How can i execute a link in a php page - php

I have a test.php page
in this page , there is a url . i need to execute that url (here database updation is doing).This is my code
<?php
$username ='testUsername';
if($_GET['age']!=''){
header('location:www.test.com/update.php?age='.$_GET['age'].'&username='.$username); //need to updatethe age of this username
$show ='hello';
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
</head>
<body>
<?php echo $show ?>
</body>
</html>
i know this code is not going to work properly.How can i write in a good way.I donot want to redirect the page.I just need to execute that link

Just call file_get_contents on the url in question instead of setting the location header to that value.

Since the update.php file is hosted on an external website, the only thing you can do is get the contents of the output of the file. (Use file_get_contents to get that output.) That is, it will call the file (with your parameters) and you can fetch the HTML result of it—nothing more. It would be a major security problem if server files could be executed on external websites.

If you need to include the code in update.php without redirecting, you can do so with the include or require functions.
require() is identical to include()
except upon failure it will ... halt
the script whereas include() only
emits a warning (E_WARNING) which
allows the script to continue.

Use the IMG tag. <img widht=0 height=0 src="<?='location:www.test.com/update.php?age='.$_GET['age'].'&username='.$username ?>" />

Related

Codeigniter internationalization redirect index.php

I'm using Codeigniter and I did the internationalization using :
CI-internationalization
I would like to add /en by default when the user access my site :
www.mysite.com -> www.mysite.com/en
What is the best way to achieve that ?
Thank you.
HTML redirects
The simplest way to redirect to another URL is with the Meta Refresh tag. You can place this meta tag inside the <head> at the top of any HTML page like this:
<meta http-equiv="refresh" content="0; URL='http://www.new-site.com/en'" />
The content attribute is the delay before the browser redirects to the new page, above example it is set to 0 seconds.
JavaScript redirects
Redirecting to another URL with JavaScript is pretty easy, we simply have to change the location property on the window object:
window.location = "http://www.new-site.com/en";
OR
window.location.href = "http://www.new-site.com/en";
OR
window.location.assign("http://www.new-site.com/en");
OR
window.location.replace("http://www.new-site.com/en");
PHP redirects
<?php
header('Location: http://www.new-site.com/en', true, 301);
exit();
?>
This has to be set before any markup or content of any other sort, however there is one small hitch. By default the function sends a 302 redirect response which tells everyone that the content has only been moved temporarily. Considering our specific use case we'll need to permanently move the files over to our new website, so we'll have to make a 301 redirect instead.
The optional true parameter above will replace a previously set header and the 301 at the end is what changes the response code to the right one
Source: https://css-tricks.com/redirect-web-page/
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>
Testing page
</title>
<meta http-equiv="refresh" content="0; URL='new/test.html'" />
</head>
<body>
Old page
</body>
</html>
second/new page
<html>
<head>
<title>new site
</title>
</head>
<body>
this is new page.
</body>
</html>

Why does declaring objects voids the HTML in my Ajax page?

Background: I am building an Ajax page which will be called by a user's browser to retrieve data already loaded in $_SESSION. I want to test that the Ajax page works properly so I am trying to do a print_r($_SESSION) on it. (Note: the print_r() works fine on the main site.)
Problem: I cannot get my PHP to produce valid HTML. If I do:
<?php
header("Content-Type: text/html; charset=utf-8");
echo '<?xml version="1.0" encoding="utf-8" ?>';
if (!session_id()) {
session_start();
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" /> <!-- See http://www.w3.org/International/O-charset.en.php-->
<title>Test for Ajax</title>
<link rel="stylesheet" media="screen" type="text/css" title="StyleSheetProjet" href="StyleSheetProjet.css" />
</head>
<body>
<pre>
Content of $_SESSION:
<?php print_r($_SESSION) ?>
</pre>
</body>
</html>
In which case the page shows:
Content of $_SESSION:
Array
(
followed by a bunch of __PHP_Incomplete_Class Object (because the objects in session have not been declared I assume).
However if I start with:
header("Content-Type: text/html; charset=utf-8");
echo '<?xml version="1.0" encoding="utf-8" ?>';
//Obects in session:
require_once("Class_User.php");
require_once ('Class_Message.php');
if (!session_id()) {
session_start();
}
//(Rest is same as above)
Then the browser renders nothing at all, not even Content of $_SESSION:. In fact, the html in the web console is simply <html><head></head><body></body></html> with nothing in between...
What am I doing wrong?
Edit 1: to replace text/xml in the header() with text/html.
Edit 2: I replaced the two require_once with:
if (file_exists('Class_User.php')) {
echo "Class_User exists";
} else {
echo "Class_User doesn't exist";
}
if (file_exists('Class_Message.php')) {
echo "Class_Message exists";
} else {
echo "Class_Message doesn't exist";
}
The page does return Class_User existsClass_Message exists so it clearly can find the files.
Suspected Reason
require_once("Class_User.php"); and require_once("Class_Message.php"); are looking for the related files, cannot find them, so stop executing the rest of the code. Check if the path to Class_User.php and Class_Message.php are correct.
Actual Reason (we found working together w/ the OP after debugging)
One of the class files was extending another class and since that file was not included in the project the execution was being blocked. The OP solved the issue by calling another require() for this third class.

PHP + JQuery - How to use these two together? Please see my example

I have a php based website. As in, all of the pages html is output via php.
Here is a simple example:
<?php
ob_start();
$pageStart = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>MY WEBSITE PAGE</title>
</head>
<body>
<p>CONTENT</p>
</body>
</html>
';
echo $pageStart;
exit;
?>
What i would like to do is make use of some jquery in this page.
So naturally my first attempt was to include the script inside of the php variable like so:
<?php
ob_start();
$pageStart = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript">
var datefield=document.createElement("input")
datefield.setAttribute("type", "date")
if (datefield.type!="date"){ //if browser doesn't support input type="date", load files for jQuery UI Date Picker
document.write('<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css" />\n')
document.write('<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"><\/script>\n')
document.write('<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"><\/script>\n')
}
</script>
<script type="text/javascript">
if (datefield.type!="date"){ //if browser doesn't support input type="date", initialize date picker widget:
jQuery(function($){ //on document.ready
$('#birthday').datepicker();
})
}
</script>
</head>
<body>
<p>CONTENT</p>
</body>
</html>
';
echo $pageStart;
exit;
?>
Now, I use dreamweavers code editor, which due to the syntax highlighting feature, will point out the masses of syntax errors produced in this.
So i at first attempted to slash out these errors. This failed.
So i tried changing the "s to 's, and visa versa, until the errors were gone. This failed too as it seems the script will not validate in this manner.
So i read a few tutorials, and found this one:
JavaScript and PHP may each bring great potential to any Web development effort, but they don't always play nice together. Read about the problems.
And the way I understand it, is that you'd need to include the js rather than have it as part of your php directly.
So have a file called page.php and another called jquery.php. So I decided to try and modify this idea to suite my problem.
So i started with something like this - index.php:
<?php
ob_start();
$pageStart = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>MY WEBSITE PAGE</title>
'. include $_SERVER['DOCUMENT_ROOT'] . '/../../path/to/include/datepicker.php'.'
</head>
<body>
<p>CONTENT</p>
</body>
</html>
';
echo $pageStart;
exit;
?>
And - datepicker.php:
<script language="Javascript">
var datefield=document.createElement("input")
datefield.setAttribute("type", "date")
if (datefield.type!="date"){ //if browser doesn't support input type="date", load files for jQuery UI Date Picker
document.write('<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css" />\n')
document.write('<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"><\/script>\n')
document.write('<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"><\/script>\n')
}
</script>
<script language="Javascript">
if (datefield.type!="date"){ //if browser doesn't support input type="date", initialize date picker widget:
jQuery(function($){ //on document.ready
$('#birthday').datepicker();
})
}
</script>
Now there are no syntax errors in either page, great... So I try it, half expecting things to finally just work...
Nope... Fatal Error: failed to open stream: No such file or directory blah blah. This error relates to the include that i added. So okay, even though the file is there, it is not being validated as php because there are no opening and closing php tags.
So I add them... Annnd... A page full of syntax errors again!
So my question is this:
Could some please share some knowledge and explain to me roughly how this process actually works. Whats the deal with all the syntax errors, and how are you supposed to go about a task like this?
I believe it is possible, and yes it would ceratinly be easier if i was not outputting the entire html via php. But this is a simple example and my actual design is alot more complex. It requires for the different parts of the page to be broken up into variables, in order to place those bits and peices when needed, dynamically.
Any input, suggestions, or insight would be greatly appreciated; and any links to pages or tutorials that cover this would also be greatly appreciated.
Thank You!!
All you need to do to use jQuery with PHP is to include the jQuery javascript file in your HTML document in the head tag. I actually use PHP along with jQuery all the time. And this is how I do it. In your code above, it looks like you have some escaping issues with your code. And it also looks like you want to hold the header of the page in a PHP variable then print it out. You don't have to do all that. Just put the plain text in your PHP file without any php tags and it will work. Also, you are using an old version of jQuery. Should probably use the latest version. But, if you need it stored in a PHP variable so that you can print it out, do this:
SO, here is some code to get you started.
<?php
$pageStart = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>MY WEBSITE PAGE</title>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.17/themes/base/jquery-ui.css" rel="stylesheet" type="text/css" />
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.17/jquery-ui.min.js"></script>
<script type="text/javascript">
$(document).ready(function(e) {
$("#date").datepicker();
});
</script>
</head>
<body>
<input type="text" id="date" name="date" />
</body>
</html>';
print $pageStart;
?>
<head>
<script type="text/javascript"
src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
// javascript & jquery code
// even better would be if you would put client code in separate file!!!
});
</script>
</head>
<body>
<?php
echo "bla bla bla";
?>
</body>
and +1111 to # Heera's comment
You're missing the basics's.
Use Heredoc. Thousands of syntax errors will be gone.
See the heredoc version of your pages,
http://pastie.org/3412925
http://pastie.org/3412929
http://pastie.org/3412935 // Here you have used include to contact. include does not return anything. It just includes. So Its changed differently.
I think it should be
. (include ($_SERVER['DOCUMENT_ROOT'] . '/../../path/to/include/datepicker.php')) .
otherwise php will try to include all the stuff after until the l is reached (tags will be interpreted as part of the file name).
also, in terms of the php code, after the file is included (on success), the include statement translates into 1 as a number, instead of the content of the file.
use
<? $abc <<<qwerty
...
...
...
qwerty;
return qwerty;
?>
for all the files that you want to include

php include not working on IE?

This include is not working in IE:
<?php
include_once 'localization.php';
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>Global Colleague</title>
<link href="css/style.css" rel="stylesheet" type="text/css"/><!--Start Kampyle Exit-Popup Code-->
<script type="text/javascript">
Calling an array inside localization.php
<?php echo l('content_p3'); ?>
EDIT: I tried the same file in another folder and it worked
"Not working" is very generic. What is it that you expect and what is actually happening? You may want to turn error reporting on and see if any error is reported. In (X)HTML, nothing should be printed before the doctype. Are you trying to add something to the HTTP response? Typically, the browser shouldn't effect how PHP outputs your code unless you've added some code to respond to the user agent which is not always wise.
Perhaps, when you tried your code in another directory it wasn't able to find the offending script as it is included by a relative path. Try removing the include in the original file and see if it "works".
The following way 100% work for you:
1) Install (Open Source) Notepad++ On your PC
2) Open the file in it
3) Go to encoding and select (Encode in UTF-8 Without BOM)
4) Then click save
5) Now it can work on (Chrome) and (IE)
:)

Simple PHP Sessions Error

I have actually discovered my problem but I am really want to know why this is an issue. I had two pages form1.php I started a session on that page and hit submit. Then I had a link to session2.php which started that session and was able to pull the information from form1.php. I am just learning about sessions and this was a very simple exercise to learn what a session can do.
Here lies the issue, I had a stylesheet link in my head and it had a blank href well it was href="#" and when that was there the session2.php would not start the session from form1.php and grab the info from the form. Without that href="#" in the style tag it worked fine, and it also worked fine if it was a fake styletag href="something.css" but href="" doesn't work either.
Why is this? I only have those in because its a template I made for workflow, maybe I cant include the css link in my template anymore to prevent future issues.
You can see this site working here, if I haven't explained myself.
form1.php
<?php
session_start();
$_SESSION['name'] = $username;
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<title></title>
<!--//CSS STYLESHEETS//-->
<link rel="stylesheet" href="#" type="text/css">
</head>
<body>
Go to session 2
<!--form stuff is in here-->
</body
session2.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<title></title>
</head>
<body>
<?php
session_start();
$username = $_SESSION['name'];
echo $username;
?>
</body>
</html>
Your second page needs to look like this:
<?php
session_start();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html>
<head>
<title></title>
</head>
<body>
<?php
$username = $_SESSION['name'];
echo $username;
?>
</body>
</html>
Note that session_start() must appear before any content is printed to the screen.
Per the note on the session_start PHP manual page:
Note: To use cookie-based sessions, session_start() must be called before outputing anything to the browser.
To work like you want it, you need to have started the session first. Sounds simple, because it is. When you say session_start, php then looks for an accepted session cookie first to process content.
From http://php.net/manual/en/function.session-start.php
Note: To use cookie-based sessions, session_start() must be called before outputing anything to the browser.
Are you trying to output stuff to the page before you send the headers? What happens if you put the stylesheet after you call session_start()?

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