I have this code to copy an html file and rename it. However it doesn't do this, and I have tried tons of variations of the code but still nothing. I'm probably just overlooking something, or I forgot something.
$file = 'example.html';
$newfile = '$bla.html;
Any ideas on how to fix this? Or a different code? Thanks in advance!
All you're doing here is creating variables, you have to actually copy the file. Check out PHP's copy() function.
Here's an example of how to use it:
$file = 'example.txt'; //path to source file, not just the filename
$newfile = 'example.txt.bak'; //same for this string as above
if (!copy($file, $newfile)) {
echo "failed to copy $file...\n";
}
http://php.net/manual/en/function.copy.php
Alternatively you can do
`$file = 'example.html';
$newfile = 'bla.html;
file_get_contents($file);
file_put_contents($file,$newfile);`
Related
In my images folder have file
1_cover.???
2_cover.???
3_cover.???
4_cover.???
5_cover.???
I wanna get file extension 4_cover.???
How to write PHP code
==========
UPDATE
Thanks for all help me,
I can use this code
$images = glob("./images/4_cover.*");
print_r($images);
Is that what you are looking for ?
$info = new SplFileInfo('photo.jpg');
$path = $info->getExtension();
var_dump($path);
PHP Documentation
If you want to look in a directory for files, this might not be the best suited way to do your method but since you don't know what the file-type is, you can do something like this: (all code should be in order from top-bottom)
The directory housing all of your files
$directory = "public/images/headers/*";
The files gathered from the glob function, use print_r($files) to see all of the files gathered for debugging if there's an error going on
$files = glob( $directory );
The file you said you were looking for, if this is from a database you'll replace this data with data from the database
$filename_to_lookfor = '4_cover.';
If statements to check the file types and see if they're existant
$file_types_to_check_for = ['gif', 'jpg', 'png'];
foreach ($file_types_to_check_for as $filetype)
if (in_array( $filename_to_lookfor.$filetype, $files)
echo "This is a {$filetype} file!";
After reading more into glob - I'm not too experienced with it.
You can simply write this line:
if (count($files = glob( 'public/images/4_cover.*' )) != 0) $file = $files[0]; else echo 'No file with extension!';
or
$file = (count($files = glob('public/images/4_cover.*') != 0)) ? $files[0] : 'NO_FILE' ;
I apologize for the quite bad quality code, but that's what OP wants and that's the easiest way I could think to do that for him.
You can use the pathinfo function
$file = "file.php";
$path_parts = pathinfo($file);
$path_parts['extension']; // return => 'php'
I have a script with a mysql query which saves a file called invoice.xml every day automatically by running a cron job. In case no data is found a no_orders.txt is saved.
I would like this file not be saved to the same folder as the script.php file is in but to a subfolder called invoices.
The renaming of the old invoice.xml is done with the following code
// rename old file
$nowshort = date("Y-m-d");
if(file_exists('invoice.xml')) {
rename('invoice.xml','invoice_'.$nowshort.'.xml');
}
The saving is done with the following code:
if($xml1 !='') {
$File = "invoice.xml";
$Handle = fopen($File, 'w');
fwrite($Handle, $xml1);
print "Data Written - ".$nowMysql;
fclose($Handle);
#print $xml;
die();
} else {
print "No new orders - ".$nowMysql;
$File = "no_orders_".$nowshort.".txt";
$Handle = fopen($File, 'w');
fclose($Handle);
die();
}
Could I please get assistance how to save this file to a subfolder. Also the renaming of the existing file would need to be within the subfolder then. I have already tried with possibilities like ../invoice/invoice.xml but unfortunately without any success.
Thank you
Just give the path of file 'invoice.xml' to $File.
Otherwise create some $Dir object which will point to Folder named 'invoice', then use accordingly
Use __DIR__ magic constant to retrieve your script.php directory, then you can append /invoice/invoice.xml .
Example if path to your script php something like this:
/var/www/path/to/script.php
$currentDir = __DIR__; //this wil return /var/www/path/to
$invoicePath = $currentDir.'/invoice/invoice.xml';
I'm having difficulty in copying an image from one folder to another, now i have seen many articles and questions regarding this, none of them makes sense or work, i have also used copy function but its giving me an error. " failed to open stream: No such file or directory" i think the copy function is only for files. The image i wanna copy is present in the root directory. Can anybody help me please. What i am doing wrong here or is there any other way???
<?php
$pic="somepic.jpg";
copy($pic,'test/Uploads');
?>
You should write your code same as below :
<?php
$imagePath = "/var/www/projectName/Images/somepic.jpg";
$newPath = "/test/Uploads/";
$ext = '.jpg';
$newName = $newPath."a".$ext;
$copied = copy($imagePath , $newName);
if ((!$copied))
{
echo "Error : Not Copied";
}
else
{
echo "Copied Successful";
}
?>
You should have file name in destination like:
copy($pic,'test/Uploads/'.$pic);
For your code, it must be like this:
$pic="somepic.jpg";
copy($pic,'test/Uploads/'.$pic);
Or use function, like this:
$pic="somepic.jpg";
copy_files($pic,'test/Uploads');
function copy_files($file_path, $dest_path){
if (strpos($file_path, '/') !== false) {
$pathinfo = pathinfo($file_path);
$dest_path = str_replace($pathinfo['dirname'], $dest_path, $file_path);
}else{
$dest_path = $dest_path.'/'.$file_path;
}
return copy($pic, $dest_path);
}
I want to move example.txt file on my server (/var/www/tmp) to different destination (/var/www/tmp/dir). I want to have this file only in one destination in which is file moved, so only one file on server. I have tried many commands but I wasn't sucessful. Can you help me with this issue? Thanks.
Source code:
<html>
<body>
<?php
// variables from the form
$blogentry = $_POST['blogentry'];
// creating or opening the file in append mode
$dataFile = "example.txt";
$fh = fopen($dataFile, 'a');
// writing to the file
fwrite($fh,"". " " . $blogentry . " " . "\n\n");
fclose($fh);
?>
</body>
</html>
You would use PHP's rename() function to move files (the name of the function can be a little confusing).
rename("/var/www/tmp/file.txt", "/var/www/tmp/dir/file.txt");
You can probably just use the rename() function. From http://php.net/manual/en/function.rename.php:
rename("var/www/tmp/example.txt", "/var/www/tmp/dir/example.txt");
I have a filename stored with the directory as a value.
Ex. /var/www/remove_this.php
In my PHP script I want to remove everthing after the last '/', so I can use mkdir on this path without creating a directory from the filename also.
There are so many string editing functions, I don't know a good approach. Thanks!
dirname() will return you the directory part of the path
Use pathinfo() to get info about the file itself.
$file = '/var/www/remove_this.php';
$pathinfo = pathinfo($file);
$dir = $pathinfo['dirname']; // '/var/www/'
You could use string functions, but for this case PHP has some smarter directory functions:
$dir = dirname('/var/www/remove_this.php'); // /var/www
pathinfo is an excellent one as well.
<?php
$file="/var/www/remove_this.php";
$folder=dirname($var);
if (!file_exsts($folder))
{
if (mkdir($folder,777,true))
{
echo "Folder created\n";
} else
{
echo "Folder creation failed\n";
}
} else
{
echo "Folder exists already\n";
}
?>