Android mysql php problem - php

Question

I have an application which gets some data from a remote database.
I use PHP with the following code to connect to the data base.
mysql_connect($host,$username,$password) or die( "no connection");
#mysql_select_db($database) or die( "Unable to select database");
$query = $_REQUEST['query'];
$q=mysql_query($query);
while($e=mysql_fetch_assoc($q)) {
$output[]=$e;
}
print(json_encode($output));
mysql_close();
I then connect via following java code
public void connect(ArrayList<NameValuePair> nameValuePairs) {
result = "";
InputStream is = null;
String url = "http://'ipadress'/PhpProject1/EmptyPHP.php";
//Get the content
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (Exception e) {
Log.e("Connect", "Error in http connection " + e.toString());
}
//Convert content toString
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is, HTTP.UTF_8), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result = sb.toString();
//result = replaceString(sb.toString());
} catch (Exception e) {
Log.e("Connect", "Error converting result " + e.toString());
}
}
When i have done that I make a query through
public void query(String query){
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("query", query));
connect(nameValuePairs);
}
While this works great with the emulator there is a problem when using it on the phone.
Anyone has a clue why this is?
Thank you in advance

Answer 1

Make sure to connect your real device to the your private network to actually be able to access that server.
Easiest option would be a WiFi network in the same subnet as the server. Otherwise your phone won't be able to access the network as it is not public.