I have written a small HTML form and added it to the page. My goal is for it to POST the value of the Checked button to a PHP page which I have also written. The PHP page is not getting the value for some reason. I am also not getting any PHP errors. The codes are below.
form.php
<form action="http://www.zbrowntechnology.com/InsaneBrain/quiz.php" method="POST">
<font color="white" size="3">
<?php
$con = mysql_connect("HOST", "USER", "PASS");
if(!$con) {
die('Unable to connect to MySQL: '.mysql_error());
}
mysql_select_db("zach_insaneB", $con);
$result = mysql_query("SELECT Name FROM quiz");
while($row = mysql_fetch_assoc($result)) {
$qname = $row['Name'];
echo "<input type='radio' name='button1' id='$qname'>";
echo "<label for='$qname'><font color='white'/>$qname</font></label>";
}
?>
</font>
</div>
</div>
<div id="Oobj12">
<div id="Gcode234" class="dfltc">
<input type="image" src="http://www.zbrowntechnology.com/InsaneBrain/begin.png" alt="Begin" />
</form></div>
</div>
getdata.php
<?php
$data = $_POST['button1'];
echo $data;
?>
Actually, I see the problem...you don't actually have a value in the radio button. You need something like:
echo "<input type='radio' name='button1' id='$qname' value='$some_value'>";
Related
This is my db : link link
<?php
$con=mysqli_connect("localhost","root","","organisation");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM org_insert");
echo "<!doctype html>
<html lang=\"en\">
<head>
<!-- Bootstrap CSS -->
<link rel=\"stylesheet\" href=\"https://stackpath.bootstrapcdn.com/bootstrap/4.1.0/css/bootstrap.min.css\">
<title>Hello, world!</title>
</head>
<body>
<table border='1'>
<tr>
<th>below_whom</th>
<th>name</th>
</tr>";
$row = mysqli_fetch_array($result);
#echo '<pre>'; print_r($row); echo '</pre>';
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['below_whom'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
<div class="form-group">
<label for="usr">below_whom:</label>
<input type="text" name ="below_whom" id="below_whom" class="form-control">
</div>
<div class="form-group">
<label for="usr">name:</label>
<input type="text" name ="name" id="name" class="form-control">
</div>
<form method="post">
<input type="button" name="submit" id="submit" class="btn btn-primary" value="submit"/>
</form>
<?php
$con=mysqli_connect("localhost","root","","organisation");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if(isset($_POST['submit']))
{
if($below_whom !=''||$name !=''){
$below_whom=$_POST['below_whom'];
$name=$_POST['name'];
$query=mysqli_query("INSERT INTO org_insert VALUES ('$below_whom','$name');");
$query_run = mysqli_query($con,$query);
echo "<p>query inserted.</p>";
}else{
echo "<p>Insertion Failed.</p>";
}
}
mysqli_close($con);
echo"</body>
</html>";
?>
The text under p tag isn't getting executed, ie, the program is not going inside the if statement itself. I have rechecked the syntax, what is the problem? Is the syntax incorrect? I am pretty sure the connection with sql is correct. I have also refereed to some articles, still I am stuck here.
use post variables before if loop as shown below
if(isset($_POST['submit']))
{
$below_whom=$_POST['below_whom'];
$name=$_POST['name'];
if($below_whom !=''||$name !=''){
$query=mysqli_query("INSERT INTO org_insert VALUES ('$below_whom','$name');");
$query_run = mysqli_query($con,$query);
echo "<p>query inserted.</p>";
}else{
echo "<p>Insertion Failed.</p>";
}
}
and in HTML Code add type as submit and start form tag before div as
<form method="post" action=""> and closes after input tag
<input type="submit" name="submit" id="submit" class="btn btn-primary" value="submit"/>
One of the issues that I am able to see is that Your query should be:
$query=mysqli_query("INSERT INTO `org_insert`(`below_whom`,`name`) VALUES ('$below_whom','$name')");
Hope this helps.
Change the mysqli_fetch_array to mysqli_fetch_assoc or add a parameter too
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
I have two files Add_Services.html and add_services.php.
My database is named as 'ecc'.
Database 'ecc' has a table named 'addservices'.
Table 'addservices' has fields 'id', 'name' and 'cost'.
Add_Services.html
Add_Services.html has a button which onClick opens a pop-up window.
Add_Services.html
<html>
<input type = "button" value = "Add Services"
onClick="MyWindow=window.open('add_services.php',
'MyWindow',width=600,height=300);
return false;">
</html>
add_services.php
add_services.php display the checkbox list extracted from database 'ecc' of table 'addservices'. Pop-up is displaying two fields from table addservices and those are 'cost' and 'name'.
add_services.php
<html>
<body>
<?php
$con = mysqli_connect("localhost", "root", "", "ecc");
if(!$con){
echo 'Not connected';
}
if(!mysqli_select_db($con,'ecc'))
{
echo 'db not selected';
}
$sql = "SELECT name, cost FROM addservices";
$records = mysqli_query($con, $sql);
$row=mysqli_fetch_array($records,MYSQLI_ASSOC);
?>
<table width ="800" border="1" cellspacing="1">
<tr>
<th>
Select
</th>
<th>
Name
</th>
<th>
Cost
</th>
</tr>
<form action="" method = "POST">
<?php
while($row = mysqli_fetch_assoc($records)){
echo "<tr>";
$n=$row['name'];
$t=$row['cost'];
echo "<td>";
echo "<input type='checkbox' name='chkbox[]' value='{$row["name"]}'>";
echo "</td>";
echo "<td>";
echo "$n";
echo "</td>";
echo "\t";
echo "<td>";
echo "{$row["cost"]}";
echo "</td>";
echo "<br>";
echo "</tr>";
}
?>
</table>
<input type="submit" value="Submit">
</form>
<?php
if(isset($_POST['submit'])){
while(!empty($_POST['chkbox'])){
echo "chkbox";
}
}
?>
</body>
</html>
My Issue: I am to display the checked content of check list on page Add_Services.html
It would be grate if some one rewrite it.
The issue is : you have not defined name of Submit Button
Change Incorrect Code :
<input type="submit" value="Submit">
To Below Corrected Code :
<input type="submit" value="Submit" name="submit">
And, Also Instead of printing values of chkbox[] using while loop, Just use a simple foreach loop.
Note : Your code will go to infinite loop, as $_POST['chkbox'] will always have value
So, Change Below Code :
while(!empty($_POST['chkbox'])){
echo "chkbox";
}
To Below corrected code :
foreach($_POST['chkbox'] as $value)
echo $value."\n";
My Form:
I'm creating a web based product database which features an edit page, I currently have a drop down menu which displays all of the products stored in the SQL database. Is it possible to make the text-boxes on the page auto-fill with the corresponding data when the product is selected?
Any help appriciated.
The code for my edit page is as follows:
<?php
session_start();
//CREATES & CHECKS MySQL CONNECTION
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn)
{
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT * FROM PRODUCTS LIMIT 0 , 30";
$result = mysqli_query($conn, $sql);
?>
<!-- HTML PAGE PROPERTIES -->
<div id="left"></div>
<div id="right"></div>
<div id="top"></div>
<div id="bottom"></div>
<div align="center"><h1>PRODUCT DATABASE</h1>
<div align="center">HOME <i class="fa fa-home" aria-hidden="true"></i><br>
<div align="left"><link rel="stylesheet" type="text/css" href="styleSheet.css">
<link rel="stylesheet" href="http://cdnjs.cloudflare.com/ajax/libs/font- awesome/4.4.0/css/font-awesome.min.css">
<?php
print "<h3>EDIT PRODUCT</h3>";
print "<p> <strong>SELECT PRODUCT: </strong>";
$conn = new mysqli()
or die ('Cannot connect to db');
$result = $conn->query("select ID, NAME from PRODUCTS");
echo "<html>";
echo "<body>";
echo "<select name='ID'>";
while ($row = $result->fetch_assoc()) {
unset($id, $name);
$id = $row['ID'];
$name = $row['NAME'];
echo '<option value="'.$id.'">'.$name.'</option>';
}
?>
</select>
<form method='POST'>
<h3>PRODUCT:</h3>
<input type='textbox' name='product' value='<?php echo $product['product'] ? >'>
<h3>ID:</h3>
<input type='textbox' name='id' value='<?php echo $product['id'] ?>'>
<h3>BARCODE:</h3>
<input type='textbox' name='barcode' value='<?php echo $product['barcode']; ?>'>
<h3>TYPE:</h3>
<select name="type">
<option value=""></option>
<option value="A">A</option>
<option value="B">B</option>
<option value="C">C</option>
</select></p>
<input type='submit' value='Save Changes' name=submitform>
<?php
//WHEN EDIT BUTTON IS PRESSED, SEND EDITED VARIABLE VALUES TO MySQL
if (isset($_POST['submitform']))
{
}
To have your form autofill you will need to use an asynchronous technology that allows for communication between your front end and your backend / database. When using AJAX (or websockets) it allows for communication wihtout having to reload the whole page. This is exactly the functionality you're looking for. I suggest using AJAX.
Take a look at this post.
I try to delete my data in "admin" database, but the delete button does not function.
This is my top part
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="admin"; // Database name
$tbl_name="admin"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>
This is my checkbox code
<tbody>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td><?php echo $rows['course_code']; ?></td>
<td><?php echo $rows['course_name']; ?></td>
<td><?php echo $rows['lecture_id']; ?></td>
<td><input name="checkbox[]" type="checkbox"
id="checkbox[]" value="<?php echo $rows['course_code'];?>"></td>
<td><form>
</form>
</td>
</tr>
<?php
}
?>
</tbody>
and, this is my button code
<input type='button' id="delete" value='Delete' name='delete'>
This is my php function code
<?php
if(isset($_POST['delete'])){
for($i=0;$i<$count;$i++){
$del_id = $checkbox[$i];
$sql = "DELETE FROM $tbl_name WHERE course_code='$del_id'";
$result = mysql_query($sql);
}
if($result){
echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete.php\">";
}
}
mysql_close();
?>
include all the input elements within your <form> tags: <form> all inputs are here </form>
update:
<input name = "checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $rows['course_code'];?>">
to (id doesn't matter here):
<input name="checkbox[]" type="checkbox" value="<?php echo $rows['course_code'];?>"/>
and your button code:
<input type='button' id="delete" value='Delete' name='delete'>
to
<input type="submit" value="Delete"/>
set opening <form> tag to <form action="delete.php" method="post">
Note:
I assume below codes are in delete.php file. if not replace "delete.php" with that name in above opening form tag.
your delete.php file:
<?php
$cheks = implode("','", $_POST['checkbox']);
$sql = "delete from $tbl_name where course_code in ('$cheks')";
$result = mysql_query($sql) or die(mysql_error());
mysql_close();
?>
Note:
Since mysql_ will deprecate on future, better is use mysqli extension. But before use that, you have to enable it on your server. mysqli is a part of php and newer version of php has it but not enabled. To enable this, view php info page and find the path of php.ini file in "Loaded Configuration File" row on that page.
You can see php info page by loading below php file in the browser:
<?php
phpinfo();
?>
open that php.ini file in a text editor and un-comment or add a line extension=php_mysqli.dll at the extensions list there.
also search for "extension_dir" and open the directory it says and make sure php_mysqli.dll file is there.
(you may have .so extension if you not use windows OS)
Then restart your server and you are done!
By Fred -ii-
Using mysqli_ with prepared statements is indeed a better and
safer method. However, some will even suggest PDO, but even PDO
doesn't have some of the functionalities that mysqli_ offers;
strangely that. Even PDO needs sanitization. Many think that using PDO will solve injection issues, which is false.
-Thanks Fred.
try this code. it is working well.
connection.php
<?php $hostname_conection = "localhost"; /* this is the server name(assigned to variable) which is localhost since it runs on local machine */
$database_conection = "company"; /* this is the database name( assigned to variable)*/
$username_conection = "root"; /* user name (assigned to variable)*/
$password_conection = ""; /*password (assigned to variable) */
$conection = mysql_connect($hostname_conection, $username_conection, $password_conection) or trigger_error(mysql_error(),E_USER_ERROR); /* Mysql_connect function is used to conncet with database it takes three parameters server/hostname, username,and password*/
mysql_select_db($database_conection,$conection) or die(mysql_error("could not connect to database!")); /* Mysql_select is used to select the database it takes two parameters databasename and connection variable in this case $conection */
?>
multiple_delete.php
<?php require_once('conection.php'); ?>
<?php
in
/* now to display the data from the database which we inserted in above form we */ /* we make the query to select data from the table EMP */
$display = "select * from test_mysql";
$result = mysql_query($display, $conection) or die(mysql_error()); /* the query is executed and result of the query is stored in variable $result */
if ($result == FALSE) {
die(mysql_error()); /* displays error */
} ?> <h1 align="center"> Displaying Recods in Table </h1>
<form method="get" action="" id="deleteform" >
<table width="245" border="1" align="center">
<tr>
<td width="51">
<input type="submit" name="delete" id="button" value="delete" onclick="document.getElementById('deleteform').action = 'delete.php';document.getElementById('deleteform').submit();"/> <!--- here on clicking the button the form is submitted and action is set to delete.php Here we have used javaScript document refers to this whole page and now we can access any tag that has its id with help of getElementById() method and after the we specify the operation we want to perform in this case action and submit. --->
</td>
<td width="50">id</td>
<td width="55">name</td>
<td width="47">lastname</td>
</tr>
<?php
while ($rows = mysql_fetch_array($result))
{ /* here we make use of the while loop which fetch the data from the $result int array form and stores in $row now we can display each field from the table with $row[‘field_name’] as below */
?>
<tr>
<td>
<input type="checkbox" name="empids[]" value="<?php echo $rows['id']; ?>" /> <!--here with each checkbox we send the id of the record in the empids[] array --->
</td>
<td>
<?php echo $rows['id'] ?>
</td>
<td>
<?php echo $rows['lastname'] ?>
</td>
<td><?php echo $rows['name'] ?></td>
<?php } ?>
</tr>
</table>
</form> ?>
</body>
</html>
delete.php
<?php
require_once('conection.php');
?>
<?php
if (isset($_GET['delete'])) /* checks weather $_GET['delete'] is set*/
{
if (isset($_GET['empids'])) /* checks weather $_GET['empids'] is set */
{
$checkbox = $_GET['empids']; /* value is stored in $checbox variable */
if (is_array($checkbox))
{
foreach ($checkbox as $key => $your_slected_id) /* for each loop is used to get id and that id is used to delete the record below */
{
$q="DELETE FROM test_mysql WHERE id=$your_slected_id "; /* Sql query to delete the records whose id is equal to $your_slected_id */
mysql_query($q,$conection) ; /* runs the query */
}
header("location:multiple_delete.php"); /* Goes back to index.php */
}
} else
{
echo" you have not selected reords .. to delete";
}
} ?>
$sql = "SELECT * FROM blacklist";
$result = $link->query($sql);
$count=mysqli_num_rows($result);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc())
{
echo "<table>";
echo "<th>";
echo "<td>" . "ID: " . $row["id"]."</td>";
echo "<td>" . " Dial Target: " . $row["dial_target"]."</td>";
echo "<td>" . " Destination: " . $row["pozn"]."</td>";
echo "<td>" . " Date: " . $row["block_date"] . "</td>";
echo "<td>" . "<div class='background' style='position: relative; top:8px;'>" . "<form>" . "<input action='index.php' method='post' type='checkbox' name='chechbox[]' value='".$row["id"]."'/>" ."</form>" . "</div>" . "</td>";
echo "</th>";
echo "</table>";
echo "</br>";
}
}
else
{
echo "0 results";
}
if(isset($_POST['Delete']))
{
for($i=0;$i<$count;$i++)
{
$del_id = $checkbox[$i];
$del = "DELETE FROM blacklist WHERE Delete='$del_id'";
$result = $link->query($del);
}
if($result)
{
echo "<meta http-equiv=\"refresh\" content=\"0;URL=index.php\">";
}
}
<!-- DELETE BUTTON -->
<form>
<input type='Submit' id="Delete" value='Delete' name='Delete'/>
</form>
<?php
$args1 = array(
'role' => 'Vendor',
'orderby' => 'user_nicename',
'exclude' => $user_id.',1',
'order' => 'ASC'
);
$subscribers = get_users($args1); foreach ($subscribers as $user) {
$fvendorck = $wpdb->get_row("select * from wp_vandor where parent_id = '".$user_id."' and child_id = '".$user->id."'");
$isfavvendor = $fvendorck->child_id;
if(!empty($isfavvendor)) {
?>
<li><input type="checkbox" id="listID" value='<?php echo $user->id; ?>' name="chk1[]" checked=""/><?php echo $user->headline; ?></li>
<?php }else{ ?>
<li><input type="checkbox" id="listID" value='<?php echo $user->id; ?>' name="chk1[]" /><?php echo $user->headline; ?></li>
<?php } }?>
</ul>
Below code !Gives me check boxes and a delete button, In input tag all check box have same name (check)!! There check box can be retreive from database with id .
Problem Is:: when I am selecting multiple checkbox for deletion...only last one checkbox is deleted ! means it can delete 1 data from a database.
url like -> http://localhost/demo/delete.php?check=10&check=13&check=14&submit=Delete
I need while I am selecting a checkbox more than 1 checkbox ,check box datas is deleted from database ! Any one help me to overcome this problem thanks
index.php
<?php
$sql = mysql_connect('localhost', 'root', '');
mysql_select_db('database_section', $sql);
?>
<form name="checkbox" method="get" action="delete.php">
<table>
<tr>
<?php
$sql = "select * from data";
$result = mysql_query($sql) or die(mysql_error());
while ($row = mysql_fetch_array($result))
{
?>
<td><input type="checkbox" name="check" value="<?php echo $row['id']?>"><?php echo $row['data'];?>
</td>
<?php
}
?>
<tr>
<td><input type="submit" name="submit" value="Delete"></td>
</tr>
</table>
</form>
Now, In delete.php..code below...
<?php
$sql = mysql_connect('localhost', 'root', '');
mysql_select_db('database_section', $sql);
if ($_REQUEST['submit']) {
$abc = $_GET['check'];
$sql = "Delete from data where id=$abc";
$result = mysql_query($sql) or die(mysql_error());
if (isset($result)) {
echo "data deleted";
}
else
{
echo "not possible";
}
}
?>
Use check box as an array holder. name it as check[] to hold all selected values. And on post you will get the selected array list.
Now your $abc will be a array, use foreach in delete.php to get the checked ids.
Change name="check" to name="check[]"
See more here: http://www.kavoir.com/2009/01/php-checkbox-array-in-form-handling-multiple-checkbox-values-in-an-array.html
[...]
while ($row = mysql_fetch_array($result))
{
?>
<td>
<input type="checkbox" name="check[]" value="<?php echo $row['id']?>"><?php echo $row['data']; ?>
</td>
<?php
}
?>
[...]