$tmp = mysql_query("SELECT commercial FROM Channels WHERE name='".mysql_real_escape_string($_POST['name'])."'");
while( $row = mysql_fetch_assoc($tmp))
{
echo $row['commercial'];
}
I only want to access the first element.
not in a while loop
You can use mysql_fetch_row to retrieve the value like that ...
$row = mysql_fetch_row($tmp);
$commercial = $row['commercial'];
Well, just remove your while loop then. This will get the first (actually current) row:
$tmp = mysql_query("SELECT commercial FROM Channels WHERE name='".mysql_real_escape_string($_POST['name'])."'");
$row = mysql_fetch_assoc($tmp);
echo $row['commercial'];
Another option is to use mysql_result:
$tmp = mysql_query('..');
$row = mysql_result($tmp, 0);
echo $row['commercial'];
Side note: If you only need one row, add LIMIT 1 to your query.
If you need just the first element, why don't you append LIMIT 1 to your query ?
Related
I've seen the question about "doing mysql_fetch_array" multiple times solved by stocking the result in another variable, or by resetting the mysql_fetch_array loop index for example...
But that's not what I need. I need to use 2 mysql_fetch_ array, one in another, like this :
$sql = mysql_query("SELECT step FROM cyclone_cities ORDER BY uid");
$inc = 0;
while ($row = mysql_fetch_array($sql,MYSQL_NUM)){
$selected = $row[0];
while ($row2 = mysql_fetch_array(mysql_query("SELECT ".$selected." FROM cyclone_players ORDER BY uid"))){
print_r($row2);
}
}
How can I make it to use two differents mysql_fetch_array indexes ?
I need to print a wine list from a database.
I need to print at first a categorie and after all the items that are inside. Thats the order. And i have multiple categorie. So at the end the result will be categorie1, many items, categorie2 many items...
This is the code that i write from now: I think that my problem is to print items according to the id of the alcool_categorie !!
$q_vine = "SELECT * FROM alcool_categorie ";
$r_vine = mysql_query($q_vine,$connection);
$n_vine = mysql_num_rows($r_vine);
$q_bouteille = "SELECT * FROM alcool_item where ALCNID = '$alid'";
$r_bouteille = mysql_query($q_bouteille,$connection);
$n_bouteille = mysql_num_rows($r_bouteille);
for($i = 0; $i < $n_vine; $i++){
echo mysql_result($r_vine,$i,'named').'<br/><br/>';
for($z = 0; $k < $n_bouteille; $k++){
echo mysql_result($r_bouteille,$k,'name').'<br/>';
}
}
I think it's best to use a "JOIN" in your query and then order the rows in the way you want them to be ordered, then you'll only need one loop. While running the loop you compare the category name with the previous category name and if it changes display the category name.
Example
$sql = "SELECT categoryName, bottleName FROM category INNER JOIN bottle ON category.categoryId = bottle.categoryId ORDER BY category.categoryId";
$result = mysql_query($sql,$connection);
$categoryName = ''; //just to make sure the first time the Category is named
while ($row = mysql_fetch_assoc($result)) {
if($categoryName != row['categoryName']){
$categoryName = row['categoryName'];
echo '<h1>'.$categoryName.'</h1>';
}
echo row['bottleName'].'<br/>';
}
Try this after correctly giving the category id field name in the query and inside the first while loop.
$q_vine = "SELECT id, named FROM alcool_categorie ";
$r_vine = mysql_query($q_vine,$connection);
$n_vine = mysql_num_rows($r_vine);
while ($row = mysql_fetch_assoc($r_vine)) {
$categories[$row['id']] = $row;
}
$q_bouteille = "SELECT name, ALCNID FROM alcool_item ";
$r_bouteille = mysql_query($q_bouteille,$connection);
$n_bouteille = mysql_num_rows($r_bouteille);
while ($row = mysql_fetch_assoc($r_bouteille)) {
$items[$row['ALCNID']] = $row;
}
foreach ($categories as $category_id=>$category) {
echo "<ul><li>{$category['named']}<ul>";
foreach ($items[$category_id] as $item) {
echo "<li>{$item['name']}</li>";
}
echo "</ul></li></ul>";
}
You will want to look into PHP's foreach construct. Foreach loops through an entire array of results, for each element inside the array, it extracts its value and optionally also its key. This will not require the use of mysql_num_rows.
Instead of calling mysql_result, you could use mysql_fetch_assoc to get a row's value from your mysql_query. The row's To get all values, you can incorporate this into a loop even. If you do the latter, you can create your own array of key/value pairs and use this inside a foreach construct.
Also note that the use of mysql is outdated, you will want to use mysqli now, which is very similar to mysql.
I have the following query:
$result = mysql_query("SELECT option_value FROM wp_10_options WHERE option_name='homepage'");
$row = mysql_fetch_array($result);
print_r ($row);
and the output I am getting is:
Resource id #2
Ultimately, I want to be able to echo out a single field like so:
$row['option_value']
Without having to use a while loop, as since I am only trying to get one field I do not see the point.
I have tried using mysql_result with no luck either.
Where am I going wrong?
Try with mysql_fetch_assoc .It will returns an associative array of strings that corresponds to the fetched row, or FALSE if there are no more rows. Furthermore, you have to add LIMIT 1 if you really expect single row.
$result = mysql_query("SELECT option_value FROM wp_10_options WHERE option_name='homepage' LIMIT 1");
$row = mysql_fetch_assoc($result);
echo $row['option_value'];
$result = mysql_query("SELECT option_value FROM wp_10_options WHERE option_name='homepage'");
$row = mysql_fetch_assoc($result);
echo $row['option_value'];
Functions mysql_ are not supported any longer and have been removed in PHP 7. You must use mysqli_ instead. However it's not recommended method now. You should consider PDO with better security solutions.
$result = mysqli_query($con, "SELECT option_value FROM wp_10_options WHERE option_name='homepage' LIMIT 1");
$row = mysqli_fetch_assoc($result);
echo $row['option_value'];
use mysql_fetch_assoc to fetch the result at an associated array instead of mysql_fetch_array which returns a numeric indexed array.
Though mysql_fetch_array will output numbers, its used to handle a large chunk.
To echo the content of the row, use
echo $row['option_value'];
Try this one if you want to pick only one option value.
$result = mysql_query("SELECT option_value FROM wp_10_options WHERE option_name='homepage'");
$row = mysql_fetch_array($result);
echo $row['option_value'];
What you should get as output with this code is:
Array ()
... this is exactly how you get just one row, you don't need a while loop. Are you sure you're printing the right variable?
Ultimately, I want to be able to echo out a signle field like so:
$row['option_value']
So why don't you? It should work.
It is working for me..
$show = mysql_query("SELECT data FROM wp_10_options WHERE
option_name='homepage' limit 1"); $row = mysql_fetch_assoc($show);
echo $row['data'];
is this is a WordPress?
You shouldn't do it like you've done!
To get option from DB use get_option!
this shoude work
<?php
require_once('connection.php');
//fetch table rows from mysql db
$sql = "select id,fname,lname,sms,phone from data";
$result = mysqli_query($conn, $sql) or die("Error in Selecting " . mysqli_error($conn));
//create an array
$emparray = array();
for ($i = 0; $i < 1; $i++) {
$row =mysqli_fetch_assoc($result);
} $emparray[] = $row;
echo $emparray ;
mysqli_close($connection);
?>
make sure your ftp transfers are in binary mode.
I have a small problem and since I am very new to all this stuff, I was not successful on googling it, because I dont know the exact definitions for what I am looking for.
I have got a very simple database and I am getting all rows by this:
while($row = mysql_fetch_array($result)){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
Now, my question is: how do I filter the 2nd result? I thought something like this could work, but it doesnt:
$name2= $row['name'][2];
Is it even possible? Or do I have to write another mysql query (something like SELECT .. WHERE id = "2") to get the name value in the second row?
What I am trying to is following:
-get all data from the database (with the "while loop"), but than individually display certain results on my page. For instance echo("name in second row") and echo("id of first row") and so on.
If you would rather work with a full set of results instead of looping through them only once, you can put the whole result set to an array:
$row = array();
while( $row[] = mysql_fetch_array( $result ) );
Now you can access individual records using the first index, for example the name field of the second row is in $row[ 2 ][ 'name' ].
$result = mysql_query("SELECT * FROM ... WHERE 1=1");
while($row = mysql_fetch_array($result)){
/*This will loop arround all the Table*/
if($row['id'] == 2){
/*You can filtere here*/
}
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
$counter = 0;
while($row = mysql_fetch_array($result)){
$counter++;
if($counter == 2){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
}
This While loop will automatically fetch all the records from the database.If you want to get any other field then you will only need to use for this.
Depends on what you want to do. mysql_fetch_array() fetches the current row to which the resource pointer is pointing right now. This means that you don't have $row['name'][2]; at all. On each iteration of the while loop you have all the columns from your query in the $row array, you don't get all rows from the query in the array at once. If you need just this one row, then yes - add a WHERE clause to the query, don't retrieve the other rows if you don't need them. If you need all rows, but you wanna do something special when you get the second row, then you have to add a counter that checks which row you are currently working with. I.e.:
$count = 0;
while($row = mysql_fetch_array($result)){
if(++$count == 2)
{
//do stuff
}
}
Yes, ideally you have to write another sql query to filter your results. If you had :
SELECT * FROM Employes
then you can filter it with :
SELECT * FROM Employes WHERE Name="Paul";
if you want every names that start with a P, you can achieve this with :
SELECT * FROM Employes WHERE Name LIKE "P%";
The main reason to use a sql query to filter your data is that the database manager systems like MySQL/MSSQL/Oracle/etc are highly optimized and they're way faster than a server-side condition block in PHP.
If you want to be able to use 2 consecutive results in one loop, you can store the results of the first loop, and then loop through.
$initial = true;
$storedId = '';
while($row = mysql_fetch_array($result)) {
$storedId = $row['id'];
if($initial) {
$initial = false;
continue;
}
echo $storedId . $row['name'];
}
This only works for consecutive things though.Please excuse the syntax errors, i haven't programmed in PHP for a very long time...
If you always want the second row, no matter how many rows you have in the database you should modify your query thus:
SELECT * FROM theTable LIMIT 1, 1;
See: http://dev.mysql.com/doc/refman/5.5/en/select.html
I used the code from the answer and slightly modified it. Thought I would share.
$result = mysql_query( "SELECT name FROM category;", db_connect() );
$myrow = array();
while ($myrow[] = mysql_fetch_array( $result, MYSQLI_ASSOC )) {}
$num = mysql_num_rows($result);
Example usage
echo "You're viewing " . $myrow[$view_cat]['name'] . "from a total of " . $num;
I need to print one row from a table so a while loop isn't necessary, is there any other method?
You need not while.
Just do your while condition outside while 1 time.
i.e
$a=mysql_fetch_row($sql);
//use $a
instead of
while($a=mysql_fetch_row($sql)){
//use $a
}
if (($dbResult = mysql_query("SELECT ... FROM ... LIMIT 1")) !== false)
{
$row = mysql_fetch_array($dbResult);
echo $row['Column_Name'];
}
Just fetch one row, no need to always loop a retrieval.
$results = mysql_query("SELECT * FROM my_table WHERE user_id = 1234");
$row = mysql_fetch_assoc($results);
echo ($row['user_id']);
Do what you would have done inside the condition of your loop, and you'll be fine.