I'm using functions with the datetime object that require a datetimezone object as an argument. I see a list of timezones here:
http://www.php.net/manual/en/class.datetimezone.php
but there's not things like 'est'. How could I create a 'datetimezone' object from EST?
$tz = new DateTimeZone('EST');
In http://www.php.net/manual/en/timezones.php you can find in the OTHER section the EST there.
To create one use date_default_timezone_set('EST');
To make sure you have it do echo date_default_timezone_get();
A very verbose loop. The construct function for the DateTime class isn't working properly for me but this works.
$date = "2011/03/20";
$date = explode("/", $date);
$time = "07:16:17";
$time = explode(":", $time);
$tz_string = "America/Los_Angeles"; // Use one from list of TZ names http://us2.php.net/manual/en/timezones.php
$tz_object = new DateTimeZone($tz_string);
$datetime = new DateTime();
$datetime->setTimezone($tz_object);
$datetime->setDate($date[0], $date[1], $date[2]);
$datetime->setTime($time[0], $time[1], $time[2]);
print $datetime->format('Y/m/d H:i:s');
?>
Be aware of that some TimeZone abbreviations like EST are not unique. See http://www.timeanddate.com/library/abbreviations/timezones/.
The usage of EST is not recommended, see
http://www.php.net/manual/en/timezones.others.php.
Use for example America/New_York instead.
Related
So I've checked the list of supported time zones in PHP and I was wondering how could I include them in the date() function?
Thanks!
I don't want a default timezone, each user has their timezone stored in the database, I take that timezone of the user and use it. How? I know how to take it from the database, not how to use it, though.
For such task, you should really be using PHP's DateTime class. Please ignore all of the answers advising you to use date() or date_set_time_zone, it's simply bad and outdated.
I'll use pseudocode to demonstrate, so try to adjust the code to suit your needs.
Assuming that variable $tz contains string name of a valid time zone and variable $timestamp contains the timestamp you wish to format according to time zone, the code would look like this:
$tz = 'Europe/London';
$timestamp = time();
$dt = new DateTime("now", new DateTimeZone($tz)); //first argument "must" be a string
$dt->setTimestamp($timestamp); //adjust the object to correct timestamp
echo $dt->format('d.m.Y, H:i:s');
DateTime class is powerful, and to grasp all of its capabilities - you should devote some of your time reading about it at php.net. To answer your question fully - yes, you can adjust the time zone parameter dynamically (on each iteration while reading from db, you can create a new DateTimeZone() object).
If I understood correct,You need to set time zone first like:
date_default_timezone_set('UTC');
And than you can use date function:
// Prints something like: Monday 8th of August 2005 03:12:46 PM
echo date('l jS \of F Y h:i:s A');
The answer above caused me to jump through some hoops/gotchas, so just posting the cleaner code that worked for me:
$dt = new DateTime();
$dt->setTimezone(new DateTimeZone('America/New_York'));
$dt->setTimestamp(123456789);
echo $dt->format('F j, Y # G:i');
Use the DateTime class instead, as it supports timezones. The DateTime equivalent of date() is DateTime::format.
An extremely helpful wrapper for DateTime is Carbon - definitely give it a look.
You'll want to store in the database as UTC and convert on the application level.
It should like this:
date_default_timezone_set('America/New_York');
U can just add, timezone difference to unix timestamp.
Example for Moscow (UTC+3)
echo date('d.m.Y H:i:s', time() + 3 * 60 * 60);
Try this. You can pass either unix timestamp, or datetime string
public static function convertToTimezone($timestamp, $fromTimezone, $toTimezone, $format='Y-m-d H:i:s')
{
$datetime = is_numeric($timestamp) ?
DateTime::createFromFormat ('U' , $timestamp, new DateTimeZone($fromTimezone)) :
new DateTime($timestamp, new DateTimeZone($fromTimezone));
$datetime->setTimezone(new DateTimeZone($toTimezone));
return $datetime->format($format);
}
this works perfectly in 2019:
date('Y-m-d H:i:s',strtotime($date. ' '.$timezone));
I have created this very straightforward function, and it works like a charm:
function ts2time($timestamp,$timezone){ /* input: 1518404518,America/Los_Angeles */
$date = new DateTime(date("d F Y H:i:s",$timestamp));
$date->setTimezone(new DateTimeZone($timezone));
$rt=$date->format('M d, Y h:i:s a'); /* output: Feb 11, 2018 7:01:58 pm */
return $rt;
}
I have tried the answers based on the DateTime class. While they are working, I found a much simpler solution that makes a DateTime object timezone aware at the time of creation.
$dt = new DateTime("now", new DateTimeZone('Asia/Jakarta'));
echo $dt->format("Y-m-d H:i:s");
This returns the current local time in Jakarta, Indonesia.
Not mentioned above. You could also crate a DateTime object by providing a timestamp as string in the constructor with a leading # sign.
$dt = new DateTime('#123456789');
$dt->setTimezone(new DateTimeZone('America/New_York'));
echo $dt->format('F j, Y - G:i');
See the documentation about compound formats:
https://www.php.net/manual/en/datetime.formats.compound.php
Based on other answers I built a one-liner, where I suppose you need current date time. It's easy to adjust if you need a different timestamp.
$dt = (new DateTime("now", new DateTimeZone('Europe/Rome')))->format('d-m-Y_His');
If you use Team EJ's answer, using T in the format string for DateTime will display a three-letter abbreviation, but you can get the long name of the timezone like this:
$date = new DateTime('2/3/2022 02:11:17');
$date->setTimezone(new DateTimeZone('America/Chicago'));
echo "\n" . $date->format('Y-m-d h:i:s T');
/* Displays 2022-02-03 02:11:17 CST "; */
$t = $date->getTimezone();
echo "\nTimezone: " . $t->getName();
/* Displays Timezone: America/Chicago */
$now = new DateTime();
$now->format('d-m-Y H:i:s T')
Will output:
29-12-2021 12:38:15 UTC
I had a weird problem on a hosting. The timezone was set correctly, when I checked it with the following code.
echo ini_get('date.timezone');
However, the time it returned was UTC.
The solution was using the following code since the timezone was set correctly in the PHP configuration.
date_default_timezone_set(ini_get('date.timezone'));
You can replace database value in date_default_timezone_set function,
date_default_timezone_set(SOME_PHP_VARIABLE);
but just needs to take care of exact values relevant to the timezones.
I have a date that I receive in MS format for JSON dates. It looks like this:
/Date(1365004652303)/
I can convert it to a PHP DateTime object by doing this:
$timestamp = round(((int) $originalMSdate) / 1000);
$convertedDate = new DateTime();
$convertedDate->setTimestamp($timestamp);
Ultimately, though, I need it to be a string in ISO 8601 format. I tried then converting it to an ISO date object & then converting that to a string with strval() but strval() doesn't work on date objects.
I've also tried
$dateString = date_format($convertedDate, 'YY-MM-DD H:i:s');
but I need it to also include timezone info, like this: 2015-10-01T21:22:57.057Z
I don't see characters for that in date_format.
How can I achieve this?
EDIT: I should clarify that I'm not printing the resulting string. I need to pass it to a field in a database that accepts a string datatype.
Please try the below code
<?php
// input
$time = microtime(true);
// Determining the microsecond fraction
$microSeconds = sprintf("%06d", ($time - floor($time)) * 1000000);
// Creating DT object
$tz = new DateTimeZone("Etc/UTC");
$dt = new DateTime(date('Y-m-d H:i:s.'. $microSeconds, $time), $tz);
$iso8601Date = sprintf(
"%s%03d%s",
$dt->format("Y-m-d\TH:i:s."),
floor($dt->format("u")/1000),
$dt->format("O")
);
// Formatting according to ISO 8601-extended
var_dump(
$iso8601Date
);
This worked:
$timestamp = round(((int) $originalMSdate) / 1000);
$dateString = date('c', $timestamp);
The format isn't EXACTLY the same. It's in this format:
2016-04-25T14:27:00-05:00 rather than
2016-04-25T14:27:00.057Z
but it's close enough that I can do some manipulation to get what I need.
this one is worked for me. For more please refer this article.
$date = date('Y-m-d H:m:s');
echo date('c', strtotime($date)); // 2020-04-08T16:04:56+05:30
echo date(DateTime::ISO8601, strtotime($date)); // 2020-04-08T16:04:56+0530
echo date(DateTime::ATOM, strtotime($date)); // 2020-04-08T16:04:56+05:30
I'm developing a PHP project and I'm using Parse SDK. What i want to do is adjust the time given by the Parse Database. It gives me time and date that 8 hours late to my timezone. Here's the code I'm using :
$query = new ParseQuery("TestObject");
$query->get("xWMyZ4YEGZ");
$dateTime = $query->getCreatedAt();
$sched = $dateTime->format("M d, Y - hA");
echo $sched;
How can i adjust it to specifically "GMT+8" TimeZone? Thanks!
You have to set the date_default_timezone_set before doing any thing as:
if(function_exists('date_default_timezone_set'))
date_default_timezone_set($timezone);
List of timezones are provided here...
Have a look at PHP date with TZ - See N.B.'s answer here is a code snippet he suggests (you may be able to use the parse date instead of the "now" parameter):
<?php
$tz = 'Europe/London';
$timestamp = time();
$dt = new DateTime("now", new DateTimeZone($tz)); //first argument "must" be a string
$dt->setTimestamp($timestamp); //adjust the object to correct timestamp
echo $dt->format('d.m.Y, H:i:s');
I want to get the date of yesterday of the current date in a specifc time zone.
I tried like this, but it is not working:
$date = new DateTime(NULL, new DateTimeZone('Pacific/Wake'));
$yesterday = $date->modify( '-1 day' );
$yesterday = $yesterday->format('Y-m-d');
I am still getting today's date.
This problem, according to the documentation for the modify() method, seems to entirely depend on which version of php you're using. In this case, method chaining(which is what you're attempting to do is called), is only available on php version 5.3.0 and up, according to the changelog on the previously linked docs.
That in mind, it explains why your code didn't work, and #Deryck's did. If you ever do upgrade your php version, or get your host to upgrade it, you could likely reduce those three lines to two:
$date = new DateTime(NULL, new DateTimeZone('Pacific/Wake'));
$date = $date->modify( '-1 day' )->format('Y-m-d');
Not much of an improvement, I realize, but there's your reason for why it failed to work.
Below are two of the methods I see of getting around this; one is creation of a class.. which seems like overkill to me unless this is apart of something grander... the other is a creation of a function. Both shove the extra lines into something that takes up less space, in a sense.
class DT {
private $now; //can be null
private $timezone; //DateTimeZone object
public function __construct($tz_str, $now = NULL) {
$this->now = $now;
$this->timezone = new DateTimeZone($tz_str);;
}
public function mod($mod,$format) {
$dt = new DateTime($this->now, $this->timezone);
$dt->modify($mod);
return $dt->format($format);
}
}
function mod_formatted_zone($tz_str, $mod, $format, $now = NULL) {
$timezone = new DateTimeZone($tz_str);
$dt = new DateTime($now,$timezone);
$dt->modify($mod);
return $dt->format($format);
}
The use of either is simple; in the case of the class, it'd be something like..
$dt = new DT('Pacific/Wake');
echo $dt->mod('-1 day', 'Y-m-d');
While in the case of the function, it'd simply be..
echo mod_formatted_zone('Pacific/Wake', '-1 day', 'Y-m-d');
Seems to work once you don't re-assign the $date variable unnecessarily. See below:
<?php
$date = new DateTime(NULL, new DateTimeZone('Pacific/Wake'));
$date->modify("-1 day");
$date = $date->format("Y-m-d");
// echo $date; // just in case you wanna echo - ya dig
?>
View demo
FYI:
Wake Island Time Zone (UTC+12:00)
Which means 1 day before is actually today (for me at least, on the western hemisphere).
I want to get the date of yesterday of the current date in a specifc time zone.
You can specify relative dates in the DateTime constructor. This will work for you:-
$yesterday = new DateTime('- 1 day', new DateTimeZone('Pacific/Wake'));
var_dump($yesterday);
Proof!.
I have date in format "m-Y-d". How can i modify this date to format "Y-d-m"? For this the best should be function where i can add old format and new format, but how can i make it?
For example i have
$date = '01-2013-13'; // "m-Y-d"
i would like receive:
$newDate = '2013-13-01'; // "Y-d-m"
See DateTime::createFromFormat() and DateTime::format()
$date = DateTime::createFromFormat('m-Y-d', '01-2013-13');
echo $date->format('Y-m-d');
PHP cannot parse the format using strtotime(). You'll have to do something like this:
function reformat($old_date)
{
$parts = explode('-', $old_date);
return $parts[1].'-'.$parts[2].'-'.$parts[0];
}
And then call it using:
$new_format = reformat($date);
Alternatively, you can use the DateTime::createFromFormat():
function reformat($old_date)
{
$new_date = DateTime::createFromFormat('m-Y-d', $old_date);
return $new_date->format('Y-m-d');
}
You can use the DateTime class, for example:
$date = new DateTime('01-2013-13');
Then use the format() method, like:
$date->format('Y-m-d');
More info:
http://www.php.net/manual/en/datetime.format.php
To create you need to use:
$newDate = date('Y-d-m');
You can find more information here!