I have a form like this:
one.php
<form id='myFormId' name='myFormName'>
<input type='text' name='myTextField'>
<a href='two.php'>Show Value</a>
</form>
Question:
I want to pass 'myTextField' textbox value to two.php and want to echo it on screen. I can't use submit button and also can't submit the form. Is there any trick ?
Thanks
You could start by giving the anchor an unique id:
<a id="mylink" href="two.php">Show Value</a>
and then register for the click event handler and send an AJAX request:
$(function() {
$('#mylink').click(function() {
$.ajax({
url: this.href,
data: { myTextField: $('#myFormId input[name=myTextField]').val() },
success: function(result) {
// TODO: use the resulting value
alert(result);
}
});
return false;
});
});
one.php
<form id='myFormId' name='myFormName'>
<input type='text' name='myTextField'>
<a href='two.php?value=myTextField'>Show Value</a>
</form>
two.php
echo $_GET['value'];
<form id='myFormId' name='myFormName'>
<input type='text' name='myTextField'>
<a href='two.php' id='myLink'>Show Value</a>
</form>
jQuery('#myLink').live('click',function() {
$.ajax({
url: this.href,
type: 'POST',
data: $('#myFormId').serialize(),
success: function( data ) {
// TODO: use the resulting value
alert(data);
}
});
return false;
});
Related
I am getting Id value from my AJAX and I am also able to display it. I set the Id value input text in the AJAX and displaying it on HTML like this <input value="4864" id="compare_id" type="hidden"> Now I have to pass that value to PHP to get the result from database.
Is there any idea how to do it?
AJAX
$(document).ready(function() {
arr = [];
$("[type=checkbox]").click(function() {
$.ajax({
type: "POST",
url: "includes/compare_process.php", //
data: 'users=' + arr,
dataType: 'json',
success: function(msg) {
$("#pics_name,#pics_Id").empty();
$.each(msg, function() {
$("#pics_Id").append("<input type=hidden value=" + this.Id + " id=compare_id name=compare_id>");
//alert(msg.id);
});
},
error: function() {
alert("failure");
}
});
});
});
//tried AJAX
$(document).ready(function(){
$('#search-button').click(function(){
$.ajax( {
type: "GET",
url: 'includes/compare_process.php?key=compare_details',
data: $('#search-form').serialize(),
success: function(response) {
//$('#response').html(response);
alert(response);
}
} );
});
});
PHP
<div class="bg-popup" style="display: none;" id="open_compare_popup">
//popup code here
<?php
$val2=htmlentities($_GET['compare_id']);
echo $val2;
$sql = "SELECT * FROM `request` WHERE Id IN($val2)";
?>
//end popup code here
This output I am getting from AJAX
<form action="#" method="get" id="search-form">
<span id="pics_Id">
<input value="4869" id="compare_id" name="compare_id" type="hidden">//output
<input value="4884" id="compare_id" name="compare_id" type="hidden">//output
<input value="5010" id="compare_id" name="compare_id" type="hidden">//output
</span>
<button class="action action--button action--compare" type="button" id="search-button" name="search-button"><span class="action__text">Compare</span></button>
</form>
I have to pass the input value to PHP after clicking on a button.
Hello I want to call my function download when the user click on the button, basically:
<input type='button' name='Release' onclick="document.write('<?php downloadFichier($tab1, $t2) ?>');" value='Click to Release'>
Of course doesn't work, so I try to do with a AJAX, I don't know this language, but it is possible to do what I want: call my PHP function with 2 parameters?
<button type="button">Click Me</button>
<p></p>
<script type="text/javascript">
$(document).ready(function(){
$("button").click(function(){
$.ajax({
type: 'POST',
url: 'file_product.php',
success: function(data) {
$("p").text(data);
}
});
});
});
</script>
Thank you for helping me.
You should call a js-function with onclick event like this:
<input type='button' name='Release' onclick="downloadFichier(param1, param2)" value='Click to Release'>
And your AJAX-function should be like this:
function downloadFichier(param1, param2){
$.ajax({
type: 'POST',
url: 'file_product.php',
data: "param1=" + param1 + "¶m2=" + param2,
success: function(data) {
$("p").text(data);
}
});
You can get your params in PHP-script from the $_REQUEST array by their names (param1, param2).
#PaulBasenko inspired this alternative, where you set the parameters through some <input type="hidden" /> :
HTML
<form action="#" method="POST" id="form1">
<input type="hidden" name="tab1" value="<?= $tab1 ?>" />
<input type="hidden" name="t2" value="<?= $t2 ?>" />
<button type="submit">Click to Release</button>
</form>
Javascript
$(function() { // equivalent of "$(document).ready(function(){"
$('body').on('submit', '#form1', function(event) {
event.preventDefault();
var formData = $(this).serialize();
$.ajax({
type : 'POST',
url : 'file_product.php',
data : formData,
success : function(data) {
$('#p').text(data);
}
});
});
});
PhP
<?php
$tab1 = (isset($_POST['tab1'])) ? $_POST['tab1'] : null;
$t2 = (isset($_POST['t2'])) ? $_POST['t2'] : null;
// process & return json_encoded data
?>
How it works ?
When clicking on the button, which is a type="submit", it will trigger the submit event for its parent form. Then, jQuery listen to this event and immediately blocks it using èvent.preventDefault() in order to call Ajax instead of a regular synchronous call to a php file.
HTML
<input type="checkbox" name=options[cid]" value='1'
onChange="chkdeptCount(this.value)" class="test">
<input type="checkbox" name=options[cid]" value='2'
onChange="chkdeptCount(this.value)" class="test">
jquery:
function chkdeptCount(val){
$.ajax({ url: '../ajax/AjaxCall.php',
data: {Action:'IMPLODEARRAY',arrVal: val},
type: 'post',
success: function(output) {
alert(output);
$('.result').html(output);
}
});
}
PHP:
if($_POST['Action']=='IMPLODEARRAY'){
$arr_val[] = $_POST['arrVal'];
print_r($arr_val);
}
When I run this code does not return array value. It returns a single value WHY?
Note that, you are missing the quote here name=options[cid]".
And you are using onChange="chkdeptCount(this.value)" event with current value this, this will only return one value at once.
This is very basic Example:
HTML:
<form method="post" id="formID" action="">
<input type="hidden" name="Action" value="IMPLODEARRAY">
<input type="checkbox" name="options[cid]" value='1' class="test">
<input type="checkbox" name="options[cid]" value='2' class="test">
<input type="submit" name="submit" value="Submit" id="SubmitButton">
</form>
AJAX:
<script type="text/javascript">
$(document).ready(function(){
$("#SubmitButton").click(function(){ // when submit button press
var data = $("#formID").serialize(); // get all form input in serialize()
$.ajax({
url: YourURL, // add your url here
type: "POST", // your method
data: data, // your form data
dataType: "json", // you can use json/html type
success: function(response) {
console.log(response); // your response
},
beforeSend: function()
{
// if you want to display any loading message
}
}); // JQUERY Native Ajax End
return false;
});
});
</script>
PHP:
<?php
if(count($_POST) > 0){ // if you have some value in AJAX request
if($_POST['Action'] == 'IMPLODEARRAY'){ // your condition
print_r($_POST['options']); // get all checkbox value.
}
}
?>
Few more example will help you to understand, you can you use: Submitting HTML form using Jquery AJAX |
jQuery AJAX submit form
I am working in wordpress and I have one form and two submit buttons. I am using ajax and it is wordpress.
When first submit button is pressed I want statement 1 to be echoed and when submit button number 2 is pressed I want state 2 be echoed. I have followed the code tutorials but when I press submit from the control returns empty or no result and in inspect there is no error in the browser. Below is my code.
HTML Form
<form id="voteform" action="" method="post">
<input name='vote' value='two' src='http://localhost:8080/test/wp-content/uploads/2015/04/up.jpg' type='submit' type='image'>
<input name='vote' value='one' src='http://localhost:8080/test/wp-content/uploads/2015/04/up.jpg' type='submit' type='image'>
</form>
I am not copying the enqueue code but just the actual php function that executes
function articlevote ()
{
if ($_POST['vote'] == 'one') {
echo json_encode("1 vote button is pressed");
die();
}
else if ($_POST['vote'] == 'two') {
echo json_encode("2 vote button is pressed");
die();
}
}
Ajax and jquery
jQuery(function ($) {
$(document).on("click","input[name=vote]", function() {
var _data= $('#voteform').serialize() + '&vote=' + $(this).val();
$.ajax({
type: 'POST',
url: yes.ajaxurl,
data:_data,
success: function(html){
$("#myresult").html(res);
}
});
return false;
});
});
Again kindly note that I am using wordpress so kindly guide me in this thanks
This should get you what you need:
Html:
<form id="voteform" action="" method="post">
<input type="text" name="field1" value="field one value"/>
<input type="text" name="field2" value="field two value"/>
<input class='vote' value='two' src='http://localhost:8080/test/wp-content/uploads/2015/04/up.jpg' type='submit' type='image'/>
<input class='vote' value='one' src='http://localhost:8080/test/wp-content/uploads/2015/04/up.jpg' type='submit' type='image'/>
</form>
jQuery
jQuery(function($) {
var yes = {ajaxurl:"mypage.php"}; // created for demo
$('.vote').click(function(e) {
e.preventDefault(); // stop the normal submit
var _data = $('#voteform').serialize()+'&vote=' + $(this).val();
//alert(_data)
$.ajax({
type: 'POST',
url: yes.ajaxurl,
data: _data,
success: function(html) {
$("#myresult").html(html); // you had `res` here
}
});
});
});
$(document).ready(function(){
$('input[value=\'one\'], input[value=\'two\']').on('click', function(){
var _data= $('#voteform').serialize() + '&vote=' + $(this).val();
$.ajax({
type: 'POST',
url: yes.ajaxurl,
data:_data,
success: function(html){
$("#myresult").html(res);
}
});
return false;
});
});
This is an example of my own page.
<?php
$do = $_GET['do'];
switch($do){
case 'finalTask':
if(isset($_POST['url'])){
echo "It's Ok!";
}else{
echo "Problem!";
}
}
This is also written in the same page.
<input type='text' id='siteName'>
<button type='submit' id='send'>Send</button>
<div id='info'></div>
<script>
$(document).ready(function(e){
$('#send').click(function(){
var name = $('#siteName').val();
var dataStr = 'url=' + name;
$.ajax({
url:"index.php?do=finalTask",
cache:false,
data:dataStr,
type:"POST",
success:function(data){
$('#info').html(data);
}
});
});
});
</script>
When I try to input and press the send button. Nothing happened..... What's wrong with the code?
Make sure file name is index.php
You need to make sure that you check in the php code when to output the form and when the
Format of ajax post request is incorrect in your case.
You forgot to import JQuery JS script, without that you can not use JQuery. (at least at this point of time)
-
<?php
if (!isset($_GET['do'])) { // Make sure that you don't get the form twice after submitting the data
?>
<input type='text' id='siteName'>
<button type='submit' id='send'>Send</button>
<div id='info'></div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function (e) {
$('#send').click(function () {
var name = $('#siteName').val();
var dataStr = 'url=' + name;
$.ajax({
url: "index.php?do=finalTask",
cache: false,
data: {url: dataStr}, // you need to send as name:value format.
type: "POST",
success: function (data) {
$('#info').html(data);
}
});
});
});
</script>
<?php
} else {
error_reporting(E_ERROR); // Disable warning and enable only error reports.
$do = $_GET['do'];
switch ($do) {
case 'finalTask':
if (isset($_POST['url'])) {
echo "It's Ok!";
} else {
echo "Problem!";
}
}
}
?>
There seems to be no form in your page, just form elements. Can you wrap them in a form:
<form method="POST" onSubmit="return false;">
<input type='text' id='siteName'>
<button type='submit' id='send'>Send</button>
</form>