My aim is to have product links like:
domain.com/test-product
domain.com/second-test-product
instead of:
domain.com/products/product/id/5
domain.com/products/product/id/123
Info about each product is get in ProductsController in productAction().
It works fine:
ProductsController:
public function productAction() {
$products = new Application_Model_DbTable_Products();
$nicelink = $this->_getParam('nicelink', 0);
$this->view->product = $products->fetchRow($products->select()->where('product_nicelink = ?', $nicelink));
// nicelink is always unique
}
The link to this method looks like:
for ($i=0; $i < count($this->products); $i++) {
echo 'LINK';
}
Info about each product is displayed in product.phtml view:
<?php echo $this->escape($this->product->product_name); ?>
And my Bootstrap.php file:
<?php
class Bootstrap extends Zend_Application_Bootstrap_Bootstrap {
protected function _initRoutes() {
$router = Zend_Controller_Front::getInstance()->getRouter();
include APPLICATION_PATH . "/configs/routes.php";
//$frontController = Zend_Controller_Front::getInstance();
$route = new Zend_Controller_Router_Route_Regex(
'(.+)',
array(
'controller' => 'products',
'action' => 'product'
),
array(
1 => 'nicelink',
),
'%s.html'
);
$router->addRoute('profileArchive', $route);
}
}
However, this solution has 1 major disadvantage: all other links such as
domain.com/contact
domain.com/about-us
are not working (probably due to the Bootstrap file).
How to fix the problem in order to make another links work and maintain current product links?
The issue is that you are matching all routes to product action in products controller. Probably you want to keep using the default routes in zend 1, which match "contact" and "about-us" to the corresponding actions in your default controller.
If you check "Zend_Controller_Router_Rewrite" function "addDefaultRoutes()" and "route()", you can see that the default routes will be checked after any custom ones.
The simplest solution, looking on what you are asking would be to match any routes that end with "-product":
$route = new Zend_Controller_Router_Route_Regex(
'(.+)\-product',
array(
'controller' => 'products',
'action' => 'product'
),
array(
1 => 'nicelink',
),
'%s.html'
);
In this case nicelink should take values "test" and "second-test" in your corresponding examples.
I have a table on my database from where I get some slug texts:
art_and_culture
business_and_financial
auto_and_moto
and display on my website through
<?php echo lang($slug_from_database); ?>
I use this method as LanguageSwticher:
multi-language-support-in-codeigniter
So in My_Controller.php I have in construct:
$this->categories_list = $this->categories_model->entries();
$list_categories['categories'] = $this->categories_list;
$this->data['sidebar_categories'] = $this->load->view('blocks/sidebar_categories', $list_categories, TRUE);
and all the categories are available on all pages from my website. The problem is when I send to the view the categories, the language is not set from the LanguageLoader.php controller witch is initialised in hooks.php (see the link example). If no language no text on echo $slug_from_database. How do you suggest to do?
I found one solution:
Created:
public function LanguageLoader() {
$site_lang = $this->session->userdata('site_lang');
if ($site_lang) {
$this->lang->load('message',$this->session->userdata('site_lang'));
} else {
$this->lang->load('message', $this->config->item('language'));
}
}
in MY_Controller.php
and call it in the constructor: $this->LanguageLoader();
and delete
$hook['post_controller_constructor'] = array(
'class' => 'LanguageLoader',
'function' => 'initialize',
'filename' => 'LanguageLoader.php',
'filepath' => 'hooks'
);
from hooks.php so now I load the language in controller`s construct not with hook.
I have create custom router class in cakephp 2.x, I'm just follow this blog post. In my app i don't have /Routing/Route folders and I create folders and put StaticSlugRoute.php file to it. In that file include following code
<?php
App::uses('Event', 'Model');
App::uses('CakeRoute', 'Routing/Route');
App::uses('ClassRegistry', 'Utility');
class StaticSlugRoute extends CakeRoute {
public function parse($url) {
$params = parent::parse($url);
if (empty($params)) {
return false;
}
$this->Event = ClassRegistry::init('Event');
$title = $params['title'];
$event = $this->Event->find('first', array(
'conditions' => array(
'Event.title' => $title,
),
'fields' => array('Event.id'),
'recursive' => -1,
));
if ($event) {
$params['pass'] = array($event['Event']['id']);
return $params;
}
return false;
}
}
?>
I add this code but it didn't seems to working (event/index is working correct).I want to route 'www.example.com/events/event title' url to 'www.example.com/events/index/id'. Is there any thing i missing or i need to import this code to any where. If it is possible to redirect this type of ('www.example.com/event title') url.
Custom route classes should be inside /Lib/Routing/Route rather than /Routing/Route.
You'll then need to import your custom class inside your routes.php file.
App::uses('StaticSlugRoute', 'Lib/Routing/Route');
Router::connect('/events/:slug', array('controller' => 'events', 'action' => 'index'), array('routeClass' => 'StaticSlugRoute'));
This tells CakePhp to use your custom routing class for the URLs that look like /events/:slug (ex: /events/event-title).
Side Note: Don't forget to properly index the appropriate database field to avoid a serious performance hit when the number of rows increases.
I am using $this->Js->submit to pass a value to my controller asynchronously and than update a div (id = #upcoming). Somehow I cannot save/retrieve the value of the field 'test' which is passed to my controller. Firebug tells me that the correct value is passed. What am I doing wrong?
View file (playlist.ctp):
echo $this->Form->create('Add', array('url' => array('controller' => 'Gods', 'action' => 'add')));
echo $this->Form->input('test');
echo $this->Js->submit('Addddd', array(
'url' => array(
'controller' => 'Gods',
'action' => 'add'
),
'update' => '#upcoming'
));
echo $this->Form->end();
echo $this->Js->writeBuffer(array('inline' => 'true'));
Controller action:
public function add()
{
$this->autoLayout = false;
$this->layout = 'ajax';
$link = $this->request->data['Add']['test'];
$this->set('test',$link);
}
And its view file (add.ctp):
<?php
echo $test;
?>
Thanks for your help!
have you tried pr($link) in the controller method? Or just send it to a log file if you prefer that. That way you can see if the data is received.
If so, I think there is nothing returned because of
$this->autoLayout = false;
Try it without this. It will still call the ajax layout instead of the default.
Otherwise you have to manualy call the render function
$this->render('add');
EDIT
As explained in the comments below, make sure your views are in the right place. (that would be the view folder associated with the controller)
I used the following code to display the menu items.
Here by default the 'Home' link should be activated. So that i used the code
active' => $this->id =='default' ? true : false
$this->widget('zii.widgets.CMenu',array(
'linkLabelWrapper' => 'span',
'items'=>array(
array('label'=>'Home', 'url'=>array('post/index'),'active'=>$this->id=='default'?true:false),
array('label'=>'About', 'url'=>array('site/page', 'view'=>'about'),'active'=>$this->id=='about'?true:false),
array('label'=>'Test', 'url'=>array('site/page', 'view'=>'test')),
array('label'=>'Contact', 'url'=>array('site/contact')),
array('label'=>'Login', 'url'=>array('site/login'), 'visible'=>Yii::app()->user->isGuest),
array('label'=>'Logout ('.Yii::app()->user->name.')', 'url'=>array('site/logout'), 'visible'=>!Yii::app()->user->isGuest)
),
));
I referred the url http://www.yiiframework.com/doc/api/1.1/CMenu#activateItems-detail
But i dont know how to use these parameters. Please help
Not the Yii way, but the (simpler) jQuery way:
// find menu-item associated with this page and make current:
$('a').each(function(index, value) {
if ($(this).prop("href") === window.location.href) {
$(this).addClass("current-page");
}
});
The code you give will be typically found inside a view. The documentation for view states that
Inside the view script, we can access the controller instance using
$this. We can thus pull in any property of the controller by
evaluating $this->propertyName in the view.
So, we have established that in the current context, $this->id refers to the CController::id property. This id will typically be the prefix of your controller's class name. For example, inside MyController you will have $this->id == "my".
With all this in mind, you can now tell that active will be true if and only if the current view is rendered from inside a controller named DefaultController. However, from the url property of that menu item we see that the associated controller for that action (assuming default routing) is PostController. So the $this->id == "default" idea is faulty.
If you want to make the "Home" item active whenever any action in your PostController is running, you should change this to $this->id == "post". Normally it should not be necessary to do this, because the activateItems property (which defaults to true) used with default routing will take into account both the controller id and the current action to determine which menu item to make active.
if you have some advanced link structure, put method below in Controller
/**
* Checks if the current route matches with given routes
* #param array $routes
* #return bool
*/
public function isActive($routes = array())
{
$routeCurrent = '';
if ($this->module !== null) {
$routeCurrent .= sprintf('%s/', $this->module->id);
}
$routeCurrent .= sprintf('%s/%s', $this->id, $this->action->id);
foreach ($routes as $route) {
$pattern = sprintf('~%s~', preg_quote($route));
if (preg_match($pattern, $routeCurrent)) {
return true;
}
}
return false;
}
//usage
'items'=>array(
array('label'=>'Some Label', 'url'=>array('some/route'),'active'=>$this->isActive(array(
'some/route',
'another/route',
)),
),
I used this way:
array('label'=>'Contact', 'url'=>array('site/contact'), 'active'=>strpos(Yii::app()->request->requestUri, Yii::app()->createUrl('site/contact'))===0)
The menu will work as we use default pages as site/contact, site/login
But many times it will not work for the module url.
suppose i have module user and i had login action in login controller, so i can do below thing form menu as how menu item gets active defined below.
array('label'=>Yii::t('frontend','Login'), 'url'=>array('/user/login/login'), 'visible'=>Yii::app()->user->isGuest), // Working, Login tag activated on login page
array('label'=>Yii::t('frontend','Login'), 'url'=>array('/user/login'), 'visible'=>Yii::app()->user->isGuest), // Not working, Login tag not activated on login page
So, we can have problem to beautify url..
For yiistarterkit just add this code in the _base.php file:
function isActive($routes = array())
{
if (Yii::$app->requestedRoute == "" && count($routes) == 0){
return true;
}
$routeCurrent = Yii::$app->requestedRoute;
foreach ($routes as $route) {
$pattern = sprintf('~%s~', preg_quote($route));
if (preg_match($pattern, $routeCurrent)) {
return true;
}
}
return false;
}
And then use:
echo Nav::widget([
'options' => ['class' => 'navbar-nav navbar-left'],
'items' => [
['label' => \Yii::t('frontend', 'Home'), 'url' => ['/'], 'active'=>isActive()],
['label' => \Yii::t('frontend', 'Services'), 'url' => ['/services'], 'active'=>isActive(['services'])],
]
]);
Take as a base the file yiisoft/yii2-boostrap/nav.php function renderItem():
...
if ($this->activateItems && $active) {
Html::addCssClass($options, 'active');
}
return Html::tag('li', Html::a($label, $url, $linkOptions) . $items, $options);
And modify $option on $linkOption for a link.
Html::addCssClass($linkOptions, 'active');
As result active class will be added to a.class, instead li.class