How do I reindex an array after using unset()? - php

I'm having a little trouble with losing my array order after using unset(). This is the code I am using.
$id = $_GET['id'];
for ($i = 0; $i < count($my_array); $i++) {
if ($my_array[$i] == $id) {
unset($my_array[$i]);
}
}
Assume that $my_array has 4 items and $my_array[1] is equal to $id. After I unset that, I loop on $my_array and I get an Undefined Offset: 1 error. With print_r($my_array), I get $my_array[0], $my_array[2], and $my_array[3].
I understand perfectly why that's happening. Is there a way to re-index the array so that item 2 'drops' to item 1, and and the rest of the items respectively to the end of the array?
Something like reindex($my_array) would be sweet. I know I could run another for loop with a new array and transfer them manually, but a one step solution would be awesome. I just couldn't find anything anywhere.

Call array_values to reindex the array.

I just discovered you can also do a
array_splice($ar, 0, 0);
That does the re-indexing inplace, so you don't end up with a copy of the original array.

Related

Foreach loop over array of objects Laravel

I'm receiving this array of objects and need to iterate over it, but the problem is that I need to get the value of the next item when its iterating, to compare the value of the current object with the next one, and if it's a different value, split this array in two.
So, I was doing it with next() php function:
//looking for the next register in the array
$next = next($finances);
//first array if exist different values
$aiuaEd = [];
//second array if exist different values
$aiua = [];
foreach ($finances as $finance) {
if ($finance->cnpj <> $next->cnpj) {
$aiua[] = $finance;
} else {
$aiuaEd[] = $finance;
}
}
This code works fine at some point, but then I got this error:
Trying to get property 'cnpj' of non-object in
I don't know why sometimes works well and sometimes don't, debugging this variables, I found that if my array have 2 objects inside only, when I'm looping over it, the $next->cnpj variable came as empty, and sometimes don't.
Can someone help me with this?
I solved it with a different approach, instead of using php next(), I first loop over this array saving the cnpj's into an array.
$cnpjs = [];
foreach($finances as $finance){
$cnpj[] = $finance->cnpj;
}
Then I use array_unique() to group this 2 differents CNPJ's and sort() to get the correct keys order.
//grouping cnpjs as unique, should exist only 2 keys
$cnpj = array_unique($cnpj);
//sort array keys to get in order
sort($cnpj);
Then I iterate over my $finances array again, but now I'm counting if this $cnpj array has more than 2 positions, which means that I have to split this data in two differents arrays.
foreach($finances as $finance){
if(count($cnpj) > 1){
if($finance->cnpj == $cnpj[1]){
$aiua[] = $finance;
}else{
$aiuaEd[] = $finance;
}
}else{
$aiuaEd[] = $finance;
}
}
I'm pretty sure that this is not the best approach for that problem, or at least the most optimized one, so I'm open for new approach's suggestions!
Just posting how I solved my problem in case anyone having the same one.
Notice that this approach is only usable because I know that will not exist more than 2 different's CNPJ's in the array.

Undefined offset error when iterating array after removing elements from it

I receive the following error message:
Undefined offset: 1
It points to this block of code:
$nbrProgrammingsRemoved = 0;
for($i = 0; $i<count($this->products); $i++){
if((($this->products[$i])->id)==$id){
array_splice($this->products, $i, 1);
for($j = 0; $j<count($this->programming); $j++){
/*ERROR LINE*/ if((($this->programming[$j]->out_prod_id)==$id) || (($this->programming[$j]->in_prod_id)==$id)){
$nbrProgrammingsRemoved++;
array_splice($this->programming, $j, 1);
}
}
return true;
}
}
return false;
Specifically, the error points to the innermost if-statement. (The one with "||" in it).
Now, important to note is that this error does not always occur. It only ever happens after the following code has been run:
foreach ($this->programming as $key => &$prog) {
if($prog->in_prod_id == $in_prod_id){
if($prog->in_index == $in_index){
unset($this->programming[$key]);
}
}
}
The purpose of this code is to iterate through my objects in my array and remove those associated with a certain ID. This does appear to work since the output on my website is as expected. It's only when I, after doing this, attempt to execute the first code-block that my error occurs.
I've tried troubleshooting this for a while now, but without success. Any ideas? Any more information that you need me to post?
Edit: For further clarification, if needed, the 1st code block iterates through an array to remove a single element of a specified ID. The 2nd code block iterates through another array and removes several elements.
As far as I understand, you have an array with indexes comming in a sequence:
$programming = array(
0 => ...,
1 => ...,
2 => ...,
);
At some point you unset one element, so you array looks like this:
$programming = array(
0 => ...,
2 => ...,
);
And then you're using a for loop to iterate over all numbers from 0 up to N-1 (0, 1, 2, 3, 4 ... to be precise) presuming that all indexes are filled.
I think the best solution is to use a foreach loop in this case as it will care about indexes automatically and bypass deleted items.

Difference between array_push() and $array[] =

In the PHP manual, (array_push) says..
If you use array_push() to add one element to the array it's better to
use $array[] = because in that way there is no overhead of calling a
function.
For example :
$arr = array();
array_push($arr, "stackoverflow");
print_r($arr);
vs
$arr[] = "stackoverflow";
print_r($arr);
I don't understand why there is a big difference.
When you call a function in PHP (such as array_push()), there are overheads to the call, as PHP has to look up the function reference, find its position in memory and execute whatever code it defines.
Using $arr[] = 'some value'; does not require a function call, and implements the addition straight into the data structure. Thus, when adding a lot of data it is a lot quicker and resource-efficient to use $arr[].
You can add more than 1 element in one shot to array using array_push,
e.g. array_push($array_name, $element1, $element2,...)
Where $element1, $element2,... are elements to be added to array.
But if you want to add only one element at one time, then other method (i.e. using $array_name[]) should be preferred.
The difference is in the line below to "because in that way there is no overhead of calling a function."
array_push() will raise a warning if the first argument is not
an array. This differs from the $var[] behaviour where a new array is
created.
You should always use $array[] if possible because as the box states there is no overhead for the function call. Thus it is a bit faster than the function call.
array_push — Push one or more elements onto the end of array
Take note of the words "one or more elements onto the end"
to do that using $arr[] you would have to get the max size of the array
explain:
1.the first one declare the variable in array.
2.the second array_push method is used to push the string in the array variable.
3.finally it will print the result.
4.the second method is directly store the string in the array.
5.the data is printed in the array values in using print_r method.
this two are same
both are the same, but array_push makes a loop in it's parameter which is an array and perform $array[]=$element
Thought I'd add to the discussion since I believe there exists a crucial difference between the two when working with indexed arrays that people should be aware of.
Say you are dynamically creating a multi-dimensional associative array by looping through some data sets.
$foo = []
foreach ($fooData as $fooKey => $fooValue) {
foreach ($fooValue ?? [] as $barKey => $barValue) {
// Approach 1: results in Error 500
array_push($foo[$fooKey], $barKey); // Error 500: Argument #1 ($array) must be of type array
// NOTE: ($foo[$fooKey] ?? []) argument won't work since only variables can be passed by reference
// Approach 2: fix problem by instantiating array beforehand if it didn't exist
$foo[$fooKey] ??= [];
array_push($foo[$fooKey], $barKey);
// Approach 3: One liner approach
$foo[$fooKey][] = $barKey; // Instantiates array if it doesn't exist
}
}
Without having $foo[$fooKey] instantiated as an array beforehand, we won't be able to do array_push without getting the Error 500. The shorthand $foo[$fooKey][] does the heavy work for us, checking if the provided element is an array, and if it isn't, it creates it and pushes the item in for us.
I know this is an old answer but it might be helpful for others to know that another difference between the two is that if you have to add more than 2/3 values per loop to an array it's faster to use:
for($i = 0; $i < 10; $i++){
array_push($arr, $i, $i*2, $i*3, $i*4, ...)
}
instead of:
for($i = 0; $i < 10; $i++){
$arr[] = $i;
$arr[] = $i*2;
$arr[] = $i*3;
$arr[] = $i*4;
...
}
edit- Forgot to close the bracket for the for conditional
No one said, but array_push only pushes a element to the END OF THE ARRAY, where $array[index] can insert a value at any given index. Big difference.

php array count max value

If I have:
$mainarray = some array of things with some repeated values
$array_counted = array_count_values ($mainarray);
How can I find the maximum value in $array_counted?
(This would be the element that appeared most often in $mainarray I think. Its mostly a syntax issue as I am pretty sure I could loop it, but not sure of the syntax to use)
You can find first max value as
$main_array = array(1,2,3,4,5,6,6,6,6,6,6,6);
$max_val = max($main_array);
for find all of max vals
in php < 5.3
function findmax($val)
{
global $max_val;
return $val == $max_val;
}
$max_values_array = array_filter($main_array,'findmax');
in php >= 5.3
$max_values_array = array_filter($main_array,function($val) use ($max_val) { return $val == $max_val; });
echo count($max_values_array);
var_dump($max_values_array);
You could sort the array and take the first, respectively last item out of it, if you don't want to loop.
Since you associate the count with the values with that:
$array_counted = array_count_values ($mainarray);
You only need to sort it afterwards, and return the first key (which is the most occured element):
arsort($array_counted);
print key($array_counted); // returns first key
ok, the guy whos answer I used has deleted his comment so here is how I did it:
I used arsort($array_counted) to sort the array, while keeping index. rsort alone does not work as the result of array_count_values is an associative array. Thank you all.

Explode the results to add a nested tree to a database in PHP and order it

I'm using a nestedsortable jQuery plugin that gives me the order/sort of the elements serialized.
And example of this serialitzation (root means parent_id=0):
id[1]=root&id[5]=1&id[2]=1&id[3]=1&id[4]=3
First thing I'll do is explode by &:
$serialized = "id[1]=root&id[5]=1&id[2]=1&id[3]=1&id[4]=3";
$exploded = explode("&", $serialized);
But I don't know then how to manage a id[1]=root or id[3]=1. How I can do it?
And another question. In this way I don't know which is how to store the order. When I've the exploded with in array like array("id"=>1, "parent"=>"root"); I've to store the order. I will do it with an index, but how I recognise nested levels?
An example:
$i = 0;
foreach($exploded as $explode)
{
//update every id in MySQL and set parent=$explode["parent"] and order=$i
$i++;
}
But if I've N levels, how I can have a index $i for every one of them?
Thank you in advance!
Rather than exploding, you could try parse_str()
<?php
parse_str("id[1]=root&id[5]=1&id[2]=1&id[3]=1&id[4]=3",$result);
print_r($result);
?>
From there you can work with the array.

Categories