PHP JSON Data Selection - php

Question

How would I go about selecting the data of each title from the following JSON?
I have the JSON decoded, but I'm not sure how to select the part I want.
{
"responseData": {
"results": [
{
"title": "Justin Giesbrecht 749",
"titleNoFormatting": "Justin Giesbrecht 749",
},
{
"title": "Gopher dunes 09",
"titleNoFormatting": "Gopher dunes 09",
},
{
"title": "dirtbike Justin",
"titleNoFormatting": "dirtbike Justin",
},
{
"title": "A Warming",
"titleNoFormatting": "A Warming",
}
],
"cursor": {
"pages": [
{
"start": "0",
"label": 1
},
{
"start": "4",
"label": 2
}
],
"estimatedResultCount": "6",
"currentPageIndex": 0,
}
},
"responseDetails": null,
"responseStatus": 200
}
I thought it would be something like this, but I don't get anything:
echo "Response ". $jsonS->responseData->results[1]->title;

Answer 1

Actually you've got the reading of the title part right, it's the JSON that is invalid.
Copying the JSON into a JSON validator/lint e.g. http://www.jsonlint.com/ will show that the you have additional , (commas) after the last object attribute in a few places (5 places to be exact, after each 'titleFormatting' attribute and after 'currentPageIndex').
If you fix those errors and parse it using json_decode e.g.:
$jsonS = json_decode($json_text);
Then your own code:
echo "Response " . $jsonS->responseData->results[1]->title;
Will output the second (index 1 being the second index) results title
Response Gopher dunes 09

Answer 2

When you json_decode something it is converted to a regular PHP array, so you can reference it like $decodedObject["nodeName"].

Answer 3

When I parse that JSON as you quoted it with PHP's json_decode method, it gives me NULL because PHP doesn't think it's valid JSON. Add a var_dump($jsonS); to see if this is happening to you as well. If it is, you may need to be sure your JSON is valid.
Here's what I did, for reference:
$json_data = <<<END_OF_JSON
{
"responseData": { "results": [
{
"title": "Justin Giesbrecht 749", "titleNoFormatting": "Justin Giesbrecht 749",
},
{
"title": "Gopher dunes 09",
"titleNoFormatting": "Gopher dunes 09",
},
{
"title": "dirtbike Justin",
"titleNoFormatting": "dirtbike Justin",
},
{
"title": "A Warming",
"titleNoFormatting": "A Warming",
}
],
"cursor": {
"pages": [ {
"start": "0",
"label": 1
},
{
"start": "4",
"label": 2
}
],
"estimatedResultCount": "6",
"currentPageIndex": 0,
}
},
"responseDetails": null,
"responseStatus": 200
}
END_OF_JSON;
$jsonS = json_decode($json_data);
var_dump($jsonS);
echo "Response ". $jsonS->responseData->results[1]->title;
And the output was:
NULL Response
If you're using different JSON, please edit your question and share it. But if you're actually using the above, it's not valid...

Answer 4

In JSON you are not allowed to leave trailing comma in array/object definition. So, when in PHP is perfectly valid to write:
$a = array(1,2,3,);
(note last comma), in JSON
a : [1,2,3,]
or
a : {x :'y',}
is invalid.