I am making a invoices page and I want the date to appear automatically as an input as well as the date of expiration (30 days later)
is there an automatic function?
I have this:
TD
can value change to something like todaysdate??? or 30 days later??
help! :D
You need to use DateTime::add method.
<?php
$date = new DateTime('2011-01-01');
$date->add(new DateInterval('P30D'));
echo $date->format('Y-m-d') . "\n";
?>
Your question is extremely difficult to decipher.
Perhaps you are looking for PHP's strtotime() function. For example, strtotime('today') returns a timestamp for today's date, and strtotime('next Wednesday') returns a timestamp for next Wednesday.
Related
I am trying to get a simple line of text to appear if todays date is after another date.
I can either get it to appear on all pages or none, but I am unable to get it to display based on whether the challenge start date is before or after todays date. I believe it could be a date format issue, but everything I have tried has fallen short.
Here is my code:
Get todays date
$date_now = new dateTime();
Challenge start date
$challengeStartDate = date('dS F Y', strtotime($this->item->start_date));
echo '<!--' . strtotime('1970/1/1 00:00:00 +' . $validity) . '-->';
New text line
if ($challengeStartDate > $date_now) echo "New Text";
date() returns a string. With $challengeStartDate > $date_now it's like comparing if one string is bigger than the other (not sure if your dateTime handles that).
Your approach is otherwise fine. Just use timestamps to compare. time() gets you the time as a Unix timestamp:
$now = time();
if ($now > strtotime($this->item->start_date)) {
// do your thing
}
Something like this is more what you need. Try it out.
I had the very same problem some time ago.
All you need to do is store your local time in a database so it would be saved statically.
Because in your example, both $challengeStartDate and $date_now will change and update simultaneously and you wiill always get the current pc time!
Try storing it in a table or idk maybe sessions would help too.
I have a problem here I want to get the +4 week date from the current date using carbon, the +4 week plan will be dynamic depending on the input entered by the user, how do I make it, I've tried using this code but it's time to step back
$dt = Carbon::now();
dd($dt->week(4)->format('Y-m-d'));
Check Carbon docs, you may use addWeeks():
$dt = Carbon::now();
dd($dt->addWeeks(4)->format('Y-m-d'));
The week() method you've used, sets the week number using given first day of week and first day of year included in the first week.
I am not sure to understand your question, but I guess you just have to use :
$dt = Carbon::now();
$dt->addWeeks(4);
dd($dt->format('Y-m-d');
You don't need carbon for such simple tasks.
With DateTime
echo date_create('+4 weeks')->format("Y-m-d");
or with date and strtotime
echo date("Y-m-d",strtotime('+4 weeks'));
I am trying to get current time and date in order to echo it out on my website. I have the follow snippet:
$date_of_msg = date("Y-m-d");
$time_of_msg = time();
When I echo $time_of_msg I get 00:00:00. I have tried to edit my code based on this solution here but which this approach, when I echo the variable, I get 838:59:59. I simply want the current time to be displayed in 24 hour format.
In addition to this, I currently have the date formatted to (Y-m-d), which is great because it works. I am trying to format it so that it displays day, number, year, i.e. today is 20th Feb, so I want the date to display Feb 20, 2016. I have tried the following based on documentation (see here)
$date_of_msg = date("F j, Y")
But again, the date displays nothing. Am I missing something?
If you need the current time in the 24h format just use
$time_of_msg = date("H:i");
The date part seems correct that way, you must be doing something wrong while displaying it.
time() (unless you override it in some weird fashion) gives you a timestamp, i.e. the amount of seconds which have passed since 1970-01-01 until now. date(), however, gives you a string representation of a date, which may or may not include the minutes and seconds - depending on how you choose to format it.
So, if you want to display the time and date to a user, you should probably go for something like
$date_of_msg = date("F j, Y H:i:s")
The documentation on date() gives you an excellent description of available options.
time() returns a UNIX timestamp while date() format a timestamp. Your call date("Y-m-d") means the same as date("Y-m-d", time()).
Even though the function is called date(), it can also format time. You just have to use the correct placeholders. E.g. date("H:i:s") would give you a 24h-time like 17:43:23.
This code
<?php
echo date("Y-m-d").PHP_EOL;
echo time().PHP_EOL;
echo date("F j, Y").PHP_EOL;
Returns this result, as expected
2016-02-20
1455927480
February 20, 2016
So what are you doing that you are not actually telling us
I have a static date 28-04-2012,. I want to update the only the month when the date gets to the 28th of the new month. So if the date is 28-05-2012, then 28-06-2012, 28-07-2012 and so on.
I would also like to update the year when I reach 2013. But always keep the date at 28? Can someone advise me how this would be done using js or php?
$current_date = "28-04-2012";
$next_month = strtotime($current_date . "+1month");
echo date('Y-m-d', $next_month);
the most simple trick i guess.
<?php
$date = '28-04-2012';
echo date('j-m-Y', strtotime("1 month", strtotime($date))) . "\n";
?>
See here: http://www.roseindia.net/tutorial/php/phpdate/php-date-add-1-month.html
$todayDate = date("Y-m-d");// current date
echo "Today: ".$todayDate."<br>";
//Add one day to today
$dateOneMonthAdded = strtotime(date("Y-m-d", strtotime($todayDate)) . "+1 month");
echo "After adding one month: ".date('l dS \o\f F Y', $dateOneMonthAdded)."<br>";
People are suggesting strtotime(), but I have to say I have a strong dislike for this function. It isn't designed for date arithmetic, but it was the only option available in older versions of PHP, so everyone uses it for that.
A better solution can be found in the PHP5 DateTime class, and in particular the DateTime::Add method (also known as the date_add() function).
The only reason to use strtotime() instead ofDateTime::Add()is if you're using a version of PHP older than 5.3, since this is when theAdd` method was added. But if that's the case, your first priority should be to upgrade your PHP.
I have been looking online for this answer and have come up empty...I am extremely tired so I thought I would give this a go....
I have a variable that has a date from a textbox
$effectiveDate=$_REQUEST['effectiveDate'];
What I am trying to do is take this date and add the current time
date('Y-m-d H:i:s', strtotime($effectiveDate))
When I echo this out I get 1969-12-31 19:00:00
Is this possible? Can someone point me in the right direction?
I found a solution to my problem....
$currentDate = date("Y-m-d");
$currentTime = date("H:i:s");
$currentDate = date("Y-m-d H:i:s", strtotime($currentDate . $currentTime));
echo $currentDate;
This takes a date from variable in one format and takes the date from another variable in another format and puts them together :)
Thanks everyone for their time.....
DateTime::createFromFormat
would also work but only if you have PHP 5.3 or higher...(I think)
The effectiveDate string is not in a format that strtotime recognizes, so strtotime returns false which is interpreted as 0 which causes the date to be displayed as January 1, 1970 at 00:00:00, minus your time zone offset.
The result you see is caused by the entered date not being in a format recognised by strtotime. The most likely case I can think of without knowing the format you used is that you used the US order of putting the month and day the wrong way around - this confuses strtotime, because if it accepts both then it can't distinguish February 3rd and March 2nd, so it has to reject US-formatted dates.
The most reliable format for strtotime is YYYY-MM-DD HH:ii:ss, as it is unambigous.
The date is just a timestamp, it is not object-oriented and i don't like it.
You can use the DateTime object.
The object-oriented best way is:
$effectiveDate=$_REQUEST['effectiveDate'];
// here you must pass the original format to pass your original string to a DateTimeObject
$dateTimeObject = DateTime::createFromFormat('Y-m-d H:i:s', $effectiveDate);
// here you must pass the desired format
echo $dateTimeObject->format('Y-m-d H:i:s');