Two arrays in foreach loop - php

Question

I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.
This is an example:
<?php
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
foreach( $codes as $code and $names as $name ) {
echo '<option value="' . $code . '">' . $name . '</option>';
}
?>
This method didn't work for me. Any suggestions?

Answer 1

foreach( $codes as $code and $names as $name ) { }
That is not valid.
You probably want something like this...
foreach( $codes as $index => $code ) {
echo '<option value="' . $code . '">' . $names[$index] . '</option>';
}
Alternatively, it'd be much easier to make the codes the key of your $names array...
$names = array(
'tn' => 'Tunisia',
'us' => 'United States',
...
);

Answer 2

foreach operates on only one array at a time.
The way your array is structured, you can array_combine() them into an array of key-value pairs then foreach that single array:
foreach (array_combine($codes, $names) as $code => $name) {
echo '<option value="' . $code . '">' . $name . '</option>';
}
Or as seen in the other answers, you can hardcode an associative array instead.

Answer 3

Use array_combine() to fuse the arrays together and iterate over the result.
$countries = array_combine($codes, $names);

Answer 4

array_map seems good for this too
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
array_map(function ($code, $name) {
echo '<option value="' . $code . '">' . $name . '</option>';
}, $codes, $names);
Other benefits are:
If one array is shorter than the other, the callback receive null values to fill in the gap.
You can use more than 2 arrays to iterate through.

Answer 5

Use an associative array:
$code_names = array(
'tn' => 'Tunisia',
'us' => 'United States',
'fr' => 'France');
foreach($code_names as $code => $name) {
//...
}
I believe that using an associative array is the most sensible approach as opposed to using array_combine() because once you have an associative array, you can simply use array_keys() or array_values() to get exactly the same array you had before.

Answer 6

This worked for me:
$codes = array('tn', 'us', 'fr');
$names = array('Tunisia', 'United States', 'France');
foreach($codes as $key => $value) {
echo "Code is: " . $codes[$key] . " - " . "and Name: " . $names[$key] . "<br>";
}

Answer 7

Your code like this is incorrect as foreach only for single array:
<?php
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
foreach( $codes as $code and $names as $name ) {
echo '<option value="' . $code . '">' . $name . '</option>';
}
?>
Alternative, Change to this:
<?php
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
$count = 0;
foreach($codes as $code) {
echo '<option value="' . $code . '">' . $names[count] . '</option>';
$count++;
}
?>

Answer 8

Why not just consolidate into a multi-dimensional associative array? Seems like you are going about this wrong:
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
becomes:
$dropdown = array('tn' => 'Tunisia', 'us' => 'United States', 'fr' => 'France');

Answer 9

You can use array_merge to combine two arrays and then iterate over them.
$array1 = array("foo" => "bar");
$array2 = array("hello" => "world");
$both_arrays = array_merge((array)$array1, (array)$array2);
print_r($both_arrays);

Answer 10

All fully tested
3 ways to create a dynamic dropdown from an array.
This will create a dropdown menu from an array and automatically assign its respective value.
Method #1 (Normal Array)
<?php
$names = array('tn'=>'Tunisia','us'=>'United States','fr'=>'France');
echo '<select name="countries">';
foreach($names AS $let=>$word){
echo '<option value="'.$let.'">'.$word.'</option>';
}
echo '</select>';
?>
Method #2 (Normal Array)
<select name="countries">
<?php
$countries = array('tn'=> "Tunisia", "us"=>'United States',"fr"=>'France');
foreach($countries as $select=>$country_name){
echo '<option value="' . $select . '">' . $country_name . '</option>';
}
?>
</select>
Method #3 (Associative Array)
<?php
$my_array = array(
'tn' => 'Tunisia',
'us' => 'United States',
'fr' => 'France'
);
echo '<select name="countries">';
echo '<option value="none">Select...</option>';
foreach ($my_array as $k => $v) {
echo '<option value="' . $k . '">' . $v . '</option>';
}
echo '</select>';
?>

Answer 11

Walk it out...
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
PHP 5.3+
array_walk($codes, function ($code,$key) use ($names) {
echo '<option value="' . $code . '">' . $names[$key] . '</option>';
});
Before PHP 5.3
array_walk($codes, function ($code,$key,$names){
echo '<option value="' . $code . '">' . $names[$key] . '</option>';
},$names);
or combine
array_walk(array_combine($codes,$names), function ($name,$code){
echo '<option value="' . $code . '">' . $name . '</option>';
})
in select
array_walk(array_combine($codes,$names), function ($name,$code){
#$opts = '<option value="' . $code . '">' . $name . '</option>';
})
echo "<select>$opts</select>";
demo

Answer 12

<?php
$codes = array ('tn','us','fr');
$names = array ('Tunisia','United States','France');
echo '<table>';
foreach(array_keys($codes) as $i) {
echo '<tr><td>';
echo ($i + 1);
echo '</td><td>';
echo $codes[$i];
echo '</td><td>';
echo $names[$i];
echo '</td></tr>';
}
echo '</table>';
?>

Answer 13

foreach only works with a single array. To step through multiple arrays, it's better to use the each() function in a while loop:
while(($code = each($codes)) && ($name = each($names))) {
echo '<option value="' . $code['value'] . '">' . $name['value'] . '</option>';
}
each() returns information about the current key and value of the array and increments the internal pointer by one, or returns false if it has reached the end of the array. This code would not be dependent upon the two arrays having identical keys or having the same sort of elements. The loop terminates when one of the two arrays is finished.

Answer 14

Instead of foreach loop, try this (only when your arrays have same length).
$number = COUNT($_POST["codes "]);//count how many arrays available
if($number > 0)
{
for($i=0; $i<$number; $i++)//loop thru each arrays
{
$codes =$_POST['codes'][$i];
$names =$_POST['names'][$i];
//ur code in here
}
}

Answer 15

array_combine() worked great for me while combining $_POST multiple values from multiple form inputs in an attempt to update products quantities in a shopping cart.

Answer 16

I think that you can do something like:
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
foreach ($codes as $key => $code) {
echo '<option value="' . $code . '">' . $names[$key] . '</option>';
}
It should also work for associative arrays.

Answer 17

I think the simplest way is just to use the for loop this way:
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
for($i = 0; $i < sizeof($codes); $i++){
echo '<option value="' . $codes[$i] . '">' . $names[$i] . '</option>';
}

Answer 18

if(isset($_POST['doors'])=== true){
$doors = $_POST['doors'];
}else{$doors = 0;}
if(isset($_POST['windows'])=== true){
$windows = $_POST['windows'];
}else{$windows = 0;}
foreach($doors as $a => $b){
Now you can use $a for each array....
$doors[$a]
$windows[$a]
....
}

Answer 19

I solved a problem like yours by this way:
foreach(array_keys($idarr) as $i) {
echo "Student ID: ".$idarr[$i]."<br />";
echo "Present: ".$presentarr[$i]."<br />";
echo "Reason: ".$reasonarr[$i]."<br />";
echo "Mark: ".$markarr[$i]."<br />";
}

Answer 20

You should try this for the putting 2 array in singlr foreach loop
Suppose i have 2 Array
1.$item_nm
2.$item_qty
`<?php $i=1; ?>
<table><tr><td>Sr.No</td> <td>item_nm</td> <td>item_qty</td> </tr>
#foreach (array_combine($item_nm, $item_qty) as $item_nm => $item_qty)
<tr>
<td> $i++ </td>
<td> $item_nm </td>
<td> $item_qty </td>
</tr></table>
#endforeach `

Answer 21

Few arrays can also be iterated like this:
foreach($array1 as $key=>$val){ // Loop though one array
$val2 = $array2[$key]; // Get the values from the other arrays
$val3 = $array3[$key];
$result[] = array( //Save result in third array
'id' => $val,
'quant' => $val2,
'name' => $val3,
);
}

Answer 22

This will only work if the both array have same count.I try in laravel, for inserting both array in mysql db
$answer = {"0":"0","1":"1","2":"0","3":"0","4":"1"};
$reason_id = {"0":"17","1":"19","2":"15","3":"19","4":"18"};
$k= (array)json_decode($answer);
$x =(array)json_decode($reason_id);
$number = COUNT(json_decode($reason_id, true));
if($number > 0)
{
for($i=0; $i<$number; $i++)
{
$val = new ModelName();
$val->reason_id = $x[$i];
$val->answer =$k[$i];
$val->save();
}
}

Answer 23

En laravel Livewire
return view('you_name_view', compact('data','data2'));
#foreach ($data as $index => $data )
<li>
<span>{{$data}}</span>
<span>{{$data2[$index]}}</span>
</li>
#endforeach

Answer 24

it works for me
$counter = 0;
foreach($codes as $code)
{
$codes_array[$counter]=$code;
$counter++;
}
$counter = 0;
foreach($names as $name)
{
echo $codes_array[$counter]."and".$name;
$counter++;
}