I've been going bananas trying to get some data from Javascript on one page to post to a php file asynchronously. I'm not even attempting to do anything with the data, just a var_dump to spit back out from the ajax call. NULL over and over again.
I've checked the JSON with JSONLint and it validates just fine. I'm getting my JSON from JSON.stringify - Firebug tells me I'm getting the following:
{"items":[["sa1074","1060"],["sa1075","1061"]]}
I've tried php://input, as well as json_decode_nice from the PHP manual comments about the function, and I've tried using utf8_encode - is there something wrong with my JSON?
EDIT: Derpity dee probably should have planned this post a bit more haha. Here's my PHP (using a suggestion from PHP manual comments)
function json_decode_nice($json, $assoc = FALSE){
$json = str_replace(array("\n","\r"),"",$json);
$json = preg_replace('/([{,])(\s*)([^"]+?)\s*:/','$1"$3":',$json);
return json_decode($json,$assoc);
}
if (isset($_POST['build'])){
$kit = file_get_contents('php://input');
var_dump(json_decode_nice($kit));
}
And the JS used to create it:
var jsonKit = JSON.stringify(kit);
$.post("kits.php?", {"build" : jsonKit},
function(data) {
$("#kitItems").html(data);
});
Also: Our host is on PHP 5.2 - I found this out when I uploaded a perfectly good redbean class only to have it explode. Had to re-implement with legacy redbean. Our host is busted.
SOLVED: Thanks to all who commented. Didn't think to check $_POST to see what was coming in. Quotes were being escaped with slashes in the $_POST and json_decode was choking on it. Adding this line before decoding solved the problem. Also forgot to set true to return an associative array. Thanks!
$kit = str_replace('\\', '', $kit);
Without seeing code - I'm just guessing here ... are you using a true assoc variable in your json_decode()?
<?php json_decode($jsonString, true); ?>
That had me stumped on a decode for quite some time my first time trying to decode something,
Related
the JSON passes string in the following format:
params{"visitor":"","submitted":"submitted","date":"02/28/2015"}
now the problem,
I am trying to check in in my PHP file the "visitor", "submitted" and "date", but all of it comes empty for some reason. I have also tried the following:
$json = $_POST['params'];
var_dump(json_decode($json));
but the result is NULL
can you please help me a little as I have tried almost everything that I could possibly try but nothing worked so far.
also if I am doing var_dump($_POST['params']); then I get the following:
string(1035) "{\"visitor\":\"\",\"submitted\":\"submitted\",\"date\":\"02/28/2015\"}"
Working on PHP 5.2.17 you must need to use stripslashes() with the $_POST variable like this $post = json_decode(stripslashes($_POST['data']));
Hope it helps
I'm trying to read data from a decompiled application of Android with a php server. I used wireshark to understand what types of data the application sends, and the result is:
{"initType":"first time","parameters":true,"details":................}
I trying to capture this data and insert them in a file with this php code:
<?php
$json = $_POST["initType"];
$decoded = json_decode($json, TRUE);
if ($decoded === FALSE) {
throw new Exception('Bad JSON format.');
}
$file_handle = fopen('tmp.json', 'w');
fwrite($file_handle, $decoded);
fclose($file_handle);
?>
The file is correctly generated but it's empty. What is the error?
Because $decoded is an array, use a loop to write it to file or write the encoded JSON to file ($json). Try using this:
fwrite('tmp.json', print_r($decoded, TRUE));
or:
file_put_contents('tmp.json', print_r($decoded, TRUE));
Update (per your comments):
If you run a print_r($decoded) and it prints nothing, there is a problem with the decoding process of the JSON object passed in. I would recommend checking this to make sure it is formatted correctly. JSON formatting is a strict business and will halt your end goal if you are missing a double-quote or bracket. Start by echoing out $json ($_POST["initType"]) and compare the format to examples posted online (just Google "json formatting"). I can tell you that one thing that stands out to me is: "parameters":true (from your example above). I have a strong suspicion that the key true should be in double quotes. If you are positive that the JSON variable is correct syntactically, I don't think I would be of any more help. Using json_decode() to produce an array to very straight forward once you get it right.
Don't decode the json at all -this only brings the problem of trying to serialize an array that burmat mentioned in his answer.
Write to the file the json content straight away:
fwrite($file_handle, $json);
Also, though I am not PHP expert it seems you access the body of the post request wrongly. Please refer to the following post.
I have the following json
country_code({"latitude":"45.9390","longitude":"24.9811","zoom":6,"address":{"city":"-","country":"Romania","country_code":"RO","region":"-"}})
and i want just the country_code, how do i parse it?
I have this code
<?php
$json = "http://api.wipmania.com/jsonp?callback=jsonpCallback";
$jsonfile = file_get_contents($json);
var_dump(json_decode($jsonfile));
?>
and it returns NULL, why?
Thanks.
<?php
$jsonurl = "http://api.wipmania.com/json";
$json = file_get_contents($jsonurl);
var_dump(json_decode($json));
?>
You just need json not jsonp.
You can also try using json_decode($json, true) if you want to return the array.
you're requesting jsonp with http://api.wipmania.com/jsonp?callback=jsonpCallback, which returns a function containing JSON like:
jsonpCallback({"latitude":"44.9718","longitude":"-113.3405","zoom":3,"address":{"city":"-","country":"United States","country_code":"US","region":"-"}})
and not JSON itself. change your URL to http://api.wipmania.com/json to return pure JSON like:
{"latitude":"44.9718","longitude":"-113.3405","zoom":3,"address":{"city":"-","country":"United States","country_code":"US","region":"-"}}
notice the second chunk of code doesn't wrap the json in the jsonpCallback() function.
The website doesn't return pure JSON, but wrapped JSON. This is meant to be included as a script and will call a callback function. If you want to use it, you first need to remove the function call (the part until the first paranthesis and the paranthesis at the end).
If your server implements JSONP, it will assume the callback parameter to be a JSONP signal and the result will be similar to a JavaScript function, like
jsonpCallback("{yada: 'yada yada'}")
And then, json_decode won't be able to parse jsonpCallback("{yada: 'yada yada'}") as a valid JSON string
If country_code( along with closing parenthesis are include in your json, remove them.
This is not a valid json syntax: json
You are being returned JSONP, not JSON. JSONP is for cross-domain-requests in JavaScript. You don't need to use it when using PHP because you aren't affected by cross-domain-policies.
Since you are getting a string from the file_get_contents() function you can do a replacement of the country_code( text (this is the JSONP specific part of the response):
<?php
$json = "http://api.wipmania.com/jsonp?callback=jsonpCallback";
$jsonfile = substr(file_get_contents($json)), 13, -1);
var_dump(json_decode($jsonfile));
?>
Note
This works but JKirchartz's solution looks better, just request the correct data rather than messing around with the incorrect data.
Obviously in this situation, using the correct URL to access the API will return pure jSON.
"http://api.wipmania.com/json"
A lot of people are providing an alternative to the API in use, rather than answering the OP's question, so here is a solution for those looking for a way of handling jSONp in PHP.
First, the API allows you to specify a callback method, so you can either use Jasper's method of getting the jSON sub string, or you can give a callback method of json_decode, and modify the result to use with a call to eval. This is my alternative to Jasper's code example since I don't like to be a copy cat:
$json = "http://api.wipmania.com/jsonp?callback=json_decode";
$jsonfile eval(str_replace("(", "('", str_replace(")", "')", file_get_contents($json)))));
var_dump($jsonfile);
Admittedly this seems a little longer, more insecure, and not as clear to read as Jasper's code:
$json = "http://api.wipmania.com/jsonp?callback=jsonpCallback";
$jsonfile = substr(file_get_contents($json)), 13, -1);
var_dump(json_decode($jsonfile));
Then the jSON "address":{"city":"-","country":"Romania","country_code":"RO","region":"-"} tells us to access the country_code like so:
$jsonfile->{'address'}->{'country_code'};
I am preparing and sending a JSON string from my PHP file to my Javascript function like this:
$json = array();
$json['slice'] = false;
$json['G500'] = false;
$json['KG1'] = false;
$encoded = json_encode($json);
die($encoded);
However, in my JS function, if I do this, it is unable to decode the JSON object:
var d = req.responseText;
var jsonObject = eval(d);
The only way, I can get it to eval the JSON object is by adding parentheses manually
jsonObject = eval("(" + d + ")");
I have the same problem going in reverse as well. Sending a JSON object to PHP and trying to decode it there fails. I believe I would need to remove the parentheses in my PHP script before attempting to decode.
Why is this happening? Is there something I can do to work around this incompatibility?
EDIT:
PHP to JS is now working if I use JSON.parse. I'm still having trouble the other way around.
This is how I'm sending the data to the PHP:
var JSONstring =
{
"Product": document.getElementById('item').value,
"Size": document.getElementById('size').value,
"Quantity": document.getElementById('quantity').value
};
url = "maintainOrder.php?json=" + JSON.stringify(JSONstring);
req.open("GET", url, true);
However, the PHP script is unable to decode it.
$newItem = json_decode($_GET['json']);
array_push($_SESSION['order'],$newItem);
Your Javascript
eval has an issue with leading { characters, because of an ambiguity with block scope.
Using the parentheses to force the input to be parsed as an expression is a solution, but you should avoid eval entirely and use a proper JSON decoding function.
Your PHP
We'd need to see the data that you send to your PHP script to know why it won't parse. In general, as long as JSONLint accepts your JSON, so will PHP's json_decode. So give that a go.
For the php to javascript issue refer to the Tomalak Geret'kal answer.
For the javascript to php maybe I have the solution:
If you want an associative array in php then you have to pass assoc parameter as true into json_decode (default to false)
Example:
$array = json_decode($jsonString, true);
I was bitten a couple of times by this: by default json_decode try to create an object if it receive a javascript object (it make perfect sense if you think of) and you have to force it to render an associative array if you need this behaviour
I think you need to do some string processing, all you need to do is echo and see the exact format of your JSON string and make sure it conforms to the standard format, then use string processing both on the server and client sides to achieve the desired effect
Are you sure php is not adding slashes to the json text?, try saving the json text in a file in the server side to verify
For some reason json_decode is returning NULL with valid JSON.
The json is located here: http://www.nfl.com/liveupdate/scorestrip/scorestrip.json
I am getting the file contents of the page (file_get_contents) and then running json_decode on it.
Also tried stripslashes b/c of magic quotes.
Thanks in advance,
Phil
$json = file_get_contents('http://www.nfl.com/liveupdate/scorestrip/scorestrip.json');
var_dump(json_decode($json));
The empty array elements are invalid JSON, ie the multiple commas with no values between
["Thu","7:30","Final",,"BAL","6","PHI","13",,,"55424",,"PRE1","2011"]
^ Here ^ Here ^Here
You could try inserting empty strings between multiple commas (thanks hakre), ie
$json = preg_replace('/,(?=,)/m', ',""', $json);
// I'm dubious about this working, don't have PHP to test but it works in JS
I don't know if this messes up your ability to continue using the data though
I came the same conclusion as Phil, but it took me about 5 minutes longer. : )
However, I noticed a problem in his output... it is dropping a field.
I don't like doing this kind of pattern detection in RegEx, only because I think it is harder to maintain. In this case, I just run it through a while loop.
while (strpos($json,',,'))
{
$json = str_replace(',,',',"",', $json);
}
I'm sure Phil can come up with a proper RegEx, but this solution will maintain the right # of entries & their ordinal positions.
For anyone looking in 2014. The new feed data link should be:
http://www.nfl.com/liveupdate/scores/scores.json