How do I form a multidimensional array using MySQL data? I'm using this code right now:
while($row = mysql_fetch_assoc($result)){
$music[$row['artist']][$row['title']][$row['id']][$row['category_id']] = $row['key'];
}
And I think it would be much easier to use a multi-dimensional array to store my data (artist array => title array => id, category_id, key) but I have no idea how to form one using data from a database. I've googled and can only find examples of static/local data multidimensional arrays, which is no good to me.
I'd also like to know how to output multidimensional data in php for real-world use. Would I use loops? Or would there be an another way?
And I'd just like to say thanks for all the help I've gotten so far at stackoverflow, it's saved me a great deal of headaches!
$music = array();
while($row = mysql_fetch_assoc($result)){
if ( !isset($music[$row['artist']] ) {
$music[$row['artist']] = array()
}
$music[$row['artist']][$row['title']]=array('id'=>$row['id'],'category_id'=>$row['category_id'],'key'=>$row['key'];
}
or more simply if memory requirement is not terribly important (I do this mostly):
$music = array();
while($row = mysql_fetch_assoc($result)){
if ( !isset($music[$row['artist']] ) {
$music[$row['artist']] = array()
}
$music[$row['artist']][$row['title']]=$row;
}
Using two for-as loops would work -- assuming you want to display a tree of artists, than subtrees of titles:
foreach ( $music as $artist => $titles ) {
foreach ( $titles as $title => $details ) {
// do stuff, $details contains all the details for the specific $artist and $title
}
}
var $music = array()
while($row = mysql_fetch_assoc($result))
{
foreach($row as $k => $v)
{
$music[$key][] = $v;
}
}
print_r($music);
Related
I've looked on stackoverflow for the answer, but no one explains it properly.
I have a while loop that works:
info = array();
while($get_info= mysql_fetch_array($info_result)){
$info['team_id'] = $get_info['team_id'];
$info['team_points'] = $get_info['team_points'];
}
And when I print out the array:
Array ( [team_id] => 26 [team_points] => 100 )
But my foreach returns an invalid argument.
foreach ($info as $info_mation ){
echo $info_mation['team_id'];
echo $info_mation['team_points'];
echo "<br/>";
}
I've tried many different ways but nothing works.
Thanks!
Problem is in fetching data from DB. Modify your while loop like this:
info = array();
while($get_info = mysql_fetch_array($info_result)){
$temp_info = array();
$temp_info['team_id'] = $get_info['team_id'];
$temp_info['team_points'] = $get_info['team_points'];
$info[] = $temp_info;
}
Now your foreach loop should work properly.
Here is a bit more explanation, if what you've seen so far doesn't make sense. When you do this:
$info = array();
while($get_info = mysql_fetch_array($info_result)) {
$info['team_id'] = $get_info['team_id'];
$info['team_points'] = $get_info['team_points'];
}
You are overwriting $info with each iteration of the while loop. So at the end of your loop, $info will only contain the last row of your query result.
This explains the result you see:
Array ( [team_id] => 26 [team_points] => 100 )
So when you iterate this array with
foreach ($info as $info_mation ){
echo $info_mation['team_id'];
echo $info_mation['team_points'];
echo "<br/>";
}
$info_mation will contain 26, and then 100, which are indeed invalid for foreach.
You need to create a multidimensional array rather than a one-dimensional array. You can do that by modifying your while loop slightly:
while($get_info= mysql_fetch_array($info_result)) {
$info[] = $get_info;
}
Doing it this way adds a new array element to the $info array with each iteration, rather than overwriting the same two elements repeatedly.
this is your code:
info = array();
while($get_info= mysql_fetch_array($info_result)){
$info['team_id'] = $get_info['team_id'];
$info['team_points'] = $get_info['team_points'];
}
change it to this:
$info = array();
while($get_info= mysql_fetch_array($info_result)){
$info[] = array(
'team_id' => $get_info['team_id'],
'team_points' => $get_info['team_points']
);
}
so, your $info variable contains all the array from the sql result you made.
foreach($info as $inf) {
echo $inf['team_id'];
echo $inf['team_points'];
echo '<br>';
}
and we're done! :)
I am basically trying to fetch results from a SQL database and load that into a multidimensional array so i can use them later on in the page.
while($row = mysqli_fetch_array($result))
{
$send = array
(
array($row['Name'],$row['Email'],$row['Mobile'])
);
$count = $count + 1;
}
That is what i am using to get the results which if i print within the while loop it will echo all the results. However when putting it into the array it loads each result into the array as the first result. My initial plan was to use a counting variable to set where in the array the result was set to with this adding by one each time. I am not certain how to specify where to add the result i thought something along the lines of
$send = array[$count]
(
array.....
so i could then refer to the results as 0 to count length but i am not sure how to make this work. Or ,which i presume, if there is a much easier and better way of going about it. I am also not sure if this is necessary as surely the results seem to be in an array when gathered from the SQL database but i am unsure if this array is populated with each while loop or stored and can be accessed at any point
If any one can give me an example of something similar or point me at some documentation much appreciated
Try this:
$count = 0;
while ($row = mysqli_fetch_array($result)) {
$send[$count] = array($row['Name'], $row['Email'], $row['Mobile']);
$count++;
}
I have a better way for you. You could also use the id for your index, if you have one:
while ($row = mysqli_fetch_array($result)) {
$send[$row['id']] = array(
"Name" => $row['Name'],
"Email" => $row['Email'],
"Mobile" => $row['Mobile']
);
}
You can use:
$count = 0;
while($row = mysqli_fetch_array($result))
{
$send[$count] = $row;
$count ++;
}
Also you might want to use the table id as an array index, so you can access the records by ID later. In that case you can do:
while($row = mysqli_fetch_array($result))
{
$send[$row['id']] = $row;
}
You're declaring your array inside your loop. So it will reset it every time.
$send = array();
while($row = mysqli_fetch_array($result))
{
$send[] = array($row['Name'],$row['Email'],$row['Mobile']);
}
i want to make a website something like popurls.com, but I will use static data stored in MySQL database. Btw I use php/mysql.
In each list i want to show around 10 links (just like on popurls). In that case, if I would have 20 lists, i would need to make 20 'for' loops (for each particular list).
My question is; is there some better way to print that 20 lists instead of using 20 'for' loops in php.
a for loop or a foreach loop will work fine, but it will be a lot less coding if you just create a single for loop and push content into an array of arrays or an array of strings... you can then do whatever you'd like with the actual content (assuming we're grouping by a column category. I'll use an example that uses an array of strings (and the query that I reference is explained here: http://explainextended.com/2009/03/06/advanced-row-sampling/)
$query = mysql_query([QUERY THAT GETS ALL ITEMS, BUT LIMITS BY EACH CATEGORY]) or die(mysql_error());
$all_items = array();
while($row=mysql_fetch_array($query)){
if (!isset($all_items[$row['category']])){ //if it isn't created yet, make it an empty string
$all_items[$row['category']] = "";
}
$all_items[$row['category']] .= "<li><a href='".$row['url']."'>".$row['title]."</a></li>"; //concatinate the new item to this list
}
Now we have an array where the block of HTML for each section is stored in an array keyed by the name of the category. To output each block, just:
echo $all_items['category name'];
PHP's foreach http://php.net/manual/en/control-structures.foreach.php
Depends a lot on your data input but I could imagine something like this:
<?php
$lists = arrray('list1', 'list2', 'list3');
foreach ($lists as $current) {
$data = fetch_data_from_mysql($current);
foreach ($data as $link) {
echo "Link";
}
}
function fetch_data_from_mysql($current)
{
$list_data = array();
// do whatever is required to fetch the list data for item $current from MySQL
// and store the data in $list_data
return $list_data;
}
You just need two foreach loops. Assuming that you take the data from a mysql table (like you wrote), this could be like this:
$list_query = mysql_query("SELECT * FROM lists";)
while( $list = mysql_fetch_array($list_query) )
{
echo "<h1>{$list['title']}</h1>";
$query = mysql_query("SELECT * FROM entries WHERE list_id = {$list['id']}");
while( $entry = mysql_fetch_array($query) )
{
echo "- {$entry['name']}<br />";
}
}
You can get all the information from the database and parse it into an array, something like
array[<news type1>] = array( link1, link2, link3, etc);
array[<news type2>] = array( link1, link2, link3, etc);
and so on
and on the layout you can use
foreach ($newsCategory AS $categoryLinks) {
foreach ($categoryLinks AS $newsLink) {
<show the link and / or extra data>
}
}
Just store your links in two-dimensional array. That way you'll have to make 1 outer loop (iterating over lists) and 1 inner loop iterating over links in a particular list.
$links = array(
'science' => array('link1', 'link2', ...),
'sports' => array('link1', 'link2'),
// ... and so on
);
foreach ($links as $category => $urls) {
echo "Links in category: $category\n";
foreach ($urls as $url) {
echo $url . "\n";
}
}
I need to sort an associative-array in the exact order of the content of another array.
The Arrays are retrieve by 2 separate sql-requests (stated below). The requests could not be combined to only one request, so I have to sort the second array into the order of the first one.
These are the arrays:
#Array which contains the id's in needed order
$sorting_array = array(1,2,3,8,5,6,7,9,11,10...);
#Array which contains the values for the id's, but in order of "id" ASC
$array_to_sort = array(
array("id" => "1", "name" => "text1", "help" => "helptxt2");
array("id" => "2", "name" => "text2", "help" => "helptxt2");
);
The SQL-Queries:
SQL-Ouery for $sorting_array: (the db-field 'conf' is setup as "text", maybe this is my problem so that I have to first explode and implode the entries before I could use it for the next query.)
$result = sql_query("select conf from config where user='me'", $dbi);
$conf = sql_fetch_array($result, $dbi);
$temp = explode(',', $conf[0]);
$new = array($temp[0], $temp[1], $temp[2], $temp[3],$temp[4],
$temp[5], $temp[6], $temp[7], $temp[8], $temp[9],
$temp[10], ...);#Array has max 30 entries, so I count them down here
$sorting_array = implode(',', $new);
SQL-Ouery for $array_to_sort:
$result = sql_query("SELECT id, name, helptxt
FROM table
WHERE id IN ($sorting_array)
AND language='english'");
while ($array_to_sort[] = mysql_fetch_array ($result, MYSQL_ASSOC)) {}
array_pop($array_to_sort);#deleting the last null entry
I could access $array_to_sort as follows to see the content one by one:
(if the lines below don't match the array above, than I mixed it up. However, the lines below is what brings the content)
echo $array_to_sort[0]["id"];
echo $array_to_sort[0]["name"];
echo $array_to_sort[0]["helptxt"];
But it is sorted by "id" ASC, but I need exactly the sorting as in $sorting_array.
I tried some things with:
while(list(,$array_to_sort) = each($sorting_array)){
$i++;
echo $array_to_sort . "<br>";
}
which only brings the Id's in the correct order, but not the content. Now I'm a bit confused, as I tried so many things, but all ended up in giving me the same results.
Maybe the sql-query could be done in one step, but I didn't brought it to work.
All results to my searches just showed how to sort ASC or DESC, but not what I want.
Furthermore I must confess that I'm relative new to PHP and MySQL.
Hopefully some one of you all could bring me back on track.
Many thanks in advance.
To fetch your results:
$result = mysql_query("SELECT id, name, helptxt
FROM table
WHERE id IN ($sorting_array)
AND language='english'");
$array_to_sort = array();
while ( ($row = mysql_fetch_assoc($result)) !== false ) {
// associate the row array with its id
$array_to_sort[ $row[ "id" ] ] = $row;
}
To display them in order of $sorting_array:
foreach ( $sorting_array as $id ) {
// replace the print_r with your display code here
print_r( $array_to_sort[ $id ] );
}
And a bonus tip for the code fetching $sorting_array:
$result = mysql_query("select conf from config where user='me'", $dbi);
$conf = mysql_fetch_array($result, $dbi);
$temp = explode(',', $conf[0]);
// limit to 30 ids
$new = array();
// no need to do this manually, use a loop
for ( $i = 0; $i < 30; ++$i )
$new[] = $temp[ 0 ];
$sorting_array = implode(',', $new);
Its a little hard to tell because there is a lot going on here, in the future you'll probably get better/more responses if you ask several simple questions and figure out yourself how to make the answers fit together.
Your best bet long term is going to be to restructure your SQL tablessuch that you can combine these query together. You can do what you're asking in PHP, but it's going to be slower than doing it in MySQL and much more complicated.
To do what you're asking (pretty slow in PHP):
$sorted = array();
foreach ( $sorting_array as $id )
{
foreach ( $array_to_sort as $values )
{
if ( $values['id'] == $id )
{
$sorted[] = $values;
break;
}
}
}
what I tend to do in such a situation is first to rearrange the array with the data. so the keys represent ids
In your case:
$array_to_sort_ids = array();
foreach ($array_to_sor as $item)
{
$array_to_sort_ids[$item['id']] = $item;
}
Then sorting is as simple as:
$array_sorted = array();
foreach ($sorting_array as $id)
{
$array_sorted[] = $array_to_sort_ids[$id];
}
This solution is quite efficient, since you only have 2 foreach loops.
EDIT!!!
As I couldn't edit my question anymore, I just like to state my solution this way:
The tip to rethink my database was what brought me to some testings and then I found the solution, with the following query:
$result = sql_query("SELECT id, name, helptxt
FROM table
WHERE id IN ($sorting_array)
AND language='english'
ORDER BY FIELD(id,$sorting_array)");
while ($array_to_sort[] = mysql_fetch_array ($result, MYSQL_ASSOC)) {}
array_pop($array_to_sort);#deleting the last null entry
Just the line:
ORDER BY FIELD(id,$sorting_array)
will do the trick. It orders the results the way you want, even if this means 1,4,2,3,9,7,...
Sometimes it's so easy, when you know where to look.
Thanks again!!!
I am pretty new to php and could sure use some help understanding how to get my result the way I need it from a database query.
What I need is an associative array like this, 'bla'=>'bla'. What I am getting from my foreach loop is this from a print:
[0] => Array
(
[0] => test0
[name] => test0
[1] => 1
[customer_id] => 1
)
[1] => Array
(
[0] => test
[name] => test
[1] => 2
[customer_id] => 2
)
Here is my loop:
foreach($res as $key=>$val)
{
// have no idea..
}
Can someone please help me to format my results so that they are like 'index'=>'value'
Thanks for any help.
Here is a sample code that uses a foreach but yet pulls an association. I don't get it. I am thinking that my result set with the indexes are because I am not writing the loop correctly. Here is the code that uses the foreach
foreach ($items as $key=>$value) {
if (strpos(strtolower($key), $q) !== false) {
echo "$key|$value\n";
}
}
Here is the part of the database class that I am using to fetch the results.
$returnArray = array();
$i=0;
while ($row = mysql_fetch_array($result, MYSQL_BOTH)) {
if($row)
$returnArray[$i++] = $row;
}
mysql_free_result($result);
return $returnArray;
After using the code that was given to me to omit the index numbers, here is what I am now left with. Its close but not what I need.
Array
(
[id] => 1
[cust] => bobs auto
)
This is what the above line should read like
'1' => 'bobs auto'
What I am trying to do is to format the output for a JSON call for a suggestion box.
I cannot get this to work. Here is everything after my db connection.
$out_array = array();
foreach($items as $key=>$val)
{
if(is_int($key))
{
continue;
}
$out[$key['id']] = $val['cust'];
}
//echo'<pre>';
//print_r($out_array);
//echo'</pre>';
foreach ($out_array as $key=>$value) {
if (strpos(strtolower($key), $q) !== false) {
echo "$key|$value\n";
}
}
OK, I think I am coming down to the home stretch. I have what I need sort of. This is the code I have so far.
$out_array = array();
foreach($items as $key)
{
$out_array[$key] = $val;
//$out_array[$key['id']] = $key['cust'];
}
Notice that the commented line does not work, It outputs like the id twice but the line that isn't commented out works just fine. Here is the output from that.
Array
(
[8] =>
[FAT BURGER] =>
)
From this point, would I just use another foreach to iterate over the entire set of data? The array output you see above is from a print_r.
This is what I now have and it returns the correct association however, I must comment out the strpos condition to get any results back and I don't know why. Am I correct in nesting these foreach loops like I have?
$out_array = array();
foreach($items as $key)
{
// $out_array[$key] = $val;
$out_array[$key['id']] = $key['cust'];
foreach ($out_array as $key=>$value)
{
if (strpos(strtolower($key), $q) !== false)
{
echo "$key|$value\n";
}
}
}
So you don't want the numeric indexes in your array? You must be using mysql_fetch_array(), which returns your results with both numeric and string keys. Use mysql_fetch_assoc() to get an array with only the string keys (the string being the column name).
Try something like this. It works by skipping the integer indices, and putting the non-integer indices into an output array.
$out_array = array();
foreach($res as $key=>$val) {
if(is_int($key)) {continue;}
$out_array[$key] = $val;
}
EDIT:
$out_array = array();
foreach($items as $key=>$val)
{
if(is_int($key))
{
continue;
}
}
$out[$out_array['id']] = $out_array['cust'];
//echo'<pre>';
//print_r($out_array);
//echo'</pre>';
foreach ($out as $key=>$value) {
if (strpos(strtolower($key), $q) !== false) {
echo "$key|$value\n";
}
}
Assuming this is a MySQL database, the results, if more than one, are returned as a multidimensional array.
When you run the query:
$query = "SELECT * FROM Table WHERE ...";
$query = mysql_query($query);
while($info = mysql_fetch_assoc($query)){
//$info is now a single row, associative array
echo print_r($info);
}
the echo print_r displays the results the way you are looking for them now 'index'=>'value'
EDIT: based on comments.
If you absolutely CAN'T get rid of the mysql_fetch_array then you'll have to hack the code. It's not clean and I strongly advise refactoring but below is the code you'll need to create an array of field name indexes only from what you're given
$my_array = array();
$info = $data[0]; //grab the first row of your data set from the original question.
foreach($info as $index => $value){
if(!is_int($index)){
$my_array[$index] = $value;
}
}
The newly created $my_array will be in the format you're looking for.
You got this array from a query and result function from PHP, yeah?
If you were using mysql, it's actually easier to do it like below.
$query = mysql_query("SELECT * FROM dbname"); //Create the query to your database
while($data = mysql_fetch_array($query)) //Loop through our results from the query
{
echo($data['fieldname']."<br/>"); //echo out data through the loop
}
$ret = array();
foreach($rows as $row)
{
$ret[$row['id']] = $row['cust'];
}
$json = json_encode($ret);
echo $json;
// Prints something like:
//
// {1:'bob'}
Note the use of json_encode.
Ok, regarding my last question. I was incorrect in nesting the foreach loops. I also had a typo in my code. It is working, finally. Thank you to all that have helped me!