How do you correctly output PNG images with PHP so their shading, and other transparent effects don't fail.
seems to be outputting as
...is there a way so this doesn't happen?
I merged two images together.
<?php
// Create image instances
$dest = imagecreatefrompng('vinyl.png');
$src = imagecreatefromjpeg('cover2.jpg');
// Copy and merge
imagecopymerge($dest, $src, 10, 10, 0, 0, 180, 180, 100);
// Output and free from memory
header('Content-Type: image/png');
imagepng($dest);
imagedestroy($dest);
imagedestroy($src);
?>
imagealphablending and imagesavealpha.
See this post: PNG Image Transparency in PHP GD
Related
I am taking a PNG image from a url as below.
I want to convert the PNG image to JPEG without saving disk with PHP.
Finally I want to assign JPEG image to $content_jpg variable.
$url = 'http://www.example.com/image.png';
$content_png = file_get_contents($url);
$content_jpg=;
Simplified answer is,
// PNG image url
$url = 'http://www.example.com/image.png';
// Create image from web image url
$image = imagecreatefrompng($url);
// Start output buffer
ob_start();
// Convert image
imagejpeg($image, NULL,100);
imagedestroy($image);
// Assign JPEG image content from output buffer
$content_jpg = ob_get_clean();
You want to use the gd library for this. Here's an example which will take a png image and output a jpeg one. If the image is transparent, the transparency will be rendered as white instead.
<?php
$file = "myimage.png";
$image = imagecreatefrompng($file);
$bg = imagecreatetruecolor(imagesx($image), imagesy($image));
imagefill($bg, 0, 0, imagecolorallocate($bg, 255, 255, 255));
imagealphablending($bg, TRUE);
imagecopy($bg, $image, 0, 0, 0, 0, imagesx($image), imagesy($image));
imagedestroy($image);
header('Content-Type: image/jpeg');
$quality = 50;
imagejpeg($bg);
imagedestroy($bg);
?>
Folks,I've some 288 points with their X,Y co-ordinates and a value assigned to them. I need to show this figuratively. I tried gd and imagettftext but simple code to draw a blank image isn't working even when I've installed and configured gd.
header('Content-Type: image/png');
$image = imagecreatetruecolor(400, 300);
// Allocate a color for the polygon
$col_poly = imagecolorallocate($image, 255, 255, 255);
// Draw the polygon
imagepolygon($image, array(
0, 0,
100, 200,
300, 200
),
3,
$col_poly);
// Output the picture to the browser
header('Content-type: image/png');
imagepng($image);
imagedestroy($image);
The output in the browser is
Try to set encoding of php file with your code to UTF-8 without BOM (e.g. in Notepad++).
Your code works right and image shows. Most probably your GD library is not working as expected. Try this
$image = imagecreatetruecolor(400, 300) or die('Cannot Initialize new GD image stream');
I'm using Creating image function to create an image with exact text message using the following code
<?PHP
header ("Content-type: image/gif");
$image=imagecreatefromgif("myimage.gif"); // will be background img
$black = imagecolorallocate($image, 0,0,0);
$message = "Hello Egypt";
imagestring($image, 4, 25, 10, $message, $black);
imagegif($image);
imagedestroy($image);
?>
The output should be like this
Now my question is there any way i can write image over it not only text
so that if i've flag image at same path (flag.gif ) and i would like to write it just after my $message to be like this
so is this possible and how could be ! ~ thanks a lot
Update
based on #MarcB idea of using imagecopy function
<?PHP
header ("Content-type: image/gif");
$image=imagecreatefromgif("myimage.gif"); // will be background img
$src = imagecreatefromjpeg('flag.jpg');// new image will add
imagecopy($image, $src, 120, 10, 0, 0, 32, 20);
$black = imagecolorallocate($image, 0,0,0);
$message = "Hello Egypt";
imagestring($image, 4, 25, 10, $message, $black);
imagegif($image);
imagedestroy($image);
?>
the output is not true color WHY :(
ANY help about this new problem ~ thanks
With the help of Surreal Dreams and Marc B
This one works fine
<?PHP
header ("Content-type: image/gif");
$image=imagecreatefromjpeg("myimage.jpg"); // will be background img
$src = imagecreatefromjpeg('flag.jpg');// new image will add
imagecopy($image, $src, 120, 10, 0, 0, 32, 20);
$black = imagecolorallocate($image, 0,0,0);
$message = "Hello Egypt";
imagestring($image, 4, 25, 10, $message, $black);
imagegif($image);
imagedestroy($image);
?>
Output
I've should have learned the following functions
imagecopy
imagecreatefromjpeg
imagecreatefromgif
imagecopy() should properly deal with differences between images' palettes; however, the GIF format does not support more than 256 colors, and neither does GD when it works with palette-based images. If 256 palette entries already exist when GD tries to use a new color, GD will pick the closest match, which can produce the results you see.
To avoid this problem, you should use imagecreatetruecolor() to create a 24-bit true-color image in memory. You can then use imagecopy() to insert each GIF image (including the background) and imagepng() to generate PNG output, which is better for line art than JPEG, offers better compression than GIF, and can support more than 256 colors.
I am using PHP to rotate an PNG image, with a transparant background. But whatever I try, there are still some black lines around the original image.
How do I remove the black lines. Everything else works fine. The image is transparant, the image is rotated, the new corners are also transparant. Just the black lines around the original square (which is rotated) are annoying me.
I use this code:
$angle = -100;
header('Content-type: image/png');
$image = 'http://mapning.com/img/plane.png';
$file = imagecreatefrompng($image);
$rotate = imagerotate($file, $angle, 0);
imageSaveAlpha($rotate, true);
ImageAlphaBlending($rotate, false);
$transparentColor = imagecolorallocatealpha($rotate, 200, 200, 200, 127);
imagefill($rotate, 0, 0, $transparentColor);
imagepng($rotate);
I found my answer here:
http://ru2.php.net/manual/en/function.imagerotate.php#47985
I think better use imagick
Here is an extension for PHP
Or if you want with GD see here
http://ru2.php.net/manual/en/function.imagerotate.php#46338
This question already has answers here:
Transparent PNG over JPG in PHP
(2 answers)
Closed 9 years ago.
I want to do the following in PHP:
I have two images, a jpg and a png. I want to resize the jpg to the same size as the png then put the png on top. The PNG has transparency so I would like to preserve that so the jpg shows underneath.
If anyone could help that would be great!
Thanks
<?
$png = imagecreatefrompng('./mark.png');
$jpeg = imagecreatefromjpeg('./image.jpg');
list($width, $height) = getimagesize('./image.jpg');
list($newwidth, $newheight) = getimagesize('./mark.png');
$out = imagecreatetruecolor($newwidth, $newheight);
imagecopyresampled($out, $jpeg, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
imagecopyresampled($out, $png, 0, 0, 0, 0, $newwidth, $newheight, $newwidth, $newheight);
imagejpeg($out, 'out.jpg', 100);
?>
This is the working code which i using
$dest = imagecreatefrompng('mapCanvas.png');
$src = imagecreatefromjpeg('si.jpg');
imagealphablending($dest, false);
imagesavealpha($dest, true);
// Copy and merge
imagecopymerge($dest, $src, 17, 13, 0, 0, 60, 100, 100);
// Output and free from memory
header('Content-Type: image/png');
imagepng($dest);
imagedestroy($dest);
imagedestroy($src);
Here is a link to an example that will overlay a transparent watermark onto an image. Might be your use case, might be related.
http://www.php.net/manual/en/image.examples.merged-watermark.php
There is also a way to load JPG images, resize images, turn on alpha tracking, and export images in GD.
Jacob