I have url like this
/cp/foo-bar/another-testing
how to parse it with the pattern
/cp/{0}-{1}/{2}
results will be
0:foo
1:bar
2:another-testing
I need a global solution to parse all kind of url with a pattern like that. I mean using {0}, {1} flag.
if (preg_match('#/cp/([^/]+?)-([^/]+?)/([^/]+)#'), $url, $matches)) {
//look into $matches[1], $matches[2] and $matches[3]
}
Instead of using {0}, {1}, {2}, I offer a new way: using {$s[0]}, {$s[1]}, {$s[2]}:
$your_url = '/cp/foo-bar/another-testing';
$s = explode('/', $your_url);
if(!$s[0])
array_shift($s);
if($temp = array_pop($s))
$s[] = $temp;
//then
$result = "/cp/{$s[0]}-{$s[1]}/{$s[2]}";
Related
I had a php file already using regex to extract m3u8 link from youtube, which was working fine until last week.
http://server.com/youtube.php?id=youtbueid
use to pass the youtube id like this.
$string = get_data('https://www.youtube.com/watch?v=' . $channelid);
if(preg_match('#"hlsManifestUrl.":."(.*?m3u8)#', $string, $match)) {
$var1=$match[1];
$var1=str_replace("\/", "/", $var1);
$man = get_data($var1);
//echo $man;
preg_match_all('/(https:\/.*\/95\/.*index.m3u8)/U',$man,$matches, PREG_PATTERN_ORDER);
$var2=$matches[1][0];
header("Content-type: application/vnd.apple.mpegurl");
header("Location: $var2");
}
else {
preg_match_all('#itag.":([^,]+),."url.":."(.*?).".*?qualityLabel.":."(.*?)p."#', $string, $match);
//preg_match_all('#itag.":([^,]+),."url.":."(.*?).".*?bitrate.":.([^,]+),#', $string, $match);
$filter_keys = array_filter($match[3], function($element) {
return $element <= 720;
});
//print_r($filter_keys);
$max_key = array_keys($filter_keys, max($filter_keys))[0];
//print_r($max_key);
$urls = $match[2];
foreach($urls as &$url) {
$url = str_replace('\/', '/', $url);
$url = str_replace('\\\u0026', '&', $url);
}
print_r($urls[$max_key]);
header('location: ' . $urls[$max_key]);
How do I solve this problem?
Based on this post, I'm guessing that the desired URLs might look like:
and we can write a simple expression such as:
(.+\?v=)(.+)
We can also add more boundaries to it, if it was necessary.
RegEx
If this expression wasn't desired, you can modify/change your expressions in regex101.com.
RegEx Circuit
You can also visualize your expressions in jex.im:
PHP Test
$re = '/(.+\?v=)(.+)/m';
$str = ' https://www.youtube.com/watch?v=_Gtc-GtLlTk';
$subst = '$2';
$result = preg_replace($re, $subst, $str);
echo $result;
JavaScript Demo
This snippet shows that we likely have a valid expression:
const regex = /(.+\?v=)(.+)/gm;
const str = ` https://www.youtube.com/watch?v=_Gtc-GtLlTk`;
const subst = `$2`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
how to get id url with preg_replace.
this is the link:
http://www.DDDD.com.br/photo/5b87f8eaa7c20f79c3257eb3ec0a35e0/id how do I get the id? in the case would be: 5b87f8eaa7c20f79c3257eb3ec0a35e0
In this case I recommend not to use preg_match (preg_replace would be used to replace something.
Simply use
$array = explode('/',$_SERVER['REQUEST_URI']);
$id = $array[1];
If you must use preg_match:
$array = array();
preg_match('#^/photo/([0-9a-f]{32})/id$#',$_SERVER['REQUEST_URI'],$array);
$id = $array[1];
You can do this easily using strripos to find the last / in the URL.
$url = $_SERVER['REQUEST_URI'];
if (($pos = strripos($url, '/')) !== false) {
$id = substr($url, $pos + 1);
}
else {
trigger_error('You must supply a valid photo ID');
}
If you would like to just extract that id string, you can use:
$id_url = "http://www.DDDD.com.br/photo/5b87f8eaa7c20f79c3257eb3ec0a35e0/id";
$pattern = "/photo\/([a-zA-Z0-9]*)/";
preg_match($pattern, $id_url, $output_array);
echo $output_array[1];
Or, to make the replacement:
$id_url = "http://www.DDDD.com.br/photo/5b87f8eaa7c20f79c3257eb3ec0a35e0/id";
$pattern = "/photo\/([a-zA-Z0-9]*)/";
$replacement = "your replacement";
$replaced_url = preg_replace($pattern, $replacement, $id_url);
echo $replaced_url;
PHP Live Regex - a useful tool for testing your patterns
This is probably simple however I am not the best with expressions..
I am trying to get the following string from..
http://www.yoursite.com/offers/838?&SITEID=2172
to this.. using an expression that will remove the ?&SITEID and the dynamic id which will vary
http://www.yoursite.com/offers/838
Can anyone suggest the best/simplest method to do this?
Check this function:
$str = 'http://www.yoursite.com/offers/838?&SITEID=2172';
function remove_query_arg($var, $url = NULL){
if(!$url){
$url = $_SERVER['REQUEST_URI'];
}
$parsed_url = parse_url($url);
$query_vars = explode('&', $parsed_url['query']);
foreach($query_vars as $key => $value){
$query_vars[$key] = explode('=', $query_vars[$key]);
$query_variables[$query_vars[$key][0]] = $query_vars[$key][1];
}
if(is_array($var)){
foreach($var as $value){
unset($query_variables[$value]);
}
}
elseif(is_string($var)){
unset($query_variables[$var]);
}
$query_vars = array();
foreach($query_variables as $key => $value){
$query_vars[] = $key.($value !== NULL || !empty($value) ? '='.$value : '');
}
$query_str = '';
$query_str = implode('&',$query_vars);
return (isset($parsed_url['scheme']) && !empty($parsed_url['scheme']) ? $parsed_url['scheme'].'://' : '').$parsed_url['host'].(isset($parsed_url['path']) && !empty($parsed_url['path']) ? $parsed_url['path'] : '').(!empty($query_str) ? '?'.$query_str : '');
}
echo remove_query_arg('SITEID', $str);
This is a URL, so parse it as one, with parse_url().
$url = "http://www.yoursite.com/offers/838?&SITEID=2172";
$parts = parse_url($url);
$url = $parts["scheme"] . "://" . $parts["host"] . $parts["path"];
Using explode function returns an array
$url=http://www.yoursite.com/offers/838?&SITEID=2172
$result=explode('?',$url)
print_r($result);
output
array
{
[0]=>http://www.yoursite.com/offers/838
[1]=>?&SITEID=2172
}
A valid URL only has one ? so you can just use explode to break it into 2 parts
$url = "http://www.yoursite.com/offers/838?&SITEID=2172";
list($path, $query) = explode("?", $url, "2");
var_dump($path);
Output
string 'http://www.yoursite.com/offers/838' (length=34)
$url = "http://www.yoursite.com/offers/838?&SITEID=2172";
$str = substr($url, strpos($url, 0, "?&SITEID"));
// $str results in "http://www.yoursite.com/offers/838"
If you want to keep the part before the ? you can search
^(.+?)(\?&SITEID|$)
and replace with
$1
You search non greedily from the beginning of the line ^ to the first ?&SITEID and leave out the rest. If no ?&SITEID is found you get the entire line by arriving at the end of the string with $
| is the OR operator that tells the regex "Stop at the first ?&SITEID or at the end of the string"
EDIT:
After the comment where you explain your need to keep the rest of the querystring I suggest you a different approach: find
&?SITEID=[^&\s]+
being
&? an optional & at the beginning of the string
SITEID= the string you are looking for followed by
[^&\s]+ any number of non&, nonspace character
and remove it from the string. However, being this the case, I'd go with a non-regex, url-specific approach like suggested in the other answers.
I have a string in PHP that is a URI with all arguments:
$string = http://domain.com/php/doc.php?arg1=0&arg2=1&arg3=0
I want to completely remove an argument and return the remain string. For example I want to remove arg3 and end up with:
$string = http://domain.com/php/doc.php?arg1=0&arg2=1
I will always want to remove the same argument (arg3), and it may or not be the last argument.
Thoughts?
EDIT: there might be a bunch of wierd characters in arg3 so my prefered way to do this (in essence) would be:
$newstring = remove $_GET["arg3"] from $string;
There's no real reason to use regexes here, you can use string and array functions instead.
You can explode the part after the ? (which you can get using substr to get a substring and strrpos to get the position of the last ?) into an array, and use unset to remove arg3, and then join to put the string back together.:
$string = "http://domain.com/php/doc.php?arg1=0&arg2=1&arg3=0";
$pos = strrpos($string, "?"); // get the position of the last ? in the string
$query_string_parts = array();
foreach (explode("&", substr($string, $pos + 1)) as $q)
{
list($key, $val) = explode("=", $q);
if ($key != "arg3")
{
// keep track of the parts that don't have arg3 as the key
$query_string_parts[] = "$key=$val";
}
}
// rebuild the string
$result = substr($string, 0, $pos + 1) . join($query_string_parts);
See it in action at http://www.ideone.com/PrO0a
preg_replace("arg3=[^&]*(&|$)", "", $string)
I'm assuming the url itself won't contain arg3= here, which in a sane world should be a safe assumption.
$new = preg_replace('/&arg3=[^&]*/', '', $string);
This should also work, taking into account, for example, page anchors (#) and at least some of those "weird characters" you mention but don't seem worried about:
function remove_query_part($url, $term)
{
$query_str = parse_url($url, PHP_URL_QUERY);
if ($frag = parse_url($url, PHP_URL_FRAGMENT)) {
$frag = '#' . $frag;
}
parse_str($query_str, $query_arr);
unset($query_arr[$term]);
$new = '?' . http_build_query($query_arr) . $frag;
return str_replace(strstr($url, '?'), $new, $url);
}
Demo:
$string[] = 'http://domain.com/php/doc.php?arg1=0&arg2=1&arg3=0';
$string[] = 'http://domain.com/php/doc.php?arg1=0&arg2=1';
$string[] = 'http://domain.com/php/doc.php?arg1=0&arg2=1&arg3=0#frag';
$string[] = 'http://domain.com/php/doc.php?arg1=0&arg2=1&arg3=0&arg4=4';
$string[] = 'http://domain.com/php/doc.php';
$string[] = 'http://domain.com/php/doc.php#frag';
$string[] = 'http://example.com?arg1=question?mark&arg2=equal=sign&arg3=hello';
foreach ($string as $str) {
echo remove_query_part($str, 'arg3') . "\n";
}
Output:
http://domain.com/php/doc.php?arg1=0&arg2=1
http://domain.com/php/doc.php?arg1=0&arg2=1
http://domain.com/php/doc.php?arg1=0&arg2=1#frag
http://domain.com/php/doc.php?arg1=0&arg2=1&arg4=4
http://domain.com/php/doc.php
http://domain.com/php/doc.php#frag
http://example.com?arg1=question%3Fmark&arg2=equal%3Dsign
Tested only as shown.
I have the following XML:
<id>tag:search.twitter.com,2005:22204349686</id>
How can i write everything after the second colon to a variable?
E.g. 22204349686
if(preg_match('#<id>.*?:.*?:(.*?)</id>#',$input,$m)) {
$num = $m[1];
}
When you already have just the tags content in a variable $str, you could use explode to get everything from the second : on:
list(,,$rest) = explode(':', $str, 3);
$var = preg_replace('/^([^:]+:){2}/', '', 'tag:search.twitter.com,2005:22204349686');
I am assuming you already have the string without the <id> bits.
Otherwise, for SimpleXML:
$var = preg_replace('/^([^:]+:){2}/', '', "{$yourXml->id}");
First, parse the XML with an XML parser. Find the text content of the node in question (tag:search.twitter.com,2005:22204349686). Then, write a relevant regex, e.g.
<?php
$str = 'tag:search.twitter.com,2005:22204349686';
preg_match('#^([^:]+):([^,]+),([0-9]+):([0-9]+)#', $str, $matches);
var_dump($matches);
I suppose you have in a variable ($str) the content of id tag.
// get last occurence of colon
$pos = strrpos($str, ":");
if ($pos !== false) {
// get substring of $str from position $pos to the end of $str
$result = substr($str, $pos);
} else {
$result = null;
}
Regex seems to me inappropriate for such a simple matching.
If you dont have the ID tags around the string, you can simply do
echo trim(strrchr($xml, ':'), ':');
If they are around, you can use
$xml = '<id>tag:search.twitter.com,2005:22204349686</id>';
echo filter_var(strrchr($xml, ':'), FILTER_SANITIZE_NUMBER_INT);
// 22204349686
The strrchr part returns :22204349686</id> and the filter_var part strips everything that's not a number.
Use explode and strip_tags:
list(,,$id) = explode( ':', strip_tags( $input ), 3 );
function between($t1,$t2,$page) {
$p1=stripos($page,$t1);
if($p1!==false) {
$p2=stripos($page,$t2,$p1+strlen($t1));
} else {
return false;
}
return substr($page,$p1+strlen($t1),$p2-$p1-strlen($t1));
}
$x='<id>tag:search.twitter.com,2005:22204349686</id>';
$text=between(',','<',$x);
if($text!==false) {
//got some text..
}