I want to generate a random number in PHP where the digits itself should not repeat in that number.
Is that possible?
Can you paste sample code here?
Ex: 674930, 145289. [i.e Same digit shouldn't come]
Thanks
Here is a good way of doing it:
$amountOfDigits = 6;
$numbers = range(0,9);
shuffle($numbers);
for($i = 0;$i < $amountOfDigits;$i++)
$digits .= $numbers[$i];
echo $digits; //prints 217356
If you wanted it in a neat function you could create something like this:
function randomDigits($length){
$numbers = range(0,9);
shuffle($numbers);
for($i = 0;$i < $length;$i++)
$digits .= $numbers[$i];
return $digits;
}
function randomize($len = false)
{
$ints = array();
$len = $len ? $len : rand(2,9);
if($len > 9)
{
trigger_error('Maximum length should not exceed 9');
return 0;
}
while(true)
{
$current = rand(0,9);
if(!in_array($current,$ints))
{
$ints[] = $current;
}
if(count($ints) == $len)
{
return implode($ints);
}
}
}
echo randomize(); //Numbers that are all unique with a random length.
echo randomize(7); //Numbers that are all unique with a length of 7
Something along those lines should do it
<?php
function genRandomString() {
$length = 10; // set length of string
$characters = '0123456789'; // for undefined string
$string ="";
for ($p = 0; $p < $length; $p++) {
$string .= $characters[mt_rand(0, strlen($characters))];
}
return $string;
}
$s = genRandomString(); //this is your random print var
or
function rand_string( $length )
{
$chars = "0123456789";
$size = strlen( $chars );
for( $i = 0; $i < $length; $i++ )
{
$str .= $chars[ rand( 0, $size – 1 ) ];
}
return $str;
}
$rid= rand_string( 6 ); // 6 means length of generate string
?>
$result= "";
$numbers= "0123456789";
$length = 8;
$i = 0;
while ($i < $length)
{
$char = substr($numbers, mt_rand(0, strlen($numbers)-1), 1);
//prevents duplicates
if (!strstr($result, $char))
{
$result .= $char;
$i++;
}
}
This should do the trick. In $numbers you can put any char you want, for example: I have used this to generate random passwords, productcodes etc.
The least amount of code I saw for something like this was:
function random_num($n=5)
{
return rand(0, pow(10, $n));
}
But I'm assuming it requires more processing to do this than these other methods.
Related
I have a function that generates a random 3-character alpha-numeric string. I need to modify it in such a way that the new string consisted of 2 alpha and 2 numeric characters. The combination of numbers and letters can be random.
function generate_random($length = 3) {
$characters = '123456789ABCDEFGHJKLMNPRSTUVWXYZ';
$rand_str = '';
for ($p = 0; $p < $length; $p++) {
$rand_str .= $characters[mt_rand(0, strlen($characters)-1)];
}
return $rand_str;
}
I need to modify it in such a way that the new string consisted of 2 alpha and 2 numeric characters. The combination of numbers and letters can be random. How do I do that?
I would personally do it this way:
function generate_random($countAlpha = 2, $countNumeric = 2, $randomize = true) {
$alpha = 'ABCDEFGHJKLMNPRSTUVWXYZ';
$numeric = '123456789';
$rand_str = '';
for ($p = 0; $p < $countAlpha; $p++) {
$rand_str .= $alpha[mt_rand(0, strlen($alpha)-1)];
}
for ($p = 0; $p < $countNumeric; $p++) {
$rand_str .= $numeric[mt_rand(0, strlen($numeric)-1)];
}
if($randomize) {
$rand_str = str_split($rand_str);
shuffle($rand_str);
return implode($rand_str);
}
return $rand_str;
}
Inside I have 2 for loops, each one based on parameters $countAlpha and $countNumeric. I also have a 3rd parameter, $randomize that will allow you to randomize the output if you wish.
You could separe numbers and letter. Then, append N values of each into an array, shuffle it, and the implode to get your string:
function generate_random($nNumbers = 2, $nAlpha = 2) {
// prepare data to use
$num = '123456789';
$numlen = strlen($num) - 1;
$alpha = 'ABCDEFGHJKLMNPRSTUVWXYZ';
$alphalen = strlen($alpha) - 1;
$out = []; // New array
// generate N numbers
for ($i = 0; $i < $nNumbers ; $i++) {
$out[] = $num[mt_rand(0, $numlen)];
}
// generate N letters
for ($i = 0; $i < $nAlpha ; $i++) {
$out[] = $alpha[mt_rand(0, $alphalen)];
}
shuffle($out); // Shuffle the array
return implode($out); // Convert to string
}
echo generate_random() ;
// echo generate_random(2, 4) ; // example
I need to generate random password with condition:
All characters are allowable except "l1o0"
Length of 8 to 12 in characters
Codes I've tried:
function generateRandomPassword() {
//Initialize the random password
$password = '';
//Initialize a random desired length
$desired_length = rand(8, 12);
for($length = 0; $length < $desired_length; $length++) {
//Append a random ASCII character (including symbols)
$password .= chr(rand(32, 126));
}
return $password;
}
How to avoid these 4 characters => "l1o0" ?
Reason:
These 4 characters are sometimes confused the user.
Thanks!
Please don't use any of the other answers currently provided for generating passwords. They're not secure by any measure.
rand() -> No
mt_rand() -> Definitely not
I'm going to pull this solution from a blog post aptly titled How to Securely Generate Random Strings and Integers in PHP.
/**
* Note: See https://paragonie.com/b/JvICXzh_jhLyt4y3 for an alternative implementation
*/
function random_string($length = 26, $alphabet = 'abcdefghijklmnopqrstuvwxyz234567')
{
if ($length < 1) {
throw new InvalidArgumentException('Length must be a positive integer');
}
$str = '';
$alphamax = strlen($alphabet) - 1;
if ($alphamax < 1) {
throw new InvalidArgumentException('Invalid alphabet');
}
for ($i = 0; $i < $length; ++$i) {
$str .= $alphabet[random_int(0, $alphamax)];
}
return $str;
}
Usage:
// Every ASCII alphanumeric except "loIO01":
$alphabet = 'abcdefghijkmnpqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ23456789';
$string = random_string(12, $alphabet);
You probably don't have random_int(), unless you're reading this in the future when PHP 7 is released. For those of us living in the present, use random_compat.
Try this:
function generateRandomPassword($length = 8) {
$characters = '23456789abcdefghjklmnpqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ';
$charactersLength = strlen($characters);
$randomPassword = '';
for ($i = 0; $i < $length; $i++) {
$randomPassword .= $characters[rand(0, $charactersLength - 1)];
}
return $randomPassword;
}
You don't need to change your code . just use str_replace to replace those word's You can try this solution :) . Just edited your code
function generateRandomPassword($length = 8) {
$characters = '23456789abcdefghjklmnpqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ';
$charactersLength = strlen($characters);
$randomPassword = '';
for ($i = 0; $i < $length; $i++) {
$randomPassword .= $characters[rand(0, $charactersLength - 1)];
}
return str_replace(['l','1','o','0'], ['A','B','C','D'], $randomPassword);
}
$string = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
$req_pword_len = 20;
$char_count = 0;
$password='';
$chars=str_split($string);
while ( $char_count < $req_pword_len ) {
$char = mt_rand(0,61);
$password .= (string) $chars[$char];
$char_count++;
}
Change the value for
$string to be just the characters you want to allow
$req_pword_len to the required length of the password
Try this:
function generateRandomPassword($length = 8) {
$randomPassword = '';
for ($i = 0; $i < $length; $i++) {
while (true) {
//remove 0,1,I,O,l,o
while(in_array(($number = rand(65, 122)), array(48, 49, 73, 79, 108, 111)));
if ($number <= 90 or $number >= 97) {
$randomPassword .= chr($number);
break ;
}
}
}
return $randomPassword;
}
echo generateRandomPassword();
I am using codes like "gjhyYhK", "HJjhkeuJ" etc. But want user to show these codes like:
gj_y__K
HJj__e_J
means code will be edited with "_" at random positions in code.
This will do what you want:
$str = "gjhyYhK";
$len = strlen($str);
$num_to_remove = ceil($len * .4); // 40% removal
for($i = 0; $i < $num_to_remove; $i++)
{
$k = 0;
do
{
$k = rand(1, $len);
} while($str[$k-1] == "_");
$str[$k-1] = "_";
}
print $str . "\n";
If you want more underscores, change the value of $underscores. This will guarantee you get how many underscores you want, so long as you want fewer than the length of the string
Try this:
$string=array(
'gjhyYhK',
'HJjhkeuJ'
);
$arr=array();
foreach ($string as $key=>$value) {
$arr[$key]='';
for ($i=1; $i <=strlen($value); $i++) {
if(rand(0,1)){
$arr[$key].=substr($string[$key],$i,1);
}else{
$arr[$key].='_';
}
}
}
var_dump($arr);
you can try below code to get the functionality what you are looking for
<?php
$string = "gjhyYhK";
$percentage = 40;
$total_length = strlen($string);
$number_of_underscore = floor(($percentage / 100) * $total_length); // I have use floor value, you can use ceil() as well
for ($i = 1; $i <= $number_of_underscore; $i++)
{
$random_position = rand(0, strlen($string) - 1); // get the random position of character to be replaced
if (substr($string, $random_position, 1) !== '_') // check if its already replaced underscore (_)
{
$string = preg_replace("/" . (substr($string, $random_position, 1)) . "/", '_', $string, 1); // here preg_replaced use to replace the character only once, (i.e str_replace() will replace all matching characters)
}
else
{
$i--; // else decrement $i for the loop to run one more time
}
}
echo $string;
?>
let me know if any other help needed
$str = "ADFJ";
$strlen = strlen($str);
$newStr = '';
for ($i = 0; $i < $strlen; $i++) {
if ($i == rand(0, $strlen)) {
$newStr .= '_';
} else {
$newStr .= $str[$i];
}
}
echo $newStr;
I wrote this function that creates a random string of UTF-8 characters. It works well, but the regular expression [^\p{L}] is not filtering all non-letter characters it seems. I can't think of a better way to generate the full range of unicode without non-letter characters.. short of manually searching for and defining the decimal letter ranges between 65 and 65533.
function rand_str($max_length, $min_length = 1, $utf8 = true) {
static $utf8_chars = array();
if ($utf8 && !$utf8_chars) {
for ($i = 1; $i <= 65533; $i++) {
$utf8_chars[] = mb_convert_encoding("&#$i;", 'UTF-8', 'HTML-ENTITIES');
}
$utf8_chars = preg_replace('/[^\p{L}]/u', '', $utf8_chars);
foreach ($utf8_chars as $i => $char) {
if (trim($utf8_chars[$i])) {
$chars[] = $char;
}
}
$utf8_chars = $chars;
}
$chars = $utf8 ? $utf8_chars : str_split('abcdefghijklmnopqrstuvwxyz');
$num_chars = count($chars);
$string = '';
$length = mt_rand($min_length, $max_length);
for ($i = 0; $i < $length; $i++) {
$string .= $chars[mt_rand(1, $num_chars) - 1];
}
return $string;
}
\p{L} might be catching too much. Try to limit to {Ll} and {LU} -- {L} includes {Lo} -- others.
With PHP7 and IntlChar there is now a better way:
function utf8_random_string(int $length) : string {
$r = "";
for ($i = 0; $i < $length; $i++) {
$codePoint = mt_rand(0x80, 0xffff);
$char = \IntlChar::chr($codePoint);
if ($char !== null && \IntlChar::isprint($char)) {
$r .= $char;
} else {
$i--;
}
}
return $r;
}
I was challenged by a friend to code some PHP to find the longest palindrome in provided text, my solution is below, how could I make it more efficient?
$string = file_get_contents("http://challenge.greplin.com/static/gettysburg.txt");
echo $string;
function isPalendrone($string) {
if ($string == strrev($string))
return true;
else
return false;
}
$longest = "";
for($i = 0; $i < strlen($string)-1; $i++) {
$afterCurrent = substr($string, $i);
for($j = 0; $j < strlen($afterCurrent)-1; $j++) {
$section = substr($afterCurrent, 0, $j);
if(isPalendrone($section)) {
if(strlen($longest)<strlen($section)) {
$longest = $section;
}
}
}
}
echo "<br /><br/>The longest was: ".$longest."<br /> which is ".strlen($longest)." chars long";
This reverses the entire string and just does substr() matches against each:
$rev = strrev($txt);
$len = strlen($txt);
$longest_len = 0;
$longest_str = null;
for ($i = 0; $i < $len; ++$i)
{
for ($j = $len - $i; $j > $longest_len; --$j)
{
if (substr($txt, $i, $j) == substr($rev, $len-$i-$j, $j))
{
$longest_len = $j;
$longest_str = substr($txt, $i, $j);
break;
}
}
}
I didn't try to optimize the implementation. e.g., It might be a little faster to skip the substr and do a char-by-char approach, because you could break out faster. In that case, you wouldn't really even need to reverse the string.
To get the longest palindrome - you have to start with longest string (not with shortest like you do now), check it and break on first match.
Also you'd better just keep 2 pointers ($i and $j) and not perform substr twice. It is enough to have i and j and substr once, right before you perform if(isPalendrone()) condition.
My implementation (~20% faster than yours):
<?php
$string = 'FourscoreandsevenyearsagoourfaathersbroughtforthonthiscontainentanewnationconceivedinzLibertyanddedicatedtothepropositionthatallmenarecreatedequalNowweareengagedinagreahtcivilwartestingwhetherthatnaptionoranynartionsoconceivedandsodedicatedcanlongendureWeareqmetonagreatbattlefiemldoftzhatwarWehavecometodedicpateaportionofthatfieldasafinalrestingplaceforthosewhoheregavetheirlivesthatthatnationmightliveItisaltogetherfangandproperthatweshoulddothisButinalargersensewecannotdedicatewecannotconsecratewecannothallowthisgroundThebravelmenlivinganddeadwhostruggledherehaveconsecrateditfaraboveourpoorponwertoaddordetractTgheworldadswfilllittlenotlenorlongrememberwhatwesayherebutitcanneverforgetwhattheydidhereItisforusthelivingrathertobededicatedheretotheulnfinishedworkwhichtheywhofoughtherehavethusfarsonoblyadvancedItisratherforustobeherededicatedtothegreattdafskremainingbeforeusthatfromthesehonoreddeadwetakeincreaseddevotiontothatcauseforwhichtheygavethelastpfullmeasureofdevotionthatweherehighlyresolvethatthesedeadshallnothavediedinvainthatthisnationunsderGodshallhaveanewbirthoffreedomandthatgovernmentofthepeoplebythepeopleforthepeopleshallnotperishfromtheearth';
function isPalendrone($string) {
return $string == strrev($string);
}
$longest = '';
$length = strlen($string);
for ($i = 0; $i < $length - 1; $i++) {
for ($j = $length - $i; $j > 1; $j--) {
if (isPalendrone(substr($string, $i, $j))) {
$new = substr($string, $i, $j);
if (strlen($new) > strlen($longest)) $longest = $new;
break;
}
}
}
echo "<br /><br/>The longest was: ".$longest."<br /> which is ".strlen($longest)." chars long";