PHP closures and implicit global variable scope - php

Is there a way that one can implicitly declare top-level variables as global for use in closures?
For example, if working with code such as this:
$a = 0; //A TOP-LEVEL VARIABLE
Alpha::create('myAlpha')
->bind(DataSingleton::getInstance()
->query('c')
)
->addBeta('myBeta', function($obj){
$obj->bind(DataSingleton::getInstance()
->query('d')
)
->addGamma('myGamma', function($obj){
$obj->bind(DataSingleton::getInstance()
->query('a')
)
->addDelta('myDelta', function($obj){
$obj->bind(DataSingleton::getInstance()
->query('b')
);
});
})
->addGamma('myGamma', function($obj){
$a++; //OUT OF MY SCOPE
$obj->bind(DataSingleton::getInstance()
->query('c')
)
.
.
.
The closures are called from a method as such:
public function __construct($name, $closure = null){
$this->_name = $name;
is_callable($closure) ? $closure($this) : null;
}
So in summary/TL;DR, is there a way to implicitly declare variables as global for use in closures (or other functions I suppose) without making use of the global keyword or $GLOBALS super-global?
I started this topic at another forum I frequent (http://www.vbforums.com/showthread.php?p=3905718#post3905718)

You have to declare them in the closure definition:
->addBeta('myBeta', function($obj) use ($a) { // ...
Otherwise you must use the global keyword. You have to do this for every closure that uses $a too.

Related

How to access PHP variable on every part of a wordpress page? [duplicate]

I have code something like this:
<?
$a="localhost";
function body(){
global $a;
echo $a;
}
function head(){
global $a;
echo $a;
}
function footer(){
global $a;
echo $a;
}
?>
is there any way to define the global variable in one place and make the variable $a accessible in all the functions at once? without making use of global $a; more?
The $GLOBALS array can be used instead:
$GLOBALS['a'] = 'localhost';
function body(){
echo $GLOBALS['a'];
}
From the Manual:
An associative array containing references to all variables which are currently defined in the global scope of the script. The variable names are the keys of the array.
If you have a set of functions that need some common variables, a class with properties may be a good choice instead of a global:
class MyTest
{
protected $a;
public function __construct($a)
{
$this->a = $a;
}
public function head()
{
echo $this->a;
}
public function footer()
{
echo $this->a;
}
}
$a = 'localhost';
$obj = new MyTest($a);
If the variable is not going to change you could use define
Example:
define('FOOTER_CONTENT', 'Hello I\'m an awesome footer!');
function footer()
{
echo FOOTER_CONTENT;
}
If a variable is declared outside of a function its already in global scope. So there is no need to declare. But from where you calling this variable must have access to this variable. If you are calling from inside a function you have to use global keyword:
$variable = 5;
function name()
{
global $variable;
$value = $variable + 5;
return $value;
}
Using global keyword outside a function is not an error. If you want to include this file inside a function you can declare the variable as global.
// config.php
global $variable;
$variable = 5;
// other.php
function name()
{
require_once __DIR__ . '/config.php';
}
You can use $GLOBALS as well. It's a superglobal so it has access everywhere.
$GLOBALS['variable'] = 5;
function name()
{
echo $GLOBALS['variable'];
}
Depending on your choice you can choose either.
Add your variables in $GLOBALS super global array like
$GLOBALS['variable'] = 'localhost';
and use it globally as
echo $GLOBALS['variable']
or you can use constant which are accessible throughout the script
define('HOSTNAME', 'localhost');
usage for define (NOTE - without the dollar)
echo HOSTNAME;
This answer is very late but what I do is set a class that holds Booleans, arrays, and integer-initial values as global scope static variables. Any constant strings are defined as such.
define("myconstant", "value");
class globalVars {
static $a = false;
static $b = 0;
static $c = array('first' => 2, 'second' => 5);
}
function test($num) {
if (!globalVars::$a) {
$returnVal = 'The ' . myconstant . ' of ' . $num . ' plus ' . globalVars::$b . ' plus ' . globalVars::$c['second'] . ' is ' . ($num + globalVars::$b + globalVars::$c['second']) . '.';
globalVars::$a = true;
} else {
$returnVal = 'I forgot';
}
return $returnVal;
}
echo test(9); ---> The value of 9 + 0 + 5 is 14.
echo "<br>";
echo globalVars::$a; ----> 1
The static keywords must be present in the class else the vars $a, $b, and $c will not be globally scoped.
You can try the keyword use in Closure functions or Lambdas if this fits your intention... PHP 7.0 though. Not that's its better, but just an alternative.
$foo = "New";
$closure = (function($bar) use ($foo) {
echo "$foo $bar";
})("York");
demo |
info
You can declare global variables as static attributes:
class global {
static $foo = "bar";
}
And you can use and modify it every where you like, like:
function echoFoo() {
echo global::$foo;
}
You answered this in the way you wrote the question - use 'define'. but once set, you can't change a define.
Alternatively, there are tricks with a constant in a class, such as class::constant that you can use. You can also make them variable by declaring static properties to the class, with functions to set the static property if you want to change it.
What if you make use of procedural function instead of variable and call them any where as you.
I usually make a collection of configuration values and put them inside a function with return statement. I just include that where I need to make use of global value and call particular function.
function host()
{
return "localhost";
}
$GLOBALS[] is the right solution, but since we're talking about alternatives, a function can also do this job easily:
function capital() {
return my_var() . ' is the capital of Italy';
}
function my_var() {
return 'Rome';
}

PHP use variable defined outside of function [duplicate]

I have code something like this:
<?
$a="localhost";
function body(){
global $a;
echo $a;
}
function head(){
global $a;
echo $a;
}
function footer(){
global $a;
echo $a;
}
?>
is there any way to define the global variable in one place and make the variable $a accessible in all the functions at once? without making use of global $a; more?
The $GLOBALS array can be used instead:
$GLOBALS['a'] = 'localhost';
function body(){
echo $GLOBALS['a'];
}
From the Manual:
An associative array containing references to all variables which are currently defined in the global scope of the script. The variable names are the keys of the array.
If you have a set of functions that need some common variables, a class with properties may be a good choice instead of a global:
class MyTest
{
protected $a;
public function __construct($a)
{
$this->a = $a;
}
public function head()
{
echo $this->a;
}
public function footer()
{
echo $this->a;
}
}
$a = 'localhost';
$obj = new MyTest($a);
If the variable is not going to change you could use define
Example:
define('FOOTER_CONTENT', 'Hello I\'m an awesome footer!');
function footer()
{
echo FOOTER_CONTENT;
}
If a variable is declared outside of a function its already in global scope. So there is no need to declare. But from where you calling this variable must have access to this variable. If you are calling from inside a function you have to use global keyword:
$variable = 5;
function name()
{
global $variable;
$value = $variable + 5;
return $value;
}
Using global keyword outside a function is not an error. If you want to include this file inside a function you can declare the variable as global.
// config.php
global $variable;
$variable = 5;
// other.php
function name()
{
require_once __DIR__ . '/config.php';
}
You can use $GLOBALS as well. It's a superglobal so it has access everywhere.
$GLOBALS['variable'] = 5;
function name()
{
echo $GLOBALS['variable'];
}
Depending on your choice you can choose either.
Add your variables in $GLOBALS super global array like
$GLOBALS['variable'] = 'localhost';
and use it globally as
echo $GLOBALS['variable']
or you can use constant which are accessible throughout the script
define('HOSTNAME', 'localhost');
usage for define (NOTE - without the dollar)
echo HOSTNAME;
This answer is very late but what I do is set a class that holds Booleans, arrays, and integer-initial values as global scope static variables. Any constant strings are defined as such.
define("myconstant", "value");
class globalVars {
static $a = false;
static $b = 0;
static $c = array('first' => 2, 'second' => 5);
}
function test($num) {
if (!globalVars::$a) {
$returnVal = 'The ' . myconstant . ' of ' . $num . ' plus ' . globalVars::$b . ' plus ' . globalVars::$c['second'] . ' is ' . ($num + globalVars::$b + globalVars::$c['second']) . '.';
globalVars::$a = true;
} else {
$returnVal = 'I forgot';
}
return $returnVal;
}
echo test(9); ---> The value of 9 + 0 + 5 is 14.
echo "<br>";
echo globalVars::$a; ----> 1
The static keywords must be present in the class else the vars $a, $b, and $c will not be globally scoped.
You can try the keyword use in Closure functions or Lambdas if this fits your intention... PHP 7.0 though. Not that's its better, but just an alternative.
$foo = "New";
$closure = (function($bar) use ($foo) {
echo "$foo $bar";
})("York");
demo |
info
You can declare global variables as static attributes:
class global {
static $foo = "bar";
}
And you can use and modify it every where you like, like:
function echoFoo() {
echo global::$foo;
}
You answered this in the way you wrote the question - use 'define'. but once set, you can't change a define.
Alternatively, there are tricks with a constant in a class, such as class::constant that you can use. You can also make them variable by declaring static properties to the class, with functions to set the static property if you want to change it.
What if you make use of procedural function instead of variable and call them any where as you.
I usually make a collection of configuration values and put them inside a function with return statement. I just include that where I need to make use of global value and call particular function.
function host()
{
return "localhost";
}
$GLOBALS[] is the right solution, but since we're talking about alternatives, a function can also do this job easily:
function capital() {
return my_var() . ' is the capital of Italy';
}
function my_var() {
return 'Rome';
}

Create and use global variable without the 'global' keyword?

As of now I create a variable like this in a file that's loaded on all pages:
<?php
add_action( 'parse_query', 'my_global_vars' );
function my_global_vars() {
/* CUSTOM GLOBAL VARIABLES */
$variable_name = get_query_var('category_name');
}
?>
And every time I want to use it (in other files), I must do it like this:
<?php
global $variable_name;
if( $variable_name = 'news' ){
// Do something
}
?>
And when I need to use the variable multiple times in the same file, I add global $variable_name; at the top of the file, and simply use $variable_name in rest of the instances.
But as the number of variables increase, I find it harder to manage the list of global $variable_names at the top of all files.
Is there a way to define a variable as global at the time of creation and simply use $variable_name everywhere else?
EDIT: One way is to define variable like this:
<?php
add_action( 'parse_query', 'my_global_vars' );
function my_global_vars() {
/* CUSTOM GLOBAL VARIABLES */
global $variable_name;
$variable_name = get_query_var('category_name');
}
?>
And use it like using $GLOBALS[] like this $GLOBALS['variable_name'] elsewhere.
Having a lot of global vars is usually bad. It becomes a mess very quickly.
If you really need global variables the best approach is to use static class variables. They are just as global as the others, but they enforce better naming and pre-declaration so the end result is somewhat better.
If you really need normal global vars you can also use the $GLOBALS variable, it is available in every scope and is basically an array of all the global variables.
global $variable_name;
do_something_with($variable_name);
is the same as
do_something_with($GLOBALS['variable_name']);
You can use a static class for this and keep it OOP:
<?php
class GlobalVariables {
private static $vars = array();
public static function get($name, $default = null) {
return (isset(self::$vars[$name]) ? self::$vars[$name] : $default);
}
public static function set($name, $value) {
self::$vars[$name] = $value;
}
}
function foo() {
GlobalVariables::set('foo', 'oof');
}
function bar() {
var_dump( GlobalVariables::get('foo') );
}
foo();
bar(); //oof
?>
DEMO
Alternatively, you can use a Singleton pattern:
<?php
class GlobalVariables {
private static $instance;
private $vars = array();
public static function get() {
if (empty(self::$instance)) {
self::$instance = new GlobalVariables();
}
return self::$instance;
}
public function __get($name) {
return (isset($this->vars[$name]) ? $this->vars[$name] : null);
}
public function __set($name, $value) {
$this->vars[$name] = $value;
}
}
function foo() {
GlobalVariables::get()->foo = 'oof';
}
function bar() {
var_dump( GlobalVariables::get()->foo );
}
foo();
bar(); //oof
?>
DEMO.
Use whichever you find most readable.
GlobalVariables::set('key', 'value');
GlobalVariables::get('key');
or
GlobalVariables::get()->key = 'value';
GlobalVariables::get()->key;
Completely alternatively, if you hate dynamicness, simply use static variables (this, however, requires you to create all variables beforehand):
<?php
class GlobalVariables {
public static $foo;
}
GlobalVariables::$foo = 'oof';
var_dump( GlobalVariables::$foo );
?>
Using global outside a function doesn't do anything. It's meant for inside functions. You can simply remove your global statements.
Edit: I suggest that you try to reduce the number of global variables you have by structuring them. Group them into arrays or objects. E.g., instead of user_name, user_id, user_is_admin, prefer user['name'], user['id'], user['is_admin'], then you only have one variable (user) to declare as global instead of three.

PHP Redefine a closure with bind() and its scope [duplicate]

When using anonymous functions in PHP, you can easily use variables from right outside of its scope by using the use() keyword.
In my case the anonymous functions are already defined somewhere, but called later on (somewhere else) in a class.
The following piece of code is to illustrate the idea:
<?php
$bla = function ( $var1 ) use ($arg)
{
echo $var1;
};
class MyClass
{
private $func;
public function __construct ( $func )
{
$this->func = $func;
}
public function test ( $arg )
{
$closure = $this->func;
$closure ( 'anon func' );
}
}
$c = new MyClass($bla);
$c->test ( 'anon func' );
What i'm doing is i create an anonymous function and store that in a variable. I pass that variable to the method of a class and that is where i want to run the anonymous function.
But i can't use the use() keyword to get the $arg parameter from the method this way. Because the anonymous function was declared outside of the method.
But i really need a way to get the variables from the method where the anonymous function is run from. Is there a way to do that, when the anonymous function is declared somewhere else..?
The point of the use keyword is to inherit/close over a particular environment state from the parent scope into the Closure when it's defined, e.g.
$foo = 1;
$fn = function() use ($foo) {
return $foo;
};
$foo = 2;
echo $fn(); // gives 1
If you want $foo to be closed over at a later point, either define the closure later or, if you want $foo to be always the current value (2), pass $foo as a regular parameter.
FWIW, you can do it if you use a use reference (php.net ex 3.3) and a global, ugly since it uses globals, but just to put it out there:
<?php
$bla = function ( $var1 ) use (&$arg)
{
return "var1:$var1, arg:$arg";
};
class MyClass
{
private $func;
public function __construct ( $func )
{
$this->func = $func;
}
public function test ( $param )
{
global $arg;
$arg=$param;
$closure = $this->func;
return $closure ( 'anon func' );
}
}
$c = new MyClass($bla);
echo $c->test ( 'bla bla' ); //var1:anon func, arg:bla bla

Use variables inside an anonymous function, which is defined somewhere else

When using anonymous functions in PHP, you can easily use variables from right outside of its scope by using the use() keyword.
In my case the anonymous functions are already defined somewhere, but called later on (somewhere else) in a class.
The following piece of code is to illustrate the idea:
<?php
$bla = function ( $var1 ) use ($arg)
{
echo $var1;
};
class MyClass
{
private $func;
public function __construct ( $func )
{
$this->func = $func;
}
public function test ( $arg )
{
$closure = $this->func;
$closure ( 'anon func' );
}
}
$c = new MyClass($bla);
$c->test ( 'anon func' );
What i'm doing is i create an anonymous function and store that in a variable. I pass that variable to the method of a class and that is where i want to run the anonymous function.
But i can't use the use() keyword to get the $arg parameter from the method this way. Because the anonymous function was declared outside of the method.
But i really need a way to get the variables from the method where the anonymous function is run from. Is there a way to do that, when the anonymous function is declared somewhere else..?
The point of the use keyword is to inherit/close over a particular environment state from the parent scope into the Closure when it's defined, e.g.
$foo = 1;
$fn = function() use ($foo) {
return $foo;
};
$foo = 2;
echo $fn(); // gives 1
If you want $foo to be closed over at a later point, either define the closure later or, if you want $foo to be always the current value (2), pass $foo as a regular parameter.
FWIW, you can do it if you use a use reference (php.net ex 3.3) and a global, ugly since it uses globals, but just to put it out there:
<?php
$bla = function ( $var1 ) use (&$arg)
{
return "var1:$var1, arg:$arg";
};
class MyClass
{
private $func;
public function __construct ( $func )
{
$this->func = $func;
}
public function test ( $param )
{
global $arg;
$arg=$param;
$closure = $this->func;
return $closure ( 'anon func' );
}
}
$c = new MyClass($bla);
echo $c->test ( 'bla bla' ); //var1:anon func, arg:bla bla

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