I have a table with a number of votes recorded in it, each vote goes against a post. What I want to be able to do is count the total occurances of each vote.
Table looks like this:
vote
-----
1
2
3
1
2
3
4
5
2
2
2
2
...and so on...
How can I count the records, e.g. In that list 1x2, 2x6, 3x2, 4x1 and 5x1 times.
select vote, count(votes) as vt
from t_your_table
group by vote
To get what you want you can use GROUP BY and COUNT:
SELECT vote, COUNT(*) AS cnt
FROM votes
GROUP BY vote
Result:
vote cnt
1 2
2 6
3 2
4 1
5 1
Votes that have zero count will not be represented in this result set. If you want to have these included with a count of zero then you will need to use an OUTER JOIN with a table listing all the possible votes.
SELECT
possible_votes.vote,
COUNT(votes.vote) AS cnt
FROM possible_votes
LEFT JOIN votes ON possible_votes.vote = votes.vote
GROUP BY possible_votes.vote
Result:
vote cnt
1 2
2 6
3 2
4 1
5 1
6 0
Check MySQL manual for GROUP BY combined with COUNT.
SELECT vote, COUNT(*) as total
FROM votes
GROUP BY vote
Related
I have a table similar the following
id user_id father_id
1 1 1
2 2 1
3 3 2
4 4 2
5 5 2
6 6 3
7 7 4
I search for a sql query (prefer Fluent or Eloquent for Laravel 4) to give me the following result:
id user_id father_id family_members
3 3 2 3
4 4 2 3
5 5 2 3
1 1 1 2
2 2 1 2
6 6 3 1
7 7 4 1
As it can be observed family_members is the count of users who have the same father_id
select id, user_id, father_id, count(*) as family_members from users group by father_id
The query above, just keeps the top row of each group, but I want to keep all the other records and not only the first one; then sorting them first according to the family_members and then according to father_id
How can I achieve it?
I don´t know Fluent, nor Eloquent, nor Laravel 4, but the sql query would be like this.
SELECT yourTable.*, auxTable.family_members
FROM yourTable
LEFT JOIN
(
SELECT father_id, COUNT(id) as family_members
FROM yourTable
GROUP BY father_id
)auxTable ON yourTable.father_id = auxTable.father_id
ORDER BY family_members DESC, yourTable.father_id ASC
I solved the problem by the following Fluent query based on the answer from segio0983
$users = DB::table('users')
->leftjoin(DB::raw('(SELECT father_id, COUNT(id) as family_members
FROM users
GROUP BY father_id) auxTable '),function($join)
{
$join->on('users.father_id', '=', 'auxTable.father_id');
})
->orderBy('auxTable.family_members','desc')
->orderBy('users.father_id','asc')
->select('users.id','users.father_id','auxTable.family_members');
Have Table :
id userid type created_date
1 4353535 1 04-06-2014
2 4353536 0 06-06-2014
3 4353537 1 11-06-2014
4 4353538 1 11-06-2014
5 4353539 0 19-06-2014
7 4353541 1 01-06-2014
10 4353544 1 12-06-2014
11 4353535 1 06-06-2014
12 4353536 1 10-06-2014
13 4353537 1 12-06-2014
What I Want : (with in date range)
How much user have single time entry with type 1
How much user have double time entry with type 1
How much user have triple time entry with type 1
How much user have four time entry with type 1
How much user have n time entry with type 1
(PHP & MYSQL)
First get the count for each user, then from that group the entrycount you can get your expected output
select EntryCount, count(userid) from (Select userid, count(id) as Entrycount from myentry group by userid where type=1) as sq group by Entrycount
This will work try
First, get the number of entries per user. Then, get the number of users grouped by number of entries.
SELECT numEntries, COUNT(*) AS numUsers
FROM (
SELECT userid, COUNT(*) AS numEntries
FROM tablename
WHERE type = 1
GROUP BY userid
) tbl
GROUP BY numEntries
Simplified demo
Demo with your data
I have two tables:
Table A: ID Cars Planes Num
1 3 5 2
2 8 44 1
3 7 23 6
4 6 2 7
Table B: ID Horses Dogs Cats Elefants Num
1 3 5 2 3 3
2 8 44 1 22 4
3 7 23 4 14 8
4 6 2 3 15 5
What I need to do: I need to get all results from both tables and sort them by the "Num" Column, where the "number" actually is unique for each result from both rows.
Is it even possible to "merge" those two tables and order them by "num" or should I just get each table separately ordered and do two loops checking always for the next num jumping between tables?
Thanks
you can merge them like that with UNION .
try this:
select num from(
select num from table1
union all
select num from table2
)t
order by num asc
DEMO HERE
EDIT:
select id ,Cars,Planes, Horses,Dogs,Cats,Elefants,num from(
select id ,Cars,Planes,'No horses' Horses,'No dogs' Dogs,'No cats' Cats,'No elefants' Elefants,num from table1
union all
select id,'No cars' Cars,'No planes' Planes,Horses,dogs,Cats,Elefants, num from table2
)t
order by num asc;
DEmo with other columns
SELECT NUM FROM TABLEA
UNION ALL
SELECT NUM FROM TABLEB
ORDER BY 1
I am using user Keevas' example, but asking a different question....
select Master_Code, SUM(Jan), SUM(Feb), SUM(Mar)
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code ORDER BY Master_Code ASC
something like this:
Master_Code sum(Jan) Sum(Feb) sum(Mar) Total
1 4 5 4 13
2 5 5 5 15
How do I get Total value column?
SELECT username,SUM(value) AS SumValue FROM
table GROUP BY username ORDER BY SumValue DESC
I have a database which contains some picture data and a linking table. The tables are build-up like this:
---pictures---
picid Lat Lon
1 5 6
2 7 31
3 31 43
4 -3 35
---user2pictures---
picid userid vote
1 1 1
1 2 1
3 1 -1
3 2 1
4 2 -1
The table pictures contains a picture id and some data about the image, the table user2votes contains vote data from the images. Each user is able to vote on images, but they can only vote 1 time, so the vote will be either 1 (like) or -1 (dislike).
I want to select everything from the pictures table from pictures which have the highest number of votes. Pseudoquery which might explain better what I want:
SELECT * FROM pictures WHERE (SELECT MAX(SUM(vote)) FROM user2pictures LIMIT 12
In this example picture 1 would return at the top, picture 3 would follow and picture 4 as the last one. I really don't know how to solve this, some help in the right direction would be very much appreciated!
Thanks!
The answer is to JOIN the tables, SUM the votes, and ORDER high-to-low by the sum of the votes
SELECT pictures.*, SUM(user2pictures.vote) AS VoteTotal
FROM pictures
JOIN user2pictures ON pictures.picid = user2pictures.picid
GROUP BY pictures.picid
ORDER BY VoteTotal DESC
LIMIT 12
try this
select p.`picid`, `Lat`, `Lon` from pictures p
inner join user2pictures u2p
on p.picid = u2p.picid
group by u2p.picid
order by sum(vote) desc
limit 12
DEMO
I'll assume that you also want to show the pictures with no votes. So, you can try this:
select
p.picId, sum(v.vote) as votes
from
pictures as p
left join user2pictures as v on p.picId = v.picId
group by
p.picId
order by
sum(v.vote) desc
limit 12;
The left join is what lets you show the pictures with no votes (the column votes will have the value 0)
Hope this helps