Get the year from specified date php - php

Question

I have a date in this format 2068-06-15. I want to get the year from the date, using php functions. Could someone please suggest how this could be done.

Answer 1

$date = DateTime::createFromFormat("Y-m-d", "2068-06-15");
echo $date->format("Y");
The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.

Answer 2

You can use the strtotime and date functions like this:
echo date('Y', strtotime('2068-06-15'));
Note however that PHP can handle year upto 2038
You can test it out here
If your date is always in that format, you can also get the year like this:
$parts = explode('-', '2068-06-15');
echo $parts[0];

Answer 3

I would use this:
$parts = explode('-', '2068-06-15');
echo $parts[0];
It appears the date is coming from a source where it is always the same, much quicker this way using explode.

Answer 4

You can try strtotime() and date() functions for output in minimum code and using standard way.
echo date('Y', strtotime('2068-06-15'));
output: 2068
echo date('y', strtotime('2068-06-15'));
output: 68

Answer 5

public function getYear($pdate) {
$date = DateTime::createFromFormat("Y-m-d", $pdate);
return $date->format("Y");
}
public function getMonth($pdate) {
$date = DateTime::createFromFormat("Y-m-d", $pdate);
return $date->format("m");
}
public function getDay($pdate) {
$date = DateTime::createFromFormat("Y-m-d", $pdate);
return $date->format("d");
}

Answer 6

<?php
list($year) = explode("-", "2068-06-15");
echo $year;
?>

Answer 7

You can achieve your goal by using php date() & explode() functions:
$date = date("2068-06-15");
$date_arr = explode("-", $date);
$yr = $date_arr[0];
echo $yr;
That is it. Happy coding :)

Answer 8

Assuming you have the date as a string (sorry it was unclear from your question if that is the case) could split the string on the - characters like so:
$date = "2068-06-15";
$split_date = split("-", $date);
$year = $split_date[0];

Answer 9

$Y_date = split("-","2068-06-15");
$year = $Y_date[0];
You can use explode also

Answer 10

You wrote that format can change from YYYY-mm-dd to dd-mm-YYYY you can try to find year there
$parts = explode("-","2068-06-15");
for ($i = 0; $i < count($parts); $i++)
{
if(strlen($parts[$i]) == 4)
{
$year = $parts[$i];
break;
}
}