How to combine two arrays into single one and i am requesting this in such a way that the 3rd combination array should contains one value from one array and the next one from other array and so on.. or ( it could be random)
ex:
$arr1 = (1, 2, 3, 4, 5);
$arr2 = (10, 20, 30, 40, 50);
and combined array
$arr3 = (1, 10, 2, 20, 3, 30, ...);
If it can be random, this will solve your problem:
$merged = array_merge($arr1, $arr2);
shuffle($merged);
I also made a function for fun that will produce the exact output you had in your question. It will work regardless of the size of the two arrays.
function FosMerge($arr1, $arr2) {
$res=array();
$arr1=array_reverse($arr1);
$arr2=array_reverse($arr2);
foreach ($arr1 as $a1) {
if (count($arr1)==0) {
break;
}
array_push($res, array_pop($arr1));
if (count($arr2)!=0) {
array_push($res, array_pop($arr2));
}
}
return array_merge($res, $arr2);
}
This will return a random array:
$merged = array_merge($arr1,$arr2);
shuffle($merged);
sort($arr3 = array_merge($arr1, $arr2));
array_merge() will merge your arrays into one. sort() will sort the combined array.
If you want it random instead of sorted:
shuffle($arr3 = array_merge($arr1, $arr2));
$arr3 contains the array you're looking for.
You can use
<?php
arr3 = array_merge ($arr1 , $arr2 );
print_r(arr3);
?>
which will output in
$arr3 = (1,2,3,4,5,10,20,30,40,50)
Related
I am wondering how in PHP would I pass multiple arrays to a for each loop.
For example, in the following I'd want to pass both $array1 and $array2 to this for each loop, rather than have the for each loop written twice.
$array1 = somestring;
$array2 = someotherstring;
foreach ($array1 as $vals) {
//do something cool
}
Edit: To clarify, I am aware that the array declarations are not valid. It is just a placeholder. That does not deserve a downvote. I want to run the entire foreach loop with $array1, and then run it again with $array2.
$array3 = array_merge($array1, $array2);
foreach ($array3 as $vals) {
// do your coolness
}
You can kind of zip two indexed arrays with array_map(null, $array1, $array2). This way you will have a list of tuples, where the first element will be from $array1 and the second - from $array2. You can iterate over this list and access both arrays elements in one iteration.
$array1 = [1, 2, 3];
$array2 = [1, 2, 3];
$zip = array_map(null, $array1, $array2);
foreach ($zip as $tuple) {
echo $tuple[0], '-', $tuple[1], PHP_EOL;
}
Here is demo.
Be aware that your arrays (in this case lists) have to be the same length. Other wise you will end up with broken tuples, one elements of which will be null.
I want to merge 2 arrays together that have a different number of elements, using the keys from one and the values from another where/if the keys match. The array that contains the desired values may have less elements in it although I would like to retain the resulting empty keys from the original array. For example:
//Array that contains keys I would like to retain
$arr1 = array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12);
//Array that contains values I'd like to use
$arr2 = array(01=>123, 03=>123, 05=>123, 07=>123, 09=>123, 11=>123);
//The desired result with some valueless elements
$results = array(01=>123, 02, 03=>123, 04, 05=>123, 06, 07=>123, 08, 09=>123, 10, 11=>123, 12);
As you can see the results array retains 12 elements but only applies values to where the keys from the 2 arrays match.
I have tried $results = array_intersect_key($arr1 + $arr2, $arr2); among other PHP functions as well as:
for ($i=1; $i < count($arr1); $i++) {
if (isset($arr2[$i])) {
$arr3[] = $arr2[$i];
} else {
$arr3[] = $arr1[$i];
}
}
print_r($arr3);
No luck as yet.
Thanks in advance!
For arrays like this
$arr1 = array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12);
$arr2 = array(1=>123, 3=>123, 5=>123, 7=>123, 9=>123, 11=>123);
this should work.
foreach ($arr1 as $key) {
$results[$key] = isset($arr2[$key]) ? $arr2[$key] : null;
}
or using some other PHP functions:
$results = array_replace(array_fill_keys($arr1, null), $arr2);
//Array that contains keys I would like to retain
$arr1 = array(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12);
//Array that contains values I'd like to use
$arr2 = array(1=>123, 3=>123, 5=>123, 7=>123, 9=>123, 11=>123);
$result = array_fill_keys(
$arr1,
null
);
array_walk(
$result,
function(&$value, $key) use($arr2) {
$value = (isset($arr2[$key])) ? $arr2[$key] : null;
}
);
var_dump($result);
First set your $arr1's values to false to retain just the keys:
$arr1 = array_fill_keys(array_keys($arr1), false); Or if you're generating $arr1 yourself, define it as such to start with: $arr1 = Array(false, false, false, false /* etc. */);
Now use the array union operator:
$result = $arr2 + $arr1;
The + operator returns the right-hand array appended to the left-hand array; for keys that exist in both arrays — from the docs: http://php.net/manual/en/language.operators.array.php)
Then if required sort the array by key: ksort($array);
This question already has answers here:
Merge two flat indexed arrays of equal size so that values are pushed into the result in an alternating fashion
(2 answers)
Closed 6 years ago.
What I want is an efficient (without looping) way to merge arrays in the way that the first element of the resulting array is the first element of the first array, the second element of the resulting array is the second element of the second array (alternatively)... etc
Example:
$arr1 = array(1, 3, 5);
$arr2 = array(2, 4, 6);
$resultingArray = array(1, 2, 3, 4, 5, 6);
assuming both arrays have the same length.
$arr1 = array(1, 3, 5);
$arr2 = array(2, 4, 6);
$new = array();
for ($i=0; $i<count($arr1); $i++) {
$new[] = $arr1[$i];
$new[] = $arr2[$i];
}
var_dump($new);
Not that I'd really advocate this "hack", but this'll do:
$result = array();
array_map(function ($a, $b) use (&$result) { array_push($result, $a, $b); }, $arr1, $arr2);
It really just hides a double loop behind array_map, so, meh...
I have an array, and I want to find all of the indexes of a certain object in the array. When I use array_search, it only returns the first index in which the object can be found.
echo array_search(3, array(3, 3, 4));
This returns 0, but I want to know that both indexes 0 and 1 have the integer 3 as their object. Is there a way of doing this without using a for loop?
Try array_keys() method :
$array = array(3, 3, 4);
print_r(array_keys($array, "3"));
For reference:
array_keys() — Return all the keys or a subset of the keys of an array Info & usuage examples : http://php.net/manual/en/function.array-keys.php
As an alternative to array_keys, array_filter() retains associativity
$key = 3;
$array = array(1, 3, 3, 4, 3, 5);
$result = array_filter(
$array,
function ($item) use ($key) {
return ($item == $key);
}
);
var_dump($result);
I need to test if one element of an array is in another array.
$array_one = array("gogo", "blabla", "toto");
$array_two = array("stackov", "renaul", "toto");
I would like to know if one element of array_one is in array_two ???
How to test that? Am trying in_array but it seems to have problems.
array_intersect()
$array1 = array("gogo", "blabla", "toto");
$array2 = array("stackov","renaul","toto");
$commonElements = array_intersect($array1,$array2);
var_dump($commonElements);
Try this one:
array_intersect($array_one, $array_two);
Mark's answer should be enough for your problem.
If you ever wish to find the intersect of more than 2 arrays, use this:
$arrays = array(
array(1, 2, 3),
array(2, 4, 6),
array(2, 8, 16)
);
$intersection = call_user_func_array('array_intersect', $arrays);