Looking for a simple way (Function/RegEx) to validate a number with grouped thousands.
Example Numbers:
.00 - 999.00 should validate
1,000.00 should validate
100,000.00 etc... should validate
100,000,000,000,000.00 should validate
Now I've seen the number_format(), but this formats the number not validates.
I wanted to use a RegEx but lost on how to do so.
preg_match(/^[\d]\,?\.[\d]{2}$/, $number);
but this doesn't work.
I've also looked at the money_format() but again this is format and not validation.
^(?:\d{1,3}(?:,\d{3})*)?\.\d{2}$
Just off the top of my head:
preg_match('%^[\d,]*\.\d{2}$%', $number);
This will match all of the numbers you mentioned (in fact: every string which starts with a combination of digits and commas and ends on "." and to digits).
Again, this is untested but should work.
If you've got a PHP5.3+ you could try the Intl number formatter:
http://www.php.net/manual/en/numberformatter.parse.php
Related
Is there a function or a easy way to strip down phone numbers to a specific format?
Input can be a number (mobile, different country codes)
maybe
+4917112345678
+49171/12345678
0049171 12345678
or maybe from another country
004312345678
+44...
Im doing a
$mobile_new = preg_replace("/[^0-9]/","",$mobile);
to kill everything else than a number, because i need it in the format 49171 (without + or 00 at the beginning), but i need to handle if a 00 is inserted first or maybe someone uses +49(0)171 or or inputs a 0171 (needs to be 49171.
so the first numbers ALWAYS need to be countryside without +/00 and without any (0) between.
can someone give me an advice on how to solve this?
You can use
(?:^(?:00|\+|\+\d{2}))|\/|\s|\(\d\)
to match most of your cases and simply replace them with nothing. For example:
$mobile = "+4917112345678";
$mobile_new = preg_replace("/(?:^(?:00|\+|\+\d{2}))|\/|\s|\(\d\)/","",$mobile);
echo $mobile_new;
//output: 4917112345678
regex101 Demo
Explanation:
I'm making use of OR here, matching each of your cases one by one:
(?:^(?:00|\+|\+\d{2})) matches 00, + or + followed by two numbers at the beginning of your string
\/ matches a / anywhere in the string
\s matches a whitspace anywhere in the string (it matches the newline in the regex101 demo, but I suppose you match each number on its own)
\(\d\) matches a number enclosed in brackets anywhere in the string
The only case not covered by this regex is the input format 01712345678, as you can only take a guess what the country specific prefix can be. If you want it to be 49 by default, then simply replace each input starting with a single 0 with the 49:
$mobile = "01712345678";
$mobile_new = preg_replace("/^0/","49",$mobile);
echo $mobile_new;
//output: 491712345678
This pattern (49)\(?([0-9]{3})[\)\s\/]?([0-9]{8}) will split number in three groups:
49 - country code
3 digits - area code
8 digits - number
After match you can construct clean number just concatnating them by \1\2\3.
Demo: https://regex101.com/r/tE5iY3/1
If this not suits you then please explain more precisely what you want with test input and expected output.
I recommend taking a look at LibPhoneNumber by Google and its port for PHP.
It has support for many formats and countries and is well-maintained. Better not to figure this out yourself.
https://github.com/giggsey/libphonenumber-for-php
$phoneUtil = \libphonenumber\PhoneNumberUtil::getInstance();
$usNumberProto = $phoneUtil->parse("+1 650 253 0000", "US");
there have a long articles, I want only remove thousand separator, not a comma.
$str = "Last month's income is 1,022 yuan, not too bad.";
//=>Last month's income is 1022 yuan, not too bad.
preg_replace('#(\d)\,(\d)#i','???',$str);
How to write the regex patterns? Thanks
If the simplified rule "Match any comma that lies directly between digits" is good enough for you, then
preg_replace('/(?<=\d),(?=\d)/','',$str);
should do.
You could improve it by making sure that exactly three digits follow:
preg_replace('/(?<=\d),(?=\d{3}\b)/','',$str);
If you have a look at the preg_replace documentation you can see that you can write captures back in the replacement string using $n:
preg_replace('#(\d),(\d)#','$1$2',$str);
Note that there is no need to escape the comma, or to use i (as there are not letters in the pattern).
An alternative (and probably more efficient) way is to use lookarounds. These are not included in the match, so they don't have to written back:
preg_replace('#(?<=\d),(?=\d)#','',$str);
The first (\d) is represented by $1, the second (\d) by $2. Therefore the solution is to use something like this:
preg_replace('#(\d)\,(\d)#','$1$2',$str);
Actually it would be better to have 3 numbers behind the comma to avoid causing havoc in lists of numbers:
preg_replace('#(\d)\,(\d{3})#','$1$2',$str);
$st1='dsdsdsd 97537 sdsdd dsddd';
$st2='fdsf 23e sdsd 434 432443454';
$st3='fdf97537 ds344dsddd';
I want to check whether a 5 digit number is available in a string.
st1-- has 5 digit number
st2--- not
st3-- has 5 digit number
A simple regex will do the job.
preg_match('/\d{5}/', $input)
See also http://www.php.net/preg_match
Try this regular expression with preg_match() or preg_match_all()
preg_match("/\b[^\d]*\d{5}[^\d]*\b/", $str);
Let's assume that each element to be checked if this is five digits number is separated by space in string. Therefore you may use explode function to convert string into array of substrings. next you can use is_numeric function to check if that is digit along with check if that sub string is five length long. Also you may use regular expression for that.
Here RegEx is far more better. As I see the #Matt's answer meets these requirements, my comments will be unnecessary.
Ok say I have my phone numbers stored in my table as:
"0008675309"
I obviously wouldn't want to display it just like that, I'd want to format it when I call it as:
(000)867-5309
Would it be better to store it in the database with a delimiter such as / - or . So that I can split it later? Or is it possible to split it by the number of characters?
The performance cost and code to process a phone number in any of those formats is simple, so it's really up to your preference. To answer your question, it is very easy to grab the first three characters, the next three, and the last four using for example, substr function.
Here is a one liner that does what you want:
$phone = preg_replace('^(\d{3})(\d{3})(\d{4})$', '($1)$2-$3', $phone);
As a added bonus it won't change the format if the input format doesn't match (international numbers).
If you are only storing North American phone numbers (10 digits), then as #mellamokb noted, you're ok either way. If you may be storing international numbers, you should capture as much detail as you can early on (if possible) since it might be hard to know how to punctuate the number later on.
use preg_split with PREG_SPLIT_NO_EMPTY
The other answers are perfectly correct. In case you wanted the actual code for it, I think the following should do the trick (the indexes may be off by one oops!):
$phone_number="0008675309"
$phone_number=substr_replace($phone_number, "(", 0, 0);
$phone_number=substr_replace($phone_number, ")", 4, 0);
$phone_number=substr_replace($phone_number, "-", 8, 0);
How can you match the following words by PHP, either by regex/globbing/...?
Examples
INNO, heppeh, isi, pekkep, dadad, mum
My attempt would be to make a regex which has 3 parts:
1st match match [a-zA-Z]*
[a-zA-Z]?
rotation of the 1st match // Problem here!
The part 3 is the problem, since I do not know how to rotate the match.
This suggests me that regex is not the best solution here, since it is too very inefficient for long words.
I think regex are a bad solution. I'd do something with the condition like: ($word == strrev($word)).
Regexs are not suitable for finding palindromes of an arbitrary length.
However, if you are trying to find all of the palindromes in a large set of text, you could use regex to find a list of things that might be palindromes, and then filter that list to find the words that actually are palindromes.
For example, you can use a regex to find all words such that the first X characters are the reverse of the last X characters (from some small fixed value of X, like 2 or 3), and then run a secondary filter against all the matches to see if the whole word is in fact a palindrome.
In PHP once you get the string you want to check (by regex or split or whatever) you can just:
if ($string == strrev($string)) // it's a palindrome!
i think this regexp can work
$re = '~([a-z])(.?|(?R))\1~';