I have a datetime column in MySQL let's call it $time. It's coming form a CakePHP form. If I try to echo it I get I just get "Array". If I print_r() on it I get:
Array ( [month] => 10 [day] => 30 [year] => 2010 [hour] => 16 [min] => 30 )
I want to echo this out as a formatted date, nothing seems to work because it's not a string but an array. Do I have to go like this:
echo $time['month'].'-'.$time['day'].'-'.$time['year'].' '.$time['hour'].':'.$time['min'];
or can I use the date function?
One simple, procedural way is to use date() in conjunction with mktime(), like so. date() formats based on a UNIX timestamp; mktime() provides a timestamp based on your array values:
$timestamp = mktime($time['hour'], $time['min'], 0, $time['month'], $time['day'], $time['year']);
echo date('M-d-Y H:i', $timestamp);
For a more object-oriented approach with the DateTime class, refer to Gordon's answer.
You can do:
$dt = new DateTime;
$dt->setDate($time['year'], $time['month'], $time['day']);
$dt->setTime($time['hour'], $time['minute']);
echo $dt->format(DateTime::ISO8601);
You can put any format into format() that is also supported with date().
You do not need PHP5.3 for this.
Use the above if you need to create a date that is not already contained in the array. If you simply want a 'Y-m-d H:i' format, you can use
printf("%d-%02d-%02d %02d:%02d",
$time['year'], $time['month'], $time['day'],
$time['hour'], $time['min']);
or with argument swapping and passing the entire array (though you have to rely on the order then):
vprintf('%3$d-%1$02d-%2$02d %4$02d:%5$02d', $time);
Needless to say, you can also use vsprintf or sprintf to create a datetime string that can be parsed with DateTime or strtotime, e.g.
$dt = new DateTime(vsprintf('%3$d-%1$02d-%2$02d %4$02d:%5$02d', $time));
which you could then format as shown in the first example.
Do I have to go like this:
That is one option, yes.
or can I use the date function?
Not with the data in the current form.
You could consider converting the array into a proper timestamp or DateTime object for maximum flexibility in formatting, calculations etc.
For a timestamp, see mktime() (You'll have to feed it the members of your array. Update: #BoltClock has an example.)
For a DateTime object - it's PHP5's new, object-oriented, Year 2038 bug-free, and much better way of dealing with dates - see CreateFromFormat() (Needs PHP 5.3+, though)
The date() function has an optional argument $timestamp. You can echo date("MM-dd-yyyy hh:mm, $time) and avoid manual formatting.
I hope the $time value is declared as TIMESTAMP in MySQL for this to work
Date function wants a timestamp. But you could use a custom function, such as:
function fd($time) {
return "$time[month]-$time[day]-$time[year] $time[hour]:$time[minute]";
}
// Sample usage
echo fd($time);
Does the Time helper not suit the needs here? Just pass the whole array to it and use the functions it provides.
Related
I am receiving JSON data with a date string with this format:
'Mon Jun 30, 2014'
What would be the way to convert this to a datetime? Checking the PHP functions for this I got unsecure if better to use date_parse_from_format or date_create_from_format.
What are the differences and which would suit better for this task?
DateTime::createFromFormat would work well here. It allows you to format the string easily and also takes timezones into consideration when appropriate and can be easily used in comparisons without having to convert to a timestamp first.
$date = DateTime::createFromFormat('D M d, Y', 'Mon Jun 30, 2014');
echo $date->format('Y-m-d');
You can convert to a unix timestamp using strtotime(). I don't know what you mean by a "datetime", but if you mean something like for MySQL then you format the timestamp with date() (you can include time but it isn't present in the original string):
echo date('Y-m-d', strtotime($string));
The second of the two likely fits you better ---
The first one only breaks down the date into an array, so you can work with the parts, individually.
But the second returns the DateTime object you are looking for.
I am new to PHP and I am trying to learn more of php date and time but I seem to get stuck with this.
I have this date format:
ddMMyyHHmmss
And an example is 120813125055 but I am trying to manipulate the string such that it will give me the format of:
yyyy-MM-dd HH:mm:ss (in the example above, 2013-08-12 12:50:55)
I tried to do something like:
date('Y-m-d H:i:s', strtotime('120813125055'));
But it always gives me a result of 1969-12-31 18:00:00.
I assume that I need to do some string manipulation in PHP for this but I was wondering if there is an easier and more efficient way to do it?
I think what you're looking for is in the second response answered here: how to re-format datetime string in php?
To summarize (and apply to your example), you could modify the code like this.
$datetime = "120813125055";
$d = DateTime::createFromFormat("dmyHis", $datetime);
echo $d->format("Y-m-d H:i:s");
Use date_create_from_format:
$ts = date_create_from_format('dmyHis', '120813125055');
$str = date('Y-m-d H:i:s', $ts);
strtotime() only works on EASILY recognizable formats. Your is a ugly mix of garbage, so no surprise that strtotime bails with a boolean FALSE for failure, which then gets typecast to an int 0 when you tried feed it back into date().
And of course, note that your time string is NOT y2k compliant. two digit years should never ever be used anymore, except for display purposes.
You're using your function call and the argument the wrong way around.
In your example, php will try to return you the date for which the time is 'strtotime('120813125055')', and this function returns false (interpreted as 0). So you get returned the date formatted in 'Y-m-d H:i:s' for the Unix epoch.
You will need to get the actual timestamp of your string, so use http://www.php.net/manual/en/datetime.createfromformat.php.
You are mistaken here..
I tried to do something like:
date('Y-m-d H:i:s', strtotime('120813125055'));
You shouldn't use only numbers ( doesnt matter its an integer or a string ), than it will always give you the same thing.
You can use any other valid date and time ( E.G. 6 Jun 2013, 5 may 12...) . Because what strtotime() do is detect a valid date and convert it into timestamp.
i am trying to format a datetime which comes fromt he database in the format of
2012-06-11 21:39:54
However i want it to display in the format of June 11
How can do this?
Thanks
echo date('M d', strtotime('2012-06-11 21:39:54'));
Output
You can also use DateTime object.
$date = new DateTime($yourString);
$date->format($yourFOrmat);
I think that it would be the best way because DateTime is really more powerful than timestamp and date/strtotime functions.
From the code I gave above you can add functionalities like modifying dates, iterate over the time, compare 2 dates without functions like str_to_time...
$date->modify('+1 day');//the day after for example
foreach(new DatePeriod($date,new DateInterval('PT1M'),10){
$date->format($yourFormat);//iterate each minute
}
and so on
PHP manual gives an excellent documentation about using Date/Time functions. Basically you will need a combination of two functions: strtotime() and date().
strtotime() will convert your date into Unix timestamp which can be supplied to date() as second argument.
The format of date you will need is: M d.
Alternative: In addition you could also try the MYSQL counterpart which won't require conversion to UNIX timestamp. It is documented here. Assuming you are using date as your Datetime field, you will need something like this,
SELECT id,..,DATE_FORMAT(`date`, '%M %d') as f_date FROM table
For formatting date using php, you need to pass timestamp of date
and format specifiers as arguments into date function .
Eg echo date('M d',strtotime('2012-06-11 21:39:54'));
I want to input a timestamp in below format to the database.
yyyy-mm-dd hh:mm:ss
How can I get in above format?
When I use
$date = new Zend_Date();
it returns month dd, yyyy hh:mm:ss PM
I also use a JavaScript calender to insert a selected date and it returns in dd-mm-yyyy format
Now, I want to convert these both format into yyyy-mm-dd hh:mm:ss so can be inserted in database. Because date format not matching the database field format the date is not inserted and only filled with *00-00-00 00:00:00*
Thanks for answer
Not sure if this will help you, but try using:
// to show both date and time,
$date->get('YYYY-MM-dd HH:mm:ss');
// or, to show date only
$date->get('YYYY-MM-dd')
Technically, #stefgosselin gave the correct answer for Zend_Date, but Zend_Date is completely overkill for just getting the current time in a common format. Zend_Date is incredibly slow and cumbersome to use compared to PHP's native date related extensions. If you don't need translation or localisation in your Zend_Date output (and you apparently dont), stay away from it.
Use PHP's native date function for that, e.g.
echo date('Y-m-d H:i:s');
or DateTime procedural API
echo date_format(date_create(), 'Y-m-d H:i:s');
or DateTime Object API
$dateTime = new DateTime;
echo $dateTime->format('Y-m-d H:i:s');
Don't do the common mistake of using each and every component Zend Frameworks offers just because it offers it. There is absolutely no need to do that and in fact, if you can use a native PHP extension to achieve the same result with less or comparable effort, you are better off with the native solution.
Also, if you are going to save a date in your database, did you use any of the DateTime related columns in your database? Assuming you are using MySql, you could use a Timestamp column or an ISO8601 Date column.
This is how i did it:
abstract class App_Model_ModelAbstract extends Zend_Db_Table_Abstract
{
const DATE_FORMAT = 'yyyy-MM-dd';
public static function formatDate($date, $format = App_Model_ModelAbstract::DATE_FORMAT)
{
if (!$date instanceof Zend_Date && Zend_Date::isDate($date)) {
$date = new Zend_Date($date);
}
if ($date instanceof Zend_Date) {
return $date->get($format);
}
return $date;
}
}
this way you don't need to be concerned with whether or not its actually an instance of zend date, you can pass in a string or anything else that is a date.
a simple way to use Zend Date is to make specific function in its business objects that allows to parameter this function the date format. You can find a good example to this address http://www.pylejeune.fr/framework/utiliser-les-date-avec-zend_date/
this is i did it :
Zend_Date::now->toString('dd-MM-yyyy HH:mm:ss')
output from this format is "24-03-2012 13:02:01"
and you can modified your date format
I've always use $date->__toString('YYYY-MM-dd HH-mm-ss'); method in the past but today didn't work. I was getting the default output of 'Nov 1, 2013 12:19:23 PM'
So today I used $date->get('YYYY-MM-dd HH-mm-ss'); as mentioned above. Seems to have solved my problem.
You can find more information on this on output formats here: http://framework.zend.com/manual/1.12/en/zend.date.constants.html
To change 2009-12-09 13:32:15 to 09/12/2009
here:
echo date("d/m/Y", strtotime('2009-12-09 13:32:15'))
You can use strtotime to get the timestamp of the first date, and date to convert it to a string using the format you want.
$timestamp = strtotime('2009-12-09 13:32:15');
echo date('d/m/Y', $timestamp);
And you'll get :
09/12/2009
[edit 2012-05-19] Note that strtotime() suffers a couple of possibly important limitations:
The format of the date must be YYYY-MM-DD; it might work in some other cases, but not always !
Also, working with UNIX Timestamps, as done with date() and strtotime() means you'll only be able to work with dates between 1970 and 2038 (possibly a wider range, depending on your system -- but not and illimited one anyway)
Working with the DateTime class is often a far better alternative:
You can use either DateTime::__construct() or DateTime::createFromFormat() to create a DateTime object -- the second one is only available with PHP >= 5.3, but allows you to specify the date's format, which can prove useful,
And you can use the DateTime::format() method to convert that object to any date format you might want to work with.
Using the date() method.
print date("d/m/Y", strtotime("2009-12-09 13:32:15"));
$long_date = '2009-12-09 13:32:15';
$epoch_date = strtotime($long_date);
$short_date = date('m/d/Y', $epoch_date);
The above is not the shortest way of doing it, but having the long date as an epoch timestamp ensures that you can reuse the original long date to get other date format outputs, like if you wanted to go back and have just the time somewhere else.