Is it possible to perfom a fulltext search against a joined column? - php

Hello I' trying to select from joined column:
SELECT
A.idAd,
A.ads_in_Cat,
A.title,
A.currency,
A.price,
A.in_dpt,
A.description,
D.*,
S.*
FROM ads A
LEFT JOIN dept D ON D.id_dept = A.in_dpt
LEFT JOIN sub_cat_ad AS ON S.id_sub_cat = A.ads_in_Cat
WHERE MATCH(A.title, A.description) AGAINST(:searchTerm)
OR MATCH (S.sub_cat_name) AGAINST(:searchTerm)
Could someone please tell me why MySQL returns : 1191 Can't find FULLTEXT index matching the column list in... unless I use IN BOOLEAN MODE?
PS the table S has fulltext defined for each colunm. MySQL ver 5.1.49

Do you still get the error when you use:
SELECT A.idAd,
A.ads_in_Cat,
A.title,
A.currency,
A.price,
A.in_dpt,
A.description,
D.*,
s.*
FROM ads A
LEFT JOIN dept D ON D.id_dept = A.in_dpt
LEFT JOIN sub_cat_ad s ON s.id_sub_cat = A.ads_in_Cat
AND MATCH (s.sub_cat_name) AGAINST(:searchTerm)
WHERE MATCH(A.title, A.description) AGAINST(:searchTerm)

Related

Left Join with subquery returns Null

I am applying Left Join with Sub query & where clause
It seems fine no syntax error but the columns I am selecting from that sub query always returns me Null. I have executed the same part in my SQL section, it gives me record. Kindly have a look on the query and let me know if any thing is possible or if question is not clear.
SELECT alt.userId, u.name, t.name AS teamName, alt.startDateTime, v.name AS villageName, c.name AS clusterName, startLat, startLong, latlng.lat, latlng.long
FROM activity_log_tim AS alt
JOIN user AS u ON u.userId = alt.userId
JOIN team_members AS tm ON tm.memberId = u.userId
JOIN team AS t ON t.teamId = tm.teamId
JOIN village AS v ON v.villageId = alt.villageId
JOIN cluster_villages AS cv ON cv.villageId = v.villageId
JOIN cluster AS c ON c.clusterId = cv.clusterId
LEFT JOIN (SELECT lat, long,dateTime, scheduleId FROM activity_log_gps LIMIT 1) AS latlng ON latlng.scheduleId = alt.scheduleId
WHERE DATE(alt.startDateTime) = '2015-09-05' AND DATE(alt.endDateTime) = '0000-00-00' GROUP BY alt.userId ORDER BY latlng.dateTime DESC
Well it's supposed to since you are performing a LEFT JOIN which produces NULL if no match occurs. So either you can perform a INNER JOIN or use a COALESCE function like below
SELECT alt.userId, u.name,
t.name AS teamName,
alt.startDateTime,
v.name AS
villageName,
c.name AS clusterName,
startLat,
startLong,
COALESCE(latlng.lat, 23), //Notice the use of COALESCE. If null will return 23 as default
COALESCE(latlng.long, 32)

mysql join return 0 for one column with other columns intact

I wish to join multiple tables like- Categories, menus, restaurants, reviews, etc.
to return the restaurants that provide the inserted food with their prices.
Everything works except numberOfReviews in reviews table.
If a restaurant has no reviews then output should be 0 for numOfReviews column but other column values should be retrieved i.e. price, name, etc.
With following query I get all fields as null and count(numReviews) as 0:
select r.id
,r.`Name`
,r.`Address`
,r.city
,r.`Rating`
,r.`Latitude`
,a.`AreaName`
,m.`Price`
,count(rv.id)
from `categories` c, `menus` m, `restaurants` r, areas a, reviews rv
where m.`ItemName`="tiramisu"
and c.`restaurant_id`=r.`id`
and m.`category_id`=c.id
and r.`AreaId`=a.`AreaId`
and if I can't match rv.restaurant_id=r.id in where clause(obviously).
Where am I getting wrong? How do I solve this?
edited
select r.id,
r.`Name`,
r.`Address`,
r.city,
r.`Rating`,
r.`Latitude`,
a.`AreaName`,
m.`Price`,
r.`Longitude`,
r.Veg_NonVeg,
count(rv.id)
from restaurants r LEFT JOIN `reviews` rv on rv.`restaurant_id`=r.`id`
inner join `categories` c on c.`restaurant_id` = r.id
inner join `menus` m on m.`category_id` = c.id
inner join `areas` a on a.`AreaId` = r.`AreaId`
where m.`ItemName`="tiramisu"
First of all, don't use this old school syntax for the jointures.
Here is a query that may solve your problem:
SELECT R.id
,R.Name
,R.Address
,R.city
,R.Rating
,R.Latitude
,R.Longitude
,A.AreaName
,M.Price
,R.Veg_NonVeg
,COUNT(RV.id) AS numOfReviews
FROM restaurants R
INNER JOIN categories C ON C.restaurant_id = R.id
INNER JOIN menus M ON M.category_id = C.id
INNER JOIN areas A ON A.AreaId = R.AreaId
LEFT JOIN reviews RV ON RV.restaurant_id = R.id
WHERE M.ItemName = 'tiramisu'
GROUP BY R.id, R.Name, R.Address, R.city, R.Rating, R.Latitude, R.Longitude, A.AreaName, M.Price, R.Veg_NonVeg
I used explicit INNER JOIN syntax instead of your old school syntax and I modified the jointure with table reviews in order to get the expected result. The GROUP BY clause is required to use the aggregate function COUNT, every rows will be grouped by the enumerated columns (every column except the one used by the function).
Here is another solution that simplify the GROUP BY clause and allow the modification of SELECT statement without having to worry about the fact that every columns need to be part of the GROUP BY clause:
SELECT R.id
,R.Name
,R.Address
,R.city
,R.Rating
,R.Latitude
,R.Longitude
,A.AreaName
,M.Price
,R.Veg_NonVeg
,NR.numOfReviews
FROM restaurants R
INNER JOIN (SELECT R2.id
,COUNT(RV.id) AS numOfReviews
FROM restaurants R2
LEFT OUTER JOIN reviews RV ON RV.restaurant_id = R2.id
GROUP BY R2.id) NR ON NR.id = R.id
INNER JOIN categories C ON C.restaurant_id = R.id
INNER JOIN menus M ON M.category_id = C.id
INNER JOIN areas A ON A.AreaId = R.AreaId
WHERE M.ItemName = 'tiramisu'
As you can see here I added a new jointure on a simple subquery that does the aggregation job in order to provide me the expected number of reviews for each restaurant.
Hope this will help you.

Loading details from multiple tables

I was using this:
SELECT res.*, rac.*, u.*, t.*, c.*
FROM Results res
INNER JOIN Races rac USING (RaceID)
INNER JOIN Users u USING (UserID)
INNER JOIN Teams t USING (TeamID)
INNER JOIN Cars c USING (CarID)
WHERE res.SeasonNumber = '$SeasonNumber' AND res.LeagueID = '$LeagueID' AND Position = '1' AND ResultConfirmed = '1'
ORDER BY Position ASC
Which works fine, but I've since realised I need to have CarID added in to Results table, but when I add it in, it gives me the error that the field is ambiguous. What I'd like to do is get the Car name from Cars table where CarID joins Cars and Results. When I try to do this though:
SELECT res.*, rac.*, u.*, t.*, c.*
FROM Results res
INNER JOIN Races rac USING (RaceID)
INNER JOIN Users u USING (UserID)
INNER JOIN Teams t USING (TeamID)
INNER JOIN Cars c USING (res.CarID)
WHERE res.SeasonNumber = '$SeasonNumber' AND res.LeagueID = '$LeagueID' AND Position = '1' AND ResultConfirmed = '1'
ORDER BY Position ASC
I get the following error:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near '.CarID) WHERE res.SeasonNumber = '1' AND res.LeagueID = '1' AND
Position = '1' ' at line 6
You can replace your USING clause with ON(),in USING() clause i guess you add the columns name that are same in other table you are joining but you placed the join in last and using alias res mysql won't allow this
INNER JOIN Cars c ON(res.CarID =c.CarID)
If you need to use USING() clause you need to adjust the join placements like
SELECT res.*, rac.*, u.*, t.*, c.*
FROM
Cars c
INNER JOIN Results res USING (CarID)
INNER JOIN Races rac USING (RaceID)
INNER JOIN Users u USING (UserID)
INNER JOIN Teams t USING (TeamID)
WHERE res.SeasonNumber = '$SeasonNumber' AND res.LeagueID = '$LeagueID' AND Position = '1' AND ResultConfirmed = '1'
ORDER BY Position ASC
But ON() clause is more readable form

mysql query dont gets all posts

I have a MYSQL query who have to list all post i want it to post. But it dont do it. It shows posts when i have more then one post in the table "meaOrder" with the same "ordCode". But when i have only on post in meaOrder, i don't show it. What can i do?
SELECT koden, wish, rnamn, bild, pris, cname, onsktext
FROM (
SELECT m.wishText as onsktext, m.meaOID as midn, m.ordcode as koden, w.wish as wish, r.meaName as rnamn, r.meaImg as bild,
r.meaPrice as pris, k.catName as cname from cats k, meals r, wishes w,
meaOrder m
join orders c on c.ordNR=4401
WHERE c.ordStatus=1 AND m.ordNR=c.ordNR AND m.meaID=r.meaID AND m.wishesID=w.id
AND r.catID=k.catID
) T
GROUP BY koden, rnamn, bild, pris, cname
ORDER BY midn DESC
TABLE orders
http://grab.by/m74E
TABLE meaOrder http://grab.by/m74Q
Try replacing the JOIN with RIGHT JOIN in this case. The difference is explained at JOIN Syntax page in MySQL docs . In short - JOIN returns row only if there are corresponding rows in both joined tables (inner join). LEFT JOIN / RIGHT JOIN return all rows from one of the tables and corresponding row if it exists from the other table (those are outer joins)
Do you need a subselect?
This seems to cover it:-
SELECT m.ordcode AS koden, w.wish AS wish, r.meaName AS rnamn, r.meaImg AS bild, r.meaPrice AS pris, k.catName AS cname, m.wishText AS onsktext
FROM cats k
INNER JOIN meals r ON r.catID = k.catID
INNER JOIN meaOrder m ON m.meaID = r.meaID
INNER JOIN wishes w ON m.wishesID = w.id
INNER JOIN orders c ON m.ordNR = c.ordNR
WHERE c.ordStatus = 1
AND c.ordNR = 4401
GROUP BY m.ordcode, r.meaName, r.meaImg, r.meaPrice, k.catName
ORDER BY midn DESC

MySQL warning of Unknown column that exists

Having found out how to find PHP problems. I am now trying to solve them, but I have no clue on this one.
I made use of mysql_error and I have found:
1054: Unknown column 'o.user_id' in 'on clause'
Is there something wrong with this:
$sql="SELECT o.*, u.user_name, u.email, od.artist_id,cm.nexchange_price
FROM ".$tableprefix."orders o,".$tableprefix."currency_master cm
INNER JOIN ".$tableprefix."users u ON o.user_id = u.user_id
INNER JOIN ".$tableprefix."order_details od ON o.order_id = od.order_id
WHERE o.order_id = ".GetSQLValueString($orderid,"text")."
AND o.vorder_currency = cm.vcurrency_code ".$qryopt . " ORDER BY o.order_date DESC";
That column exists in the orders table?!
You have a comma after "orders o,", which means that you are trying to join the currency_master table with the users table, instead of orders and users. I suppose you wanted to have:
$sql="
SELECT
o.*, u.user_name, u.email, od.artist_id,cm.nexchange_price
FROM
".$tableprefix."currency_master cm,
".$tableprefix."orders o
INNER JOIN
".$tableprefix."users u
ON
o.user_id = u.user_id // et cetera"

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