MySQL returns only one row - php

Question

I have this simple PHP code:
$query = mysql_query("SELECT `title`, `url_title` FROM `fastsearch` WHERE `tags` LIKE '%$q%' LIMIT 5");
$query2 = mysql_fetch_assoc($quer);
print_r($query2);
It only returns this:
Array ( [title] => Kill Bill Vol 1. [url_title] => kill_bill_vol_1 )
I have 3500+ rows in the table, and running the SQL in PhpMyAdmin works perfectly.

Answer 1

$query = mysql_query("SELECT `title`,
`url_title`
FROM `fastsearch`
WHERE `tags`
LIKE '%$q%'
LIMIT 5");
while ($row = mysql_fetch_assoc($query)) {
print_r($row);
}
You misspelled $query in your example
mysql_fetch_assoc() will return a row each time it is called, and FALSE when out of rows. Use that to your advantage, by assigning a variable to it in the condition. Within the while() loop, $row will be the current row.

Answer 2

Right, you are not fetching the results properly.
mysql_fetch_assoc() only returns one row at a time. Use a loop to read all rows.
$query = mysql_query("SELECT `title`, `url_title` FROM `fastsearch` WHERE `tags` LIKE '%$q%' LIMIT 5");
$resultSet = array();
while ($cRecord = mysql_fetch_assoc($query)) {
$resultSet[] = $cRecord;
}

Answer 3

As documentation http://php.net/manual/en/function.mysql-fetch-assoc.php states:
mysql_fetch_assoc — Fetch a result row as an associative array
So if you want to iterate over result you have to use a loop e.g.:
while ($row = mysql_fetch_assoc($result)) {
echo $row["title"];
echo $row["url_title"];
}

Answer 4

mysqli_fetch_assoc() is functions which is fetching multiple records
and displaying through print_r().
$query = "SELECT `title`, `url_title` FROM `fastsearch` WHERE `tags` LIKE '%$q%' LIMIT 5";
$result = mysqli_query($conn,$query);
while(null ! == ($query = mysqli_fetch_assoc($result))){
print_r($query);
}

Answer 5

the method fetch_assoc() returns one row, you need to loop with it