I have a function which checks my database to see if a date exists, if it does exist, i want to display the next date which isnt in the database.
Is this possible?
My function returns 1 if there is a date in the database and 0 if there isnt, im using codeigniter, but not using any built in functions.
Its basically an availability checker, it allows us to input many different dates in the database, so calling my function i use
$availcheck = $ci->availability->check_availability_by_date(date('d/m/Y'));
The i use a if statement to check if the first time it runs it returns a value, this is how i have it
if($availcheck > 0){
// loop through the next dates and run the function again to see if it returns 0
} else {
echo 'available now';
}
I guess i would add 1 to the current date, check that one, then add another 1 and check that and so on.
Im just not sure how.
Cheers,
if i understand you correct , your problem is adding the day ?
if so i would suggest using the epoch or unix time
so convert the date to unix time using mktime than just add 1 day in seconds (24*60*60)
and then convert back to d/m/y format.
you can use the date function.
$date = time(); // get current timestamp
while ($availcheck) // while date IS found in database
{
$availcheck = $ci->availability->check_availability_by_date(date('d/m/Y',$date));
$date = $date + (24*60*60); // add one day
}
$date = $date - (24*60*60); // reduce one day
echo date('d/m/Y',$date); // prints the first date that is not in the DB
This SQL code could work for me.
$today = date("Y-m-d"); //today
$sql = "SELECT date FROM calendar WHERE date>'{$today}' AND date<='2100-12-31' AND date='0000-00-00' LIMIT 1";
Since you can't determine the ending date, 2100 could be for testing.
Related
I'm suck on the logic for this, my goal is to execute if an item is with in a given date range.
I get yesterday's date and the date from 8 days ago with Carbon like so:
$dt = \Carbon\Carbon::yesterday();
$dtB = \Carbon\Carbon::yesterday()->subDays(8);
$today = $dt->toDateString();
$todayBack = $dtB->toDateString();
I then need to execute this if statement to find if the item in the database fits with in these time frames.
if($orderSet->item_clicked == 'printing' && $orderSet->completed_date == $today) {
// run some stuff here
}
Currently I can execute if it's today but I would like do in between these two days. In example. 09-20-19 - 10-09-19 in between these two dates. Just as an example.
Carbon has a between() method. Use the original carbonized dates instead of the date strings.
$dtCompleted = \Carbon\Carbon::parse($orderSet->completed_date);
if (if($orderSet->item_clicked == 'printing' && $dtCompleted->between($dtB, $dt)) {
// run some stuff
}
See the documentation of Comparison
I am trying to compare to date to figure out how much time is between them, which I know how to do, date_diff(), but I want to then compare the time between the dates and if it is greater than 7 days do something and if not do something else. I think it sounds easy and I know there are probably fairly simple solutions to do so but I am just not a fan of dates and comparisons. Here is a snippet of what I got so far as it is just one case of a switch statement so the rest are basically identical.
$array = array();
$today = date("Y-m-d"); // get today's date
foreach($arrayOfObjs as $obj){
if ($obj->get("renewalDate") >= $today){
array_push($array, $obj->get("renewalDate"));
}else{
switch($obj->get("recurrencePeriod")){
case 1:
/*
* All cases follow same structure
* Build the date in format Y-m-d from renewalDate out of the obj.
* Loop through the date while it's less than today.
* After date is greater than today return date add to array
*/
$date = DateTime::createFromFormat("Y-m-d", $obj->get('renewalDate'));
while($date <= $today){
$date->add(new DateInterval('P7D'));
}
$diff = date_diff($today, $date);
if($diff->format('%a') <= 7){
$obj->renewalDate($date);
array_push($array, $obj);
}
break;
Basically, my database stores dates and those dates could be passed but it could be a reoccurring event. To calculate the next time that event would happen I check if the data in the database is before today's date and if it is then I continue to add the incremental amount (in this case 7 for a weekly reoccurring event) and compare the dates again. After the date that is incremented passes today's date I want to find out if it is within 7 days and if so add it to an array to get returned. I know... since I'm adding 7and it's within 7 days the first reoccurring event will always be within 7 days but that is not the case for monthly events or anything greater.
All cases are broken so I only included this one for simplicity. I can get date_Diff to return something like 7 or 12 or whatever the number may be but how can I check if that number is within the 7 days I want?
Thanks, I will include more information if needed to clarify any misunderstandings.
I'm not entirely sure what you are trying to do, but how about the following if you are just projecting dates forward and backwards and want to know if they are 7 days or more either way:
$today = date("Y-m-d");
$todaytime = strtotime($today);
$testdate = "2017-06-31";
$testtime = strtotime($testdate);
$back7days = strtotime("-7 days",$todaytime);
if($testtime < $back7days)
echo "X"; // do somthing if testdate was more than 7 days ago
$fwd7days = strtotime("+7 days", $todaytime);
if($testtime > $fwd7days)
echo "Y"; // do somthing if testdate is more than 7 days in future
Just make sure that you use less-than or less-than-and-equals comparators etc to handle the boundary conditions you need.
I have a string "date" which can be DD.MM.YYYY or D.M.YYYY (with or without leading zeros), it depends what a user types.
Then I use it in a condition to send another email when the day is today.
if($_POST["date"]== date("d.m.Y")){
$headers.="Bcc: another#mail.cz\r\n";
}
The problem is that the mail is send when the date format DD.MM.YYYY (with leading zeros) only.
My proposed solution
As I'm not very good in PHP, I only know the solution theoretically but not how to write the code - I would spend a week trying to figure it out on my own.
What's in my mind is dividing the date into three parts (day, month, year), then checking the first two parts if there's just one digit and adding leading zeros if it's the case. I don't know how to implement that to the condition above, though. I have read a few topics about how to do this, but they were a bit more different than my case is.
You should equalize to same format d.m.Y and you can do this with strtotime and date function:
$post_date = date("d.m.Y", strtotime($_POST["date"]));
if($post_date == date("d.m.Y")){
$headers.="Bcc: another#mail.cz\r\n";
}
I changed date to $post_date for more clear. I'll try to explain difference with outputs
echo $_POST["date"]; // lets say: 8.7.2013
echo date("d.m.Y"); // 09.09.2013 > it's current day
strtotime($_POST["date"]); // 1373230800 > it's given date with unix time
$post_date = date("d.m.Y", strtotime($_POST["date"])); // 08.07.2013 > it's given date as right format
If you use date function without param, it returns as current date.
Otherwise if you use with param like date('d.m.Y', strtotime('given_date'));, it returns as given date.
$post_date = date("d.m.Y", strtotime($_POST["date"]));
At first, we converted your date string to unix with strtotime then equalized and converted format that you used in if clause.
first set date format with leading Zero
$postdate = strtotime('DD.MM.YY', $_POST['date']);
and also matching date will be in same format
$matching_date = date('DD.MM.YY', strtotime('whatever the date'));
then
if ( $postdate === $matching_date )
{
// send mail
}
Why don't you just check the length of the _POST (it can be either 8 or 10)
if (strlen($_POST["date"]) == 10) {
$headers.="Bcc: another#mail.cz\r\n";
}
Is there a way to convert an input time string (ex: 01:13) to a Zend date object, so that I store it later in a timestamp column in a Mysql database.
Examples:
If the current datetime is 2013-07-15 17:33:07 and the user inputs 18:05 the output should be 2013-07-15 18:05:00.
If the current datetime is 2013-07-15 17:33:07 and the user inputs 02:09 the output should be 2013-07-16 02:09:00. Notice that since the time entered was lower than the current time, so it was treated as tomorrows time.
I simply want to get the next point in time that satisfies the entered time. I'm open for solution using plain PHP or Zend_Date.
I think you should compare the current time with the time entered by the user and create a DateTime object of either "today" or "tomorrow". DateTime accepts strtotime() relative time parameters.
Quick hack. Works as of today, 15.07.2013 23:58 local time:
$nextTime = new DateTime('today 18:10');
if ($nextTime < new DateTime('now')) { // DateTime comparison works since 5.2.2
$nextTime = new DateTime('tomorrow 18:10');
}
echo $nextTime->format('d.m.Y H:i:s');
here is working example for you just add your dynamic variable to check date with user inputs
You can use mktime function to manage your date.
$input_date = date("Y-m-d H:i:s",mktime(18,05,0,date("m"),date("d"),date("Y")));
echo "current time".$current_time = date('Y-m-d H:m:s');
echo "<br>User input is ".$input_date;
if(strtotime($current_time) > strtotime($input_date)){
$input_date = date("Y-m-d H:i:s",mktime(18,05,0,date("m"),date("d")+1,date("Y")));
echo "in";
}else{
// nothing to do
}
echo "<br> result->".$input_date;
i hope it will sure solve your issue
I have a problem where I need to handle dates where the month and day parts are optional. For example, the year will always be known but sometimes the day or month and day will be unknown.
In MySQL I can create a table with a date field and while I can't find any reference in the MySQL Manual it will accept the following as valid:
(YYYY-MM-DD format):
2011-02-10 // Current date
2011-02-00 // Day unknown so replaced with 00
2011-00-00 // Day and month unkown so replaced with 00-00
Test calculations from within the database work fine so I can still sort results easily. In the manual it says that month needs to be between 01 and 12, and day between 01 and 31 - but it does accept 00.
First question: Am I going to run into trouble using 00 in the month or day parts or is this perfectly acceptable?
Next question: Is there a PHP function (or MySQL format command) that will automatically format the following dates into the required format string?
2011 becomes 2011-00-00
2011-02 becomes 2011-02-00
Or do I need write a special function to handle this?
The following doesn't work:
<?php
$date = date_create_from_format('Y-m-d', '2011-00-00');
echo date_format($date, 'Y-m-d');
// Returns 2010-11-30
$date = date_create_from_format('Y-m-d', '2011-02-00');
echo date_format($date, 'Y-m-d');
// Returns 2011-01-31
?>
Third question: Is there a PHP function (or MySQL command) to format the dates for use in PHP?
Finally, is this the best approach? Or is there a 'best practise' method?
EDIT:
Here is what I'm currently doing:
A date field can accept a date in the format YYYY, YYYY-MM, or YYYY-MM-DD and before sending to the database it is processed in this function:
/**
* Takes a date string in the form:
* YYYY or
* YYYY-MM or
* YYYY-MM-DD
* and validates it
*
* Use date_format($date, $format); to reverse.
*
* #param string $phpDate Date format [YYYY | YYYY-MM | YYYY-MM-DD]
*
* #return array 'date' as YYYY-MM-DD, 'format' as ['Y' | 'Y-m' | 'Y-m-d'] or returns false if invalid
*/
function date_php2mysql($phpDate) {
$dateArr = false;
// Pattern match
if (preg_match('%^(?P<year>\d{4})[- _/.]?(?P<month>\d{0,2})[- _/.]?(?P<day>\d{0,2})%im', trim($phpDate), $parts)) {
if (empty($parts['month'])) {
// Only year valid
$date = $parts['year']."-01-01";
$format = "Y";
} elseif (empty($parts['day'])) {
// Year and month valid
$date = $parts['year']."-".$parts['month']."-01";
$format = "Y-m";
} else {
// Year month and day valid
$date = $parts['year']."-".$parts['month']."-".$parts['day'];
$format = "Y-m-d";
}
// Double check that it is a valid date
if (strtotime($date)) {
// Valid date and format
$dateArr = array('date' => $date, 'format' => $format);
}
} else {
// Didn't match
// Maybe it is still a valid date
if (($timestamp = strtotime($phpDate)) !== false) {
$dateArr = array('date' => date('Y-m-d', $timestamp), 'format' => "Y-m-d");
}
}
// Return result
return $dateArr;
}
So it pattern matches the input $phpDate where it must begin with 4 digits, then optionally pairs of digits for the month and the day. These are stored in an array called $parts.
It then checks if months or days exist, specifying the format string and creating the date.
Finally, if everything checks out, it returns a valid date as well as a format string. Otherwise it returns FALSE.
I end up with a valid date format for my database and I have a way of using it again when it comes back out.
Anyone think of a better way to do this?
I have a problem where I need to handle dates where the month and day parts are optional.
For example, the year will always be known but sometimes the day or month and day will be
unknown.
In many occasions, we do need such 'more or less precise' dates, and I use such dates as 2011-04-01 (precise), as well as 2011-04 (= April 2011) and 2011 (year-only date) in archives metadata. As you mention it, MySQL date field tolerates '2011-00-00' though no FAQs tell about it, and it's fine.
But then, I had to interface the MySQL database via ODBC and the date fields
are correctly translated, except the 'tolerated' dates (Ex: '2011-04-00' results empty in the resulting MySQL-ODBC-connected ACCESS database.
For that reason, I came to the conclusion that the MySQL date field could be converted in a plain VARCHAR(10) field : As long as we don't need specific MySQL date functions, it works fine, and of course, we can still use php date functions and your fine date_php2mysql() function.
I would say that the only case when a MySQL date field is needed
is when one needs complex SQL queries, using MySQL date functions in the query itself.
(But such queries would not work anymore on 'more or less precise' dates!...)
Conclusion : For 'more or less precise' dates,
I presently discard MySQL date field and use plain VARCHAR(10) field
with aaaa-mm-jj formated data. Simple is beautiful.
Since the data parts are all optional, would it be tedious to store the month, day, and year portions in separate integer fields? Or in a VARCHAR field? 2011-02-00 is not a valid date, and I wouldnt't think mysql or PHP would be excited about it. Test it out with str_to_time and see what kind of results you get, also, did you verify that the sorting worked right in MySQL? If the docs say that 1 through 31 is required, and it is taking 00, you might be relying on what is, in essence, a bug.
Since 2011-02-00 is not a valid date, none of PHP's formatting functions will give you this result. If it handled it at all, I wouldn't be surprised if you got 2001-01-31 if you tried. All the more reason to either store it as a string in the database, or put the month, day, and year in separate integer fields. If you went with the latter route, you could still do sorting on those columns.
I have also encountered this problem. I ended up using the PEAR Date package. Most date classes won't work with optional months or optional days, but the PEAR Date package does. This also means you don't need custom formatting functions and can use the fancy formatting methods provided by the Date package.
I have found this link in a textbook. This states that month and day values can be zero to allow for the possiblity of storing incomplete or unknown data
http://books.google.co.uk/books?id=s_87mv-Eo4AC&pg=PA145&lpg=PA145&dq=mysql+date+of+death+when+month+unknown&source=bl&ots=tcRGz3UDtg&sig=YkwpkAlDtBP1KKTDtqSyZCl63hs&hl=en&ei=Btf5TbL1NIexhAfkveyTAw&sa=X&oi=book_result&ct=result&resnum=8&ved=0CFMQ6AEwBw#v=onepage&q&f=false
If you pull your date in pieces from the database you can get it as if it's 3 fields.
YEAR(dateField) as Year, MONTH(dateField) as Month, DAY(dateField) as DAY
Then pushing those into the corresponding fields in the next bit of PHP will give you the result you're looking for.
$day = 0;
$month = 0;
$year = 2013;
echo $datestring;
$format = "Y";
if($month)
{
$format .= "-m";
if($day)
$format .="-d";
else
$day = 1;
}
else
{
$month = 1;
$day = 1;
}
$datestring = strval($year)."-".strval($month)."-".strval($day);
$date = date($format, strtotime($datestring));
echo $date; // "2013", if $month = 1, "2013-01", if $day and $month = 1, "2013-01-01"