php array generation challenge - php

I need to randomly generate an two-dimensional n by n array. In this example, n = 10. The array should have this structure. One example:
$igra[]=array(0,1,2,3,4,5,6,7,8,9);
$igra[]=array(6,9,1,5,0,2,7,3,4,8);
$igra[]=array(2,5....................
$igra[]=array(1,7.....................
$igra[]=array(5,4...................
$igra[]=array(4,2...................
$igra[]=array(9,0.....................
$igra[]=array(8,3.....................
$igra[]=array(7,6....................
$igra[]=array(3,8....................
where
`$igra[x][z]!=$igra[y][z]` (x={0,9},y={0,9});
as you see it's like a matrix of numbers each row of it and column also consist from numbers 0-9, and there is never one number two times in each row or in each column.
how to generate such an array, and each time randomly.

Okay, so here's my version:
$n = 10;
$v1 = range(0, $n-1);
$v2 = range(0, $n-1);
shuffle($v1);
shuffle($v2);
foreach ($v1 as $x => $value)
foreach ($v2 as $y)
$array[$y][$x] = $value++ % $n;
This should be a really fast algorithm, because it involves only generating two random arrays and doesn't involve any swapping at all. It should be random, too, but I cannot prove it. (At least I don't know how to prove something like this.)
This is an optimized version of a very simple algorithm:
First a non-random matrix is created this way (imagine we want only 5*5, not 10*10):
0 1 2 3 4
1 2 3 4 0
2 3 4 0 1
3 4 0 1 2
4 0 1 2 3
In this matrix we now randomly swap columns. As we don't change the columns themselves your rules still are obeyed. Then we randomly swap rows.
Now, as you can see the above algorithm doesn't swap anything and it doesn't generate the above matrix either. That's because it generates the cols and rows to swap in advance ($v1 and $v2) and then directly writes to the correct position in the resulting array.
Edit: Just did some benchmarking: For $n = 500 it takes 0.3 seconds.
Edit2: After replacing the for loops with foreach loops it only takes 0.2 seconds.

This is what I did. Made a valid matrix (2d array) that isn't random. So starting out, row 0 is 0-9, row 1 is 1-0 (ie: 1,2,3...8,9,0), row 2 is 2-1 (2,3...9,0,1)...row 8 is 8-7...etc. Then shuffle that array to randomize the rows and perform a simple column swap to randomize the columns. Should get back exactly what you want. Try this:
<?php
//simple function to show the matrix in a table.
function show($matrix){
echo '<table border=1 cellspacing=0 cellpadding=5 style="float: left; margin-right:20px;">';
foreach($matrix as $m){
echo '<tr>';
foreach($m as $n){
echo '<td>'.$n.'</td>';
}
echo '</tr>';
}
echo '</table>';
}
//empty array to store the matrix
$matrix = array();
//this is what keeps the current number to put into matrix
$cnt = 0;
//create the simple matrix
for($i=0;$i<=9;$i++){
for($j=0;$j<=9;$j++){
$matrix[$i][$j] = $cnt % 10;
$cnt++;
}
$cnt++;
}
//display valid simple matrix
show($matrix);
//shuffle the rows in matrix to make it random
shuffle($matrix);
//display matrix with shuffled rows.
show($matrix);
//swap the columns in matrix to make it more random.
for($i=0;$i<=9;$i++){
//pick a random column
$r = mt_rand(0, 9);
//now loop through each row and swap the columns $i with $r
for($j=0;$j<=9;$j++){
//store the old column value in another var
$old = $matrix[$j][$i];
//swap the column on this row with the random one
$matrix[$j][$i] = $matrix[$j][$r];
$matrix[$j][$r] = $old;
}
}
//display final matrix with random rows and cols
show($matrix);
?>
In my solution, by not generating a random array and checking if it already exists, it should run much faster (especially if the array ever went above 0-9). When you get down to the last row, there is only one possible combination of numbers. You will be generating random arrays trying to find that one answer. It would be pretty much the same as picking a number from 1 to 10 and generating a random number until it hits the one you picked. It could be on the first try, but then again you could pick 1000 random numbers and never get the one you wanted.

Hmm.. I see you got some good answers already, but here's my version:
$n = 10;
$seed_row = range(0, $n - 1);
shuffle($seed_row);
$result = array();
for($x = 0; $x < $n; $x++)
{
$tmp_ar = array();
$rnd_start = $seed_row[$x];
for($y = $rnd_start; $y < ($n + $rnd_start); $y++)
{
if($y >= $n) $idx = $y - $n;
else $idx = $y;
$tmp_ar[] = $seed_row[$idx];
}
$result[] = $tmp_ar;
}
for($x = 0; $x < $n; $x++)
{
echo implode(', ', $result[$x]) . "<br/>\n";
}
sample output:
4, 3, 0, 2, 6, 5, 7, 1, 8, 9
0, 2, 6, 5, 7, 1, 8, 9, 4, 3
7, 1, 8, 9, 4, 3, 0, 2, 6, 5
2, 6, 5, 7, 1, 8, 9, 4, 3, 0
6, 5, 7, 1, 8, 9, 4, 3, 0, 2
9, 4, 3, 0, 2, 6, 5, 7, 1, 8
8, 9, 4, 3, 0, 2, 6, 5, 7, 1
5, 7, 1, 8, 9, 4, 3, 0, 2, 6
1, 8, 9, 4, 3, 0, 2, 6, 5, 7
3, 0, 2, 6, 5, 7, 1, 8, 9, 4
It creates a random random array as a starting point
Then it walks through the seed array taking each element as a starting point for itself to create a new base.

Related

How to efficiently sum paired array elements and avoid offset errors in case of pairless array?

Pair every two arrays is the task – store it, print it and repeat it until it becomes one value.
input : 1, 2, 3, 4, 5, 6, 8, 9, 9
output: 3 7 11 17 9
10 28 9
38 9
47
My code is working fine in this scenario. Somehow I managed to add 0 at the end for pairless elements. But my main focus is how can I make the logic even more clearer to avoid grumpy offset errors?.
My code:
function sumForTwos($arr)
{
if(count($arr) == 1){
exit;
}
else {
$sum = [];
for ($i = 0; $i < count($arr) -1; $i++)
{
//logic to add last array for odd count to avoid offset error
if(count($arr) % 2 == 1){ $arr[count($arr)] = 0; }
//logic to pair arrays
if($i != 0) { $i++; }
$sum = $arr[$i] + $arr[$i + 1];
$total[] = $sum;
echo $sum . " ";
}
echo "<br>";
$arr = $total;
//Recursion function
sumForTwos($arr);
}
}
sumForTwos([1, 2, 3, 4, 5, 6, 8, 9, 9]);
You can adopt an iterative approach and look at this as processing each level of values with every next level have 1 value less from total values. In other words, you can look at this as a breadth first search going level by level. Hence, you can use a queue data structure processing each level one at a time.
You can use PHP's SplQueue class to implement this. Note that we can advantage of this class as it acts as a double-ended queue with the help of below 4 operations:
enqueue - Enqueues value at the end of the queue.
dequeue - Dequeues value from the top of the queue.
push - Pushes value at the end of the doubly linked list(here, queue is implemented as doubly linked list).
pop - Pops a node from the end of the doubly linked list.
Most certainly, all the above 4 operations can be done in O(1) time.
Algorithm:
Add all array elements to queue.
We will loop till the queue size is greater than 1.
Now, if queue level size is odd, pop the last one and keep it in buffer(in a variable).
Add all pairwise elements by dequeueing 2 at a time and enqueue their addition for next level.
After level iteration, add the last element back if the previous level size was odd.
Print those added elements and echo new lines for each level accordingly.
Snippet:
<?php
function sumForTwos($arr){
if(count($arr) == 1){
echo $arr[0];
return;
}
$queue = new SplQueue();
foreach($arr as $val){
$queue->enqueue($val); // add elements to queue
}
while($queue->count() > 1){
$size = $queue->count();
$last = false;
if($size % 2 == 1){
$last = $queue->pop(); // pop the last odd element from the queue to make queue size even
$size--;
}
for($i = 0; $i < $size; $i += 2){
$first = $queue->dequeue();
$second = $queue->dequeue();
echo $first + $second," ";
$queue->enqueue($first + $second);
}
if($last !== false){// again add the last odd one out element if it exists
echo $last; // echo it too
$queue->push($last);
}
echo PHP_EOL;// new line
}
}
sumForTwos([1, 2, 3, 4, 5, 6, 8, 9, 9]);
Demo: http://sandbox.onlinephpfunctions.com/code/5b9f6d4c9291693ac7cf204af42d1f0ed852bdf9
Does this do what you want?
function pairBySums($inputArray)
{
if (sizeof($inputArray) % 2 == 1) {
$lastEntry = array_pop($inputArray); //$inputArray now has even number of elements
}
$answer = [];
for ($ii = 0; $ii < sizeof($inputArray) / 2; $ii++) {
$firstIndexOfPair = $ii * 2; // 0 maps to 0, 1 maps to 2, 3 maps to 4 etc
$secondIndexOfPair = $firstIndexOfPair + 1; // 0 maps to 1, 1 maps to 3, 2 maps to 5 etc
$answer[$ii] = $inputArray[$firstIndexOfPair] + $inputArray[$secondIndexOfPair];
}
if (isset($lastEntry)) {
array_push($answer, $lastEntry);
}
echo implode(' ', $answer) . "<br>";
if (sizeof($answer) > 1) {
pairBySums($answer);
}
}
The algorithm makes sure it operates on an even array and then appends the odd entry back on the array if there is one.
$input = [1, 2, 3, 4, 5, 6, 8, 9, 9];
pairBySums($input);
produces:
3 7 11 17 9
10 28 9
38 9
47
With an even number of items,
$input = [1, 2, 3, 4, 5, 6, 8, 9];
pairBySums($input);
produces:
3 7 11 17
10 28
38

PHP: Number of consecutive elements in array [closed]

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Improve this question
I have been working on one problem:
Find the largest group of consecutive numbers in an array.
Say we have an array [5, 43, 4, 56, 3, 2, 44, 57, 58, 1], the biggest group of consecutive numbers in this array is 5 (1, 2, 3, 4, and 5).
The solution algorithm must be time complexity of O(n).
I have solved this with the following ruby code but I am having trouble porting it to PHP as the solution requires.
arr = [8, 13, 14, 10, 6, 7, 8, 14, 5, 3, 5, 2, 6, 7, 4]
result = []
stage = []
for i in arr:
if len(stage) > 0 and i != stage[-1]+1:
if len(stage) > 1:
result.append(stage)
stage = []
stage.append(i)
print result
$a = [8, 13, 14, 10, 6, 7, 8, 14, 5, 3, 5, 2, 6, 7, 4];
$res = [];
$stage = [];
foreach($a as $i) {
if(count($stage) > 0 && $i != $stage[count($stage)-1]+1) {
if(count($stage) > 1) {
$res[] = $stage;
}
$stage = [];
}
$stage[] = $i;
}
print_r($res);
It's not O(n) but you can try this:
// Define array
$array = array(5,8,3,2,10,11,15,13,12,1,4,5,16);
// Sorting
asort($array);
$previous = null;
$result = array();
$consecutiveArray = array();
// Slice array by consecutive sequences
foreach($array as $number) {
if ($number == $previous + 1) {
$consecutiveArray[] = $number;
} else {
$result[] = $consecutiveArray;
$consecutiveArray = array($number);
}
$previous = $number;
}
$result[] = $consecutiveArray;
// Get length of each sub array
$count = array_map('count', $result);
You can get max length by max($count).
This solution gives you following array:
array(
0 => array(1,2,3,4,5)
1 => array(5)
2 => array(8)
3 => array(10,11,12,13)
4 => array(15,16)
Here is a python (my PHP is not too good) that does what your description asks, in o(n) if your sequence is decreasing:
lists = dict()
for i in val:
if i in lists:
continue
a = {i}
if (i + 1) in lists:
b = lists[i+1]
b.update(a)
a = b
if (i - 1) in lists:
b = lists[i-1]
# this messes up the complexity
for k in b:
lists[k] = a
a.update(b)
lists[i] = a
The idea is that lists maintain a dict of sets indexed on all the elements in the list. Whenever you encounter a new element, the previous and next sets are merged, if present.
The update operation is technically o(n), but it is not compounded by the external loop, as there can only be n insertion into sets by merging. The overall is o(n)
If the sequence is not sorted, the merge of the +1 and -1 sets gives a not-so-good complexity.

Finding prime and composite numbers in a string

I have the following randomly generated string:
$text = 's$bp4q1hsq3#g88nsjm5hr#i9#3078e2m';
What I need is to take all integers from it and classify them as either prime or composite numbers and estimate their sum. All numbers should be assumed that are one digit so this shortens the values to only four per each group:
$primes = array(2, 3, 5, 7);
$composites = array(4, 6, 8, 9);
This means: Primes: 5, 3, 3, 2 = 13 and Composites: 4, 8, 8, 9, 8 = 37 as duplicate numbers also count.
I have tried grabbing the numbers like so:
$asArray = str_split($text);
foreach ($asArray as $element) {
if (is_int($element)) {
echo $element;
}
}
But it seems to end up in a blank page. So my question is how can I find out the numbers in a string and then classify them as either prime or composite?
Here you have the sum of the primes and composites:
$text = 's$bp4q1hsq3#g88nsjm5hr#i9#3078e2m';
$primes = array(2, 3, 5, 7);
$sum_primes = $sum_composites = 0;
preg_match_all("/\d/", $text, $matches);
foreach($matches[0] as $number)
{
if (in_array($number, $primes))
$sum_primes += $number;
else
$sum_composites += $number;
}
echo "Sum of primes: ".$sum_primes."\n";
echo "Sum of composites: ".$sum_composites."\n";
It would print,
Sum of primes: 20
Sum of composites: 38

Generate numbers orderly

I want generate a range of numbers orderly. I mean opposite of rand function in php. I test with range but it generate only array of numbers
For example
min 1 and max 3
rand(1,3);// 2,1,3
but i want 1,2,3
Any in built in functions in php like rand for getting this features without using any loops?
Use range() to generate numbers
// array(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)
foreach (range(0, 12) as $number) {
echo $number;
}
You can achieve this using for loop
for ($i = 1; $i <= 3; $i++) {
echo $i;
}
// array(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)
foreach (range(0, 12) as $number) {
echo $number;
}
If you are using php then take a look at range function
If I understand your slightly missleading question.. this might do it:
$string = implode(', ', range(1,3));
echo $string;
And not a loop in sight :)
Or as a one liner:
echo implode(', ', range(1,3));

php/mysql compare arrays

My question:
I got a phpmyadmin database ( and using php 5),
with 2 tables to compare a football toto tournament.
the strings that i must compaire are like the following :
1|2|3|1|1|2|3|1|2|3|3
( in total 43 numbers) i know that i must use explode for taking out the "|" between them (because its saved as a string)
but the final score is also saved like that. so i must compare all (guessed outcomes from matches with the final score string. how do it do it so that i can see who has got the most guessed right?
And that it would be shown as 1e place, 2e place, 3e place and so on?
Would be a great help,
sorry if i lack at something.
I'm not entirely certain that I understand the question correctly, but if the two arrays are of the same length, you can use the same iterator for both of them.
After you've explode()d the strings into arrays:
$one = array(1, 2, 3, 4, 5);
$two = array(8, 2, 3, 6, 1);
$results = array();
for ($i = 0; $i < count($one); $i++) {
$results[$i] = $one[$i] - $two[$i];
}
Note that the above code is untested, and instead of whatever calculation you use, I just subtract the value of each $two element from each $one element.
Hope it helps.
if i understand the question well...
$guess = array(1, 2, 1, 3, 1, 2, 3);
$real = array(2, 2, 1, 2, 2, 1, 1);
$score = 0;
$length = count($real);
for($i = 0; $i < $length; $i++) {
if($guess[$i] == $real[$i])
++$score;
}
echo $score;

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