Display image via local path - file:\\\c:\ using PHP - php

I want to load image via c:/user_name/image/image_name.jpg using http://intranet/user/index.php.
<img src="file:///c:/user_name/image/image_name.jpg">
How do I display them?
Thanks
Jean

You realize this would only work if that image is in the exact same location on every machine which will be viewing this page? Is there any reason you can't serve up the image normally, via the web server itself?
Since you're using an absolute Windows path, this would only work on Windows machines, which actually have a C drive, the same directories, etc... It won't work at all on a Mac or Linux or whatever else box, since they don't bother with drive letters.
followup:
after pondering your question a bit, it looks like you want to serve up a specific image that's not stored in your document root and serve it from a specific page. If you put something like this at the start of your index.php:
<?php
if (isset($_GET['username']) && isset($_GET['image'])) {
$user = $_GET['username'];
$image = $_GET['image'];
$path = "C:\\{$user}\\image\\{$image}";
if (is_readable($path)) {
$info = getimagesize($path);
if ($info !== FALSE) {
header("Content-type: {$info['mime']}");
readfile($path);
exit();
}
}
}
?>
and within the HTML:
<img src="index.php?user=user_name&image=image_name" />
Of course, this is very basic, and serving up files this way is highly insecure, but most likely this is the basics of what you wanted.

<?php
$path = "C:\\xampp\\htdocs\\Create.jpg";
if (is_readable($path))
{
$info = getimagesize($path);
if ($info !== FALSE)
{
header("Content-type: {$info['mime']}");
readfile($path);
echo '<img src="data:image/jpeg;base64,'. base64_encode($path) .'" height="100" width="100"/>';
}
}
?>

Related

Get image from PHP displaying using an img src

The code I have should output a jpg from a list of files in a directory however it is not. I have trawled this site and tried different methods but not helped. I am a relative beginner at php so looking for any help at all.
I have tried using img src in the php code but I am trying to get the image to display within a Wordpress post so I cannot echo the img src within the script. I have tried file_get_contents and read file as well but it may be my lack of knowledge holding me back.
<?php
$imagepath = htmlspecialchars($_GET["image"]);
$imagenum = htmlspecialchars($_GET["num"]);
define('LOCALHOST', 'localhost' === $_SERVER['SERVER_NAME'] );
If(LOCALHOST){
define('PATH_IMAGES', 'this_path');
}else{
define('PATH_IMAGES', '../../../Images/');
}
$arrnum = $GLOBALS[imagenum] - 1;
$dirname = PATH_IMAGES . $GLOBALS[imagepath]."/";
$images = scandir($dirname);
rsort($images);
$ignore = Array(".", "..");
foreach($images as $curimg){
if(!in_array($curimg, $ignore)) {
header('Content-type: image/jpeg');
file_get_contents('$dirname$images[$arrnum]');
}
}
?>
Have you tried readfile(...); should read and output the file. In your example you are not outputting the image data
http://php.net/manual/en/function.readfile.php

Yii2: Error Not allowed to load local resource

Im trying to display images from backend of my app
<?php foreach ($img as $key=>$row): ?>
<div class="products_inside_wrapper intro_wrapper">
<div class="classes_inside_item bordered_wht_border">
<?php
foreach (explode(';',rtrim($row['images'],';')) as $key_img => $value_img)
{
?>
<?php echo Html::img('#backend/web'.'/'.$value_img);?>
<?php
}
?>
</div>
</div>
<?php endforeach; ?>
Tried with above code to display all images, but getting error Not allowed to load local resource when I open Google Chrome Inspect Element
i think you are using a local url instead of using this
<?php echo Html::img('#backend/web'.'/'.$value_img);?>
try using it like
<?= Html::img(Yii::getAlias('#web').'/images/'.$value_img]);?>
As stig-js answered you can't load local saved image directly, If you're really interested into loading resources from a local path, you can open image as a binary file with fopen and echo the content of it with a proper header to output. In general way, you can add a method to your model like this:
public function getImage($imageName)
{
$imagePath = '#backend/web' . '/' . $imageName;
$fileInfo = finfo_open(FILEINFO_MIME_TYPE);
$contentType = finfo_file($fileInfo, $imagePath);
finfo_close($fileInfo);
$fp = fopen($imagePath, 'r');
header("Content-Type: " . $contentType);
header("Content-Length: " . filesize($imagePath));
ob_end_clean();
fpassthru($fp);
}
P.S: Also you can use combination of this answer with showing image as base64 on HTML. See How to display Base64 images in HTML?
Images must be accesible by an url, like
yoursite.com/backend/imagedir/IMG'
If yoursite.com/backend points to your backend/web folder.
Backend alias points to your local path, so you need a custom alias to reach image folders.
Yii2 aliases: http://www.yiiframework.com/doc-2.0/guide-concept-aliases.html

Image Caching with PHP

i am trying to learn how to cache an image that is created in PHP, this current piece of PHP wil cache text to a file, but i want to get it to cache an image called 'my_barcode.png' to the cache folder, any help would be greatly appreciated.
<?php
$h = opendir('data/');
$chace = 'cache/test.cache.php';
if(file_exists($chace))
{
include($chace);
}
else
{
$result = NULL;
while (($file = readdir($h)) !=false)
{
$result .= $file. '<br />';
}
closedir($h);
echo $result;
$fs = fopen($chace, 'w+');
fwrite($fs, $result);
fclose($fs);
}
?>
If the purpose is to serve cached files, PHP should create them when not existing but the http server (such as Apache) should be serving the static files if they exist. Implementing cache the way you did takes too many resources as PHP is still called.

CodeIgniter doesn't see images (using file_exists)

I'm learning CodeIgniter. I have a directory img with images (path /img/). I am trying to access it through CI view and check if exists with this code:
$av = '../../../img/content/users/'.$userID.'.jpg';
if(file_exists($av)) {
$avatar = $av;
} else {
$avatar = 'img/content/users/none.jpg';
}
Funny thing is, echoing <img src="'.$av.'"> works. What should I do?
CI always runs on index.php, so paths are always relative from there.
Assuming index.php and /img are at the same level in the root, try this:
$av = 'img/content/users/'.$userID.'.jpg';
if(is_file($av)) { // or better yet, make sure it's really an image
$avatar = $av;
} else {
$avatar = 'img/content/users/none.jpg';
}
Funny thing is, echoing <img src="'.$av.'"> works
It's because the browser is looking in a different place than the server. I'd recommend not using ../../relative/paths but using functions like base_url() and img(). When there are additional segments in the URL, relative paths break.
URLs and file paths are not the same. From the current URL ../../../img/content/users may and likely is something completely different than the file path on the hard disk where the view file is located.
Use following steps
1) Create a custom config file name site_config.php in config file (/application/config/) and paste following code
<?php
$config['base_url'] = "http://".$_SERVER['SERVER_NAME'] . str_replace(basename($_SERVER['SCRIPT_NAME']),"",$_SERVER['SCRIPT_NAME']);
if(!defined('DOCUMENT_ROOT')) define('DOCUMENT_ROOT',str_replace('system/application/config','',substr(__FILE__, 0, strrpos(__FILE__, '/'))));
$config['base_path'] = constant("DOCUMENT_ROOT");
?>
2) Edit autoload.php to autoload site_config.php (/application/config/autoload.php)
$autoload['config'] = array('site_config');
3) Then using following code to view image
$image_path = $this->config->item('base_path').'folder_name/'.$userID.'.jpg';
if(file_exists($image_path)) {
$avatar = $this->config->item('base_url').'folder_name/'.$userID.'.jpg';
} else {
$avatar = $this->config->item('base_url').'default_folder_name/profile.jpg';
}
echo '<img src="'.$avatar.'" />';
I think it will help you
Try this:
$av = './img/content/users/'.$userID.'.jpg';

echoing thumbnails that link to the larger image

I have a script that scans a directory of thumbnails and echoes them to the page. It works nicely, but the thumbnails are not clickable, and i would really like this to be the case. echo "<img src='$thumbnail' class='resizesmall'>"; is the line where the thumbnails are echoed. I'm not sure how to write the path to the larger image inside the php without breaking it. Maybe this should be done inside the foreach statement? thanks for your help?
$dir = "../mysite/thumbnails/";
$dh = opendir($dir);
// echo "$dh";
$gallery = array();
while($filename = readdir($dh))
{
$filepath = $dir.$filename;
//pregmatch used to be ereg
if (is_file($filepath) and preg_match("/\.png/",$filename))
{
$gallery[] = $filepath;
}
}
sort($gallery);
foreach($gallery as $thumbnail)
{
echo "<img src='$thumbnail' class='resizesmall'>";
}
?>
</div>
<??>
The easiest way would be to setup a situation where your thumbs and your full size images were named the same. So you may have thumbs/image1.png and full/image1.png. Then instead of using $thumbnail use a variable $image, or something similar just so the code reads better. You'll also want to leave the $filepath out of the mix so that $image ends up as just the file name.
foreach($gallery as $image)
{
echo "<a href='full/$image'><img src='thumb/$image' class='resizesmall'></a>";
}
You may want to throw in some checks to make sure there is a matching image just to prevent errors or bad UX. However, the code above should work.

Categories