I have 2 tables in MySQL:
Persons
|ID | Name | Address
---------------------------------
| 1 | Someone | Somewhere
| 2 | Person2 | Somewhere else
And the table ActivePages
|ID | PersonID | Page
---------------------------------------
| 1 | 1 | somepage
| 1 | 1 | someotherpage
Now I need a query to return the following:
|PersonID | Count
------------------
|1 | 2
|2 | 0
------------------
Who can help me with this? I think its straight forward but I keep getting wrong values...
Thanks in advance!
SELECT p.ID AS PersonID,
COUNT(a.PersonID) AS `Count`
FROM Persons p
LEFT JOIN ActivePages a ON a.PersonID = p.ID
GROUP BY p.ID
select personid,count(personid) as count from activepages
right join Persons on ActivePages.PersonID = Persons.ID group by personid
Related
My database looks something like this, in order of user, userteam (connection table) and team:
Usertable UserTeam Teamtable
+--------+------+ +--------+--------+ +--------+-------+
| userid | name | | userid | teamid | | teamid | name |
+--------+------+ +--------+--------+ +--------+-------+
| 1 | eric | | 1 | 1 | | 1 | awsm |
| 2 | john | | 1 | 2 | | 2 | doe |
| 3 | carl | | 2 | 1 | | 3 | empty |
+--------+------+ | 3 | 1 | +--------+-------+
+--------+--------+
How do I select all users that IS NOT in a team, and echo them out only once? I've tried doing it with the usertable, but then it will echo for instance, if I try and select all members not in team 3:
SELECT userid FROM userteam WHERE teamid!=3;
SELECT * FROM user WHERE userid='$previousSql';
1 eric
1 eric
2 john
3 carl
What I'd like instead is:
1 eric
2 john
3 carl
I'm making an add members function, and I'd very much not like everyone to show up more than once.. Any directions, help or guiding would be much appreciated.
add
GROUP BY name
to the query
This should do it:
SELECT u.userid, u.name FROM Usertable u
INNER JOIN UserTeam ut ON ut.userid = u.userid
INNER JOIN Teamtable tt ON tt.teamid = ut.teamid
WHERE tt.teamid != 3
GROUP BY u.userid, u.name;
SELECT userid, name FROM usertable
JOIN userteam ON userteam.userid = usertable.userid
JOIN teamtable on teamtable.teamid = userteam.teamid
WHERE teamtable.teamid = 3;
The SQL above should do the proper joins between all the tables and then will only list the userid/names of people who have a teamid of 3 in the teamtable
EDIT* Removed ! from WHERE clause.
I have 3 tables,
itemmaster
|--------|----------|
| id | name |
|--------|----------|
| 1 | Pizza |
|--------|----------|
| 2 | Burger |
|--------|----------|
| 3 | Pepsi |
---------------------
order
|--------|----------|
|orderid | date |
|--------|----------|
| 1 | 1-1-11 |
|--------|----------|
| 2 | 2-1-11 |
|--------|----------|
| 3 | 3-1-11 |
---------------------
orderdetails
|--------|-------------|---------|---------|
| id | orderid |itemid |quantity |
|--------|-------------|---------|---------|
| 1 | 1 | 1 | 10 |
|--------|-------------|---------|---------|
| 2 | 1 | 2 | 20 |
|--------|-------------|---------|---------|
| 3 | 2 | 1 | 10 |
-------------------------------------------
I want to join these 3 tables to get quantity of items of an order that placed on a particular date.
What I have tried is
$this->db->from('itemmaster');
$this->db->join('orderdetails', 'orderdetails.itemid= itemmaster.id','left');
$this->db->join('order', 'order.orderid= orderdetails.orderid');
$this->db->where('order.date',"1-1-11");
$query = $this->db->get();
I got Result as,
Pizza------ 10
Burger------10
What I want is,
Pizza-------10
Burger------20
Pepsi-------0
If changing the all the joins to left joins, you can always do it in two separate query and do a union between the two of them. One would get all the lines that actualy have a quantity and the other would get the rests and put them toguether.
It would look a bit like this. there might be some synthax error, but you'll have to rewrite it in php anyway:
p.s. to add up the quantities, you can use sum()
Select itemmaster.name, orderdetails.quantity from itemmaster
left join orderdetails on orderdetails.itemid = itemmaster.id
left join order on order.orderid = orderdetails.orderid
where order.date = '1-1-11'
group by itemmaster.name
Union
Select itemmaster.name, '0' as quantity From itemmaster
except (Select itemmaster.name, orderdetails.quantity from itemmaster
left join orderdetails on orderdetails.itemid = itemmaster.id
left join order on order.orderid = orderdetails.orderid
where order.date = '1-1-11'
group by itemmaster.name)
group by itemmaster.name
hope this helps ! good luck
I having two tables
table 1: users
| id | username |
| 1 | john |
| 2 | marry |
| 3 | deep |
| 4 | query |
| 5 | value|
and
table 2:users_2
| table_2_id | user_id |
| 1 | 2,4 |
I need required something like this
| table_2_id | username |
| 1 | marry,query |
anyone can help me for this output in mysql
Is this what you are looking ?
select
`users_2`.`table_2_id` , GROUP_CONCAT(`users`.`username`) as `usernames`
from `users_2`
inner join `users` on FIND_IN_SET(`users`.`id`,`users_2`.`user_id`)
Check output here
http://sqlfiddle.com/#!2/c498bc/3
select a.table_2_id,b.username
from users b,users_2 a
where a.table_2_id=b.id
and b.id in(a.user_id)
group by a.table_2_id
First of all, you should not store a multiple value in a single field. For table users_2, the data should be:
table_2_id user_id
1 2
1 4
After you normalized your table, you can use mysql GROUP_CONCAT() to get the result in the format you mentioned
SELECT
users_2.table_2_id,
GROUP_CONCAT(users.username) AS username
FROM
users_2
JOIN
users ON users.id = users_2.user_id
GROUP BY
users_2.table_2_id
;
I have two tables : ticket & history_ticket
Table ticket :
ticket_id | ticket_desc
1 | software
2 | hardware
3 | other
Table history_ticket :
history_id | ticket_id | message | status
1 | 1 | text | process
2 | 2 | text | solve
3 | 3 | text | process
4 | 3 | text | solve
I want result like this
ticket_id | ticket_desc | status
1 | software | process
2 | hardware | solve
3 | other | solve
I've tried various joins and subselects, but no luck
Any help/directions will be much appreciated!
UPDATE : How if i change the result, like this
ticket_id | ticket_desc | last_status | count_message
1 | software | process | 1
2 | hardware | solve | 1
3 | other | solve | 2
Try this:
SELECT
t.ticket_id,
ticket_desc,
ht.status
FROM ticket AS t
INNER JOIN history_ticket AS ht ON t.ticket_id = ht.ticket_id
INNER JOIN
(
SELECT ticket_id, MAX(history_id) maxid
FROM history_ticket
GROUP BY ticket_id
) AS ht2 ON ht.history_id = ht2.maxid;
SQL Fiddle Demo
This will give you:
| TICKET_ID | TICKET_DESC | STATUS |
-------------------------------------
| 1 | software | process |
| 2 | hardware | solve |
| 3 | Problem | solve |
UPDATE 1
To get the count of messages for each ticket, you can simply include COUNT(history_id) AS sum_message in the subquery like this:
SELECT
t.ticket_id,
ticket_desc,
ht.status,
ht2.sum_message
FROM ticket AS t
INNER JOIN history_ticket ht ON t.ticket_id = ht.ticket_id
INNER JOIN
(
SELECT
ticket_id,
MAX(history_id) maxid,
COUNT(history_id) AS sum_message
FROM history_ticket
GROUP BY ticket_id
) AS ht2 ON ht.history_id = ht2.maxid;
Updated SQL Fiddle Demo
This will give you:
| TICKET_ID | TICKET_DESC | STATUS | SUM_MESSAGE |
---------------------------------------------------
| 1 | software | process | 1 |
| 2 | hardware | solve | 1 |
| 3 | Problem | solve | 2 |
Update 2
If you want to select names for the ids divisi_id, for simple values, you can use the CASE expression for this:
SELECT
t.ticket_id,
ticket_desc,
CASE
WHEN t.divisi_id = 101 THEN 'Divisi A'
WHEN t.divisi_id = 102 THEN 'Divisi B'
END AS 'Divisi',
ht.status,
ht2.sum_message
FROM ticket AS t
INNER JOIN history_ticket ht ON t.ticket_id = ht.hticket_id
INNER JOIN
(
SELECT hticket_id, MAX(history_id) maxid, COUNT(history_id) AS sum_message
FROM history_ticket
GROUP BY hticket_id
) AS ht2 ON ht.history_id = ht2.maxid;
Updated SQL Fiddle Demo
This will give you:
| TICKET_ID | TICKET_DESC | DIVISI | STATUS | SUM_MESSAGE |
--------------------------------------------------------------
| 1 | software | Divisi A | process | 1 |
| 2 | hardware | Divisi B | solve | 1 |
| 3 | Problem | Divisi A | solve | 2 |
For multiple values, you can put them in a temp table, or you can select them in a subquery and join the table to get the name like this:
SELECT
t.ticket_id,
ticket_desc,
d.Divisi,
ht.status,
ht2.sum_message
FROM ticket AS t
INNER JOIN history_ticket ht ON t.ticket_id = ht.hticket_id
INNER JOIN
(
SELECT hticket_id, MAX(history_id) maxid, COUNT(history_id) AS sum_message
FROM history_ticket
GROUP BY hticket_id
) AS ht2 ON ht.history_id = ht2.maxid
INNER JOIN
(
SELECT 101 AS divisi_id, 'Divisi A' AS Divisi
UNION ALL
SELECT 102 , 'Divisi B'
... -- here you put other values or you can join a temp table instead
) AS D ON t.divisi_id = D.divisi_id;
Updated SQL Fiddle Demo
select distinct ticket.ticket_id, ticket.ticket_desc, history_ticket.status
from ticket
join history_ticket on ticket_id
This, as far as I remember, will choose a description and status at random if you have more than one. If you want to apply a specific rule to which one to pick, give more info and we can help you on that.
Try
SELECT DISTINCT
tk.ticket_id,
tk.ticket_desc,
ht.status
FROM ticket tk JOIN history_ticket ht ON tk.ticket_id = tk.ticket_id
ORDER BY tk.ticket_id
Try,
Select distinct t.ticket_id, t.ticket_desc, h.status
from ticket t, history_ticket h
where t.ticket_id = h.ticket_id
order by t.ticket_id
I will try to be as explanatory as possible regarding my question. I am using MYSQL/PHP to fetch data from two tables with the structure looking like the following:
table A
+---------+------------+
| userid | username |
+---------+------------+
| 1 | john |
| 2 | doe |
| 3 | lewis |
+---------+------------+
table B
+---------+------------+-----------+
| id |from_userid | to_userid |
+---------+------------+-----------+
| 1 | 1 | 3 |
| 2 | 3 | 2 |
| 3 | 1 | 2 |
| 4 | 2 | 1 |
+---------+------------+-----------+
Am trying to achieve the following:
+---------+------------+----------------------+
| id |sender username| receiver username |
+---------+------------+----------------------+
| 1 | john | lewis |
| 2 | lewis | doe |
| 3 | john | doe |
| 4 | doe | john |
+---------+------------+----------------------+
As you can see, instead of returning the sender or receiver user id, I am returning their username according to Table A.
can I use left or right joins in this scenario? Thanks in advance
Try this
SELECT b.id, sender.username AS sender_username, receiver.username AS receiver_username
FROM tableB AS b
JOIN tableA AS sender ON b.from_userid = sender.userid
JOIN tableA AS receiver ON b.to_userid = receiver.userid
Inner joins would work fine, you just need to do two of them...
Left and right joins are only needed when you want to get all records from one table and some from another table. In this case you have two distinct relationships thus the need for two joins. My MySQL skills are a bit rusty so I don't know if ' or [ are used as separators on the table/field names with spaces.
Select t1.ID, T1.userName as 'Sender userName', T2.username as 'Receiver username'
FROM [Table A] A
INNER JOIN [Table B] T1
on T1.from_userid = A.userID
INNER JOIN [Table B] T2
on T2.to_userid = A.userID