I'm using a PHP sticky form and was wondering is there a way I can clear a forms fields once its been submitted by the user?
A sticky form is simply a standard HTML form that remembers how you filled it out. This is a particularly nice feature for end users, especially if you are requiring them to resubmit a form (for instance, after filling it out incorrectly in the first place).
You could have some default values and update the fields to the values using Javascript , in case you do not want to reload the page. If you do want to reload the page, and use PHP sticky form, populate the form after clearing out the GET values.
If you want it to clear the data, you can do this:
<html>
<head>
<title>A Self-Clearing Form</title>
<script>
function clearForms()
{
var i;
for (i = 0; (i < document.forms.length); i++) {
document.forms[i].reset();
}
}
</script>
</head>
<body onLoad="clearForms()" onUnload="clearForms()">
<h1>A Self-Clearing Form</h1>
<form method="post" action="page2.php" name="test">
<input name="field1"/> Field One
<p>
<input name="field2" type="radio" value="One"/>One
<input name="field2" type="radio" value="Two"/>Two
<input name="field2" type="radio" value="Three"/>Three
<input name="field2" type="radio" value="Four"/>Four
<p>
<input type="submit" value="Submit Form Data"/>
</form>
</body>
</html>
This will clear the form when the HTML body loads completely.
It depends on your implementation, but the solution probably involves clearing the session variables that are used to hold the form data. If you're using a cut and paste solution I would suggest reading the documentation further or maybe looking over the code in detail to see how everything is stored.
If you want to check the session variables to see if the form data is in there you can use:
echo '<pre>';
print_r($_SESSION);
echo '</pre>';
die; // this line is optional
Related
I am working on a website that has a kind of questionare. It is a PHP script that reads the questions from a database and shows some content depending on your answers. The user will click an answer and the page will reload re-posting the previously entered form data so the already answered questions will show disabled buttons/radio forms with the answers checked.
I noticed during debugging that the previously sent stuff is not cleared and always reposted (the page works however, i just thought it looks unclean)
example:
?position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1&p_item9=2&position=9&p_item1=4&p_item2=2&p_item3=4&p_item4=2&p_item5=2&p_item6=2&p_item7=2&p_item8=1#lastrow
how can i get rid of the post/put data getting exponentially bigger?
I am assuming that the "answer" you are referring to is a link. If so, you can easily use the $_POST superglobal to send the data:
<!-- javascript that creates the post() function-->
<script>
function post(event) {
event.preventDefault();
document.getElementById("my_form").submit();
}
</script>
<!-- form with the information you want to post-->
<form action="action.php" method="post" id="my_form" style="display: none;">
<?php
/*You'll have to create the needed php code that will echo the
hidden inputs for the form that should look like this:
<input type="hidden" name="position" value="9" />
<input type="hidden" name="p_item1" value="4" />
... and so on.*/
?>
</form>
Your Link
<html>
<script>
function changeText()
{
document.getElementById("input1").value = <?php echo '"'.$_POST['input'].'"'; ?>;
return true;
}
</script>
<form name="mainform" action="" method="post">
<input type="text" name="input" id="input1" />
<input type="submit" onclick = "changeText()" name="Submit" value="Submit!" />
</form>
<html>
i have this code here. can you make it work as intended ?
everytime i click Submit! i want to change the value of the textarea to the last input the user inserted.
PHP code is parsed by a PHP interpreter before any HTML output is sent to the browser.
If your form action is the same page and the same form will be shown before and after submission, then you can let PHP print the value of the input field directly into it.
<input type="text" name="input" id="input1" value="<?php echo htmlspecialchars($_POST['input']);" />
If you're trying to revert the value of this input field whenever a user clicks the submit button, then your code (even if it's prone to code injection) should work but this is useless since the page will be requested again when submit is clicked.
I assume you need to fill in
action=""
By the name of your file, like
action="myFile.php"
Few tips :
NEVER trust the user. The user can manually change the value of the input and send some dangerous values in your $_POST variable. You need to check it using filter_input() by example.
Like #Charles said this is pretty simple problem, use google next time.Here for example
what I am trying to do is to create a from, and execute a php script after the submit has been pressed. the problem seems to be that the page of wprdpress with the form and the code gets executed all at once.
If I put the code below into a regular test.php file on my server, it does what it is supposed to do (echo "Form Submitted!") after I click submit. However if I put the same code in a page template or a wp page it spits it out all at once (the form, and the "form submitted).
<html>
<head>
<title>Notify on Submit</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<label>Name: <input type="text" name="name" /></label>
<input type="submit" value="Submit" />
</form>
<?php if (count($_POST)>0) echo "Form Submitted!"; ?>
</body>
</html>
I have no idea why this is like that, and would really need some help on this.
What I have also done is to create two different wp pages(one goes to the other). It works, but will create a bit of a mess. I would like to do this in one page.
page 1
<form action="page2" method="POST">
Your form input.
<input type="submit" name="submit" />
</form>
Page 2
<?php
if (count($_POST)>0)
{
echo "Form Submitted!";
unset($_POST);
$_POST = array();
}
else echo "Form has been reset!";
?>
Probably there is another form on the Wordpress page using the POST method. Instead of checking for $_POST > 0 (which will only tell you that something was posted) add some identifier to your form, and check for that so you can tell if your form was posted.
A simple way to do this is with a hidden input:
<html>
<head>
<title>Notify on Submit</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<label>Name: <input type="text" name="name" /></label>
<input type="hidden" name="whatform" value="myform" />
<input type="submit" value="Submit" />
</form>
<?php if (isset($_POST['whatform']) && $_POST['whatform'] == 'myform') echo "My Form Submitted!"; ?>
</body>
</html>
I think you just need to remove the php from your action. The action defaults to the current url on any form.
PHP_SELF refers to the file path - thats why it works when you do it on just a solo file. As part of the wordpress application, you can't run files directly - you have to reach that url.
Remember that WP uses actions and hooks, and so if you put code "in a WP page" or "in a template" it may fire at various times. You might get an echo statement that fires something to the screen before the content comes out. Consider putting all your output within filters, actions and hooks.
Your logic seems to depend on the post count. Consider using a unique name, i.e. the name of the submit button on your form. Check for if(isset($_POST['my-unique-submit-button'])). Is anything else in WP submitting via post? You might not know!
I've been working for several hours trying to get this to work properly. The page I have a form on is /index.php?action=pagename. I have a form that needs to get a variable from the following /index.php?action=pagename&thing=something. My HTML form going like this:
<form role="form" action="pagename" method="get">
<input type="text" name="thing">
</form>
This form is located on /index.php?action=pagename and I want to get &thing from that URL.
Any ideas?
The problem I'm having is that when the form is submitted, the URL redirects to index.php?thing instead of staying on index.php?action=pagename.
It looks like you might be having some trouble with <forms> in general and not just PHP so here is an overview:
<!-- the action is where you want to send the form data -->
<!-- assuming THIS code is the index.php file then we want to send the data to ourselves -->
<!-- the method is GET so it will be directly accessible from the URL later -->
<form action="index.php" method="GET">
<!-- add a hidden value for pagename -->
<input type="hidden" name="action" value="pagename">
<!-- the name called "thing" will be appended to the URL and it's value as well -->
<input type="text" name="thing" value="<?php echo (isset($_GET['thing']) ? $_GET['thing'] : ''); ?>">
<br>
<!-- click this button to submit the form to itself -->
<!-- once this has been submitted then you can retrieve the URL value with $_GET as you can see above -->
<input type="submit" value="submit" />
</form>
You can simply use the PHP-variable $_GET['thing'] to get the value.
The action attribute of the form element is the target script which will be called on submit. If blank it will be the current script which is showing the form. You also can only give url parameters beginning with ?.
<form role="form" action="?action=pagename" method="get">
<input type="text" name="thing">
</form>
Exerpt from php.net: http://www.php.net/manual/de/tutorial.forms.php
One of the most powerful features of PHP is the way it handles HTML
forms. The basic concept that is important to understand is that any
form element will automatically be available to your PHP scripts.
Please read the manual section on Variables from external sources for
more information and examples on using forms with PHP. Here is an
example HTML form:
Example #1 A simple HTML form
<form action="action.php" method="post">
<p>Your name: <input type="text" name="name" /></p>
<p>Your age: <input type="text" name="age" /></p>
<p><input type="submit" /></p>
</form>
There is nothing special about this form. It is a straight HTML form
with no special tags of any kind. When the user fills in this form and
hits the submit button, the action.php page is called. In this file
you would write something like this:
Example #2 Printing data from our form
Hi <?php echo htmlspecialchars($_POST['name']); ?>.
You are <?php echo (int)$_POST['age']; ?> years old.
A sample output of this script may be:
Hi Joe. You are 22 years old.
Basic script I made to get the variables from the URL:
<?php
if (isset($_GET["action"]) && isset($_GET["thing"])) {
$action = $_GET["action"];
$thing = $_GET["thing"];
echo $action .PHP_EOL . $thing;
}
?>
This will output the following for the URL /index.php?action=pagename&thing=something
pagename
something
Though you should probably learn how to use forms properly first.
I was wondering if my code below is even correct, I've been having numerous errors with this, but am not sure if the problem really exists here. The code is below:
The user will click 'Exit Group'.
<p class="logout"><a id="exit" name="logout" href="#">Exit Group</a></p>
The code that should be execute when 'Exit Group' is clicked is below:
if(isset($_GET['logout'])){
//CODE TO BE EXECUTED
}
However, the code I am trying to execute when the user clicks 'Exit Group' is not even being executed. There is nothing wrong with the code within the braces, as numerous people have checked it. But I was wondering if my problem may lie in the code above? Thank you.
If you click the link, nothing happens because the URL only contains the fragment identifier #. Not even a GET request will be issued.
You use this kind of link normally to jump to an element inside the page (e.g. Top to jump to an element with ID top). This is completely handled in the browser.
And if you only put the fragment identifier there, just nothing will happen. This is very often used if the link should execute some JavaScript and should actually not link to something else.
You are testing the $_POST array at the server side. But this array only contains elements, if you initiate a POST request by a form. That means you need to create a form with a submit button, e.g.:
<form action="" method="POST">
<input type="submit" name="logout" value="Exit Group" />
</form>
Here comes the name attribute into play, which will be the key in the $_POST array. But assigning this on a normal link will have no effect.
You could do it also with the link, but with a GET request this way:
<a id="exit" href="?logout=1">Exit Group</a>
<!-- ^-- parameter must be part of the URL, name has no effect -->
and
if(isset($_GET['logout'])){
//CODE TO BE EXECUTED
}
Note that you have to pass a parameter logout it here.
It seems you have mixed up GET and POST requests. If you have a form, the name s of the form elements will be transmitted as parameters to the server. That means given this form:
<form method="POST">
<input type="text" name="foo" value="" />
<input type="text" name="bar" value="" />
<input type="submit" name="send" value="Send" />
</form>
if the user clicks on the submit button, the $_POST array at the server side will have the keys:
$_POST['foo']
$_POST['bar']
$_POST['send']
This does not work with links though. A click on a link will create a normal GET request, and here, the parameters must be part of the URL, appended after a question mark ? and separated by an ampersand &:
Link
will result in
$_GET['foo']
$_GET['bar']
$_GET['andMore']
You probably should read about the HTTP protocol.
a isnt a form control. it needs to be an input or select if it's within a form.
For manual linking, do href="/page?logout"
You're using a regular hyperlink, no form will get posted. you need a submit button of some kind in a form with method="post" to do that. regular links just result in GET requests and nothing will ever be posted that way.
edit: added simple example:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01//EN">
<html>
<head>
<title>Form test</title>
</head>
<body>
<?if ($_SERVER['REQUEST_METHOD'] == 'POST'):?>
<pre><? print_r($_POST)?></pre>
<?endif;?>
<? // $_SERVER['REQUEST_URI'] holds the current URL, so we know that ?>
<? // we'll end up back in this file when the form is submitted. ?>
<form method="post" action="<?= $_SERVER['REQUEST_URI']; ?>">
<input type="text" name="textbox"
value="<?= isset($_POST['textbox'])?$_POST['textbox']:'Type something' ?>" />
<input type="submit" name="submitbutton" value="Submit" />
</form>
</body>
</html>
$_POST will only be filled if you use a form with method=post.
Yes. A POST and a GET are two different things ;)
if(isset($_GET['logout']))
This <a id="exit" name="logout" href="#"> should be <a id="exit" href="?logoff=true#">.
Then logoff will be in the $_GET array.