I have some php code that generates a random password. Next to a text box I have some text which says "click to Generate a random password".
What I am looking to achieve is when the text in double quotes above is clicked that the PHP code is run and the generated random password is then pasted into the text box which is beside the text above in double quotes.
How could do this? I am thinking maybe jQuery but not sure how I would do what I want above.
Here you are... complete and working example :)
Put files 'index.html' and 'passgenerator.php' into same directory.
index.html
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title></title>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#generate').click(function(){
$.get('passgenerator.php', function(data) {
$('[name=password]').val(data);
});
})
});
</script>
</head>
<body>
<form action="">
<input type="text" name="password">
<input type="button" id="generate" value="Generate password">
</form>
</body>
</html>
passgenerator.php
<?php
echo sha1(uniqid());
?>
either use ajax to call the script page that generates the password or like col. shrapnel says port the generating function to javascript (which is a better idea)
Example (with jquery using ajax)
$.get("/PasswordGenerator.php",function(password)
{
$("#TextboxID").val( password );
});
where TextboxID is the id of the textbox u want the password to be added to.
Don't do it in php. Just do it in javascript. Here is a very neat tutorial that should show you the step by step instructions:
http://www.mediacollege.com/internet/javascript/number/random.html
Patrick Evans is right. You can setup your form like this :
<input type="button" value="Generate" onclick="generate();">
And in section you have to define a function
<script type="text/javascript">
function generate(){
$.get("/PasswordGenerator.php",function(password)
{
$("#TextboxID").val( password );
});
}
</script>
Try this ajax call to get the content using ajax and display it on the div.
$("#generate").click(function(){
$.get('url:to:urPHP',{
data:urData
},function(data){
$("#generatedPassword").html(data);
});
});
<input type="" id="generate" value="click to Generate a random password" />
<div id="generatedPassword">
<div>
Related
I am very new to web designing. I want to create a web page such that when the user is typing in the form, at the same moment that data must be shown on the left side of the same page as in the image below. Example, as the user types in the about me text box, the data area on the left side with about me title should also get updated instantly and dynamically with the same speed the user is typing.
Can anyone please help me how this is possible? or which language will i have to use to do this?
thanks in advance.
example image
You will have to use javascript to achieve this.
<input type="text" id="input">
<div id="output">
</div>
<script>
var input = document.getElementById('input');
var output = document.getElementById('output');
// add event listener to the input element
input.onkeyup= function() {
// set the output element HTML to what you type in
output.innerHTML = this.value;
}
</script>
Fiddle: https://jsfiddle.net/xpvt214o/124485/
Use the following code :
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"> </script>
<script>
$(document).ready(function(){
$('#name').keyup(function () {
$('#display').text($(this).val());
});
});
</script>
</head>
<body>
<input type="text" id="name"/>
<span id="display"></span>
</body>
</html>
My login.html file:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="lv">
<head>
<?php require_once 'inc/metahead.php'; ?>
<title>Logg inn</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js">
</script>
<script type="text/Javascript" src="functions.js">
</script>
</head>
<body>
<div id="content">
<center>
<form>
<label for="epost"></label> <input type="text" name="epost" id="epost"
placeholder="Epost/Bruker" /></br> </br> <label
for="passord"></label> <input type="password" name="passord" id="passord"
placeholder="Passord" /></br> </br> <input
type="button" onclick="login()" value="Logg inn">
</form>
<br /> Glemt passord?
</center>
</div>
</body>
</html>
This piece of code is from my header.php file:
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script type="text/javascript">
function loginNow(){
$(document).ready(function() {
$("#content").load("login.html");
});
}
</script>
If i go directly in login.html - It calls the function without problems. BUT, if I go through my index-file and click "Logg inn", so the script above run, the script in login.html never gets called.
I have tried to alert something out instead of calling my script - That works. Any help would be greatly appreciated!
what i think is you have two jquery files with different version loaded there which is creating the conflict
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js">
in login.html
and other is
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
in header.php
so either you use noConflict().. or remove one of them
The function name is different here
onclick="login()" // you are calling login()
function loginNow(){ // but declaring loginNow()
Your HTML code:
...
<input type="password" name="passord" id="passord"
placeholder="Passord" /></br> </br> <input
type="button" **onclick="login()"** value="Logg inn">
...
Your Javascript Code:
function **loginNow()**{
$(document).ready(function() {
$("#content").load("login.html");
});
}
Check the enclosed parts - Different function names ;)
Don't use onlick="". Since you are using jQuery, hook an event to your input element:
$(document).ready(function(){
$('input[type=button]').click(loginNow);
});
Eventually give the button an id or a name and use this as the selector in jQuery.
I am new in jQuery and need help to figure out why $.get does not reply.
Let me explain what I have: There is a main index.php as follows:
<!DOCTYPE html>
<html lang="en">
<head> <meta charset="utf-8"> </head>
<body>
<script type="text/javascript" src="js/jquery.js"></script>
<script type="text/javascript" src="js/reqhan.js"> </script>
<input id="string" type="text" />
<input id="button" type= "button" value="Go" />
<div id="div"></div>
</body>
</html>
the js/reqhan.js contains
$(document).ready(function(e) {
alert('1');
$('#button').click(function() {
$.get('php/reverse.php',{input: string},function(data){alert('2');});
$('#div').text(data);
alert('3');
});
});
and reverse.php contains a simple code (I pasted here but does not preview it) that gets the text from reqhan.js file and returns an echo message.
when running the code on Google Chrome, the first alert is shown but not the rest and of course the `$('#div').text(data);' doesn't send back the data to the js file.
Please let me know if further info is required.
many thanks.
You're closing your callback function before you do anything with the data
Try this instead:
$(document).ready(function(e) {
alert('1');
$('#button').click(function() {
$.get('php/reverse.php',{input: string},function(data){
alert('2');
$('#div').text(data);
alert('3');
});
});
});
Try to format your code so that each pair of brackets gets its own indentation. It should help catch small things like this.
I was following a tutorial to understand how AJAX/PHP works but i'm having an issue.
Let me start with the code.
escalationTest.php:
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>
<form>
<input type="text" id="name" placeholder="Enter Name.." /> <br>
<input type="text" id="age" placeholder="Enter Name.." />
<input type="button" value="Submit" onClick="post();" />
</form>
<div id="result"></div>
<script type="text/javascript">
function post()
{
var name= $('#name').val();
var age= $('#age').val();
$.post('escalation.php',{postname:name,postage:age},
function(data)
{
$('#result').html(data);
});
}
</script>
</body>
</html>
escalation.php:
<?php
echo "working";
?>
I've typed the code exactly how its in the tut. From its output when i click the submit button i should "working" in the result div which is not happening.
What am i doing wrong here..?
Thanks.
<script type="text/javascript" src="jquery.min.js"></script>
Download a version of jQuery and then link to it with this script tag.
While you can link to an online version, it's not ideal for eventual production use and you should definitely get a local copy.
add the folowing line to your head tag
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
This is a pretty simple fix - you're missing jQuery. Add the following:
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
in your head element.
I have a index.php file where I have canvas game. This game is loaded from separate game.js file where I have variable: ballsCought. I want this wariable and name inputet to text input pass on click to another php file. my code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Simple Canvas Game</title>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(document).ready(function(){
function score(){
$('#score').fadeIn(1000);
$('#score').load("load_players.php");
};
setInterval(score , 1000);
var nam = $("#name").val();
$('#submit').keyup(function(e){
if(e.keyCode == 13){
$.post('upload_score.php','n=' +nam, 'score=' +ballsCought);
}
});
$('#submit').click(function(e){
$.post('upload_score.php','n=' +nam, 'score=' +ballsCought);
});
});
</script>
</head>
<script src="game.js"></script>
<body>
<canvas id="canvas" width="525" height="525"></canvas>
<br /><p><span id="points"></span><input type="text" id="name" placeholder="Name..."/><input type="submit" id="submit" value="Submit"/></p>
<br /><span id="score"></span>
</body>
</html>
But this post function is not working any idea? THank you...
Looks like your $.post method is not correct. If you want to pass data to the PHP page you need to use the JavaScript object notation like so:
$.post('upload_score.php', {n: nam, score: ballsCought});
You can read more about the various ways to call $.post from the jQuery Docs page
Now there could still be problems with your PHP page. You should use something like Firebug to see the Ajax request and any errors that might be returned.