getting wrong IP address in php - php

Question

i have following php code to get vistor ip
function VisitorIP()
{
if(isset($_SERVER['HTTP_X_FORWARDED_FOR']))
$TheIp=$_SERVER['HTTP_X_FORWARDED_FOR'];
else $TheIp=$_SERVER['REMOTE_ADDR'];
return trim($TheIp);
}
$Users_IP_address = VisitorIP();
but every time i execute this script on my localhost i got ::1 as IP
how can i get exact internet IP & system IP address
because my script will run on LAN nwteork and i want to record IP of lan pcs & internet IP and save it in mysql database.
i need PHP code which privide local system IP and system internet IP.
Thanks

Answer 1

Technically, you are getting the right IP. ::1 is your loopback (localhost) IPv6 address.

Answer 2

First, throw this stupid function away, because HTTP_X_FORWARDED_FOR is not an IP address but merely an HTTP header, and make it just
$Users_IP_address = $_SERVER['REMOTE_ADDR'];
Next, you have to set up your server to work with ipv4, not ipv6.
Though it is not really a PHP question and should be asked on the serverfault, provided with full system setup: OS, version, your rights etc.

Answer 3

When you run above script on localhost you can get ::1 this result.
It's very common.
If you want to get your system IP address with localhost use this code.
1) Script for localhost
<?PHP
$ip = #file_get_contents("http://www.apps-tube.com/apps/ip-address/ip.php");
echo $ip;
?>
2) Script for Servers
<?PHP
function getUserIP()
{
$client = #$_SERVER['HTTP_CLIENT_IP'];
$forward = #$_SERVER['HTTP_X_FORWARDED_FOR'];
$remote = $_SERVER['REMOTE_ADDR'];
if(filter_var($client, FILTER_VALIDATE_IP))
{
$ip = $client;
}
elseif(filter_var($forward, FILTER_VALIDATE_IP))
{
$ip = $forward;
}
else
{
$ip = $remote;
}
return $ip;
}
$user_ip = getUserIP();
echo $user_ip; // Output IP address [Ex: 177.87.193.134]
?>