I am trying to print a variable between curly braces as
Product_number{product_version}
I tried
echo "$product_number{$product_version}";
But that does not work. I don't understand why :(
try using double braces:
echo "$product_number{{$product_version}}";
You can also do:
echo "$product_number{".$product_version."}";
{ followed by $ is treated specially. It is mainly used when you want to append a string immediately at the end of a variable's value:
$v = 'hack';
echo "I {$v}ed it";
echo $product_number . "{" . $product_version . "}";
Escape the "{":
echo "$product_number\{$product_version}";
Related
i have this problem i hope some of you can help me with. I try to make a html link that get the link from my database.
echo "<p><pre><a href=$Feed['socialfacebook']><img src=facebook-24.png></a></pre></p>
You need to put the link in '".$variable ."' and the image src should be in ' ', too.
echo "<p><pre><a href='".$Feed['socialfacebook']."'><img src='facebook-24.png'></a></pre></p>";
Double-quoted strings don't work with array elements quite like that. You should close and concatenate the strings.
echo "<p><pre><img src=facebook-24.png></pre></p>"
You might also want to put some quotes on your attributes.
Close your string with a double quote and end your statement with a semi-colon,
When getting array elements inside a string literal like you're doing, leave out the key quotes,
Use single quotes around your attribute in case of any spaces:
echo "<p><pre><a href='$Feed[socialfacebook]'><img src=facebook-24.png></a>";
Eval.in
u need to put the variable $Feed['socialfacebook'] in " . $Feed['socialfacebook'] ."
echo "<p><pre><a href=" . $Feed['socialfacebook'] . "<img src=facebook-24.png></a></pre></p>";
and don't forget the ;
Shouldn't it be:
echo "<p><pre><a href='$Feed["socialfacebook"]'><img src=facebook-24.png></a>";
Don't forget that is href="".
I have a problem with my page. I am displaying images using PHP Loop statement. Now I want to assign these images with different id's. Example first loop the first image displayed will have an id="img1", next loop and second image has id="img2". Numbers on the id changes based on the loop iteration variable, while "img" is constant. Here's my code:
for ($i=1;$i<=6;$i++){
echo ("<img src='gangjeong.png' width='113' id='img'.$i>");
}
but it's not working. Any help would be much appreciated.
UPDATE: I got it to work now, thanks for the answers. The working code is:
for ($i=1;$i<=6;$i++){
echo ("<img src='gangjeong.png' width='113' id='img$i'>");
}
You can't use unescaped single quotes if you start your string by single quotes.
These are the possibilities you have:
Using double quotes inside single quotes:
for ($i=0;$i<6;$i++){
echo ('<img src="gangjeong.png" width="113" id="img' . ($i+1) . '" />');
}
Using escaped single quotes inside single quotes (ugly):
for ($i=0;$i<6;$i++){
echo ('<img src=\'gangjeong.png\' width=\'113\' id=\'img' . ($i+1) . '\' />');
}
Using double quotes for starting/ending the string:
for ($i=0;$i<6;$i++){
echo ("<img src='gangjeong.png' width='113' id='img" . ($i+1) . "' />");
}
Using escaped double quotes inside double quotes (ugly):
for ($i=0;$i<6;$i++){
echo ("<img src=\"gangjeong.png\" width=\"113\" id=\"img" . ($i+1) . "\" />");
}
Quotes inside quotes are a no no without proper escaping. Also you have a missing > for the img tag. This should do:
for ($i=1;$i<=6;$i++){
echo "<img src='gangjeong.png' width='113' id='img".$i."'>";
}
Where's your escape characters? Your quotes need escaping, or put your HTML part in double quotes and PHP strings in single, or vice versa. Just make sure you're not confusing start and end quotes.
your syntax is not correct, use:
for ($i=1;$i<=6;$i++){
echo '<img src="gangjeong.png" width="113" id="img'.$i.'" alt="">';
}
Use:
for ($i=1;$i<=6;$i++){
echo "<img src=\"gangjeong.png\" width=\"113\" id=\"img$i\">";
}
I cant get this to work and its driving me mad, pls help
echo "<a href='#' onclick='javascript:$.jGrowl
(\"".$_SESSION['product_description'][$i]."\")' >?</a>";
the problem comes down to the 'product_description' - those single ' marks are breaking it, what should i do sigh
EDIT: if i replace the .$_SESSION['product_description'][$i]. with a bunch of charecters it works, its not a problem with anything but PHP and those ''
Chances are the real problem lies with the $.jGrowl. Within double quotes, PHP tries to parse found variables. e.g.
$foo = 'foo';
echo "This is foo: $foo"; // output: This is foo: foo
So, to avoid this you need to escape the $ using \$ within the string...
echo "...\$.jGrowl..."
See this demo.
Keep this here for reference:
Escape them with a backslash, like you would with double quotes. e.g.
// which ever quote is used to encapsulate the string
// must be escaped within the output.
echo 'Hello, \'world!\''; // output: Hello, 'world!'
echo "Hello, \"world!\""; // output: Hello, "world!"
// but, if you use the opposite quote, it does not need
// to be escaped for output.
echo 'Hello, "world!"'; // output: Hello, "world!"
echo "Hello, 'world!'"; // output: Hello, 'world!'
See the PHP Docs on strings for more information and what characters need escaping.
Are you missing your opening "?
echo "<a href='#' onclick='javascript:$.jGrowl(\"".$_SESSION['product_description'][$i]."\")' >?</a>";
Make it
echo "<a href='#' onclick='javascript:$.jGrowl(\"".$_SESSION['product_description'][$i]."\")' >?</a>";
Try:
echo "<a href='#' onclick='javascript:\$.jGrowl(\"".str_replace('"','\"',$_SESSION['product_description'][$i])."\");' >?</a>";
You need to ensure you are escaping any double quotes within the value...
This one works for me:
echo "<a href=\"#\" onclick=\"javascript:$.jGrowl('".$_SESSION['product_description'][$i]."')\" >?</a>";
I want to pass the php variable value in onClick function.
When i pass the php variable, in the UI i am getting the variable itself instead I need the value in the variable.
Below is code snippet, please help me.
<?php
print '<td>';
$node = $name->item(0)->nodeValue;
$insert= "cubicle"."$node<br>";
Echo '<a href= "#" onClick= showDetails("$node");>'. $insert .'</a> ';
print '</td>';
?>
Variable parsing is only done in double quoted strings. You can use string concatenation or, what I find more readable, printf [docs]:
printf('%s ', $node, $insert);
The best way would be to not echo HTML at all, but to embed PHP in HTML:
<?php
$node = $name->item(0)->nodeValue;
$insert = "cubicle" . $node;
?>
<td>
<a href= "#" onClick="showDetails('<?php echo $node;?>');">
<?php echo $insert; ?> <br />
</a>
</td>
You have to think less about quotes and debugging your HTML is easier too.
Note: If $node is representing a number, you don't need quotations marks around the argument.
you shouldn't be wrapping $node in '"':
Echo '<a href= "#" onClick= showDetails($node);>'. $insert .'</a> ';
If you want the value of $node to be in a string, thn i would do:
Echo '<a href= "#" onClick= showDetails("' . $node. '");>'. $insert .'</a> ';
$var = "Hello World!";
echo "$var"; // echoes Hello World!
echo '$var'; // echoes $var
Don't mix up " and ', they both have importance. If you use some " in your string and don't want to use the same character as delimiter, use this trick:
echo 'I say "Hello" to ' . $name . '!';
I think you are searching for PHP function json_encode which converts PHP variable into JavaScript object.
It's more secure than passing the value right in the output.
Echo '<a href= "#" onClick= showDetails("'.$node.'");>'. $insert .'</a> ';
I have been using curly braces lately instead of concatenation. I think it looks better/is more readable, and mostly I find it is easier and less prone to human error - keeping all those quotes straight! You will also need quotes around the contents inside of onClick.
Instead of this:
Echo '<a href= "#" onClick= showDetails($node);>'. $insert .'</a> ';
Try this:
Echo '{$insert} ';
As a side note, I usually use double quotes to wrap my echo statement and strictly use single quotes within it. That is just my style though. However you do it, be sure to keep it straight. So my version would look like this:
echo "<a href='#' onClick='showDetails({$node});'>{$insert}</a>";
The is a very simple echo statement but I can't solve it?
echo '"What is your name?'";
Mismatch of single quotes, use this:
echo '"What is your name?"';
Your first enclosing character was single quote but ending one was double quote causing the problem
Incorrect:
echo '"What is your name?'";
^ Unexpected character
Correct:
echo '"What is your name?';
Correct:
echo "What is your name?";
Correct:
echo 'What is your name?';
Correct:
echo '"What is your name?"';
Correct:
echo "'What is your name?'";
Your quotes are nested incorrectly.
echo "\"What is your name?\"";
This is where your interpreter is choking:
echo '"What is your name?'";
expecting ; not "
echo "What is your name?";
This is Simply the best. No confusion No problem..:)