If I have a URL that is http://www.example.com/sites/dir/index.html, I would want to extract the word "sites". I know I have to use regular expressions but for some reason my knowledge of them is not working on PHP.
I am trying to use :
$URL = $_SERVER["REQUEST_URI"];
preg_match("%^/(.*)/%", $URL, $matches);
But I must be doing something wrong. I would also like it to have a catch function where if it is at the main site, www.example.com then it would do the word "MAIN"
Edit: sorry, I've known about dirname...It gives the full directory path. I only want the first directory.... So if its www.example.com/1/2/3/4/5/index.html then it returns just 1, not /1/2/3/4/5/
Use the dirname function like this:
$dir = dirname($_SERVER['PHP_SELF']);
$dirs = explode('/', $dir);
echo $dirs[0]; // get first dir
Use parse_url to get the path from $_SERVER['REQUEST_URI'] and then you could get the path segments with explode:
$_SERVER['REQUEST_URI_PATH'] = parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
$segments = explode('/', substr($_SERVER['REQUEST_URI_PATH'], 1));
echo $segments[1];
The dirname function should get you what you need
http://us3.php.net/manual/en/function.dirname.php
<?php
$URL = dirname($_SERVER["REQUEST_URI"]);
?>
Just wanted to recommend additionally to check for a prefixed "/" or "\"
and to use DIRECTORY_SEPARATOR :
$testPath = dirname(__FILE__);
$_testPath = (substr($testPath,0,1)==DIRECTORY_SEPARATOR) ? substr($testPath,1):$testPath;
$firstDirectory = reset( explode(DIRECTORY_SEPARATOR, dirname($_testPath)) );
echo $firstDirectory;
A simple and robust way is:
$currentWebDir = substr(__DIR__, strlen($_SERVER['DOCUMENT_ROOT']));
If you are worried about DIRECTORY_SEPARATORS, you could also do:
$currentWebDir = str_replace('\\', '/', substr(__DIR__, strlen($_SERVER['DOCUMENT_ROOT'])));
Also be aware of mod_rewrite issues mentioned by FrancescoMM
Related
I'm trying to find the way to convert an uri like
public://field/image/link-carousel.png
to a relative path
sites/default/files/directory/link-carousel.png
(of course this is an example because public:// could have other path).
How to do it?
Code:
if(isset($article_node['field_image']['und']['n0'])){
$uri = $article_node['field_image']['und']['n0']['uri'];
$realpath = \Drupal::service('file_system')->realpath($uri);
$path = str_replace($_SERVER['DOCUMENT_ROOT'] . '/', '', $realpath);
}
here on printing $uri will get public://field/image/link-caribbean-carousel-epic-press-release.png.on printing $realpath it gives a blank page.
Taken from https://gist.github.com/illepic/fa451e49c5c43b4a1742333f109dbfcd:
// public://images/blah.jpg
$drupal_file_uri = File::load($fid)->getFileUri();
// /sites/default/files/images/blah.jpg
$image_path = file_url_transform_relative(file_create_url($drupal_file_uri));
/** #var Drupal\file\Entity\File $file */
$file = // get file.
$file->createFileUrl(TRUE); // to get relative path
$file->createFileUrl(FALSE); // to get absolute path https://
Link : https://api.drupal.org/api/drupal/core%21modules%21file%21src%21Entity%21File.php/function/File%3A%3AcreateFileUrl/8.7.x
Use FileSystem::realpath() to convert from sream-wrapped URIs:
use Drupal\Core\File\FileSystem;
//$realpath = drupal_realpath($uri); // D7, D8 deprecated
$realpath = FileSystem::realpath($uri);
$path = str_replace($_SERVER['DOCUMENT_ROOT'].'/','',$realpath);
UPD: For some reason the above example is not valid, we need to use file_system service instead:
$uri = $node->field_document->entity->getFileUri();
$realpath = \Drupal::service('file_system')->realpath($uri);
$path = str_replace($_SERVER['DOCUMENT_ROOT'] . '/', '', $realpath);
Since Drupal 9.3 you can do:
$relativePathToFile = \Drupal::service('file_url_generator')->generateString($thumbnailUri);
See: https://www.drupal.org/node/2940031
I have to extract a specific part of an URL.
Example
original URLs
http://www.example.com/PARTiNEED/some/other/stuff
http://www.example.com/PARTiNEED
in case 1 I need to extract
/PARTiNEED/
and in case 2 I need to extract the same part but add an additional "/" at the end
/PARTiNEED/
What I've got right now is this
$tempURL = 'http://'. $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
$tempURL = explode('/', $tempURL);
$tempURL = "/" . $tempURL[3] . "/";
is there a more convenient way to do this or is this solution fine?
It's normally a good idea to use PHP's built in functions for things like this where possible. In this case, the parse_url method is designed for parsing URLs.
In your case:
// Extract the path from the URL
$path = parse_url($url, PHP_URL_PATH);
// Separate by forward slashes
$parts = explode('/', $path);
// The part you want is index 1 - the first is an empty string
$result = "/{$parts[1]}/";
You don't need this part:
'http://'. $_SERVER['SERVER_NAME']
you can just do:
$tempURL = explode('/', $_SERVER['REQUEST_URI']);
$tempURL = "/" . $tempURL[1] . "/";
Edited index from 0 to 1 as commented.
Maybe regex suits your needs better?
$tempURL = "http://www.example.com/PARTiNEED/some/other/stuff"; // or $tempURL = "http://www.example.com/PARTiNEED
$pattern = '#(?<=\.com)(.+?)(?=/|$)#';
preg_match($pattern, $tempURL, $match);
$result = $match[0] . "/";
Here this should solve your problem
// check if the var $_SERVER['REQUEST_URI'] is set
if(isset($_SERVER['REQUEST_URI'])) {
// explode by /
$tempURL = explode('/', $_SERVER['REQUEST_URI']);
// what you need in in the array $tempURL;
$WhatUNeed = $tempURL[1];
} else {
$WhatUNeed = '/';
}
Dont worry about the trailing slash, that can be added anytime in your code.
$WhatUNeed = $tempURL[1].'/';
This will give you proper idea about your requirment.
<?php
$url_array = parse_url("http://www.example.com/PARTiNEED/some/other/stuff");
$path = $url_array['path'];
var_dump($path);
?>
now you can use string explode function to get your job done.
I have this URL on localhost: http://localhost:7777/somesite/sites/default/files/devel-7.x-1.5.zip and want to get c:\xampp\htdocs\somesites\default\files\devel-7.x-1.5.zip.
As mentioned on this question PHP: Get absolute path from absolute URL:
$path = parse_url($url, PHP_URL_PATH);
echo $_SERVER['DOCUMENT_ROOT'] . $path;
The above snippet should let me get the actual path of the file. Unfortunately this is not working. When printing $path it returns the $url instead of somesites\default\files. Could this be because I'm running it on localhost:7777?
You can do this with server variables:
echo $_SERVER['DOCUMENT_ROOT'] . $_SERVER['REQUEST_URI'];
This might be causing because correct url is not being passed to parse_url function. Print the $url value before passing to parse_url function and check if it is printing appropriate value. You might be passing something like this http://http://localhost:7777/http://localhost:7777/somesite/sites/default/files/devel-7.x-1.5.zip in $url because of which when parse_url processes the $url, it returns your original $url.
Hope this helps :)
Try
$path = parse_url($url);
echo str_replace('/', "\\", $_SERVER['DOCUMENT_ROOT'].$path['host'].$path['path']);
Alright.
Think I am doing this far too complicated and there is an easier solution. I need to get the current server path $_SERVER['DOCUMENT_ROOT']; minus the current folder.
$full_path = $_SERVER['DOCUMENT_ROOT'];
$current_folder = strrchr( $full_path, '/' );
$strlength = strlen( $current_folder ) - 1;
$pathlength = strlen( $full_path );
$newlength = $pathlength - $strlength;
$newpath = substr( $full_path, 0, $newlength );
This code works, but I think it might be overkill.
Thanks,
Pete
dirname() is very handy for this.
dunno what path you're asking for though, gonna give you both:
$above_root = dirname($_SERVER['DOCUMENT_ROOT'])."/";
$above_current = dirname(dirname(__FILE__))."/";
Use the function realpath and go one folder higher by adding /../:
$newpath = realpath($_SERVER["DOCUMENT_ROOT"] . "/../");
Couldn't you just do something like this? It's not really pretty, but as far as I know you can just append .. to a path.
$parent = $_SERVER['DOCUMENT_ROOT'].'/../';
You might want to check if $_SERVER['DOCUMENT_ROOT']; has the directory separator in the end, and if you need to add it or not.
Try:
dirname($_SERVER['DOCUMENT_ROOT']);
PHP offers all kind of functions when working with paths and filesystem: http://www.php.net/manual/en/ref.filesystem.php
$newpath = preg_replace("/[^\/]+$/", "", $_SERVER['DOCUMENT_ROOT']);
Check out this:
$path = $_SERVER['DOCUMENT_ROOT'];
$dirs = explode('\\', $path);
$pathWithoutDir = array_slice($dirs, 0, count($dirs) - 1);
I guess that dirty code aboive will work. You can also change $_SERVER['DOCUMENT_ROOT']; to __DIR__ which is equal to dirname(__FILE__).
EDIT: Code updated.
This is the url of my script: localhost/do/index.php
I want a variable or a function that returns localhost/do (something like $_SERVER['SERVER_NAME'].'/do')
$_SERVER['SERVER_NAME'] . dirname($_SERVER['REQUEST_URI']);
Try:
$url = $_SERVER['REQUEST_URI']; //returns the current URL
$parts = explode('/',$url);
print_r($parts);
EDIT:
$url = $_SERVER['REQUEST_URI']; //returns the current URL
$parts = explode('/',$url);
$dir = $_SERVER['SERVER_NAME'];
for ($i = 0; $i < count($parts) - 1; $i++) {
$dir .= $parts[$i] . "/";
}
echo $dir;
This should return localhost/do/
I suggest not to use dirname(). I had several issues with multiple slashes and unexpected results at all. That was the reason why I created currentdir():
function currentdir($url) {
// note: anything without a scheme ("example.com", "example.com:80/", etc.) is a folder
// remove query (protection against "?url=http://example.com/")
if ($first_query = strpos($url, '?')) $url = substr($url, 0, $first_query);
// remove fragment (protection against "#http://example.com/")
if ($first_fragment = strpos($url, '#')) $url = substr($url, 0, $first_fragment);
// folder only
$last_slash = strrpos($url, '/');
if (!$last_slash) {
return '/';
}
// add ending slash to "http://example.com"
if (($first_colon = strpos($url, '://')) !== false && $first_colon + 2 == $last_slash) {
return $url . '/';
}
return substr($url, 0, $last_slash + 1);
}
Why you should not use dirname()
Assume you have image.jpg located in images/ and you have the following code:
<img src="<?php echo $url; ?>../image.jpg" />
Now assume that $url could contain different values:
http://example.com/index.php
http://example.com/images/
http://example.com/images//
http://example.com/
etc.
Whatever it contains, we need the current directory to produce a working deeplink. You try dirname() and face the following problems:
1.) Different results for files and directories
File
dirname('http://example.com/images/index.php') returns http://example.com/images
Directory
dirname('http://example.com/images/') returns http://example.com
But no problem. We could cover this by a trick:
dirname('http://example.com/images/' . '&') . '/'returns http://example.com/images/
Now dirname() returns in both cases the needed current directory. But we will have other problems:
2.) Some multiple slashes will be removed
dirname('http://example.com//images//index.php') returns http://example.com//images
Of course this URL is not well formed, but multiple slashes happen and we need to act like browsers as webmasters use them to verify their output. And maybe you wonder, but the first three images of the following example are all loaded.
<img src="http://example.com/images//../image.jpg" />
<img src="http://example.com/images//image.jpg" />
<img src="http://example.com/images/image.jpg" />
<img src="http://example.com/images/../image.jpg" />
Thats the reason why you should keep multiple slashes. Because dirname() removes only some multiple slashes I opened a bug ticket.
3.) Root URL does not return root directory
dirname('http://example.com') returns http:
dirname('http://example.com/') returns http:
4.) Root directory returns relative path
dirname('foo/bar') returns .
I would expect /.
5.) Wrong encoded URLs
dirname('foo/bar?url=http://example.com') returns foo/bar?url=http:
All test results:
http://www.programmierer-forum.de/aktuelles-verzeichnis-alternative-zu-dirname-t350590.htm#4329444
php has many functions for string parsing which can be done with simple one-line snippets
dirname() (which you asked for) and parse_url() (which you need) are among them
<?php
echo "Request uri is: ".$_SERVER['REQUEST_URI'];
echo "<br>";
$curdir = dirname($_SERVER['REQUEST_URI'])."/";
echo "Current dir is: ".$curdir;
echo "<br>";
address bar in browser is
http://localhost/do/index.php
output is
Request uri is: /do/index.php
Current dir is: /do/
When I was implementing some of these answers I hit a few problems as I'm using IIS and I also wanted a fully qualified URL with the protocol as well. I used PHP_SELF instead of REQUEST_URI as dirname('/do/') gives '/' (or '\') in Windows, when you want '/do/' to be returned.
if (empty($_SERVER['HTTPS']) || $_SERVER['HTTPS'] === 'off') {
$protocol = 'http://';
} else {
$protocol = 'https://';
}
$base_url = $protocol . $_SERVER['SERVER_NAME'] . dirname($_SERVER['PHP_SELF']);
If you want to include the server name, as I understood, then the following code snippets should do what you are asking for:
$result = $_SERVER['SERVER_NAME'] . dirname(__FILE__);
$result = $_SERVER['SERVER_NAME'] . __DIR__; // PHP 5.3
$result = $_SERVER['SERVER_NAME'] . '/' . dirname($_SERVER['REQUEST_URI']);
dirname will give you the directory portion of a file path. For example:
echo dirname('/path/to/file.txt'); // Outputs "/path/to"
Getting the URL of the current script is a little trickier, but $_SERVER['REQUEST_URI'] will return you the portion after the domain name (i.e. it would give you "/do/index.php").
the best way is to use the explode/implode function (built-in PHP) like so
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$parts = explode('/',$actual_link);
$parts[count($parts) - 1] = "";
$actual_link = implode('/',$parts);
echo $actual_link;
My Suggestion:
const DELIMITER_URL = '/';
$urlTop = explode(DELIMITER_URL, trim(input_filter(INPUT_SERVER,'REQUEST_URI'), DELIMITER_URL))[0]
Test:
const DELIMITER_URL = '/';
$testURL = "/top-dir";
var_dump(explode(DELIMITER_URL, trim($testURL, DELIMITER_URL))[0]);
$testURL = "/top-dir/";
var_dump(explode(DELIMITER_URL, trim($testURL, DELIMITER_URL))[0]);
$testURL = "/top-dir/test";
var_dump(explode(DELIMITER_URL, trim($testURL, DELIMITER_URL))[0]);
$testURL = "/top-dir/test/";
var_dump(explode(DELIMITER_URL, trim($testURL, DELIMITER_URL))[0]);
$testURL = "/top-dir/test/this.html";
var_dump(explode(DELIMITER_URL, trim($testURL, DELIMITER_URL))[0]);
$testURL = "/top-dir/test.html";
var_dump(explode(DELIMITER_URL, trim($testURL, DELIMITER_URL))[0]);
Test Output:
string(7) "top-dir"
string(7) "top-dir"
string(7) "top-dir"
string(7) "top-dir"
string(7) "top-dir"
string(7) "top-dir"
A shorter (and correct) solution that keeps trailing slash:
$url = $_SERVER['REQUEST_SCHEME'] . '://' . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];
$url_dir = preg_replace('/[^\/]+\.php(\?.*)?$/i', '', $url);
echo $url_dir;
My Contribution
Tested and worked
/**
* Get Directory URL
*/
function get_directory_url($file = null) {
$protocolizedURL = $_SERVER['REQUEST_SCHEME'] . '://' . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];
$trailingslashURL= preg_replace('/[^\/]+\.php(\?.*)?$/i', '', $protocolizedURL);
return $trailingslashURL.str_replace($_SERVER['DOCUMENT_ROOT'], '', $file);
}
USAGE
Example 1:
<?php echo get_directory_ur('images/monkey.png'); ?>This will return http://localhost/go/images/monkey.png
Example 2:
<?php echo get_directory_ur(); ?>This will return http://localhost/go/