<a href="companies.php?id='. $_GET['id'] .'&offset='. $next_offset .'"><input id="button" type="button" value="More"/>
i somehow want to send &offset=avalue but useing a input button. without the id.
how can i do the similer thing with useing form action get ?
like ( warning epic fail ) i should add a hidden input or something ?
echo '<form action="welcome.php" method="get">';
echo '<input id="button" type="button" value="More"/>';
echo '</form>';
please comment if you guys dont understand thanks!
ok somehow i have manage to make it work
echo '<form action="companies.php?id='. $_GET['id'].'" method="get">';
echo '<input type="hidden" name="offset" value="'.$next_offset.'">';
echo '<input id="button" type="submit" value="More"/></a>';
echo '</form>';
but still have an error http://local.host/networks/companies.php?offset=5, where does my get id goes ?
btw im still checking it out and thanks guys :)
and aha! it works
// MORE PLUGIN
echo '<form action="companies.php" method="get">';
echo '<input type="hidden" name="id" value="'.$_GET['id'].'">';
echo '<input type="hidden" name="offset" value="'.$next_offset.'">';
echo '<input id="button" type="submit" value="More"/></a>';
echo '</form>';
// END PLUGIN
For one thing, you can put parameter in the form's action attribute, just like you did with the link and href.
More readable option is hidden input element: <input type="hidden" name="offset" value="your_value">
Is this what you asked?
<? echo '<input type=button onclick=\'window.location="companies.php?offset='. $next_offset .'"\'>';?>
Related
I have a simple form in HTML that contains two buttons. Button 1 which action in the form tag submits it to another php page e.g. button1-action.php which submits data to a third party API and Button 2 which I want to submit to the same page if it is clicked without going to button1-action.php.
In its simplest method the form is as follows:
<?php
echo '<form name="form123" id="form123" action="button1-action.php" method="POST">';
echo '<input type="text" name="first_name" id="first_name></input>';
echo '<button name="button1" id="button1" value="button1">Button 1</button>';
echo '<button name="button2" id="button2" value="button2">Button 2</button>';
echo '</form>';
?>
This is what I tried so far
$action = null;
if (isset($_POST['button1'])) {
$action = 'button1-action.php';
} elseif (isset($_POST['button2'])) {
$action = $_SERVER["PHP_SELF"];
}
echo '<form name="form123" id="form123" action="' . $action . '" method="POST">';
echo '<input type="text" name="first_name" id="first_name></input>';
echo '<button name=" button1" id="button1" value="button1">Button 1</button>';
echo '<button name="button2" id="button2" value="button2">Button 2</button>';
echo '</form>';
However, it doesn't seem to be working. I tried to look for solutions but I haven't been successful.
I'm interested in any solution, but I would prefer solving it using PHP and not JavaScript.
The Issue might be that you forgot to close the <form> tag with </form> and you should use the <input> for buttons aswell with type="submit" .
If this still doesn't resolve your issue then maybe you should try this :
On the same page.
<?PHP
//// place this on top
if($_POST["button1"]) {
// add code to send data to Third Party API
}
if($_POST["button2"]) {
// will show data here
} ?>
////////
<?php
echo '<form name="form123" id="form123" action="/">';
echo '<input type="text" name="first_name" id="first_name></input>';
echo '<input type="submit" name="button1" id="button1" value="button1" >';
echo '<input type="submit" name="button2" id="button2" value="button2" >';
echo '</form>';
?>
I hope this answers your question 😊
This is the solution for you in html
<form name="form123" id="form123" method = "post">
<input type="text" name="first_name" id="first_name"></input>
<button name=" button1" id="button1" value="button1" formaction="button1-action.php" >Button 1</button>
<button name="button2" id="button2" value="button2" >Button 2</button>
</form>
button 1 will submit the form to button1-action.php and button 2 will submit the form to same page.
Documentation: https://developer.mozilla.org/en-US/docs/Web/HTML/Element/button#attr-formaction
You appear to be using the value submitted from the form to set the action of the form. This makes no sense - by the time you read the submitted values, the action has already happened. So your code would just set the action for next time the form is submitted. Not useful.
At the heart of this there seems to be a conceptual / design issue. A more sensible approach (but not the only one) would be to simply post the form to the same place every time, and then use if statements to decide what to do next.
e.g.
if (isset($_POST['button1'])) {
require_once "button1-action.php";
} elseif (isset($_POST['button2'])) {
//do whatever it is you want to do in ths script
}
else {
?>
<form name="form123" id="form123" method="POST">';
<input type="text" name="first_name" id="first_name></input>
<button name=" button1" id="button1" value="button1">Button 1</button>
<button name="button2" id="button2" value="button2">Button 2</button>
</form>
<?php
}
To improve a bit more on that, instead of using a bare require to include the code from another script, we could encapsulate the code from button1-action.php into a function which we can call, instead of a script with global scope. This makes the code more re-usable, maintainable, testable, less likely to cause scope conflicts, etc.
e.g.
if (isset($_POST['button1'])) {
callTheApi($_POST["first_name"]);
} elseif (isset($_POST['button2'])) {
doSomethingElse($_POST["first_name"]);
}
else {
?>
<form name="form123" id="form123" method="POST">';
<input type="text" name="first_name" id="first_name></input>
<button name=" button1" id="button1" value="button1">Button 1</button>
<button name="button2" id="button2" value="button2">Button 2</button>
</form>
<?php
}
(Even better if you then encapsulate that function in a class containing closely related functionality, but let's just get as far as a funtion for now.)
Alternatively, Virender Kumar's answer would also be reasonable - simply setting the form action of each button directly.
First of all your form is not structured properly.
index.php
<form name="form123" id="form123" action="button1-action.php">
<input type="text" name="first_name" id="first_name"></input>
<button name=" button1" id="button1" value="button1">Button 1</button>
<button name="button2" id="button2" value="button2">Button 2</button>
</form>
button1-action.php
if (isset($_GET['button1'])) {
echo 'button1 submitted'; // Send data to the third party API
} else if (isset($_GET['button2'])) {
echo 'button1 submitted'; // Submit on the same page
}
Edit: ignore my solution; Virender Kumar’s solution here is correct, elegant and doesn’t need JS.
Original answer:
The issue is not with your buttons, but with the fact that a form can only post to a single endpoint (the action attribute). You will have to handle what happens with the form data from there. If you truly want your form to be posted to a different endpoint in the client based on what button the user clicks, you can’t do it without JavaScript.
If you can live with JS, this could work:
<body>
<!-- your form here -->
<script>
const form = document.forms[0]; // assuming your form is the first form on the page, or the only one
document.querySelectorAll('button').forEach(button => {
button.addEventListener('click', event => {
if (event.target.name === 'button1') {
form.action = 'button1-action.php';
} else if (event.target.name === 'button2') {
form.action = 'other-destination';
}
});
});
</script>
</body>
Here is a part of my code in a PHP file :
echo '<form action="verification.php" method="POST">';
echo '<label><b>Name</b></label>';
echo '<input type="text" placeholder="name" name="username" required>';
echo '<input type="submit" id="submit" value="go" ></form>';
How can I get the input value of the form without submitting it and put it in a variable $var?
My goal : when we click on submit, it opens a window with the name of the input.
Thank you for your help
I am creating a button in php and want to call a php with parameter when clicked:
echo '<form method="get" action="./ash.php?q=Y" >';
echo '<button type="submit" >QUERY</button>';
echo '</form>';
When I click on the button, ash.php gets indeed called, but the q parameter has been 'forgotten' in the process.
How can that be?
echo '<form method="get" action="./ash.php" >';
echo '<input type="hidden" name="q" value="Y" />';
echo '<button type="submit" >QUERY</button>';
echo '</form>';
I want to disable a button after the button onclick and then enable the other one .
echo '<input type="text" id="txtbox1" name="tb1" value="'.$value.'" />';
echo '<input type="submit" id="btn1" name = "btnstart" value="START" onClick="this.disabled=true;"/><input type="submit" id="btn2" name = "btnend" value="End" onClick="this.disabled=true;"/>';
In this case, i can only disable the button but the rest of the process skipped. I cannot update the input textbox value.
Also, How can i disable the btn2 the before onclick btn1?
$value= $_POST['tb1'];
echo '<form name="f1" method="POST" action="">';
echo '<input type="text" id="txtbox1" name="tb1" value="'.$value.'" />';
echo '<input type="submit" id="btn1" name = "btnstart" value="START" onClick="this.disabled=true;"/><input type="submit" id="btn2" name = "btnend" value="End" onClick="this.disabled=true;"/>';
echo '</form>';
echo '</td>';
if ( isset( $_POST['tb1'] ) ) {
$new = $value *12;
}
Try this:
<input type="submit" id="btn1" name = "btnstart" value="START" onClick="document.getElementById('btn2').disabled=false;this.disabled=true;"/>
<input type="submit" id="btn2" name = "btnend" value="End" onClick="this.disabled=true;" disabled/>
Working example: jsfiddle
Can you try this,
How can i disable the btn2 at the before onclick btn1?
Added onClick="document.getElementById(\'btn2\').disabled=true;this.disabled=true;"
echo '<input type="text" id="txtbox1" name="tb1" value="'.$value.'" />';
echo '<input type="submit" id="btn1" name = "btnstart" value="START" onClick="document.getElementById(\'btn2\').disabled=true;this.disabled=true;"/>
<input type="submit" id="btn2" name = "btnend" value="End" onClick="this.disabled=true;"/>';
try jquery
first load the html with submit button 2 disabled
echo '<input type="text" id="txtbox1" name="tb1" value="" />';
echo '<input type="submit" id="btn1" name = "btnstart" value="START" /><input type="submit" id="btn2" name = "btnend" value="End" disabled="disabled" />';
then using jquery
$(document).ready(function(){
$("input[type='submit']").click(function(){
$("input[type='submit']").prop('disabled',false);
$(this).prop('disabled',true);
});
});
disable the clicked submit button and enable other submit button
I placed an example in jQuery. jQuery is much easier then normal Javascript. Dont forget that jQuery is still javascript but then with functions that are already named to do their function:
.click() //When clicked
.next() //Next element/attribute
.mouseenter //When hover
.text() //Set the text
$('#mydiv').text('Contains this text');
Do the codecadamy.com training, its very helpfull, easy to follow and very quick.
I placed an example in jQuery for you:
JSFiddle
i am writing html form code with in php script
here it is
<?php
$problem_code="STR";
echo '<form name="submit-button" action="/codejudge/submit.php?id='.$problem_code.'">';
echo '<button type="submit" >Submit</button>';
echo "</form>";
?>
But after submitting url look like this localhost/codejudge/submit.php ?
but it should be like this localhost/codejudge/submit.php?id=STR
If a form is method="GET" (which is the default), as this one is, then submitting it will erase the existing query string in the action.
Store the data in a hidden input instead.
<?php
$problem_code="STR";
?>
<form name="submit-button" action="/codejudge/submit.php">
<input type="hidden" name="id" value="<?php echo htmlspecialchars($problem_code); ?>">
<button type="submit">Submit</button>
</form>
You should specify a method of form submit.
$problem_code="STR";
echo '<form method=post name="submit-button" action="/codejudge/submit.php?id='.$problem_code.'">';
echo '<button type="submit" >Submit</button>';
echo "</form>";