I'm trying to build a tiny skeleton framework for a friend, where each time a button is pressed a certain animation is played. He wants a way to count the number of times the button is clicked, as well, but I can't seem to get that part working. What am I doing wrong?
<?php
if( isset($_POST['mushu']) )
{
echo "Working.";
playAnimation();
clickInc();
}
function playAnimation()
{
/* ... */;
}
function clickInc()
{
$count = ("clickcount.txt");
$clicks = file($count);
$clicks[0]++;
$fp = fopen($count, "w") or die("Can't open file");
fputs($fp, "$clicks[0]");
fclose($fp);
echo $clicks[0];
}
?>
<html>
<head>
<title>Adobe Kitten</title>
</head>
<body>
<form action="<?php $_SERVER['PHP_SELF']; ?>">
<input type="button"
value="Let's see what Mushu is up to."
name="mushu">
</form>
</body>
</html>
<form action="<?php $_SERVER['PHP_SELF']; ?>" method="post">
<input type="submit"
value="Let's see what Mushu is up to."
name="mushu">
</form>
First of all use the form with method="post", or change $_POST[] to $_GET[] in your Script.
And If your Button is not a Submit button, then you are not submitting the form. So I've changed type="button" to type="submit".
Should work
The code looks fine, I tested it and it worked for me.
I suggest:
Make sure the file isn't read-only.
Make sure the file is called "clickcount.txt"
Make sure it's in the same folder as your script.
It would be helpful to know the error but a shot in the dark - it could be a problem with Write permissions?
also, change to:
<input type="submit" value="Let's see what Mushu is up to." name="mushu" />
Related
I'll preface this with I'm not a coder nor aspiring to become one.
I just want to play around with something simple.
Please don't feel bad about spoon-feeding me here haha.
All I want is when I hit a my submit button the text entered in the text field is saved to a file called log.text
I want it to overwrite each time.
Once data has been written I want it to redirect to another page.
Tried this but it doesn't create the file nor write to it even if I create it manually. The redirect also doesn't work because I'm an idiot.
Any help guys? :(
<?php
$email = $_REQUEST['email'];
$file = fopen("log.txt","a+");
fwrite($file,$email);
print_r(error_get_last());
header("Location: http://www.example.com/");
?>
<form action= "" method="post" name="form">
<input type="text" name="email">
<br>
<br>
<input type="submit" name="submit" value="submit"><br>
</form>
It is because the action element of the form is empty.
It should be \n
<form action="action.php(or any other php file that is handling the form)" method="post" name="form">
This guide offered me the solution I was after.
Thanks anyway guys!
http://www.howtoplaza.com/save-web-form-data-text-file
Because you dint checked whether the form is submitted or not. if submited create log. code given below
<?php
if(isset($_REQUEST['submit']))// if to check whether submit name is passed or not
{
$email = $_REQUEST['email'];
$file = fopen("log.txt","a+");
fwrite($file,$email);
print_r(error_get_last());
header("Location: http://www.example.com/");
}
?>
<html>
<form action= "" method="post" name="form">
<input type="text" name="email">
<br>
<br>
<input type="submit" name="submit" value="submit"><br>
</form>
</html>
First time i try to create a simple form using the POST method.Problem is when i click the button nothing gets echoed.
here is my insert.php file :
<?php
if(isset($_POSΤ["newitem"])){
echo $itemnew = $_POSΤ["newitem"];
}
?>
<form action="insert.php" method="POST" >
<input type="text" name="newitem">
<input type="submit" value="Save">
</form>
EDIT: I tried the GET method and it works...Any ideas why that happened? Server configurations?
NEW EDIT: So it turns out i switched method to GET and it worked.Then i switched back to POST (like the code i posted on top) and it works...I have no clue why this happened.Any suggests?
The code you have posted is perfectly valid and should work.
I'm going to guess that you do not have PHP enabled, or it is not working.
<?php ... ?> looks to the browser like a long, malformed HTML tag, and therefore ignores it, making the effect invisible.
Try right-clicking the page and selecting View Source. If you see your PHP there, then the server is indeed not processing it.
The most likely reason for this is probably the same problem I had with my very first bit of PHP code: you're trying to "run" it directly in your browser. This won't work. You need to upload it to a server (or install a server on your computer and call it from there)
Use !empty($_POST['newitem'] instead:
if(!empty($_POSΤ["newitem"])){
echo $itemnew = $_POSΤ["newitem"];
}
empty()
Try the following:
if($_POST) {
if(!empty($_POST['newitem'])) {
$itemnew = $_POSΤ['newitem'];
echo $itemnew;
// or leave it as is: echo $itemnew = $_POSΤ['newitem'];
}
}
?>
<form action="insert.php" method="POST" >
<input type="text" name="newitem">
<input type="submit" value="Save">
</form>
The if($_POST) will make sure the code is only executed on a post. The empty() function will also check if it isset() but also checks if it is empty or not.
Try this :
<?php
if(isset($_POSΤ["newitem"])){
echo $itemnew = $_POSΤ["newitem"];
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" >
<input type="text" name="newitem">
<input type="submit" value="Save">
</form>
$_SERVER['PHP_SELF']; is pre-defined variable in php.It allows the user to stay on same page after submitting the form.
I'm trying to work with ajax. I have two pages: request.html and reply.php.
request.html:
<html>
<script language="javascript">
var xht = new XMLHttpRequest();
function testAJAX()
{
xht.open("get","http://localhost:9999//a.php", true);
xht.send();
xht.onreadystatechange=function() {
if (xht.readyState==4) {
alert("Text: "+xht.responseText);
}
}
}
</script>
<form id="form1" name="form1" method="post" action="">
btn
<input name="btn" type="submit" id="btn" onClick="testAJAX();" value="Submit" />
</form>
</html>
reply.php:
<?php
echo 'hi';
?>
The problem is that I don't get a response via xht.responseText and with xht.responseXML I get null and with xht.status I get 0.
I asked the link http://localhost:9999//a.php via browser and got hi correctly.
P.S: I tried this on Chrome 29.0.1547.18 and Maxthon v4.1.1
any ideas..
You don't need to mention "http://localhost".
The main mistake is you have given the input type as Submit If it is submit the form will be submitted first the click event will not trigger. Change the input type to button.
If you want to do form submission do it in java script
The corrected code is below.
<form id="form1" name="form1" method="post" action="">
btn
<input name="btn" type="button" id="btn" onClick="testAJAX();" value="Submit" />
// change type to button
</form>
var xht = new XMLHttpRequest();
function testAJAX()
{
xht.open("get","a.php", true); /// Change to a.php
xht.send();
xht.onreadystatechange=function() {
if (xht.readyState==4) {
alert("Text: "+xht.responseText);
}
}
}
Adding to SarathPrakash's answer, I would like to point out that there is nothing wrong with specifying localhost. It will still work as long as the PHP file's address is valid.
You can also have the submit button. But you'll have to modify the form opening tag as follows:-
<form id="form1" name="form1" method="POST" action="" onsubmit="return false">
This is will stop the default behaviour of the form being submitted. Although in my opinion, it is best to avoid it altogether, and just stick with assigning the correct event handler to the onclick attribute.
Also, it is good practice to follow the correct syntax for HTML documents.
<html>
<head>
<title> Your title here </title>
<script type="text/javascript"> Your script here </script>
</head>
<body>
Your main document text here. Forms, tables etc.
</body>
</html>
For a simple tutorial, you could try this.
It is very difficult for me to put in words my query. But I will try.
I have a site xyz.com which has search facility for listed products. The search page url is generated like this :www.wyz.com/search/search_term
I want to create a iframe page in a third party site with a search facility which can directly communicated with my site xyz.com.
I have tried to create a search box with a submit button. I want to append the search query in as a variable to my form action url string.
So the search string should look like this :www.wyz.com/search/my_string_variable
The code I have written is:
<?php
$url='http://www.xyz.com/search/';
?>
<?php
if (isset($_POST['submit']))
{
$r1=$_POST['num1'];
}
?>
<?php
$result=$url.$r1
?>
<html><body>
<form action="<?php echo $result; ?>" method="post">
Num1:<input name="num1"><br>
<input type="submit" name="submit">
</form>
</body></html>
==================================================================
But output what I get, is only "http://www.xyz.com/search/". It removes my variable from the url. I am not able to find what is the reason? I have also tried to print result via to check the actual output and it shows that it has added the value at the end of url. But when I want to achieve the same thing via form action it does not work. please help?
<?php
$url='http://www.xyz.com/search/';
?>
<?php
if (isset($_POST['submit']))
{
$r1=$_POST['num1'];
$result=$url.$r1;
header("location:$result");
}
?>
<html><body>
<form action="" method="post">
Num1:<input name="num1"><br>
<input type="submit" name="submit">
</form>
</body></html>
Please try the above code. I have made some modifications. The main reason your code is not working is whenever you press the submit button it is going to the the url "http://www.xyz.com/search/" directly .The if condition is never executed. In the above mentioned code it will work properly
action="" - you are submitting to the wrong url. Here is alternate version -
<?php $url='http://www.xyz.com/search/';
if (isset($_POST['submit'])) {
$r1=$_POST['num1']; header("Location: ".$r1); // 302 redirection
}
?>
<html><body> <form target="_SELF" method="post"> Num1:<input name="num1" type="text" /><br /> <input type="submit" name="submit" /> </form> </body></html>
maybe very easy!
I'm php coder and I don't have experience in js but I must do this for one of my codes
suppose I have sub1 in page after clicking it must be that sub1 but value now is sub2
<html>
<head>
<title>pharmacy</title>
</head>
<body>
<form method="post" action="pharmacy.php">
<?php
//some code
if(array_key_exists('update',$_POST)){
//somecode
}
?>
<input type="submit" name="update" value="<?php echo if(isset($_GET['update'])) ? 'Show' : 'Update' ?> ">
</form>
</body>
</html>
show as function name does not really make sense here (imo), but you could do:
<input type="submit" name="sub" value="sub1" onclick="show(this)">
and
function show(element) {
element.value = 'sub2';
}
Important:
But that will actually not solve your problem. As soon as you click the button, the form is submitted, meaning the browser initiates a new request and will load a new page. So every change you made the current page is lost anyway.
The question is: What are you trying to do?
It seems to me that you should change the value of the button on the server side. You have to keep track which form was submitted (or how often, I don't know what you are trying to do) and set the value of the button accordingly.
Update:
I see several possibilities to solve this:
You could keep using JavaScript and send and get the data via Ajax. As you have no experience with JavaScript, I would say you have to learn more about JavaScript and Ajax first before you can use it.
You could add a GET parameter in your URL with which you can know which label to show for the button. Example:
<form method="post" action="?update=1">
and
<input type="submit" name="sub" value="<?php echo isset($_GET['update']) ? 'Show' : 'Update' ?> ">
Similar to 2, but use a session variable (and not a GET parameter) to keep track of the state.
Update2:
As you are already having $_POST['update'] you don't need the URL parameter. It could just be:
<html>
<head>
<title>pharmacy</title>
</head>
<body>
<form method="post" action="pharmacy.php">
<input type="submit" name="update" value="<?php echo isset($_POST['update']) ? 'Update' : 'Show'; ?> ">
</form>
</body>
</html>
This should do it
function show(){
document.getElementsByName('sub')[0].value = 'sub2';
return false;
}
Edit: if you don't want it to submit the form, just add a return false, but then you'd need to change your onclick from your submit button to your forms onsubmit;
<html>
<head>
<title>test</title>
<script>
function show()
{
document.getElementById("sub").value= "sub2";
return true;
}
</script>
</head>
<body>
<form method="post">
<input type='submit' id="sub" name='sub' value="sub1" onclick="return show()">
</form>
</body>
</html>