I am extracting a zip file in PHP and trying to rename it to content.txt. Here is my code:
if($this->copyFile($this->src,$this->dest)) {
$this->log .= "Successfully copied the file. Starting unzip.<br />";
$res = $this->zip->open($this->dest);
if ($res === TRUE) {
$this->zip->extractTo("/htdocs/content-refresh/");
$this->extracted = $this->zip->getNameIndex(0);
$this->log .= "Extracted ".$this->extracted." onto our server.<br />";
if($this->zip->renameIndex(0,'content.txt')) {
$this->log .= "Renamed update file to content.txt.<br />";
} else {
$this->log .= "Could not rename update file to content.txt.<br />";
}
$this->zip->close();
$this->log .= "The update file is ready to go. Now you can use the update functions.<br />";
} else {
$this->log .= "Could not unzip the file.<br />";
}
}
Here is the file output:
Successfully copied the file. Starting unzip.
Extracted Hotel_All_Active 01-19-11.txt onto our server.
Renamed update file to content.txt.
The update file is ready to go. Now you can use the update functions.
The problem is that it does not rename the file. I have also tried:
$this->zip->renameName(strval($this->extracted),'content.txt')
But that also prints out that it renamed the file, but does not. Am I doing something wrong here, or is this function buggy?
The renameIndex() function is for renaming a file inside an archive.
Looking at the code in the PHP Manual for that function, it's you can see it's modifying the archive:
$zip = new ZipArchive;
$res = $zip->open('test.zip');
if ($res === TRUE) {
$zip->renameIndex(2,'newname.txt');
$zip->close();
} else {
echo 'failed, code:' . $res;
}
You need to use the rename() function instead.
Related
I'm trying to extract a directory of zip files in the same directory they are located in.
public function buildRecords($quickCheckOutputDir, $salvageVinsDir)
{
//unzip
$files_to_extract = $this->getFiles($salvageVinsDir);
$zip = new ZipArchive();
foreach($files_to_extract as $file) {
$res = $zip->open($salvageVinsDir . $file);
if($res) {
echo $zip->extractTo($salvageVinsDir);
//$zip->deleteName($salvageVinsDir . $file);
$zip->close();
} else {
echo 'failed, code:' . $res;
}
}
}
The echo $zip->extractTo($salvageVinsDir) returns 1 so I would think that the method is working but when I check the directory only the zipped files are there. Nothing has been extracted. What is the issue here?
Edit: I gave the directory I'm working in chmod 777.I'm working on centos 7.
I have been trying to read a PHP file inside a ZIP archive. I have coded the following code, which can read text documents and echo without errors, but when I tested it with a PHP file, nothing appear. So what can I do to read the PHP file without extracting?
<?php
$zip = zip_open("test.zip");
$filename= "test.php";
if (is_resource($zip))
{
while ($zip_entry = zip_read($zip))
{
if (zip_entry_open($zip, $zip_entry) && zip_entry_name($zip_entry) == $filename)
{
echo "Name: " . zip_entry_name($zip_entry) . "<br />";
echo "<p>";
echo "File Contents:<br/>";
$contents = zip_entry_read($zip_entry);
echo "$contents<br />";
zip_entry_close($zip_entry);
}
}
zip_close($zip);
}
Thanks in advance!
There aren't a lot of resources out there for using the default zip_read() php function, but this https://github.com/Ne-Lexa/php-zip library makes using zip files in php a breeze, you should check it out.
You can use stream wrappers to read a file directly from within a zip, in one line, without extracting anything to disk. For example:
$str = file_get_contents('zip://test.zip#test.php');
I have a zip file containing one folder, that contains more folders and files, like this:
myfile.zip
-firstlevel
--folder1
--folder2
--folder3
--file1
--file2
Now, I want to extract this file using PHPs ZipArchive, but without the "firstlevel" folder. At the moment, the results look like this:
destination/firstlevel/folder1
destination/firstlevel/folder2
...
The result I'd like to have would look like this:
destination/folder1
destination/folder2
...
I've tried extractTo, which produces the first mentioned result, and copy(), as suggested here, but this doesn't seem to work at all.
My current code is here:
if($zip->open('myfile.zip') === true) {
$firstlevel = $zip->getNameIndex(0);
for($i = 0; $i < $zip->numFiles; $i++) {
$entry = $zip->getNameIndex($i);
$pos = strpos($entry, $firstlevel);
if ($pos !== false) {
$file = substr($entry, strlen($firstlevel));
if(strlen($file) > 0){
$files[] = $file;
}
}
}
//attempt 1 (extractTo):
//$zip->extractTo('./test', $files);
//attempt 2 (copy):
foreach($files as $filename){
copy('zip://'.$firstlevel.'/'.$filename, 'test/'.$filename);
}
}
How can I achieve the result I'm aiming for?
Take a look at my Quick Unzipper script. I wrote this for personal use a while back when uploading large zip files to a server. It was a backup, and 1,000s of files take forever with FTP so using a zip file was faster. I use Git and everything, but there wasn't another option for me. I place this php file in the directory I want the files to go, and put the zip file in the same directory. For my script, they all have to operate in the same directory. It was an easy way to secure it for my needs, as everything I needed was in the same dir.
Quick Unzipper: https://github.com/incomepitbull/QuickUnzipper/blob/master/unzip.php
I linked the file because I am not showcasing the repo, just the code that makes the unzip tick. With modern versions of PHP, there should't be anything that isn't included on your setup. So you shouldn't need to do any server config changes to use this.
Here is the PHP Doc for the ZipArchive class it uses: http://php.net/manual/en/class.ziparchive.php
There isn't any included way to do what you want, which is a shame. So I would unzip the file to a temp directory, then use another function to copy the contents to where you want. So when using ZipArchive, you will need to return the first item to get the folder name if it is unknown. If the folder is known, ie: the same pesky folder name every time, then you could hard code the name.
I have made it return the first item from the index. So if you ALWAYS have a zip with 1 folder inside it, and everything in that folder, this would work. However, if you have a zip file without everything consolidated inside 1 folder, it would fail. The code I have added will take care of your question. You will need to add further logic to handle alternate cases.
Also, You will still be left with the old directory from when we extract it to the temp directory for "processing". So I included code to delete it too.
NOTE: The code uses a lot of if's to show the processing steps, and print a message for testing purposes. You would need to modify it to your needs.
<?php
public function copyDirectoryContents($source, $destination, $create=false)
{
if ( ! is_dir($source) ) {
return false;
}
if ( ! is_dir($destination) && $create === true ) {
#mkdir($destination);
}
if ( is_dir($destination) ) {
$files = array_diff(scandir($source), array('.','..'));
foreach ($files as $file)
{
if ( is_dir($file) ) {
copyDirectoryContents("$source/$file", "$destination/$file");
} else {
#copy("$source/$file", "$destination/$file");
}
}
return true;
}
return false;
}
public function removeDirectory($directory, $options=array())
{
if(!isset($options['traverseSymlinks']))
$options['traverseSymlinks']=false;
$files = array_diff(scandir($directory), array('.','..'));
foreach ($files as $file)
{
if (is_dir("$directory/$file"))
{
if(!$options['traverseSymlinks'] && is_link(rtrim($file,DIRECTORY_SEPARATOR))) {
unlink("$directory/$file");
} else {
removeDirectory("$directory/$file",$options);
}
} else {
unlink("$directory/$file");
}
}
return rmdir($directory);
}
$file = dirname(__FILE__) . '/file.zip'; // full path to zip file needing extracted
$temp = dirname(__FILE__) . '/zip-temp'; // full path to temp dir to process extractions
$path = dirname(__FILE__) . '/extracted'; // full path to final destination to put the files (not the folder)
$firstDir = null; // holds the name of the first directory
$zip = new ZipArchive;
$res = $zip->open($file);
if ($res === TRUE) {
$firstDir = $zip->getNameIndex(0);
$zip->extractTo($temp);
$zip->close();
$status = "<strong>Success:</strong> '$file' extracted to '$temp'.";
} else {
$status = "<strong>Error:</strong> Could not extract '$file'.";
}
echo $status . '<br />';
if ( empty($firstDir) ) {
echo 'Error: first directory was empty!';
} else {
$firstDir = realpath($temp . '/' . $firstDir);
echo "First Directory: $firstDir <br />";
if ( is_dir($firstDir) ) {
if ( copyDirectoryContents($firstDir, $path) ) {
echo 'Directory contents copied!<br />';
if ( removeDirectory($directory) ) {
echo 'Temp directory deleted!<br />';
echo 'Done!<br />';
} else {
echo 'Error deleting temp directory!<br />';
}
} else {
echo 'Error copying directory contents!<br />';
}
} else {
echo 'Error: Could not find first directory';
}
}
I wrote this code to create a ZIP file and to save it. But somehow it just doesn't show any error, but it doesn't create a ZIP file either. Here's the code:
$zip = new ZipArchive;
$time = microtime(true);
$res = $zip->open("maps/zips/test_" . $time . ".zip", ZipArchive::CREATE);
if ($res === TRUE) {
echo "RESULT TRUE...";
$zip->addFile("maps/filename.ogz","filename.ogz"); //Sauerbraten map format
$zip->addFromString('how_to_install.txt', 'Some Explanation...');
$zip->close();
$zip_created = true;
echo "FILE ADDED!";
}
What am I doing wrong, and how can I fix it?
Probably apache or php has not got permissions to create zip archives in that directory. From one of the comments on ZipArchice::open:
If the directory you are writing or
saving into does not have the correct
permissions set, you won't get any
error messages and it will look like
everything worked fine... except it
won't have changed!
Instead make sure you collect the
return value of ZipArchive::close().
If it is false... it didn't work.
Add an else clause to your if statement and dump $res to see the results:
if($res === TRUE) {
...
} else {
var_dump($res);
}
There are 2 cases when zip doesn't generate the error.
Make sure every file you are adding to the zip is valid. Even if
one file is not available when zip->close is called then the archive
will fail and your zip file won't be created.
If your folder doesn't
have write permissions zip will not report the error. It will finish
but nothing will be created.
I had an exactly same issue, even when with full writing/reading permissions.
Solved by creating the ".zip" file manually before passing it to ZipArchive:
$zip = new ZipArchive;
$time = microtime(true);
$path = "maps/zips/test_" . $time . ".zip"
touch($path); //<--- this line creates the file
$res = $zip->open($path, ZipArchive::CREATE);
if ($res === TRUE) {
echo "RESULT TRUE...";
$zip->addFile("maps/filename.ogz","filename.ogz"); //Sauerbraten map format
$zip->addFromString('how_to_install.txt', 'Some Explanation...');
$zip->close();
$zip_created = true;
echo "FILE ADDED!";
}
Check out that each of your file exists before calling $zip->addFile otherwise the zip won't be generated and no error message will be displayed.
if(file_exists($fichier->url))
{
if($zip->addFile($fichier->url,$fichier->nom))
{
$erreur_ouverture = false;
}
else
{
$erreur_ouverture = true;
echo 'Open error : '.$fichier->url;
}
}
else
{
echo 'File '.$fichier->url.' not found';
}
break it into steps.
if ($res === TRUE) {
check if file_exist
check if addFile give any error
}
if($zip->close())
{
$zip_created = true;
echo "FILE ADDED!"
}
Check the phpinfo for zip is enabled or not :)
One of the reasons for zip file is not created is due to missing check if you are adding file and not a directory.
if (!$file->isDir())
I found the solution here.
I have searched the forum but the closest question which is about the control stream did not help or I did not understand so I want to ask a different question.
I have an html form which uploads multiples files to a directory. The upload manager that handles the upload resides in the same script with a different code which I need to pass the file names to for processing.
The problem is that the files get uploaded but they don't get processed by the the other code. I am not sure about the right way to pass the $_FILES['uploadedFile']['tmp_name']) in the adjoining code so the files can be processed with the remaining code. Please find below the script.
More specif explanation:
this script does specifically 2 things. the first part handles file uploads and the second part starting from the italised comment extracts data from the numerous uploaded files. This part has a variable $_infile which is array which is suppose to get the uploaded files. I need to pass the files into this array. so far I struggled and did this: $inFiles = ($_FILES['uploadedFile']['tmp_name']); which is not working. You can see it also in the full code sample below. there is no error but the files are not passed and they are not processed after uploading.
<?php
// This part uploads text files
if (isset($_POST['uploadfiles'])) {
if (isset($_POST['uploadfiles'])) {
$number_of_uploaded_files = 0;
$number_of_moved_files = 0;
$uploaded_files = array();
$upload_directory = dirname(__file__) . '/Uploads/';
for ($i = 0; $i < count($_FILES['uploadedFile']['name']); $i++) {
//$number_of_file_fields++;
if ($_FILES['uploadedFile']['name'][$i] != '') { //check if file field empty or not
$number_of_uploaded_files++;
$uploaded_files[] = $_FILES['uploadedFile']['name'][$i];
//if (is_uploaded_file($_FILES['uploadedFile']['name'])){
if (move_uploaded_file($_FILES['uploadedFile']['tmp_name'][$i], $upload_directory . $_FILES['uploadedFile']['name'][$i])) {
$number_of_moved_files++;
}
}
}
}
echo "Files successfully uploaded . <br/>" ;
echo "Number of files submitted $number_of_uploaded_files . <br/>";
echo "Number of successfully moved files $number_of_moved_files . <br/>";
echo "File Names are <br/>" . implode(',', $uploaded_files);
*/* This is the start of a script to accept the uploaded into another array of it own for* processing.*/
$searchCriteria = array('$GPRMC');
//creating a reference for multiple text files in an array
**$inFiles = ($_FILES['uploadedFile']['tmp_name']);**
$outFile = fopen("outputRMC.txt", "w");
$outFile2 = fopen("outputGGA.txt", "w");
//processing individual files in the array called $inFiles via foreach loop
if (is_array($inFiles)) {
foreach($inFiles as $inFileName) {
$numLines = 1;
//opening the input file
$inFiles = fopen($inFileName,"r");
//This line below initially was used to obtain the the output of each textfile processed.
//dirname($inFileName).basename($inFileName,'.txt').'_out.txt',"w");
//reading the inFile line by line and outputting the line if searchCriteria is met
while(!feof($inFiles)) {
$line = fgets($inFiles);
$lineTokens = explode(',',$line);
if(in_array($lineTokens[0],$searchCriteria)) {
if (fwrite($outFile,$line)===FALSE){
echo "Problem w*riting to file\n";
}
$numLines++;
}
// Defining search criteria for $GPGGA
$lineTokens = explode(',',$line);
$searchCriteria2 = array('$GPGGA');
if(in_array($lineTokens[0],$searchCriteria2)) {
if (fwrite($outFile2,$line)===FALSE){
echo "Problem writing to file\n";
}
}
}
}
echo "<p>For the file ".$inFileName." read ".$numLines;
//close the in files
fclose($_FILES['uploadedFile']['tmp_name']);
fflush($outFile);
fflush($outFile2);
}
fclose($outFile);
fclose($outFile2);
}
?>
Try this upload class instead and see if it helps:
To use it simply Upload::files('/to/this/directory/');
It returns an array of file names that where uploaded. (it may rename the file if it already exists in the upload directory)
class Upload {
public static function file($file, $directory) {
if (!is_dir($directory)) {
if (!#mkdir($directory)) {
throw new Exception('Upload directory does not exists and could not be created');
}
if (!#chmod($directory, 0777)) {
throw new Exception('Could not modify upload directory permissions');
}
}
if ($file['error'] != 0) {
throw new Exception('Error uploading file: '.$file['error']);
}
$file_name = $directory.$file['name'];
$i = 2;
while (file_exists($file_name)) {
$parts = explode('.', $file['name']);
$parts[0] .= '('.$i.')';
$new_file_name = $directory.implode('.', $parts);
if (!file_exists($new_file_name)) {
$file_name = $new_file_name;
}
$i++;
}
if (!#move_uploaded_file($file['tmp_name'], $file_name)) {
throw new Exception('Could not move uploaded file ('.$file['tmp_name'].') to: '.$file_name);
}
if (!#chmod($file_name, 0777)) {
throw new Exception('Could not modify uploaded file ('.$file_name.') permissions');
}
return $file_name;
}
public static function files($directory) {
if (sizeof($_FILES) > 0) {
$uploads = array();
foreach ($_FILES as $file) {
if (!is_uploaded_file($file['tmp_name'])) {
continue;
}
$file_name = static::file($file, $directory);
array_push($uploads, $file_name);
}
return $uploads;
}
return null;
}
}