I am being returned this time format from an API:
1287498792000
Can anyone advise what format that is and how I would parse it in PHP?
This format is the Number of milliseconds since 1970-01-01.
Your date represents 2010-10-19 # 14h33 if i'm not mistaken.
Just divide it by 1000 and use the standard php functions for unix timestamps like date to display it or getdate to extract the different parts.
It's a Unix timestamp represented in milliseconds — equivalent to the return value from time() multiplied by 1,000 (timestamp in PHP are in seconds, not milliseconds).
You can use it directly1 in PHP, e.g. for the date() function:
print date('l jS \of F Y h:i:s A', 1287498792000 / 1000);
// Outputs: Tuesday 19th of October 2010 02:33:12 PM
EDIT
1 Yes, it seems to be in milliseconds. Divide by 1,000 in order to get a timestamp that PHP understands.
It's a UNIX timestamp - it represents the count of seconds since January 1st, 1970.
You can use PHP's date() function to convert it to a human readable format.
Related
$dayBasedOnUTC = date('l', $_GET['day']);
Why is it that when I echo the value of $dayBasedOnUTC the day returned is a Tuesday?
The UTC value of $_GET['day'] is: 1409393126144
If you put that number into any Unix Timestamp Converter you will see the date is Saturday.
It appears that 1409393126144 is a Javascript timestamp, which is counted in milliseconds. PHP expects its UNIX timestamps in seconds though. So 1409393126144 to PHP is a timestamp in the far future.
Divide by 1000 to get the correct value:
echo date('l', 1409393126144 / 1000);
I have a xml file, containing several dates, in this format: 2016-07-23T07:00:00.000Z. I'm using a php function to convert this in to a format for publishing on a website. This should actually result in something like Saturday, 24th of July (24th, not 23rd, because of the time offset. My function somehow ignores the T07:00:00.000Z part and thus returns Friday, 23rd of July. Can anybody help me out with the proper way to convert this date?
Thanks, Peter
The string in question
2016-07-23T07:00:00.000Z
is a W3C datetime format (W3C DTF) (Complete date plus hours, minutes, seconds and a decimal fraction of a second) which can be properly parsed incl. the fractions of a second with the date_create_from_format](http://php.net/date_create_from_format) function:
$originalDate = "2016-07-23T07:00:00.000Z";
date_create_from_format('Y-m-d\TH:i:s.uO', $originalDate);
It does create a new DateTime which then can be formatted with the for PHP standard codes, e.g.
date_create_from_format('Y-m-d\TH:i:s.uO', $originalDate)
->format('Y-m-d H:i:s'); # 2016-07-23 07:00:00
As that W3C format carries the timezone already and it is UTC, and you wrote you want a different one, you need to specify it:
date_create_from_format('Y-m-d\TH:i:s.uO', $originalDate)
->setTimezone(new DateTimeZone('Asia/Tokyo'))
->format('Y-m-d H:i:s');
The reason why this is not visible (and controlable with the code given) in the previous answer is because date formats according to the default set timezone in PHP where as each DateTime has it's individual timezone.
An equivalent with correct parsing (incl. decimal fraction of a second) with the other answers then is:
$dateTime = date_create_from_format('Y-m-d\TH:i:s.uO', $originalDate);
date('Y-m-d H:i:s', $dateTime->getTimestamp());
Hope this explains it a bit better in case you need the complete date value and / or more control on the timezone.
For the format, see as well: In what format is this date string?
$oldDateTime= "2016-07-23T07:00:00.000Z"; // Your datetime as string, add as variable or whatever.
$newDateTime= date("Y-m-d H:i:s", strtotime($originalDate));
I have wierd issues with time / date in PHP this year. Code have not changed at all and my dates are bugged.
Code is for example:
$date = strtotime($order['date']);
$dateNew = date('Y-m-d h:i A', $date);
print $dateNew;
Returns 1969-12-31 07:00 PM for some reasson, altough:
print $order['date'];
Returns 2013-01-12 18:25:43
I'm confused because I'm quite sure that my code is correct.
I dare you to solve this bugger!
The function strtotime() was made for transform English into date format.
The function expects to be given a string containing an English date format and will try to parse that format into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 UTC), relative to the timestamp given in now, or the current time if now is not supplied.
As i don't know what is really into your $order variable i will suggest 2 solutions :
Maybe you can avoid the strtotime function and replace it by date() directly like this :
$order = ['date' => '2013-01-12 18:25:43'];
$date = date($order['date']);
It works well here: http://codepad.viper-7.com/cbNA87
Or, if it's not working consider to use mktime(), it will convert the date into seconds since the epoch.
The Unix epoch is the reference point for all time stamps. PHP calculates the times from this date in seconds.
The $date should be null and your server in the east coast of the US so it's returns the epoch :)
PHP returns the date 1969-12-31 when there is not a proper date. So if you did
$date = 0;
$dateNew = date('Y-m-d', strtotime($date));
Your result would be 1969-12-31, since that is the default Unix epoch time. http://php.net/manual/en/function.time.php
Unexpected dates of "1969-12-31 07:00 PM" means something went wrong with date() .
your strototime($order['date']) is probably returning false (failing to parse it to a unix timestamp).
Try this and ensure its returning an int (not false)
var_dump($order['date'], strtotime($order['date']));
See the error state of date: http://php.net/date
See the return values of strtotime: http://php.net/strtotime
Hello i need to get this date value from php 1328569380 and convert it to javascript date.
By the way how is this date "1328569380" type of form called ?
The numeric date time your are referring to is called a timestamp. It is the number of seconds elapsed since january 1st of 1970 if i'm not wrong.
To send a date to javascript, just print it out using the timestamp x 1000 since it also accepts millisecond initialization format:
mydate = new Date(<?php echo $mytimestamp*1000; ?>);
Good luck
This is a Unix epoch timestamp. See the following thread for the how-to:
Convert a Unix timestamp to time in JavaScript
Your value is the number of seconds that has passed since 1970-01-01 00:00:00, called the Unix epoch.
JavaScript counts the number of milliseconds instead, thus you have to multiply your timestamp with 1000 prior to using it to create a JavaScript date-object.
var phptimestamp = 1328569380;
var date = new Date(phptimestamp * 1000);
If I do
alert(new Date(1313690400000))
returns: Thu Aug 18 2011 13:00:00 GMT-0500 (CDT)
however, PHP
echo date('Y-m-d H:i:s', 1313690400000);
returns: 1951-12-14 05:50:24
JavaScript uses milliseconds as a timestamp, whereas PHP uses seconds. As a result, you get very different dates, as it is off by a factor 1000.
So remove three zeroes at the PHP side:
echo date('Y-m-d H:i:s', 1313690400);
Javascript Date is milliseconds since Epoch, whereas PHP date uses unix timestamp which is in seconds.
So to get the same date in php, divide by 1000 first
PHP's date/time functions use the number of seconds since the epoch, while Javascript uses the number of milliseconds. In your php func:
echo date('Y-m-d', 1313690400000 / 1000);