jQuery submit ajax form with 2 submit buttons - php

im trying to achieve the following, in php i have a form like this:
<form method="post" id="form_1" action="php.php">
<input type="submit" value="add" name="sub"/>
<input type="submit" value="envoi" name="sub"/>
</form>
the form action file is:
<?php
if( $_POST["sub"]=="add"){ ?>
<script>
alert("")
</script>
<?php echo "ZZZZZZ"; ?>
<?php } ?>
so this means if i press sub with value add an alert prompt will come up, how can i do the same thing(differentiate both submit) but using a Ajax request:
the following code so does not work:
$(function(){
$('form#form_1').submit(function(){
var _data= $(this).serialize()
$.ajax({
type: 'POST',
url: "php.php?",
data:_data,
success: function(html){
$('div#1').html(html)
}
})
})
})
</script>
</head>
<body>
<div id="1" style="width: 100px;height: 100px;border: 1px solid red"></div>
<form method="post" id="form_1" action="javascript:;">
<input type="submit" value="add" name="sub"/>
<input type="submit" value="envoi" name="sub"/>
</form>
</body>

You could put the event handler on the buttons instead of on the form. Get the parameters from the form, and then add a parameter for the button, and post the form. Make sure the handler returns "false".
$(function() {
$('input[name=sub]').click(function(){
var _data= $('#form_1').serialize() + '&sub=' + $(this).val();
$.ajax({
type: 'POST',
url: "php.php?",
data:_data,
success: function(html){
$('div#1').html(html);
}
});
return false;
});
});
You have to explicitly add the "sub" parameter because jQuery doesn't include those when you call "serialize()".

In this case you need to manually add the submit button to the posted data, like this:
$(function(){
$('form#form_1 :submit').submit(function(){
var _data = $(this).closest('form').serializeArray(); //serialize form
_data.push({ name : this.name, value: this.value }); //add this name/value
_data = $.param(_data); //convert to string
$.ajax({
type: 'POST',
url: "php.php?",
data: _data,
success: function(html){
$('div#1').html(html);
}
});
return false; //prevent default submit
});
});
We're using .serializeArray() to get a serialized version of the form (which is what .serialize() uses internally), adding our name/value pair to that array before it gets serialized to a string via $.param().
The last addition is a return false to prevent the default submit behavior which would leave the page.

Lots of semicolon missing, see below
$(function(){
$('form#form_1').submit(function(){
var _data= $(this).serialize();
$.ajax({
type: 'POST',
url: "php.php?",
data:_data,
success: function(html){
$('div#1').html(html);
}
});
});
});

jQuery Form plugin provide some advance functionalities and it has automated some tasks which we have to do manually, please have a look at it. Also it provides better way of handling form elements, serialization and you can plug pre processing functions before submitting the form.

Related

value is not coming $POST array in php

I am building a simple sign up form using ajax when I creating a data object and pass to PHP file.It shows variables and doesn't show values of that PHP variable.
The code of HTML of form is
<form id="myForm" name="myForm" action="" method="POST" class="register">
<p>
<label>Name *</label>
<input name="name" type="text" class="long"/>
</p>
<p>
<label>Institute Name *</label>
<input name="iname" type="text" maxlength="10"/>
</p>
<div>
<button id="button" class="button" name="register">Register »</button>
</div>
</form>
The code of js is
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var form=$("#myForm").serialize();
$("#button").click(function(){
$.ajax({
type:"POST",
url: "mainlogic.php",
data:form,
success: function(result){
alert(result);
}
});
});
})
</script>
The code of PHP is
(mainlogic.php)
if(isset($_POST)) {
print_r($_POST);//////varaibles having null values if it is set
$name=trim($_POST['name']);
echo $name;
}
You are serializing your form on document load. At this stage, the form isn't filled yet. You should serialize your form inside your button click event handler instead.
$(document).ready(function(){
$("#button").click(function(){
var form=$("#myForm").serialize();
$.ajax({
type:"POST",
url: "mainlogic.php",
data:form,
success: function(result){
alert(result);
}
});
});
})
In this code you serialize blank form, just after document is ready:
<script>
$(document).ready(function(){
var form=$("#myForm").serialize();
$("#button").click(function(){
$.ajax({
type:"POST",
url: "mainlogic.php",
data:form,
success: function(result){
alert(result);
}
});
});
})
</script>
Valid click function should begins like:
$("#button").click(function(){
var form=$("#myForm").serialize();
$.ajax({...
It means - serialize form right after button clicked.
var form = $("#myForm").serialize();
That is the line that collects the data from the form.
You have it immediately after $(document).ready(function() { so you will collect the data as soon as the DOM is ready. This won't work because it is before the user has had a chance to fill in the form.
You need to collect the data from the form when the button is clicked. Move that line inside the click event handler function.
The problem is that you calculate the form values at the beginning when loading the page when they have no value yet. You have to move the variable form calculation inside the button binding.
<script>
$(document).ready(function(){
$("#button").click(function(){
var form=$("#myForm").serialize();
$.ajax({
type:"POST",
url: "mainlogic.php",
data:form,
success: function(result){
alert(result);
}
});
});
})
</script>
Alpadev got the right answer, but here are a few leads that can help you in the future:
ajax
You should add the below error coding in your Ajax call, to display information if the request got a problem:
$.ajax({
[…]
error: function(jqXHR, textStatus, errorThrown){
// Error handling
console.log(form); // where “form” is your variable
console.log(jqXHR);
console.log(textStatus);
console.log(errorThrown);
}
});
$_POST
$_POST refers to all the variables that are passed by the page to the server.
You need to use a variable name to access it in your php.
See there for details about $_POST:
http://php.net/manual/en/reserved.variables.post.php
print_r($_POST); should output the array of all the posted variables on your page.
Make sure that:
⋅ The Ajax request ended correctly,
⋅ The print_r instruction is not conditioned by something else that evaluates to false,
⋅ The array is displayed in the page, not hidden by other elements. (You could take a look at the html source code instead of the output page to be sure about it.)

Sending Multiple data to PHP page without reloading page

Please I am new to jQuery so i just copied the code:
<div id="container">
<input type="text" id="name" placeholder="Type here and press Enter">
</div>
<div id="result"></div>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#name').focus();
$('#name').keypress(function(event) {
var key = (event.keyCode ? event.keyCode : event.which);
if (key == 13) {
var info = $('#name').val();
$.ajax({
method: "POST",
url: "action.php",
data: {name: info},
success: function(status) {
$('#result').append(status);
$('#name').val('');
}
});
};
});
});
</script>
And here is the php code:
<?php
if (isset($_POST['name'])) {
echo '<h1>'.$_POST['name'];
}
?>
Its Working perfectly but now i want to have more than one input field like this:
<input type="text" id="name" >
<input type="text" id="job">
but i don't know how to run the jQuery code for the 2 input fields so that it can transfer them to the php page. Please i need help
You can pass multiple values using data param of ajax request like this.
$.ajax({
method: "POST",
url: "action.php",
data: {
name: $('#name').val(),
job: $('#job').val()
},
success: function(status) {
$('#result').append(status);
$('#name, #job').val(''); // Reset value of both fields
}
});
You need to change your code with some addition in html and JS.
Wrap your inputs in form tag. and add a preventDefault on submit.
Use jQuery .serialize() method
and event.preventDefault()
event.preventDefault() : If this method is called, the default
action of the event will not be triggered. (it will prevent page
reload / redirection) to any page.
.serialize() : Encode a set of form elements as a string for
submission.
serialized string output will be like key=value pair with & separated. :
name=john&job=developer.....
HTML
<form id="myform">
<input type="text" id="name" placeholder="Type here and press submit">
<input type="text" id="job" placeholder="Type here and press submit">
<input type="submit" name="submit" value="Submit Form">
</form>
JS
$(document).ready(function() {
$('#myform').submit(function(event) {
event.preventDefault();
var serialized = $('#myform').serialize();
$.ajax({
method: "POST",
url: "action.php",
data: serialized,
success: function(status) {
$('#result').append(status);
$('#myform').reset();
}
});
});
});

Sending a lot of fields through a post AJAX request

I have like 143 form fields (text, textarea and select) that I would like to send through an AJAX post request. Is there a way I can do this quick without manually add every field to the query?
Alright so I've set up thing like this:
jquery
$("#submitbtn").click(function(){
$.ajax({url: "check_data.php", data: $("#form").serialize(), success: function(result){
alert(result);
}});
});
The form is declared like this:
<form class="pure-form" onsubmit="return false;" method="POST" id="form">
I tried also without the "return: false"
And the button as follow:
<button id="submitbtn" class="pure-button pure-button-primary">INSERT</button>
But it does not work, when I press the button I get no js or network activity whatsoever on the console, and nothing happens.
I solved it by using this:
$(function() {
$("#form").on("submit", function(event) {
event.preventDefault();
$.ajax({
url: "check_data.php",
type: "POST",
data: $(this).serialize(),
success: function(d) {
alert(d);
}
});
});
});

Processing Jquery Post with PHP

I've been at this for hours, and i'm at a complete loss.... I've tried everything I can but the problem is that i'm not very familiar with Jquery, this is the first time I've ever used it.... Basically, i'm attempting to pass form data to a php script, and then return a variable which will contain the source code of a webpage.
Here is the jquery:
$("button").click(function(){
hi = $("#domain").serialize();
var page;
$.ajax({
type: "POST",
url: "webcrawler.php",
data: hi,
//dataType: "text",
success: function(data){
page = data;
document.write(page);
}
});
});
Here is the html it references:
<div id="contact_form">
<form name="contact" action="">
<fieldset>
<label for="domain" id="domain_label">Name</label>
<input type="text" name="domain" id="domain" size="30" value="" class="text-input" />
<input type="submit" name="submit" class="button" id="submit_btn" value="Send" />
</fieldset>
</form>
</div>
Here is the PHP that process it:
$search = $_POST["domain"];
if(!$fp = fopen($search,"r" )) {
return false;
}
fopen($search,"r" );
$data = "";
while(!feof($fp)) {
$data .= fgets($fp, 1024);
}
fclose($fp);
return $data;
?>
I think the variable $search is blank, but is that because i'm not sending it correctly with jquery or receiving it correctly with php? Thanks!
Well, when you serialize form data using jQuery, you should serialize the <form>, not the <input> field.
So try this:
$("button").click(function() {
var formData = $('form[name="contact"]').serialize();
var page;
$.ajax({
type: "POST",
url: "webcrawler.php",
data: formData,
success: function(data) {
page = data;
document.write(page);
}
});
});
See you have to do several things:
$("form[id='contact_form']").submit(function (e) {//<---instead click submit form
e.preventDefault(); //<----------------you have to stop the submit for ajax
Data = $(this).serialize(); //<----------$(this) is form here to serialize
var page;
$.ajax({
type: "POST",
url: "webcrawler.php",
data: Data,
success: function (data) {
page = data;
document.write(page);
}
});
});
So as in comments:
Submit form instead button click
Stop the form submission otherwise page will get refreshed.
$(this).serialize() is serializing the form here because here $(this) is the form itself.

Display content dynamically based on user input using php and jquery

I have a form that will display a list of transactions based on the name and date.
<form id="form1" name="form1" method="post" action="<?php echo base_url() ?>options/history">
Name
<input name="name" type="text" id="name" />
date
<input name="date" type="text" id="date" />
<input name="find" type="submit" id="find" value="find" />
</form>
Once the form is submitted all the relevant details are being displayed.
Can someone explain to me how I can use jquery to loads the data on the same page?
I'm new to jquery and learning stuff. I did some research and below is what I have found:
<script type="text/javascript">
$(document).ready(function() {
$('#find').click(function() {
$.ajax({
type: "GET",
cache: false,
url: "<?php echo base_url() ?>options/history",
success: function(data) {
alert('Data Loaded');
}
});
});
});
</script>
And also how do I pass the form variables to my controller? Is it possible to directly pass the values to the controller or do I have to pass it along with the URL?
<script type="text/javascript">
$(document).ready(function() {
$('#form1').submit(function() {
// get the data of the form
var data_form = $('#form1').serialize();
$.ajax({
type: "GET",
cache: false,
data: data_form,
url: "<?php echo base_url() ?>options/history",
success: function(data) {
alert('Data Loaded');
// Your data is in the var data returned, you can use it with, for example: $("#content").html(data);
}
});
// Prevent default behaviour
return false;
});
});
</script>
I am a bit confused here. But I suppose you actually want this:
$('form#form1').submit(function(evt){
$.ajax({
type: "GET",
data: $(this).serialize(),
cache: false,
url: "<?php echo base_url() ?>options/history",
success: function (data) {
alert('Data Loaded');
}
});
evt.preventDefault();
return false;
});
You can use .submit() to bind to the JavaScript's submit event instead. By returning false at the end of this handler you can stop the form submission as shown above; or, by using evt.preventDefault().
The data property in $.ajax specifies the data to be sent to the server. As for getting this data you can use .serialize(), it will encode the form elements ready for submit them.

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