I have a problem with displaying a view. When I pass var to view, view doesn't render.
Controller:
public function indexAction()
{
$branchModel = new Application_Model_Branches();
$branches = $branchModel->getAllBranches();
$this->view->menu = $branches;
}
View (index.phtml):
<h2>Menu</h2>
<?php
$this->htmlList($this->menu);
?>
When I try debug $branches without assign it to view, all seems to be ok, but when I try push it to view,index.phtml don't appear.
Regards
You're just missing an echo in your code, the htmlList view helper returns a value - it doesn't echo it. Some examples of the various form view helpers can be seen here
<h2>Menu</h2>
<?php
echo $this->htmlList($this->menu);
?>
controller
$this->view->variableName = "Hello World!";//assign here
$this->view->assign('variableName1', "Hello new World!");//assign here
view
echo $this->variableName;//echo here
echo $this->variableName1;//echo here
Related
I know that you can use extract() to achieve this however my circumstances are as followed:
I am building a very small basic MVC framework for personal projects and I have this in my controller:
public function index(){
$data = [
'title' => 'Welcome'
];
$this->view('pages/index', $data);
}
As you can see this passes the data array into the view and you can echo it like:
echo $data['title'];
But I want to echo it like echo $title; I know that extract() can do this but that means I have to manually put extract($data); at the top of every page which isnt the end of the world but I was just curious if there was a way it could be done automatically? I have tried to use extract by putting it inside the view function but that did not work. I have also tried to use extract by putting it in the header file that is required_once in index.php (thus making the header file a static header thats always required) but neither has worked so any advice would be great.
Here is the code for the view function as requested:
public function view($view, $data = []){
if(file_exists('../../views/'.$view.'.php')){
require_once '../../views/'.$view.'.php';
} else {
die('View does not exist');
}
}
Simple that is it ,use compact and extract function
index method
public function index(){
$title='Welcome';
$this->view('pages/index', compact('title'));
}
Wiew method
public function view($view, $data = []){
extract($data);
if(file_exists('../../views/'.$view.'.php')){
require_once '../../views/'.$view.'.php';
} else {
die('View does not exist');
}
}
In html
<h1> hello <?php echo $title; ?></h1>
Here is where I went wrong, I put extract in the view method before and it didn't work.
However the advice here was to put it in the view function and I now understand that I put the extract function after require_once '../../views/'.$view.'.php'; I just put extract before that line of code and it is now working!
Here is my controller:
class CommonController extends CI_Controller {
public function __construct() {
parent::__construct();
$this->load->model('common_model'); //load your model my model is "common model"
}
public function add_work(){
$names = $_POST['name'];
$works = $_POST['work'];
$allValues = array(); // array to contains inserted rows
foreach($names as $key => $name){
$name= "your specified name";
$insertdata = array();
$insertdata['work'] = $works[$key];
$insertdata['name'] = $name;
$this->common_model->insert($insertdata);
array_push($allValues,$insertdata);
//$insert = mysql_query("INSERT INTO work(name,work) values ( '$name','$work')");
}
foreach($allValues as $insertRow){
echo $insertRow['work'];
echo $insertRow['name'];//this shows data well. but how to pass data in view.php
}
//view code will add here to show data in browser
}
Basically I want to pass all data to view.php for printing or exporting purpose. How can I do so.
To load a view you should do like this.
$this->load->view("filename");
If you want to pass data to view, you should do like this.
$this->load->view("filename",$data);
$data should have all parameters which you want to print in view.
The syntax goes like this.
$this->load->view("filename","data to view","Returning views as data(true / false");
If third parameter is true, view will come as data. It will not go to browser as output.
Edit:
Change
$this->load->view('print_view',$insertdata);
to
$data['insertdata'] = $insertdata;
$this->load->view('print_view',$data);
For more info, check this link
How CI Classes Pass Information and Control to Each Other
Calling Views
We will see.how the controller calls a view and passes data to it:
First it creates an array of data ($data) to pass to the view; then it loads and calls the view in the same expression:
$this->load->view('testview', $data);
You can call libraries, models, plug-ins, or helpers from within any controller, and models and libraries can also call each other as well as plug-ins and helpers.
However, you can't call one controller from another, or call a controller from a
model or library. There are only two ways that a model or a library can refer back to a controller:
Firstly, it can return data. If the controller assigns a value like this:
$foo = $this->mymodel->myfunction();
and the function is set to return a value, then that value will be passed to the variable $foo inside the controller.
//sample
public function display()
{
$data['text_to_display'] = $this->text_to_display;
$data['text_color'] = $this->text_color;
$this->load->view('display_view',$data);
}
Adding Dynamic Data to the View
Data is passed from the controller to the view by way of an array or an object in the second parameter of the view
loading method. Here is an example using an array:
$data = array(
’title’ => ’some’,
’heading’ => ’another some’,
’message’ => ’and another some’
);
$this->load->view(’view’, $data);
And here’s an example using an object:
$data = new Someclass();
$this->load->view(’view’, $data);
Sending Multiple Dimensional array
if we pull data from your database it will typically be
in the form of a multi-dimensional array.
<?php
class foo extends CI_Controller {
public function index()
{
$data[’Books’] = array(’POEAA’, ’TDD’, ’Clean C’);
$data[’title’] = "Title";
$data[’heading’] = "Heading";
$this->load->view(’view’, $data);
}
}
in view
<html>
<head>
<title><?php echo $title;?></title>
</head>
<body>
<h1><?php echo $heading;?></h1>
<h3>My Books List</h3>
<ul>
<?php foreach ($Books as $item):?>
<li><?php echo $item;?></li>
<?php endforeach;?>
</ul>
</body>
</html>
More Learning
NOTE:
There is a third optional parameter lets you change the behavior of the method so that it returns data as a string rather
than sending it to your browser.The default behavior is false, which sends it to your browser. Remember to
assign it to a variable if you want the data returned:
$string = $this->load->view(’view’, ’’, TRUE);
Above will not solve your problem directly but definetly help in understanding concepts.
I am having difficulty getting the correct URL when I call a method to load a view.
Heres my controller:
public function post() {
$title = $this->input->post('title');
$data = $this->p_Model->post($title);
$this->qs($data);
}
public function qs($id){
$title = $this->s_Model->getTitle($id);
$result = $title->result();
$this->load->view('q_View', array('results' => $result));
}
Heres my view:(note this view is not the view which gets loaded from the qs function, but one which calls the qs function)
<html>
<body>
<table>
<?php
if (isset($qs)) {
foreach ($qs as $row) {
$id = $row->qID;
echo '<a href="'.site_url('myController/qs/'.$id).'">';
echo $row->title;
echo "<br>";
}
}
?>
</table>
</body>
</html>
So in my controller I have two functions, the qs function works separately by itself so can be called in the view and give the following url myController/qs/1 however when I use the post function I get a url like this myController/post so my question is how can I get my url to be like the first example?
Instead of using the line:
$this->qs($data);
You can use a redirect:
redirect('/mainController/qs/'.$data);
That should work in the same way that you have used in your view
Try base_url and also you can use current_url() returns the full URL (including segments) of the page being currently viewed.
echo '<a href="'.base_url('myController/qs/'.$id).'">';
Where should we process mysql queries in CodeIgniter application?
For example in a simple project we do like this :
for controller:
class Blog extends CI_Controller {
function posts(){
$data['query'] = $this->blog_model->index_posts();
$this->load->view('blog_view', $data);
}
}
and in view :
<?php
while ($post = mysql_fetch_object($query)):
?>
<div>
<p><?= $post->body; ?></p>
</div>
<?php endwhile; ?>
But, if we want to do something with body of post before print where should it be done?
For example, I want to write a function that formats the body of post and pass the body to it before doing echo.
Where should it be placed according to CoeIgniter's structure and recommended practices? (best option)
in the controller? (if so , how to use it)
in the view?
write a helper?
other approaches ?
Here's what is recommended:
Controller:
function posts() {
$this->load->model("blog_model");
$data['rows'] = $this->blog_model->index_posts();
$this->load->view("blog_view", $data);
}
Model: (blog_model.php)
function index_posts() {
$this->load->database();
$query = $this->db->get('your_table');
$return = array();
foreach ($query->result_array() as $line) {
$line['body'] = ... do something with the body....
$return[] = $line;
}
return $return;
}
View: (blog_view.php)
<?php foreach ($rows as $line): ?>
<div>
<p><?php echo $line['column']; ?></p>
</div>
<?php endforeach; ?>
Basically what happens is your model returns a multidimensional array that is passed the view and processed using a foreach() loop.
Good luck!
If you want to reuse that function create a helper. If you want this function only once put it in your controller and call from that controller.
Models are just for accessing database or maybe in few other cases, but mostly just for accessing things in database or editing, deleting etc. and sending the result to controller for further processing.
In your case I would stick with helper.
E.g. you will create a file top_mega_best_functions.php and put it inside helpers folder.
Than you write ther e.g. something like
function red_text($input) {
echo '<span style="color: red;">';
echo $input;
echo '</span>';
}
Then load the helper in your autoloader file or load before using.
And use in your view or controller like
$blablabla = "This text will be red";
red_text($blablabla);
My View :-
<html>
<?= link_tag(base_url().'css/simple.css'); ?>
<body>
<?php $this->load->helper('form'); ?>
<?php $this->load->view('commentform'); ?>
<?php $id=$this->uri->segment(3);?>
<?php echo $id;?>
</body>
</html>
i would like to use the variable $id in my controller.I'm using codeigniter by the way, and am a beginner. I would appreciate any help on this.
you should not call the $id from the View, you should get it at the controller level and pass it to the View.
as Bulk said. you URL will be something like that
www.mysite.com/thecontrollername/thefunction/id
for example your controller if home and there is a show_id function in it and your view is call show_id_view.php.
you will have your url like this: www.mysite.com/home/show_id/id
your function in home will read the id"
in your home controller:
function show_id(){
$id=$this->uri->segment(3);
$view_data['id'] = $id;
$this->load->view('show_id_view',$view_data);
}
in the view (show_id_view):
<?php echo $id ?>
nothing else..
hope this helps.
Well, ideally you wouldn't do it this way. You should assign the variable first in the controller and pass it to the view if you need to use it there.
$data['id'] = $this->uri->segment(3);
$this->load->view('view_file', $data);
$id would then be available in your view as well.
in my view i add link
<li><a href="<?php echo base_url()?>link/show_id/mantap"> coba </li>
in my link.php controler i add function show_id
function show_id(){
$id=$this->uri->segment(3);
$data['coba'] = $id;
$this->mobile->view('**daftarmember_form**',$data);
in my next view daftarmember_form.html
)
<?php echo $id;?>
they print mantap,