My Jquery code
function nalozi() {
var id_skupine = $('#skupina option:selected').val();
$('#artikel option').remove();
//$('#artikel').append('<option value="'+id_skupine+'">'+id_skupine+'</option>');
$.getJSON('artikli.php', {id_skupine:$('#skupina').val()}, function(data) {
$.each(data, function(index,item) {
$("#artikel").append("<option value=" + item.id + ">" + item.ime_artikla + "</option>");
});
});
}
$(document).ready(function() {
nalozi();
$('#skupina').change(function() {
nalozi();
});
});
AND PHP CODE
<?php
if(isset($_GET['id_skupine']))
{
$id_skupine = $_GET['id_skupine'];
$poizvedba = mysql_query("SELECT id,ime_artikla FROM artikli WHERE id_skupine = '$id_skupine'");
$velikost = mysql_num_rows($poizvedba);
for ($i=0;$i<$velikost;$i++)
{
$elements[]=mysql_fetch_assoc($poizvedba);
}
}
echo json_encode($elements);
?>
I don't get the values back.
Update:
You should never put variable before sanitalizing/validating/type-converting into your sql queries. If your the value you expect in query string is a number, you need to properly type-cast it like this:
$id_skupine = (int) $_GET['id_skupine'];
And if it is a string, the least you can do is to use mysql_real_escape_string function:
$str = mysql_real_escape_string($_GET['str']);
Shouldn't you be grabbing the records from db like this:
if(isset($_GET['id_skupine']))
{
$id_skupine = $_GET['id_skupine'];
$poizvedba = mysql_query("SELECT id,ime_artikla FROM artikli WHERE id_skupine = '$id_skupine'");
$velikost = mysql_num_rows($poizvedba);
while($row = mysql_fetch_assoc($poizvedba)){
$elements[] = $row['ime_artikla'];
}
}
echo json_encode($elements);
Might be your query is not returning anything
$poizvedba = mysql_query("SELECT id,ime_artikla FROM artikli WHERE id_skupine = '$id_skupine'");
Remove single quote from '$id_skupine'
Try
$poizvedba = mysql_query("SELECT id,ime_artikla FROM artikli WHERE id_skupine = '".$id_skupine."'");
Related
I have been struggling with this for a while. There are tons of topics on the subject but none is actually working for me, but being a newbie might be the cause so please elaborate.
I simplified the code and it won't work, I posted the code below
I am queering the Database, and saving the values to an array in a function
I then need to pass that array to a jquery in the same function. I used json_encode but i am getting this error:
Uncaught SyntaxError: Unexpected token <
Here is the code:
function Test()
{
$query1 = $wpdb->get_results("SELECT(element_value) FROM wp_piic_formmaker_submits WHERE form_id = 13 AND element_label = 1 AND user_id_wd = 1 ORDER BY date asc", OBJECT);
if($query1)
{
foreach($query1 as $q)
{
$PHPArray[$i] = $q->element_value ;
$i = $i + 1;
}
}
$UserInput = "<script type='text/javascript'>
jQuery('#wdform_1_element13').on('change',function()
{
var test = <?php echo json_encode($PHPArray); ?>;
jQuery.each(test , function (i, elem)
{
alert('here');
});
});
</script>";
return $UserInput ;
}
Change it to this:
$UserInput = "<script type='text/javascript'>
jQuery('#wdform_1_element13').on('change',function()
{
var test = ".json_encode($PHPArray)."; //Notice the change here
jQuery.each(test , function (i, elem)
{
alert('here');
});
});
</script>";
return $UserInput ;
}
You have to escape the string correctly:
function Test()
{
$query1 = $wpdb->get_results("SELECT(element_value) FROM wp_piic_formmaker_submits WHERE form_id = 13 AND element_label = 1 AND user_id_wd = 1 ORDER BY date asc", OBJECT);
if($query1)
{
foreach($query1 as $q)
{
$PHPArray[$i] = $q->element_value ;
$i = $i + 1;
}
}
$UserInput = "<script type='text/javascript'>
jQuery('#wdform_1_element13').on('change',function()
{
var test = " . json_encode($PHPArray) . ";
jQuery.each(test , function (i, elem)
{
alert('here');
});
});
</script>";
return $UserInput ;
}
If you put PHP inside JavaScript the PHP part is only text, do this:
function Test()
{
$query1 = $wpdb->get_results("SELECT(element_value) FROM wp_piic_formmaker_submits WHERE form_id = 13 AND element_label = 1 AND user_id_wd = 1 ORDER BY date asc", OBJECT);
if($query1)
{
foreach($query1 as $q)
{
$PHPArray[$i] = $q->element_value ;
$i = $i + 1;
}
}
$UserInput = "<script type='text/javascript'>
jQuery('#wdform_1_element13').on('change',function()
{
var test = " . json_encode($PHPArray) . ";
jQuery.each(test , function (i, elem)
{
alert('here');
});
});
</script>";
return $UserInput ;
}
At least from what is shown, neither $i nor $PHPArray are initialized. PHP can be messy about these things, but you cannot directly refer to indexes of non-existent arrays, or variables that have not been declared.
I'll guess the token error was from your browser trying to deal with the text output of a PHP error being flushed, along the lines of 'undefiend' or 'undefined index.'
Also, the real (or at least convenient) purpose of the foreach construct is not fooling with indexes. Try the following substitute for your current loop:
$PHPArray = array(); // $PHPArray = [];
if($query1){
foreach($query1 as $q){
$PHPArray[] = $q->element_value;
}
}
Beyond that, "wpdb" suggests calls related to specific frameworks, but in case this is a mysqli_stmt call, i believe the call is singular: get_result.
Im retrieving an array from php file called check_num.php :-
check_num.php
<?php
include 'config.php';
session_start();
$VALUE = $_SESSION["some_session_variable"];
if(isset($_POST['default'])){
$ert = "SELECT * FROM table_name WHERE something = '$VALUE' ORDER BY p_id ASC ";
$qty = mysql_query($ert);
$fgh = mysql_num_rows($qty);
$ertz = "SELECT something, COUNT(something) FROM table_name WHERE something = '$VALUE'
AND something >= 1 GROUP BY p_id ORDER BY p_id ASC";
$qtyz = mysql_query($ertz);
$tyui = mysql_num_rows($qtyz);
$data = array(
"post" => $fgh,
"likes" => $tyui
);
echo json_encode($data);
} else {
echo "0";
}
?>
Now comes the jquery part :-
<script>
$(document).ready(function(){
setInterval(function(){
var def = "one";
$.post("check_num.php", {'default': def }, function(response){
if(response != 0){
document.getElementById("total_array_count").innerHTML = response;
//document.getElementById("total_like_count").innerHTML = response.likes;
//document.getElementById("total_post_count").innerHTML = response.post;
------------------OR THIS Method-----------------
var my_array = response;
//var post_number = my_array["post"];
document.getElementById("total_array_count").innerHTML = my_array;
//document.getElementById("total_post_count").innerHTML = '<b>'+post_number+'</b>';
}
else {
document.getElementById("total_array_count").innerHTML='Error occured !';
}
});
},2500);
});
</script>
Now received output is {"post":10,"likes":1} , its an array . But when i access array values response.post or my_array["post"] the value returned is undefined.
I had gone through this :- http://www.w3schools.com/js/tryit.asp?filename=tryjs_array_object
And kind of this too:- jQuery .val() returns undefined for radio button
Followed it but no success !
Please correct my mistakes .
Run JSON.parse() on your result before trying to access the values. The result comes as a raw string and you have to convert it to an object first.
result = JSON.parse(result);
Alternatively, since you're already using jQuery, you can use jQuery's alias for the function.
result = $.parseJSON(result);
They are essentially the same thing.
I try to use the plugin from "devbridge autocomplete" : https://www.devbridge.com/sourcery/components/jquery-autocomplete/
I would like to get 3 values from my search.php page (and not just 1).
It works for "value" but not for "data1" and "data2" (result for each = null)
My jQuery code :
$('#search-adress').autocomplete({
serviceUrl: 'search.php',
dataType: 'json',
onSelect: function (value,data1,data2) {
alert('You selected: ' + value + ', ' + data1 + ', ' + data2);
}
});
My search page :
$term=$_GET['query'];
$query = mysql_query("select distinct adress,id,city from myadresstable where (adress like '%{$term}%') order by adress limit 10 ");
if (mysql_num_rows($query))
{
while($row = mysql_fetch_assoc($query))
{
$reply['suggestions'][] = ''.utf8_encode($row['nom_voie']).'';
$reply['data1'][] = ''.utf8_encode($row['id']).'';
$reply['data2'][] = ''.utf8_encode($row['city']).'';
}
echo json_encode($reply);
}
Thank you for helping me :)
You can just change a bit the php array this way:
$term=$_GET['query'];
$query = mysql_query("select distinct adress,id,city from myadresstable where (adress like '%{$term}%') order by adress limit 10 ");
if (mysql_num_rows($query))
{
$arr = array();
while($row = mysql_fetch_assoc($query))
{
$reply['suggestions'] = utf8_encode($row['nom_voie']);
$reply['data'] = utf8_encode($row['id']);
$reply['value'] = utf8_encode($row['city']);
$arr[] = $reply;
}
echo json_encode($arr);
}
And in your jquery code:
$(function(){
$('#autocomplete').autocomplete({
lookup: datos,
onSelect: function (suggestion) {
console.log(suggestion);
alert('You selected: ' + suggestion.value + ', ' + suggestion.data + ', ' + suggestion.nom_voie);
}
});
});
Sample fiddle: https://jsfiddle.net/robertrozas/n6oLLfmc/
Try selecting "Valdivia" to see the alert
I found the solution :)
The problem was the PHP Array. To get some data values with this autocomplete plugin you have to use array() :
PHP Code
$suggestions = array();
if (mysql_num_rows($query))
{
while($row = mysql_fetch_assoc($query))
{
$mydata1='$row['data1']';
$mydata2='$row['data2']';
$nom_voie=''.utf8_encode($row['nom_voie']).'';
$suggestions[] = array(
"value" => $nom_mydata1,
"data" => $nom_mydata2
);
}
}
echo json_encode(array('suggestions' => $suggestions));
i have this code on the server side:
<?php
header('Content-Type: text/html; charset=utf-8');
require "../general.variables.php";
require "../functions_validation.php";
require "../functions_general.php";
require "../../db_con.php";
$keyword = mysql_real_escape_string($_POST["keyword"]);
$query = mysql_query("
SELECT user_id, user_fullname, user_area, user_city, user_quarter, user_tmb
FROM `migo_users`
WHERE (
user_fullname LIKE '%".$keyword."%' AND user_id NOT IN (".$superAdmins2string.")
)
ORDER BY tmb_set DESC, user_fname ASC
LIMIT 7;
");
$i = 0;
while ($userInfo = mysql_fetch_array($query)) {
$area_name = mysql_fetch_array(mysql_query("
SELECT area_name
FROM `migo_areas`
WHERE
area_id='".$userInfo['user_area']."';
"));
$city_name = mysql_fetch_array(mysql_query("
SELECT city_name
FROM `migo_cities`
WHERE
city_id='".$userInfo['user_city']."';
"));
if ($userInfo['user_quarter'] != 0) {
$quarter_name = mysql_fetch_array(mysql_query("
SELECT quarter_name
FROM `migo_quarters`
WHERE
quarter_id='".$userInfo['user_quarter']."';
"));
}
else {
$quarter_name['quarter_name'] = "";
}
$rsl[$i]['user_id'] = $userInfo['user_id'];
$rsl[$i]['user_fullname'] = $userInfo['user_fullname'];
$rsl[$i]['user_area_name'] = $area_name['area_name'];
$rsl[$i]['user_city_name'] = $city_name['city_name'];
$rsl[$i]['user_quarter_name'] = $quarter_name['quarter_name'];
$rsl[$i]['user_tmb'] = $userInfo['user_tmb'];
$i++;
}
echo json_encode($rsl);
mysql_close();
?>
and this code on the client side:
$.ajax({
type : 'POST',
url : 'php/general.ajax/header_search.php',
//async : false,
//cache : false,
dataType : 'json',
data: {
keyword : sb_keyword
},
success : function(data) {
var hs_hits = 0;
var hs_row_nr = 1;
var hs_results = "<div class='sb_spacing'></div><div id='sb_rows_cont'>";
if (data != null) {
$.each(data, function(index, arr) {
hs_hits++;
if (arr['user_quarter_name'] != "") {
var quarter_text = " - " + arr['user_quarter_name'];
}
else {
var quarter_text = "";
}
hs_results = hs_results + "<a class='search_links' href=profile.php?id=" + arr['user_id'] + "><div class='sbr_row' row_nr='" + hs_row_nr + "'><div class='sbr_imgFrame'><img src='images/user_48x48/" + arr['user_tmb'] + "' alt=''></div><div class='sbr_name'>" + arr['user_fullname'].replace(regexp_hs_user_fullname, '<span>$&</span>') + "</div><div class='sbr_area'>" + arr['user_area_name'] + "</div><div class='sbr_area'>" + arr['user_city_name'] + quarter_text + "</div></div></a>";
hs_row_nr++;
});
}
if (hs_hits > 0) {
hs_results = hs_results + "</div><div class='sb_spacing'></div><a class='search_links' href='search.php?name=" + sb_keyword + "'><div id='sbr_botttom'>Se flere resultater for <span class='gay'>" + sb_keyword + "</span></div></a>";
$("#sb_results").html(hs_results).show();
searchSet = 1;
total_rows = hs_hits;
$("#sb_rows_cont > a:first .sbr_row").addClass('sbr_row_act');
on_a = $("#sb_rows_cont > a:first");
first_a = on_a;
last_a = $("#sb_rows_cont > a:last");
sb_url = $(on_a).attr('href');
search_navigator_init();
}
else {
$("#sb_results").hide();
searchSet = 0;
}
},
error : function() {
alert("ajax error");
}
});
one problem tho, if the query gives 0 results, and the each function tries to run on the client side my js code stops working..
so i was wondering what i could do here.
how can i retrieve the amount of hits from the server side, before i run the each loop?
You're instantiating $rsl in the middle of a loop (implicitly), but you aren't entering the loop unless you have at least one entry.
Instantiate $rsl up above your while loop:
...
$i = 0;
$rsl = array();
while ($userInfo = mysql_fetch_array($query)) {
...
And now when you encode it, it is an empty array instead of null. This will also save your HTTP error_log, and generally be happier. : )
I would try json_encode() your PHP array to allow JavaScript to eval it as a native JS object.
echo json_encode($some_array);
Just a note, json_encode() is only available for PHP versions 5.2 and higher.
$.getJSON('ajax.php',{form data}, functon(data){
if(data == '') return;
});
I create a huge JSON-Object and save it in my database. But when I load the "string" and echo it in PHP, I can't access the JSON Object in JQuery. Do I have to consider something if I want to save my JSON Object in a MySQL Database (when I just create the Array and then echo it with "echo json_encode($arr);" it works fine, but I need to save the Object for caching).
{"247":{"0":"This is a
question","1":"","2":"247","3":"0","answers":[["Answer1","960","1"],["Answer
2","962","0"],["Answer
3","961","0"],["Answer
4","963","0"]]},{"248":{"0":"This is a
question","1":"","2":"247","3":"0","answers":[["Answer1","960","1"],["Answer
2","962","0"],["Answer
3","961","0"],["Answer
4","963","0"]]}}
just an excerpt
If I just echo this JSON-Object, everything works fine, but if I load the same string from the database and echo it, it doesn't work.
Update 1: forget to tell that I'm using a TEXT-Field with UTF8_general_ci collation
Update 2: Maybe a little bit more code:
function start() {
$(".start").click(function () {
$.post("load_script.php", { }, function(data){
alert(data[247][0]);
}, "json");
return false;
});
}
this loads the script and should alert "This is a question"
<?php
require_once('connect.php');
$ergebnis = mysql_query("SELECT text FROM cache_table ORDER BY RAND() LIMIT 1");
while($row = mysql_fetch_object($ergebnis)) {
$output = $row->text;
}
echo $output;
?>
this is the script, where I load the database entry with the JSON-Object.
Update 3:
I think I solved the problem. Some break sneaked into my JSON-Object so I do this, before the output:
$output = str_replace("\n", "", $output);
$output = str_replace("\r", "", $output);
$output = str_replace("\r\n", "", $output);
I'd suggest looking at what your javascript is seeing. Instead of asking jQuery to interpret the json for you, have a look at the raw data:
function start() {
$(".start").click(function () {
$.post("load_script.php", { }, function(data){
alert(data);
}, "text");
return false;
});
}
For example, if part of the string gets oddly encoded because of the UTF-8, this might cause it to appear.
Once you've done that, if you still can't spot the problem, try this code:
var data1, data2;
function start() {
$(".start").click(function () {
$.post("load_script.php", {src: "db" }, function(data){
data1 = data;
}, "text");
$.post("load_script.php", {src: "echo" }, function(data){
data2 = data;
}, "text");
if (data1 == data2) {
alert("data1 == data2");
}
else {
var len = data1.length < data2.length ? data1.length : data2.length;
for(i=0; i<len; ++i) {
if (data1.charAt(i) != data2.charAt(i)) {
alert("data1 first differs from data2 at character index " + i);
break;
}
}
}
return false;
});
}
And then change the PHP code to either return the data from the database or simply echo it, depending on the post parameters:
<?php
if ($_POST['src'] == 'db')) {
require_once('connect.php');
$ergebnis = mysql_query("SELECT text FROM cache_table ORDER BY RAND() LIMIT 1");
while($row = mysql_fetch_object($ergebnis)) {
$output = $row->text;
}
}
else {
$output = '{"247":{"0":"This is a question","1":"","2":"247","3":"0","answers":[["Answer1","960","1"],["Answer 2","962","0"],["Answer 3","961","0"],["Answer 4","963","0"]]},{"248":{"0":"This is a question","1":"","2":"247","3":"0","answers":[["Answer1","960","1"],["Answer 2","962","0"],["Answer 3","961","0"],["Answer 4","963","0"]]}}';
}
echo $output;
?>
Hope that helps!
I got this to work in a slightly different manner. I've tried to illustrate how this was done.
In Plain English:
use urldecode()
In Commented Code Fragments
$json = $this->getContent($url); // CURL function to get JSON from service
$result = json_decode($json, true); // $result is now an associative array
...
$insert = "INSERT INTO mytable (url, data) ";
$insert .= "VALUES('" . $url . "', '" . urlencode(json_encode($result)) . "') ";
$insert .= "ON DUPLICATE KEY UPDATE url=url";
...
/*
** Figure out when you want to check cache, and then it goes something like this
*/
$sqlSelect = "SELECT * FROM mytable WHERE url='" . $url . "' LIMIT 0,1";
$result = mysql_query($sqlSelect) or die(mysql_error());
$num = mysql_numrows($result);
if ($num>0) {
$row = mysql_fetch_assoc($result);
$cache = json_decode(urldecode($row['data']), true);
}
Hope this is helpful
Maybe you use varchar field and your string just doesn't fit in 255 chars?