I have a table within a mysql database. What i want to do, is in a php page, run a select statement and output the result into an excel file.
I've seen quite a few tutorials out there and tried them, however these output the contents of the webpage into the excel file. I just want the mysql table data and headers.
Is there a way to do this?
You can use one of the available PHP libraries for that. One, two.
One thing that is pretty fast to develop but not as neat as using a LIBRARY for that is:
Perform your MySQL query
Create an HTML table with the results
Set content type of the response to: application/vnd.ms-excel
In most browsers, using that page will open the HTML table as a spreadsheet in Excel. You can use other HTTP headers to suggest file name for that file.
I've used PHPExcel for quite a while now and I must say, it's pretty easy to use if you can read the doc.
Did what you want in an afternoon (reading the doc, trying stuff and finalizing)
Definitely you have to use a component to generate a Excel file. I use this lib:
Spreadsheet::WriteExcel: A library for generating Excel Spreadsheets
Copyright (C) 2002 Xavier Noguer xnoguer#rezebra.com
Here is a small snippet:
header("Content-type: application/vnd.ms-excel");
header("Content-Disposition: attachment; filename=$filename" );
header("Expires: 0");
header("Cache-Control: must-revalidate, post-check=0,pre-check=0");
header("Pragma: public");
$formato1 =& $workbook->add_format();
$formato1->set_border(1);
$formato1->set_bg_color('white');
$formato1->set_fg_color('grey');
$formato1->set_pattern();
$formato1->set_size(10);
$formato1->set_color('white');
$formato1->set_align('center');
$formato1->set_bold();
$formato2 =& $workbook->add_format();
$formato2->set_size(10);
$formato2->set_border(1);
$worksheet1 =& $workbook->add_worksheet('Relatório de Inscrições');
$linha = 1;
//Query dos dados das inscrições recebidas
$sql = "select
A.Name, A.Code
from
Customers A
order by
A.Name";
$resultado = $conn ->_execute($sql);
$worksheet1->write_string(0, 0, 'Name', $formato1);
$worksheet1->write_string(0, 1, 'Code', $formato1);
for($a = 0; $a < count($resultado); $a++)
{
$row = $resultado[$a];
$worksheet1->write_string($linha, 0, utf8_decode($row->Name), $formato2);
$worksheet1->write_number($linha, 1, $row->Code, $formato2);
$linha++;
}
$workbook->close();
Related
I want to create an application that when you import the CSV then it will export to .xlsx. But there are some conditins:
I need to change the column order and remove some of the columns when its exported
I need also to change the color and font(size,color)
And also create a multiple worksheets on single .xlsx file.
Which is better to use on this kind of application, can anybody help me and share some points which is better. I do the exploring on both but I need some guidance and some better solutions. Thank you.
// output headers so that the file is downloaded rather than displayed
header('Content-Type: text/csv; charset=utf-8');
header('Content-Disposition: attachment; filename=file.csv');
// create a file pointer connected to the output stream
$output = fopen('php://output', 'w');
// output the column headings
fputcsv($output, array('First Name', 'Last Name'));
You dot need to use a plugin or anything. PHP has the functionality within itself. What i wrote above is an example of defining the file and outputting the first row of the CSV.
Each use of fputcsv() outputs a new row.
So you can define the order of things by telling it in the array which value goes where in the row.
I am working on a web application (php, javascript, html) that holds a large amount os user information. It is designed for temporary jobs.
The thing is, I have three tables (mysql) with information about the users. One for the address and other things, other for driver license, certificates, ..., and the last one for user experience.
What I want to do, is have a "print" button that generates a txt file with all that data in one file. The thing is that I alredy have an idea of how to do it.
1) retrieve all the information for the tables in a join with username.
2) I already had the function to "resource_to_array" for building an array with all the data
3) I could just go for each column of the array and saving the information that I want
But what I am asking is for experience doing something like this. This is the first time for me, and I want it to make it good and scalable for the future.
How will be a good way to do implement it? also, how could I create a plain text with all that information? (this part is in where I have more doubts about)
I know that maybe is a weird question..but I do not want code, I just want a vision for the implementation. Also, is there is a library os something similar that do what I want to do
Thank you very much.
First of all make a link that will generate text file.
Print
Now, in print.php you have to put your logic.
Execute the join Query for fetching the data.
Fetch "array" for building an array with all the data.
Get the element from the array that you want to save in text file.
Now logic is here, Use file handling for creating the text file with save data.
Logic is here(print.php) :
<?php
$conn = new mysqli("host-name","username","password","database-name");
$query = "....";
$result = $conn->query($query);
$rs = $result->fetch_array(MYSQLI_BOTH);
while($rs = $result->fetch_array(MYSQLI_BOTH))
{
$data = $rs['column-name']; // data you want to save in text file
$f = fopen("save.txt", 'a');
fwrite($f, $data);
fclose($f);
}
$filename = "save-data.txt"; // name of the file you want to download on clicking the link
$file = "save-data.txt";
$type = filetype($file);
// Send file headers
header("Content-type: $type");
header("Content-Disposition: attachment;filename=$filename");
header("Content-Transfer-Encoding: binary");
header('Pragma: no-cache');
header('Expires: 0');
// Send the file contents.
set_time_limit(0);
readfile($file);
?>
Sidenote: The a switch appends to file. If you do not wish to keep adding to it, use the w switch:
$f = fopen("save.txt", 'w');
I hope it will help you.
Of course after hours of pondering this problem, the first comment on my question lead me to solve it immediately.
The problem was that, although I was including this code within its own function at the top of the page, I was calling it only if a certain flag was set in the $_POST array. I wasn't checking for the flag until the end of the PHP file. I moved that check before the function, and it worked.
The original question is below:
I'm trying to use the fopen() function in PHP to output a CSV file, and although it contains the data I want, it also contains the entire HTML structure of the page, as well as inline stylesheets, before the content that I actually want to output.
I'm using this code (from here) pretty much unchanged. I'm very unfamiliar with PHP streaming and output, so I started from what I hope was a firm foundation:
$fileName = 'somefile.csv';
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
header('Content-Description: File Transfer');
header("Content-type: text/csv");
header("Content-Disposition: attachment; filename={$fileName}");
header("Expires: 0");
header("Pragma: public");
$fh = #fopen( 'php://output', 'w' );
global $wpdb;
$query = "SELECT * FROM `{$wpdb->prefix}my_table`";
$results = $wpdb->get_results( $query, ARRAY_A );
$headerDisplayed = false;
foreach ( $results as $data ) {
// Add a header row if it hasn't been added yet
if ( !$headerDisplayed ) {
// Use the keys from $data as the titles
fputcsv($fh, array_keys($data));
$headerDisplayed = true;
}
// Put the data into the stream
fputcsv($fh, $data);
}
// Close the file
fclose($fh);
// Make sure nothing else is sent, our file is done
exit;
My assumption is that this example was intended to be included in its own external PHP file, but due to the constraints I'm dealing with, I'm trying to include it inline instead. I've mucked about with output buffering a bit with no positive results, but the PHP documentation on these is quite sparse, so there's probably something I'm missing.
Problem seems to be that, at the same time you try to output from the same PHP file, the CSV file AND some html content. You've got to separate them, to have 2 different URLs.
I guess your PHP code is surrounded by the html code (and css inline) you're talking about.
What you've got to do is:
have a PHP script that only outputs the CSV content (which only contains the code you showed us, with the opening php tag of course)
have another PHP script which produces html code, and provides a link to the previous script (for example).
You are on the right track with the 'include it inline' reason to why you're getting everything else before the data.
This script will need to be it's own separate file called directly, instead of including it inline in another script. I understand you have other database connections and such that have to be set up first. You'll have to extract those out of your standard pages and include those on this page.
Of course after hours of pondering this problem, the first comment on my question lead me to solve it immediately.
The problem was that, although I was including this code within its own function at the top of the page, I was calling it only if a certain flag was set in the $_POST array. I wasn't checking for the flag until the end of the PHP file. I moved that check before the function, and it worked.
I'm no php expert (a mere beginner) but need some help!
After hours searching Google and trying out about 100 different scripts, I finally found one that does what I need - almost.
Basically, my site has a button marked 'Export to Excel'. Visitor to site clicks button and a download begins containing all data from a specified table.
I found this on here - PHP code to convert a MySQL query to CSV
which does exactly what I want except the user sees the following error when trying to open the file:
Error - 'The file you are trying to open, 'export.xls', is in a different format than specified by the file extension. Verify that the file is not corrupted and is from a trusted source before opening the file. Wo you want to open the file now?'
User clicks 'Yes' and file opens with all data! Brilliant! Except users will not open the file with this error.
I would be very grateful if someone knows a way to fix this.
Many thanks
TT
Or, you could just change the script in the above solution to return a file with the .csv extension. .csv files are associated with Excel, so they should open directly.
Ok, this results from a feature specified by Excel 2007 called Extension Hardening. You can turn it off, but that can only be done client-side. If you click "OK" or "Yes" the file should open anyway. Check this blog post for more info.
EDIT: What this means is that Excel is finding that the file is of a different type (say HTML or CSV) that what is specified by the file extension. Therefore Excel wants to warn you that this file is not what it says it is. Unless you are going to create native Excel files on the server then prompt the user to download them, there is no getting around this error except for each user to turn off Extension Hardening on their own computer.
if you make the first letters “ID” of a text file Excel incorrectly
assumes you are trying to open an SYLK file.
Meaning if the first row & column value is "ID", Excel will throw this warning. Just change it from "ID" to anything else.
Credit: http://alunr.com/excel-csv-import-returns-an-sylk-file-format-error/
Dim objXL As Excel.Application
Dim objWkb As Excel.Workbook
Set objXL = New Excel.Application
'turn off excel warnings
objXL.DisplayAlerts = False
'Open the Workbook
Set objWkb = objXL.Workbooks.Open(fpath)
functions sendFile($filename,$content_type="application/ms-excel") {
header('Content-type: '.$content_type);
header('Content-disposition: Attachment; filename=' . $filename);
readfile($filename);
}
I had the same problem so I looked at the following link: PHP code to convert a MySQL query to CSV
I modified one of the answers to get the headers to work.
include('DBFILE.PHP');
$select="SELECT * FROM SOMETable";
$result = mysqli_query($conn, $select);
if (!$result) die('Couldn\'t fetch records');
$num_fields = mysql_num_fields($result);
//This is what I changed...
$headers ="";
while ($property = mysqli_fetch_field($result)) {
$headers.= $property->name.",";
}
$headers.="\n";
//////
$fp = fopen('php://output', 'w');
if ($fp && $result) {
header('Content-Type: text/csv');
header('Content-Disposition: attachment; filename="export.csv"');
header('Pragma: no-cache');
header('Expires: 0');
fputcsv($fp, $headers);
while ($row = $result->fetch_array(MYSQLI_NUM)) {
fputcsv($fp, array_values($row));
}
die;
}
I Tested this and it works like a charm, you just need to add your db connection or include the db.php file that you have.
you can change the name of the file if you edit the following line
header('Content-Disposition: attachment; filename="export.csv"');
Change export to what ever name you like.
I have installed PEAR, Spreadsheet_Excel_Writer and OLE. The sample program is executed successfully but when I try to read the file it shows garbage values. I also tried $workbook->setVersion(8); and $worksheet->setInputEncoding('UTF-8');
I am using this tutorial and Google lot for this problem.
http://www.sitepoint.com/article/getting-started-with-pear/3/
Thanks in advance.
I try to use PEAR only when I really need to...you can easily generate an excel spreadsheet( assuming it's just data) with something like this:
$header = "Last Name\tFirst Name\tAge\tJob\n"; // new line is start of new row, tab is next column
//ideally you would get this from a DB and just loop through it and append on
$row1 = "Smith\tBob\t25\tManager\n";
$row2 = "Anderson\tTrent\t32\tCEO\n";
$excel = $header.$row1.$row2;
$xlsfile = "excel_example".date("m-d-Y-hiA").".xls";
header('Content-type: application/vnd.ms-excel');
header("Content-Disposition: attachment; filename=$xlsfile");
echo $excel;
that's just a tab seperated value file though and you're sending headers suggesting the browser treat that data as an excel file. so there's no formatting of data which the poster may require.