Is it possible to print html div tag with style on image in PHP?. if not, then what is the alternative way?
Some hosts have ImageMagick for PHP. To add text to your image, take a look at the syntax of the commands here. The example given on that page should help some - it's pretty easy to get text on an image.
The benefits of using ImageMagick over a fixed image is that you can vary the content of the text, which is what you might want (you didn't mention needing a static text; for this, I'd use an image with a transparent background). For more comprehensive font commands, take a look here.
To put a transparent image on top of your base image, take a look at this very nicely designed site.
I'll also give the code presented on that site here:
$photo = imagecreatefromjpeg("original.jpg");
$watermark = imagecreatefrompng("watermark.png");
// This is the key. Without ImageAlphaBlending on, the PNG won't render correctly.
imagealphablending($photo, true);
// Copy the watermark onto the master, $offset px from the bottom right corner.
$offset = 10;
imagecopy($photo, $watermark, imagesx($photo) - imagesx($watermark) - $offset, imagesy($photo) - imagesy($watermark) - $offset, 0, 0, imagesx($watermark), imagesy($watermark));
// Output to the browser
header("Content-Type: image/jpeg");
imagejpeg($photo);
To output the image to a file, please Google that and replace the last two lines of the example given above.
For ImageMagick stuff, take a look here
I hope this helps :-)
James
You can set the image as the background graphic of any div using CSS. Then the text within that div will appear on top of the image.
(CSS)
.mydiv {
background:url(/path/to/image.gif);
width:100px; /* set to width of the image */
height:100px; /* set to height of the image */
}
(HTML)
<div class='mydiv'>Some text here</div>
There is no easy way to print text on images using html/css on server side, because php can't parse html, so you'd better find another solution like php GD.
Related
I have a PHP function that does on-the-fly image resizing for thumbnail creation.
I am having trouble as it's just displaying raw image stream instead of the actual image.
My code is using a function called thumbnail:
$thumbnail = thumbnail($item['filename'], 209, 137);
imagejpeg($thumbnail);
I've tried putting in:
header("Content-type: image/jpeg");
However, this just expects the full page to be an image. I have absolutely no idea where to go from here, been working at it for a while. I'd rather not save the image to disk although it's looking like this might be necessary.
You either
Do it the normal way
This mean you point at one url, and serve the contents of one image:
<img src="myimage.php">
and myimage.php is a script that looks like:
header('Content-type: image/jpeg');
imagejpeg($thumbnail);
die;
This technique has the advantage of being.. the normal way of doing things.
OR
Output the image inline
Using data uris outputting the contents as a base64 encoded string
<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==" alt="Red dot">
This technique is most appropriate with small images.
It has the advantage of meaning all the images are in the main http request - at the (possibly sizable) disadvantage of making the page harder to edit/build and possibly negating the benefits of browser caching (unless the html page is itself cached).
Being normal is easier
Regarding this statement in the question:
However, this just expects the full page to be an image
That's right - if you do it the normal way you want to point at your php script with the src attribute of an image tag, and server only an image - i.e. the exact same response as if you were pointing at an image file with a browser.
Unless you have a good reason to do things a different way - the "normal" way is a good place to start.
You can point an html img tag to an php file.
<img src='thumbnail.php?file=<?php echo $item['filename']; ?>' />
Then on your php file you display the image and change the headers since all it is doing is displaying an image.
$thumbnail = thumbnail($_GET['filename'], 209, 137);
imagejpeg($thumbnail);
header("Content-type: image/jpeg");
You need to insert the image like you would a normal image in HTML and create the image in a separate PHP file:
image.php
<?php
$img = imagecreate(100,100); //Create an image 100px x 100px
imagecolorallocate($img, 255,0,0); //Fill the image red
header('Content-type: image/jpeg'); //Set the content type to image/jpg
imagejpeg($img); //Output the iamge
imagedestroy($img); //Destroy the image
?>
myWebpage.html
<img src="image.php" />
I'm trying to use DomPDF to generate a PDF out of some HTML. I need the page to be 20mm x 20mm, so I use the following:
CPDF_Adapter::$PAPER_SIZES['my_square_page'] = array(0, 0, 566.929134, 566.929134);
$dompdf->set_paper('my_square_page','portrait');
It works properly, if I check the PDF properties the size is ok. The HTML that will appear in the PDF has a container div of 490x490px. This size cannot be changed, as the elements inside that div are absolutely positioned.
The problem, then, is that in the generated PDF the div does not cover the entire page. I've tried setting the DPI, using different values in
def("DOMPDF_DPI", 150);
But it does not seem to make any difference at all. The output I get is this (gray borders are from the PDF reader):
I've tried setting the width and height of body and html in the CSS of the content, but it does not work.
You can check the source code of my sample case here.
Ok, I figured it out. Looks like the line
def("DOMPDF_DPI", 150);
does not actually do anything. I did change the dompdf_config.custom.inc file and then it worked. Added this:
define("DOMPDF_DPI", 62.230);
But now the images look too big :S
I have a PHP function that does on-the-fly image resizing for thumbnail creation.
I am having trouble as it's just displaying raw image stream instead of the actual image.
My code is using a function called thumbnail:
$thumbnail = thumbnail($item['filename'], 209, 137);
imagejpeg($thumbnail);
I've tried putting in:
header("Content-type: image/jpeg");
However, this just expects the full page to be an image. I have absolutely no idea where to go from here, been working at it for a while. I'd rather not save the image to disk although it's looking like this might be necessary.
You either
Do it the normal way
This mean you point at one url, and serve the contents of one image:
<img src="myimage.php">
and myimage.php is a script that looks like:
header('Content-type: image/jpeg');
imagejpeg($thumbnail);
die;
This technique has the advantage of being.. the normal way of doing things.
OR
Output the image inline
Using data uris outputting the contents as a base64 encoded string
<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==" alt="Red dot">
This technique is most appropriate with small images.
It has the advantage of meaning all the images are in the main http request - at the (possibly sizable) disadvantage of making the page harder to edit/build and possibly negating the benefits of browser caching (unless the html page is itself cached).
Being normal is easier
Regarding this statement in the question:
However, this just expects the full page to be an image
That's right - if you do it the normal way you want to point at your php script with the src attribute of an image tag, and server only an image - i.e. the exact same response as if you were pointing at an image file with a browser.
Unless you have a good reason to do things a different way - the "normal" way is a good place to start.
You can point an html img tag to an php file.
<img src='thumbnail.php?file=<?php echo $item['filename']; ?>' />
Then on your php file you display the image and change the headers since all it is doing is displaying an image.
$thumbnail = thumbnail($_GET['filename'], 209, 137);
imagejpeg($thumbnail);
header("Content-type: image/jpeg");
You need to insert the image like you would a normal image in HTML and create the image in a separate PHP file:
image.php
<?php
$img = imagecreate(100,100); //Create an image 100px x 100px
imagecolorallocate($img, 255,0,0); //Fill the image red
header('Content-type: image/jpeg'); //Set the content type to image/jpg
imagejpeg($img); //Output the iamge
imagedestroy($img); //Destroy the image
?>
myWebpage.html
<img src="image.php" />
Simple question with yes/no answer and if yes...then how?
Suppose you have an HTML page with an image on it without any sort of watermark.
Is it possible to place a watermark on that image if a user saves it to their computer?
I need a simple function that watermarks an image upon download or save...
I do understand that once the image loads in the browser, it is technically downloaded, so is there a way to display the image without a watermark on screen, and if the user opens browser cache, he/she finds a watermarked copy?
If anybody has done this using any platform (PHP, GD, jQuery, etc.), your contribution would be appreciated.
One trick might be to combine 2 images, so they become one.
I have image A:
Then I add image B (watermark version)
So when you display the image for the user you use one as background and the other one as image, so when user tries to download, they will get only one part. Of course as already mentioned, the user will be able to get all they can see on the screen, but most users won't be able to combine the images properly.
Please note that the image on top must be transparent.
I would recommend doing this server side and cache the modified images when you have cut out the watermark
Here you can read how to do it with PHP: http://www.sitepoint.com/watermark-images-php/
I personally don't think that it is possible with javascript, because as you already have said yourself, it is already downloaded.
But don't nail me on that.
On the server side it is for sure possible, as you can see in the above link.
A possible alternate solution is to contain the image inside an element with a hidden overflow.
For example:
Your image has a height of 200px, you add an extra 20px watermark (when uploading) at the bottom of the image (so it isn't actually on top of the image). So the total image now has a height of 220px; but you place it inside an element give that element a 200px height and a hidden overflow.
You can change the source of the image when a user right-clicks it. This way you can change the source to the watermarked version when the user tries to save the image.
Yes, the user will already have the non-watermarked version in their cache, but only advanced users are going to know how to get to those images.
$('img').on('mousedown', function (event) {
//check which mouse button was clicked, 1 == left, 2 == middle, 3 == right
if (event.which == 3) {
//update the source of this image
this.src = this.src.replace('.jpg', '_watermarked.jpg');
}
});
Here is a demo: http://jsfiddle.net/s6A9m/
Anything that the user can see they can take. There is no way to watermark ONLY if downloaded. When an image is displayed in the browser it has already downloaded.
There are several approaches you could take. I would recommend you use PHP to add the watermark to the image before it is displayed. This means that all protected images on the site will display a visible watermark. A second approach I have seen used is to display a low quality version that is not watermarked, but restrict the full quality version to only those who are supposed to see it.
Yes it is possible. All you have to do is,
Call the download function, in which we can implement the downloading of watermarked images.
I have used AngularJS, HTML, JQuery and watermarkJS which you find here(http://brianium.github.io/watermarkjs/)
HTML:
Download Sample
Javascript:
$scope.selectedWatermarkType = 'Text';
$scope.selectedPosition = 'Bottom-left';
$scope.text = 'Sample Watermark';
$scope.size = '45';
$scope.selectedFont = 'Arial';
$scope.ColorCodeGlobalObj.colorcode = 'ffff';
$scope.DownloadSample = function () {
if ($scope.selectedWatermarkType == 'Text') {
if ($scope.selectedPosition == 'Bottom-left') {
watermark(['/assets/js/node_modules/watermarkjs/examples/img/shepherd.jpg'])
.image(watermark.text.lowerRight($scope.text, $scope.size + 'px ' + $scope.selectedFont, '#' + $scope.ColorCodeGlobalObj.colorcode, 0.5))
.then(function (img) {
saveImageAs(img);
});
}
}
'img' is the watermarked image object which can be used to download the image.
function saveImageAs(imgOrURL) {
imgOrURL.src.replace('image/png', 'image/octet-stream');
if (typeof imgOrURL == 'object')
imgOrURL = imgOrURL.src;
var link = document.createElement("a");
link.setAttribute("href", imgOrURL);
link.setAttribute("download", 'watermarkSample.png');
link.click();
}
This code performs download of watermarked image. Still the unwatermarked image is available in the mentioned srcpath which can be appended to an 'img' tag and can be viewed.
Hope this helps !
How can I convert images on my website into greyscale? I don't care if it's PHP or JS, but I think PHP is nicer.
In particular I have a blog with various posts containing images, and I want the thumbnail images that preview the blog post on the index page to be greyscale while the represented images in the blog post stay colored. These thumbnail images share a class called .post-thumbnail there the img tag is inside the element with that class.
All I want is something that would look like this in CSS is there would be that property:
.post-thumbnail img { image-transform: greyscale; }
In PHP or JS.
Quick search on StackOverflow finds this:
$im = imagecreatefrompng('dave.png');
imagefilter($im, IMG_FILTER_GRAYSCALE);
imagepng($im, 'dave.png');
See Making an Image Greyscale with GD Library