...
OK I can parse it and remove the T and Z and get a time but these letters mean something, probably they affect the result time...
The result time is for example 2013-02-17 18:00:00, probably there will be a difference due to the letters T and Z which are probably time offset.
Use DateTime. It's much better for working with timezones:
$datetime = new DateTime('2013-02-17T15:00:00Z');
$datetime->setTimeZone(new DateTimeZone('Europe/Sarajevo'));
echo $datetime->format('c');
Reference
DateTime
DateTimeZone
See it in action
You can use php date function like this
$date = '2013-02-17T15:00:00Z';
echo date('Y-m-d H:i:s',strtotime($date));
See the Manual
Okay so I have an array of results from a table, we have a start and end time we are retrieving. the start/end time would look something like this:
1345497551
Now I'm trying to convert this to a real time, for instance 1345497551 might become 2012/05/09 17:23:12 or something. I've found a few things but none seem to work correctly. one solution I tried, according to what someone was saying on another question on here, was
$createdate = date('H:i:s',$numberofsecs);
where $numberofsecs was the time pulled in from the array. but this only ever outputs 17:00:00 repeatedly for every time we had available for testing.
How can I go about making this work correctly?
Assuming that that's a standard unix timestamp string (seconds since midnight 1/1/1970), then you should be able to use date as you mentioned, but just modify the format string:
echo date('Y/m/d H:i:s', $numberofsecs);
The example you mention where you were always getting 17:00:00 could have been because your test cases were all only datestamps, encoded as timestamps, and having an offset from GMT . . .
I have tried below code:
$ts = 1345497551;
$date = new DateTime("#$ts");
echo $date->format('U = Y-m-d H:i:s');
output : 1345497551 = 2012-08-20 21:19:11
$t = DateTime::createFromFormat('Gi', '900');
$time_str = $t->format('gi a');
echo $time_str; //outputs 600 pm instead of 9am. Why? and How do I get 9am?
I am not sure where I am going wrong.. I am following what is given here in terms of date formatting:
http://php.net/manual/en/function.date.php
Thanks!
The documentation you linked is for the date() function. The DateTime::createFromFormat is not the same (though the format strings are pretty much identical).
I expect the format parsing is having trouble recognizing the difference between the hour and minute components.
If you split them up with a space, you get the desired result:
$t = DateTime::createFromFormat('G i', '9 00');
$time_str = $t->format('gi a');
echo $time_str;
// Output is 900 am
Edit:
The inability for PHP to parse a format string like Gi is a known bug. The parser for G doesn't know whether to read 9 or 90 and in the latter case that 90 is too high.
As i said in my comment this works :
$t = DateTime::createFromFormat('G i', '9 00');
$time_str = $t->format('gi a');
echo $time_str.PHP_EOL;
Cannot find any where written down - but suspect the time needs to be separated ... either by space or colon or something else