MySQL get all affected rows for multiple statements in one query - php

MySQL/PHP:
For a query with multiple statements, which deletes rows in four different tables, I want to know the combined number of affected rows. The PHP manual says I'll only get the result from the last 'operation', which suggests it will only tell me how many rows were affected by the last of the DELETE statements.
How to get around this?
$deleteContactSQL = "DELETE FROM `persons` WHERE `persons`.`id` = '$person' AND `owner = '$user' AND `userOrContact` = 'contact';
DELETE FROM `tabs` WHERE `person` = '$person' AND `ownerIdentity` = '$user' AND `selfOrOther` = 'other';
DELETE FROM `tabAccess` WHERE `person`= '$person' AND `givenToIdentity` = '$user';
DELETE FROM `personAccess` WHERE `viewedPerson` = '$person' AND `viewerIdentity` = '$user';
;";
include $_SERVER['DOCUMENT_ROOT'].'/goalview/includes/db.inc.php';
$deleteContacts = mysqli_query($link, $deleteContactSQL);
$success = mysqli_affected_rows($link);

Something like this maybe?
include $_SERVER['DOCUMENT_ROOT'] . '/goalview/includes/db.inc.php';
$sql = array();
$sql[] = "DELETE FROM `persons` WHERE `persons`.`id` = '$person' AND `owner = '$user' AND `userOrContact` = 'contact';"
$sql[] = "DELETE FROM `tabs` WHERE `person` = '$person' AND `ownerIdentity` = '$user' AND `selfOrOther` = 'other';"
$sql[] = "DELETE FROM `tabAccess` WHERE `person`= '$person' AND `givenToIdentity` = '$user';"
$sql[] = "DELETE FROM `personAccess` WHERE `viewedPerson` = '$person' AND `viewerIdentity` = '$user';"
$aff_rows = 0;
foreach($sql as $current_sql)
{
$deleteContacts = mysqli_query($link, $current_sql);
$aff_rows = $aff_rows + mysqli_affected_rows($link);
}

Here is a compact, procedural-style mysqli_multi_query() solution for counting combined affected rows:
$deleteContactSQL="DELETE FROM `persons` WHERE `id`='$person' AND `owner='$user' AND `userOrContact`='contact';
DELETE FROM `tabs` WHERE `person`='$person' AND `ownerIdentity`='$user' AND `selfOrOther`='other';
DELETE FROM `tabAccess` WHERE `person`='$person' AND `givenToIdentity`='$user';
DELETE FROM `personAccess` WHERE `viewedPerson`='$person' AND `viewerIdentity`='$user';";
include $_SERVER['DOCUMENT_ROOT'].'/goalview/includes/db.inc.php';
if(mysqli_multi_query($link,$deleteContactSQL)){
do{
$success+=mysqli_affected_rows($link);
}while(mysqli_more_results($link) && mysqli_next_result($link));
}
Alternatively, this group of queries may be a good candidate for some TRIGGERs in the persons table.

I'd be doing it like this, but, I do like to keep things simple which not everyone can appreciate ;)
$deleteContactSQL = sprintf("call cascade_delete_persons(%d,%d)", $person, $user);
$deleteContacts = mysqli_query($link, $deleteContactSQL);
drop procedure if exists cascade_delete_persons;
delimiter #
create procedure cascade_delete_persons
(
in p_pid int unsigned,
in p_oid int unsigned
)
begin
declare v_persons_count int unsigned default 0;
declare v_tabs_count int unsigned default 0;
delete from persons where id = p_pid and owner = p_oid and userOrContact = 'contact';
set v_persons_count = row_count();
delete from tabs where person = p_pid and ownerIdentity = p_oid and selfOrOther = 'other';
set v_tabs_count = row_count();
-- etc...
select v_persons_count as person_count, v_tabs_count as tabs_count;
end #
delimiter ;
You can use this method too if you must : http://php.net/manual/en/mysqli.multi-query.php

Related

PHP MySQL Query with NOT LIKE specific id

I have 2 tables. The first one is messages and the second is room. msg_id from messages table is the same as id from room table. What I'm doing is selecting all msg_id and for each of them I wanna run a query that deletes all rooms that their ids dont match with msg_id:
My code:
$result = mysql_query("SELECT `msg_id` FROM `messages`");
while($row = mysql_fetch_array( $result )) {
$me = $row[0]; //$me as a string
$int = (int)$me;//transform $me's value to int
$result2 = mysql_query("DELETE FROM `room` WHERE `id` NOT LIKE '%" . $int . "%'");}
The $result2 query will delete all entries from room table, no matter the value of $int variable. That means that the check is not working. If I change the $result2 to this i.e.:
$result2 = mysql_query("DELETE FROM `room` WHERE `id` NOT LIKE '%86%'");
all entries will be Deleted except the room entry with id = 86 (it works fine)
The basic plan is that I must keep all room entries that match their id with msg_id .
DELETE FROM `room` WHERE `id` NOT IN (SELECT `msg_id` FROM `messages`)
if you can't use subquery you can try:
$result = mysql_query("SELECT `msg_id` FROM `messages`");
$ids = [];
while($row = mysql_fetch_array($result)) {
$ids[] = (int) $row[0];
}
$result2 = mysql_query("DELETE FROM `room` WHERE `id` NOT IN (" . implode(',', $ids) . "));
and PLS don't USE mysql_query it is DEPRECATED
Could you use a subquery?
DELETE FROM ROOM WHERE id not in(SELECT msg_id FROM messages);
Try this query,
delete from 'room' where 'id' not in(select 'msg_id' from 'messages');
if it don't work for you, you can try NOT EQUAL TO query
delete from 'room' where 'id' <>(select 'msg_id' from 'messages');

Issue On Updating a Temporary Table Using SQL Select Statement

Can you please take a look at this code and let me know why I am not able to UPDATE a temporary table on $query3
$query = "CREATE TEMPORARY TABLE IF NOT EXISTS `charts_ecolo_yes` (
SET `econo_sum_projects` = (SELECT COUNT(`project`) FROM `ecolo-cu-yes` WHERE c_1000=1 ),
SET `econo_sum_powerline` = (SELECT SUM(`powerline_length`) FROM `ecolo-cu-yes` WHERE c_1000=1 ),
SET `econo_sum_roads` = (SELECT SUM(`road_length`) FROM `ecolo-cu-yes` WHERE c_1000=1 ),
SET `econo_sum_cost` = (SELECT SUM(`cost_per_year`) FROM `ecolo-cu-yes` WHERE c_1000=1 ),
SET `econo_sum_penstlock` = (SELECT SUM(`penstlock` FROM `ecolo-cu-yes` WHERE c_1000=1 )
";
$con->query($query3);
$query4 = "SELECT * FROM `charts_ecolo_yes`" ;
$results = $con->query($query4);
if ($results) {
$row = $results->fetch_array(MYSQLI_NUM);
$row = array_map('floatval', $row); // Convert strings to numbers
echo json_encode($row);
}
Here is the sample result page, which you can see even after running the $con->query($query3); I am still getting default values(100) at last 5th columns.
Thanks
Your UPDATE query syntax is wrong, you don't need SET for all column. It should be
$query3= " UPDATE `charts_ecolo_yes`
SET `econo_sum_projects` = some_value,
`econo_sum_powerline` = some_other_value,

Solve with only one query?

I have the following table:
CREATE TABLE list(
country TINYINT UNSIGNED NOT NULL,
name VARCHAR(10) CHARACTER SET latin1 NOT NULL,
name_index INT UNSIGNED NOT NULL,
UNIQUE KEY(country, name), PRIMARY KEY(country, name_index)) ENGINE = INNODB
I want to:
Given: ($country, $name, $new_index)
Check if a row with country = $country && name = $name exists.
If the row exists, get the index $index = name_index.
If the row doesn't exist, add it and then get the index.
I can do the following using many queries, but I am looking for an efficient way to do it, using only one query. Is this possible?
It's not possible with only one query.
You CAN do this:
$sql = "SELECT name_index FROM (your table) WHERE country = '$country' AND
name = '$name' LIMIT 1";
$query = mysql_query($sql);
$numrows = mysql_num_rows($query);
if($numrows == 1) {
$row = mysql_fetch_row($query);
$index = $row[0];
} else {
$sql = "INSERT INTO (your table) (country, name)
VALUES('$country','$name')";
$query = mysql_query($sql);
$check = mysql_num_rows($query);
if($check > 0) {
$sql = "SELECT name_index FROM (your table) WHERE country = '$country' AND
name = '$name' LIMIT 1";
$query = mysql_query($sql);
$row = mysql_fetch_row($query);
$index = $row[0];
} else {
echo "Error occured while trying to insert new row";
}
}
Hope this helps :).

MySQL Update 2 tables using 2 mysql_query() in single php script

for(some loop condition):
mysql_query("UPDATE `details` SET
`url_battlelog` = '".$stats[$out]['url_battlelog']."',
`url_bf3stats` = '".$stats[$out]['url_bf3stats']."',
`rank_img_medium` = '".$stats[$out]['rank_img_medium']."',
`country_name` = '".$stats[$out]['country_name']."',
`country` = '".$stats[$out]['country']."',
`country_flag` = '".$stats[$out]['country_flag']."',
`rank_number` = '".$stats[$out]['rank_number']."',
`score_total` = '".$stats[$out]['score_total']."',
`time_total` = '".$stats[$out]['time_total']."',
`dogtag_basic_img` = '".$stats[$out]['dogtag_basic_img']."',
`dogtag_basic` = '".$stats[$out]['dogtag_basic']."',
`dogtag_advance_img` = '".$stats[$out]['dogtag_advance_img']."',
`dogtag_advance` = '".$stats[$out]['dogtag_advance']."'
WHERE `name_player` = '".$stats[$out]['name_player']."'
")
or die(mysql_error());
for(2nd loop condition):
mysql_query("UPDATE `weapons` SET
`img` = '".$gun_img."',
`name` = '".$gun_name."',
`kit` = '".$gun_kit."',
`time` = '".$gun_time."',
`kills` = '".$gun_kills."',
`headshots` = '".$gun_hs."',
`shots` = '".$gun_shots."',
`hits` = '".$gun_hits."',
`star_total` = '".$gun_star_c."',
`star_img` = '".$gun_star_i."',
`star_need` = '".$gun_star_n."',
`rank_curr` = '".$gun_rank_c."',
`rank_all` = '".$gun_rank_w."',
`desc` = '".$gun_desc."',
`category` = '".$gun_cat."',
`range` = '".$gun_range."',
`fire_rate` = '".$gun_fire_rate."',
`ammo` = '".$gun_ammo."',
`auto_fire` = '".$gun_fire_auto."',
`burst_fire` = '".$gun_fire_burst."',
`single_fire` = '".$gun_fire_single."',
`unlock_total` = '".$unlock_total."',
`unlock_done` = '".$unlock_done."',
`unlock_p` = '".round($unlock_p)."'
WHERE `name_player` = '".$stats[$out]['name_player']."'
")
or die(mysql_error());
the problem is that only 2nd table (weapons) is updating, 1st table (details) is not showing any changes. Doesn't show any error.
I have same type of script for inserting data into both tables and its working fine.
I'm new to MySQL and PHP. sorry for bad English....
did you test by writing your SQL ? I think your [WHERE] condition is not fully filled

Mysql Multiple PHP Queries, Skipped

If i'm doing multiple mysql queries on the same table, occasionally some get skipped.
Why is that?
For example:
<?php
mysql_query("UPDATE `tb` SET `field` = '' WHERE `Id` = '$something'");
mysql_query("UPDATE `tb` SET `field2` = '' WHERE `Id` = '$something'");
mysql_query("UPDATE `tb` SET `field3` = '0' WHERE `Id` = '$something'");
?>
Sometimes one of the queries will not be executed?
Why is that?
-Or is it something wrong with my server not general mysql?
(Obviously I know now to update the same table in the same query, but before that I was very confused as to why it happens, can anyone please explain?)
Thanks!
You do not need to make 3 queries, if you are updating the same rows:
$q = "
UPDATE table
SET field = '',
field2 = '',
field3 = 0
WHERE Id = :id
";
$statement = $pdo->prepare( $q );
$statement->bindParam(':id', $something, PDO::PARAM_INT);
$statement->execute();
Also, you should stop using the ancient mysql_* functions. They are not maintained anymore and process for deprecation has already begun.
Maybe you should avoid the 10+ year old API and learn something for this decade: PDO Tutorial for MySQL Developers.
debug your code to see if a query fails:
$result = mysql_query("UPDATE `tb` SET `field` = '' WHERE `Id` = '$something'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
$result = mysql_query("UPDATE `tb` SET `field2` = '' WHERE `Id` = '$something'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
$result = mysql_query("UPDATE `tb` SET `field3` = '0' WHERE `Id` = '$something'");
if (!$result) {
die('Invalid query: ' . mysql_error());
}
Use the following to debug the code:
mysql_query("UPDATE `tb` SET `field` = '' WHERE `Id` = '$something'") or die(mysql_error());
mysql_query("UPDATE `tb` SET `field2` = '' WHERE `Id` = '$something'") or die(mysql_error());
mysql_query("UPDATE `tb` SET `field3` = '0' WHERE `Id` = '$something'") or die(mysql_error());
UPDATE
Make sure you are escaping $something using:
$something = mysql_real_escape_string($something);

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