PHP date(): minutes without leading zeros - php

Question

I'd like to know if there is a formatting letter for PHP's date() that allows me to print minutes without leading zeros, or whether I have to manually test for and remove leading zeros?

Answer 1

Use:
$minutes = intval(date('i'));

Answer 2

For times with more information than just minutes:
ltrim() - Strip whitespace (or other characters) from the beginning of a string
ltrim(date('i:s'), 0);
returns:
8:24

Answer 3

According to the PHP Documentation, the date() function does not have a placeholder for minutes without leading zeros.
You could, however, get that information by simply multiplying the dates, with a leading zero, by 1, turning it into an integer.
$minutesWithoutZero = 1* date( 'i' );

Answer 4

I tried to find this for seconds as well, gave up the search and just casting the result as a int like this:
echo (int)date("s");
That will get rid of the leading zero's in a fast efficient way.

Answer 5

Doesn't look like it, but you could do something like...
echo date('g:') . ltrim(date('i'), '0');
Alternately, you could cast the second call to date() with (int).

Answer 6

This also works
$timestamp = time(); // Or Your timestamp. Skip passing $timestamp if you want current time
echo (int)date('i',$timestamp);

Answer 7

I use this format if I need a XXmXXs format:
//Trim leading 0's and the 'm' if no minutes
ltrim(ltrim(gmdate("i\ms\s", $seconds), '0'), 'm');
This will output the following:
12m34s
1m23s
12s

Answer 8

i just did this one line solution
$min = intval(date('i',strtotime($date)));
Using ltrim method may remove all the leading zeroes.For ex if '00' min.In this case this will remove all the zeroes and gives you empty result.

Answer 9

My solution:
function seconds2string($seconds) {
if ($seconds == 0) {
return '-';
}
if ($seconds < 60) {
return date('0:s', $seconds);
}
if ($seconds < 3600) {
return ltrim(date('i:s', $seconds), 0);
}
return date('G:i:s', $seconds);
}
This will output:
0 seconds: -
10 seconds: 0:10
90 seconds: 1:30
301 seconds: 5:01
1804 seconds: 30:04
3601 seconds: 1:00:01

Answer 10

Just use this:
(int) date('i');

Answer 11

Or in mySQL just multiply it by 1, like such:
select f1, ..., date_format( fldTime , '%i' ) * 1 as myTime, ..., ...

Answer 12

$current_date = Date("n-j-Y");
echo $current_date;
// Result m-d-yy
9-10-2012

Answer 13

A quickie from me. Tell me what you think:
<?php function _wo_leading_zero($n) {
if(!isset($n[1])) return $n;
if(strpos($n, '.') !== false) {
$np = explode('.', $n); $nd = '.';
}
if(strpos($n, ',') !== false) {
if(isset($np)) return false;
$np = explode(',', $n); $nd = ',';
}
if(isset($np) && count($np) > 2) return false;
$n = isset($np) ? $np[0] : $n;
$nn = ltrim($n, '0');
if($nn == '') $nn = '0';
return $nn.(isset($nd) ? $nd : '').(isset($np[1]) ? $np[1] : '');
}
echo '0 => '._wo_leading_zero('0').'<br/>'; // returns 0
echo '00 => '._wo_leading_zero('00').'<br/>'; // returns 0
echo '05 => '._wo_leading_zero('05').'<br/>'; // returns 5
echo '0009 => '._wo_leading_zero('0009').'<br/>'; //returns 9
echo '01 => '._wo_leading_zero('01').'<br/>'; //returns 1
echo '0000005567 => '._wo_leading_zero('0000005567').'<br/>'; //returns 5567
echo '000.5345453 => '._wo_leading_zero('000.5345453').'<br/>'; //returns 0.5345453
echo '000.5345453.2434 => '._wo_leading_zero('000.5345453.2434').'<br/>'; //returns false
echo '000.534,2434 => '._wo_leading_zero('000.534,2434').'<br/>'; //returns false
echo date('m').' => '._wo_leading_zero(date('m')).'<br/>';
echo date('s').' => '._wo_leading_zero(date('s')).'<br/>'; ?>

Answer 14

use PHP's absolute value function:
abs( '09' ); // result = 9
abs( date( 'i' ) ); // result = minutes without leading zero

Answer 15

My Suggestion is Read this beautiful documentation it have all details of php date functions
Link of Documentation
And as per your question you can use i - Minutes with leading zeros (00 to 59) Which return you minutes with leading zero(0).
And Also introducing [Intval()][2] function returns the integer value of a variable. You can not use the intval() function on an object