Assign every TD in PHP While Loop Table a Link - php

I have a while loop that retrieves info from the mysql db. Now there is a column called profile. So I want every <td> in the profile to be a button that would have an action which would lead to a PHP page. How do I do that?
<form action="profile.php" method="get">
while($result)
{
echo '<table>';
echo '<tr>';
echo '<td>';
echo $result['profile'];
echo '</tr>';
echo '</td>';
echo '</table>';
}
Now every $result['profile'] should be a submit like - <input type="submit">
Thanks.

rewrite
echo $result['profile'];
to this code:
echo ''.$result['name'].'' ;

First of all,
echo '</tr>';
echo '</td>';
should be:
echo '</td>';
echo '</tr>';
To add a Submit button, change
echo '<td>';
to
echo '<td><input type="Submit" value="Submit">';
and
echo '</td>';
to
echo '</input></td>';
You will need to add the appropriate attributes to the submit button if applicable. Also, you will need to surround the submit button with a form element. Whether each link has its own form, or the entire table is surrounded by one is up to you.
Edit
To surround the table with a form tag, change echo '<table>'; to echo '<form><table>';. Then, change echo '</table>'; to echo '</table></form>';. Submit buttons are automatically "linked" to the form element they are contained in. All you have to do is to define the form action.
Edit
Actually, because you are using a GET request, this entire thing can be simplified by using links instead of forms. So go with RAMe0's answer.

Related

Saving a specific row using PHP and a search option

I have the following program, it searchs for the text placed in a previous php file, and it displays the results, by adding a radiobox to check the item that will be purchased. I am not able to make the page save the item that was checked from the items found into a new table, I don't know how to do that, because the items found are placed as fetched items, therefore I don't know how to select one to save the entire row selected. Please help!.
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Search option</title>
</head>
<body>
<?php
echo "<form action='slips.php' method='post'>";
if(isset($_POST['name_prod2'])){
$word=$_POST['name_prod2'];
$conn = oci_pconnect('dbname', 'password', 'localhost/XE');
if (!$conn) {
$e = oci_error();
trigger_error(htmlentities($e['Error'], ENT_QUOTES), E_USER_ERROR);
}
$stid = oci_parse($conn, "SELECT * FROM product WHERE LOWER(name) LIKE '%" . $word . "%'");
oci_execute($stid);
echo "<table width='950' table border='1' align='center'>\n";
echo "<tr>\n";
echo "<th width='50'> <div align='center'>buy</div></th>";
echo "<th width='110'> <div align='center'>Product ID</div></th>";
echo "<th width='190'> <div align='center'>Product name</div></th>";
echo "<th width='250'> <div align='center'>Description</div></th>";
echo "<th width='100'> <div align='center'>in Store</div></th>";
echo "<th width='100'> <div align='center'>price</div></th>";
echo "<th width='190'> <div align='center'>Quantity to purchase</div></th>";
echo "</tr>\n";
while ($product = oci_fetch_array($stid, OCI_ASSOC+OCI_RETURN_NULLS)) {
echo "<tr>\n";
//echo "<td><div style='text-align:center'><label><input type='radio' name='radio1' value='valor'></label></td></div>";
echo sprintf('<td><div style="text-align:center"><label><input type="radio" name="product" value="%s"></label></td></div>', $product['product_id']);
foreach ($product as $aspect) {
echo '<td><div style="text-align:center">'.($aspect !== null ? htmlentities($aspect, ENT_QUOTES) : '')."</td></div>\n";
}
echo '<td width="50"><div align="center"><input name="quantity" type="text" size="27" maxlength="50" placeholder="Enter quantity"></div></td>';
}
echo "</table>\n";
}
echo "<div style='text-align:center'><input type='submit' value='Comprar'></div>";
echo"</form>";
?>
</body>
</html>
These are two of the Javascripts that I have tried so far to complete this, but they fail to tell me when one has been selected, I don't know if I can try adding this code to a button, and when I click it, it will tell me which row from the radio box was checked, and then save it:
<script type="text/javascript" src="js/jquery.js"> </script>
<script type="text/javascript">
var user_cat = $("input[radio1='user_cat']:checked").val();
if (!$("input[radio1='radio1']").is(':checked')) {
alert('Nothing is checked!');
}
else {
alert('One of the radio buttons is checked!');
}
$(document).ready(function() {
$('#btnStatus').click(function(){
var isChecked = $('#rdSelect').prop('checked');
alert(isChecked);
});
});
</script>
When is use this line echo "<td><div style='text-align:center'><label><input type='radio' name='radio1' value='valor'></label></td></div>"; it works and displays this results
But when I use this line echo sprintf('<td><div style="text-align:center"><label><input type="radio" name="product" value="%d"></label></td></div>', $product['product_id']);it doesn't work and displays this results
OK, picking up the information from the comments to the question and doing a little guess work I will try to point you into the right direction. It is not possible to give a read-to-use answer, since still there are things not clear, but let's have a try to get started...
I see you have an html form which includes a table. That table has a header row and dynamic generated rows holding some product information each. You want to have a radio button in front of each row to allow to select a row. And you want a text input field at the end of each row which allows to enter a quantity. Then you want to post that information to the server to be able to process it.
I will stick with the "conservative" html approach and not introduce scripting here. Reason is that for the purpose described before that is not required. So let's keep things simple. Obviously nothing speaks against making things more complicated later on :-)
Your radio buttons have to be changed, they currently make no sense. You have to give the an individual value, so that you can identify which row has been selected later on. Currently you give them all the same static value 'value'. So change the loop that iterates over the products to something like:
while ($product = oci_fetch_array($stid, OCI_ASSOC+OCI_RETURN_NULLS)) {
echo "<tr>\n";
echo sprintf('<td><div style="text-align:center"><label><input type="radio" name="product" value="%s"></label></td></div>'."\n", $product['product_id']);
foreach ($row as $aspect) {
echo '<td><div style="text-align:center">'
.($aspect !== null ? htmlentities($aspect, ENT_QUOTES) : '')
."</td></div>\n";
}
echo '<td width="50"><div align="center"><input name="quantity" type="text" size="27" maxlength="50" placeholder="Enter quantity"></div></td>'."\n";
}
Note: I took the liberty to change the chosen names to be more logical to product, aspect and quantity...
That is all... Now when you press the submit button the form should get posted to the target you specified: slips.php which is probably a script of yours... Inside that script you now can access the data like that:
$product = $_POST['product'];
$quantity = $_POST['quantity'];
There are more issue worth discussing and modifying, but as said: let's keep things simple and take one step after the other!
ChangeLog:
changed the literal key of the array element used as a value inside the radio button definition from id to procduct_id according to one of the comments below
Your radiobox need to stay inside the form.

How to check which button have been submitted

I have a form, like this:
echo '<table align=center border=1>';
echo '<form method="post">';
echo '<tr>';
echo '<th>Lista Echipamente</th>';
echo '<th>Actiune</th>';
echo '</tr>';
while($row=mysql_fetch_array($sql)){
echo '<tr>';
echo '<td><input class="search-logi" id="tip" type="text" name="tip" value="'.$row['tip'].'"></td>';
echo '<td><input type=submit name=modifica value=Modifica></td>';
echo '</tr>';
}
echo '</form>';
echo '</table>';
Because of the loop, this form will have multiple rows. For each input, will be a button.
Lets say I want to add a value in the second input, then I will submit it (also the second button, obviously). Here comes the problem, in my code I have just a button, but the user see as many as the loop goes. How can I check which button is submitted?
Alternatively, you could utilize <button> tags for this purpose:
echo '<form method="post">'; // form tags are outside to be valid!!!
echo '<table align=center border=1>';
echo '<tr>';
echo '<th>Lista Echipamente</th>';
echo '<th>Actiune</th>';
echo '</tr>';
while($row = mysql_fetch_assoc($sql)){
echo '<tr>';
echo '<td><input class="search-logi" type="text" name="tip['.$row['id'].']" value="'.$row['tip'].'"></td>';
echo '<td><button type="submit" name="modifica" value="'.$row['id'].'">Modifica</button</td>';
echo '</tr>';
}
echo '</table>';
echo '</form>';
Then on the processing form:
$modifica = $_POST['modifica']; // shoud return the index num
$tip = $_POST['tip'][$modifica]; // select which textbox
Keep some unique reference to both input and button. Let say start a counter as 1 and then make the input id as input_1 and button as button_1 and then when you click button get the counter value that is 1 for above and then get the value of input_1 as per counter 1 and submit the form. And then increase counter so that id will increase as well. I think this will help you what you need.
Check all your $_POST variales which are empty and which are not.
Else you could write a javascript function to set all unused fields the value to "0" or to a string and check if it is used or not e.g "unused". In your php script you can check now for the value if it is set to "0" or "unused".
One way is to prefix the name of the input text field with a counter or other prefix. Bases on the name of the input field you can determine which button fired.

PHP newbie, how to send data on new page?

I'm learning PHP and I need help to "send" informations on an another page.
I read a text file and I put data on 2 arrays :
$nomVille;
$nomFichier;
$index; // index is use for arrays
Now I want to build a drop-down list and a submit button.
The drop-down list : show all items on $nomVille
The button : open "villes.php"
villes.php will have to retrieve $nomFichier and $index but I'm not able to do that.
Here is a part of my code :
echo 'Make your choice : ';
echo "<select name='ville'>";
foreach($nomVille as $option){
echo "<option value='{$option}'>{$option}</option>";
}
echo "</select>";
echo '<FORM METHOD="post" ACTION="villes.php">';
echo '<INPUT TYPE="submit" VALUE="Display">';
echo '</FORM>';
Is that correct ?
You've not got your select element wrapped in form tags which will prevent it being sent. What you actually want is this:
echo '<FORM METHOD="post" ACTION="villes.php">';
echo 'Make your choice : ';
echo "<select name='ville'>";
foreach($nomVille as $option){
echo "<option value='{$option}'>{$option}</option>";
}
echo "</select>";
echo '<INPUT TYPE="submit" VALUE="Display">';
echo '</FORM>';
On the page "villes.php", you should then be able to refer to the variable $_POST["ville"] which will contain the selected option in the select.
echo $_POST["ville"];
In order to transfer the values of $nomFichier and $index, you want to send them as hidden elements as part of the form, so add the lines:
echo "<input type='hidden' name='nomFichier' value='".$nomFichier."'>";
echo "<input type='hidden' name='index' value='".$index."'>";
Which will again, be able to be grabbed from the $_POST array.
Moving your select into the FORM element will allow the application to post the data on submit.
echo 'Make your choice : ';
echo '<FORM METHOD="post" ACTION="villes.php">';
echo "<select name='ville'>";
foreach($nomVille as $option){
echo "<option value='{$option}'>{$option}</option>";
}
echo "</select>";
echo '<INPUT TYPE="submit" VALUE="Display">';
echo '</FORM>';
From the villes.php page you then have data retrievable in the data that you can access like this:
if (isset($_POST['ville'])) {
$someVar = $_POST['ville'];
}
You'll find it worth your time to Google "PHP form tutorial" and seeing how things work from there.

Submit form without input field.

I am trying to submit a form (or a request) to do some tasks. The form doesn't have input field except a submit button.
I know it's kinda strange but I want to submit the form and get the data by using only php.
Is that possible?
My codes
if($_GET['submitImage']){
//do the stff I want......
}
<form id='formSubmitImage' name='submitImage' method='get' action='cm_ct_generate_preview.html'>
<?php
echo "<table>";
echo "<th>ID</th>";
echo "<th>Type</th>";
echo "<th>Name</th>";
echo "<th>Image</th>";
foreach($tests as $test){
echo '<tr>';
echo '<td>';
echo $test['ID'];
echo '</td>';
echo '<td>';
echo $test['Type'];
echo '</td>';
echo '<td>';
echo $test['Name'];
echo '</td>';
echo '<td>';
echo $test['FileName'];
echo '</td>';
echo '</tr>';
}
echo "</table>";
echo "<input type='submit' value='Set Images'></input><br>";
?>
</form>
Are there any alternative way to do this? Thanks a lot!
Instead of:
echo "<input type='submit' value='Set Images'></input><br>";
Why not:
echo "<button type='submit'>Set Images</button><br>";
You can add a GET parameter to the end of your action URL (in your case it would then be something like cm_ct_generate_preview.html?submitImage=1 or you can add a hidden input field in the form and check if that is submitted, for example:
<input type="hidden" name="submitImage" value="1" />
As your form method is already set to GET it should be sent as a GET parameter.
If the user needs to activate it, let them just press the submit button. However if you want to do it automatically, you will need to use a little javascript. To send the data with it, you can just specify your inputs like this:
echo '<input type="hidden" name="id" value="'.$test['ID'].'">';
the input fields will not appear but the data will be send like with an input field.

identify jquery button click in php rows

I have an input button in :
while ($row = $result->fetch()) {
echo '<table class="cart-row" cellspacing="0" cellpadding="0" width="100%">';
echo '<tbody>';
echo '<tr>';
echo '<td width="75"><img border="0" width="59px" height="78px" title="" alt="" src=' . $row["ImagePath"] .'></td>';
echo '<td width="203"><span id="itemName" class="itemElements">'. $row["Name"] .'</span></td>';
echo '<td width="135"><span id="qtyNum">('. $row["Qty"] .')</span> <br />';
echo '<span id="qtyRemoveLink"><input class="linkbtn" type="submit" id="btnRemove" value="Remove"></td>';
echo '<td width="180"><span id="orderStatus" class="itemElements">In Stock Usually dispatched within 24 hours</span></td>';
echo '<td width="175" id="itemPriceRow"><span id="itemPrice">€ '. $row["Price"] .'</span></td>';
echo '</tr>';
echo '</tbody>';
echo '</table>';
echo '<br>';
}
I'm trying to use this method to trigger an event when the button is clicked however the event is only being fired for the first button generated in the first row. I'm using this method:
$(document).ready(function() {
$('#btnRemove').click(function() {
alert("test");
});
});
Any ideas how I can fix this problem? I know in C# there is on row databound method however in jQuery I dont now if it exsists. Thanks
You are selecting an element to bind the click event handler to that has a unique ID. When you select by ID you will be returned only the first matching element because to be a valid ID it must be unique.
Change the ID to a class and change your selector to .btnRemove and the alert will work for all the buttons.
echo '<span id="qtyRemoveLink"><input class="linkbtn" type="submit" id="btnRemove" value="Remove"></td>';
Should change to:
echo '<span id="qtyRemoveLink"><input class="linkbtn btnRemove" type="submit" value="Remove"></td>';
And:
$('#btnRemove').click(function() {
Should change to:
$('.btnRemove').click(function() {
Here is a demo: http://jsfiddle.net/rSyCw/
Here is an excellent answer on the site regarding the creation of valid HTML IDs: What are valid values for the id attribute in HTML?
Use a class for the button, not an ID. IDs are unique identifiers (can only be one with that name on the whole page), however classes may be applied to multiple elements. So...
<input type="submit" id="btnRemove" />
Becomes
<input type="submit" class="btnRemove" />
And, as such, your selector changes to .btnRemove.
And, now that you know that IDs need to be unique, you should go ahead and re-configure the output to use classes, or use IDs with a unique ID appended. e.g.
<?php
while ($row = $result->fetch()){
?>
<!-- Other HTML -->
<input type="submit" id="btnSubmit_<?= $row['Unique_Column_Id']; ?>" ... />
Then you can modify your selector:
$('[id^="btnSubmit_"]').click(...); // All elements with an
// ID that starts with "btnSubmit_"
One red flag here is that you are generating multiple elements with the same ID on each iteration of your loop. Element IDs need to be unique in your document. My guess is that jQuery is only binding to the first element it finds with the ID "btnRemove" because it assumes that your IDs are unique.
As others have stated, using a class name on your button would help your problem, but you should still come up with a way to put unique IDs on your itemName, qtyNum, qtyRemoveLink, orderStatus, itemPriceRow, and itemPrice elements, and anywhere else you might be using this technique.

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