pass variables in array as function paramaters? - php

I have a function that does something similar to this:
function load_class($name){
require_once('classes/'.$name.'.php');
return new $name();
}
what I want to do is modify it so I can do something like this
function load_class($name, $vars = array()){
require_once('classes/'.$name.'.php');
return new $name($array[0], $array[1]);
}
The general gist of it is.
I want to be able to pass in an array of values that, gets used as the parameters for the class.
I dont want to pass in the actual array.
is this possible?

Of course, it's called var args and you want to unpack them. http://php.net/manual/en/function.func-get-arg.php. Check out the examples... unpacking an array of arguments in php.
See Also How to pass variable number of arguments to a PHP function

if you are trying to load classes then you could use __autoload function
more information here

You can call functions this way with call_user_func_array, but in the case of a class constructor, you should use ReflectionClass::newInstanceArgs:
class MyClass {
function __construct($x, $y, $z) { }
}
$class = new ReflectionClass("MyClass");
$params = array(1, 2, 3);
// just like "$instance = new MyClass(1,2,3);"
$instance = $class->newInstanceArgs($params);
Your code might look like this:
function load_class($name, $vars = array()){
require_once('classes/'.$name.'.php');
$class = new ReflectionClass($name);
return $class->newInstanceArgs($vars);
}

Related

Problems using extract() function to insert arguments into class method directly

Is this possible Im trying to do this with the extract() function since Im unable to get the method arguments in advance
class Test{
public function getData($id){
//use $id here
}
}
$class = 'Test'; //this is determined dymanically
$method = 'getData'; //this is also determined dynamically
$arguments = ['id'=>'1234'];
$test = new $class();
$test->{$method}(extract($arguments));
//this generates a warning Missing argument 1 for Test::getData(),
called
How can this be implemented?
EDIT
It appears I've simplified it too much, the code is intended to be the main deployment mechanism in a mini-framework Im developing so the method - getData is determined dynamically and therefore I cant know the arguments for each method in advance.
Thanks
extract is for assigning to variables. For each element of the associative array, it will assign to a variable in the current scope with that name. It returns the number of variables it assigned, not the value of any of the variables.
There's no reason to use extract in your case, just get the element of the array that you want:
$test->getData($arguments['id']);
I'm not sure why you're getting an error about a missing argument. It should pass 1 as the $id argument, since there's one element in the array.
If you don't know which elements the function needs, a better design would be to pass the whole $arguments array to the function, and let it use the parts it wants.
public function getData($args) {
$id = $args['id'];
// Use $id
}
...
$test->getData($arguments);
Just extract your array and pass $id
<?php
class Test{
public function getData($id){
echo $id;
}
}
$arguments = array('id'=>'1234');
extract($arguments);
$test = new Test();
$test->getData($id);
or
$arguments = array('id'=>'1234');
extract($arguments);
$test = new Test();
foreach($arguments as $key=>$value){
$test->getData($$key);
}
Ive found the solution using ReflectionMethod
$reflection = new \ReflectionMethod('Test', 'getData');
$pass = [];
foreach($reflection->getParameters() as $param){
//parse the method to get its arguments and filter through the sent arguments array
if(isset($args[$param->getName()])){
//check if the arguments exists and select them
$pass[] = $args[$param->getName()];
}
else{
$pass[] = $param->getDefaultValue();
}
}
//execute the resolved parameters
return $reflection->invokeArgs(new Test, $pass);

Getting a Calling Function's Arguments in PHP

I'm working on a logging class, and I'd like to add a convenience function which would log the arguments of the function from which it is called. A little convoluted, so here's some code:
function MyFunc($arg1, $arg2) {
global $oLog;
$oLog->logArgs();
}
So, I can get the name of the calling function (MyFunc) using debug_backtrace(). I'd be interested in getting the names and values of the arguments, preferably without having to add func_get_args() in the call to logArgs().
I know it's a tall order, but PHP continues to surprise me, so I'm putting it out there, just in case.
Thanks.
You can do this with reflection:
function logger()
{
$bt = debug_backtrace();
$previous = $bt[1];
if(empty($previous['class'])) {
$fn = new ReflectionFunction($previous['function']);
} else {
$class = new ReflectionClass($previous['class']);
$fn = $class->getMethod($previous['function']);
}
$parameters = $fn->getParameters();
//Get a parameter name with $parameters[$paramNum]->getName()
//Get the value from $previous['args'][$paramNum]
}
This particular implementation won't work with closures, but it will work with both global functions and class methods.

Get PHP callable arguments as an array?

Say I have a callable stored as a variable:
$callable = function($foo = 'bar', $baz = ...) { return...; }
How would I get 'bar'?
if (is_callable($callable)) {
return func_get_args();
}
Unfortunately func_get_args() is for the current function, is it possible to get a key value pair of arguments?
You can use reflection:
$f = new ReflectionFunction($callable);
$params = $f->getParameters();
echo $params[0]->getDefaultValue();
You may want to use get_defined_vars to accomplish this, this function will return an array of all defined variables, specifically by accessing the callable index from the output array.
I came across this question because I was looking for getting the arguments for a callable which is not just the function itself. My case is
class MyClass{
public function f(){
// do some stuff
}
}
$myclass = new MyClass();
$callable = array($myclass, "f);
This is a valid callback in php. In this case the solution given by #Marek does not work.
I worked around with phps is_callable function. You can get the name of the function by using the third parameter. Then you have to check whether your callback is a function or a (class/object) method. Otherwise the Reflection-classes will mess up.
if($callable instanceof Closure){
$name = "";
is_callable($callable, false, $name);
if(strpos($name, "::") !== false){
$r = new ReflectionMethod($name);
}
else{
$r = new ReflectionFunction($name);
}
}
else{
$r = new ReflectionFunction($callable);
}
$parameters = $r->getParameters();
// ...
This also returns the correct value for ReflectionFunctionAbstract::isStatic() even though the $name always uses :: which normally indicates a static function (with some exceptions).
Note: In PHP>=7.0 this may be easier using Closures. There you can do someting like
$closure = Closure::fromCallable($callable);
$r = new ReflectionFunction($closure);
You may also cause have to distinguish between ReflectionFunction and ReflectionMethod but I can't test this because I am not using PHP>=7.0.

How to pass a reference to a callback function for use in array_filter with extra arguments?

The signature for my method looks like this:
public function ProgramRuleFilter(&$program, $today=null) {
When I invoke it like this,
$programs = array_filter($programs, array($this,'ProgramRuleFilter'));
Everything works as expected. The ProgramRuleFilter method updates the $program array and then returns true/false if it succeeded which correctly filters $programs.
However, now I want to pass an extra argument to the filter, $today. How can I do that?
I'm trying to invoke it like this:
$programs = array_filter($programs, new CallbackArgs(array($this,'ProgramRuleFilter'),$today));
Using this little class as a wrapper:
class CallbackArgs {
private $callback;
private $args;
function __construct() {
$args = func_get_args();
$this->callback = array_shift($args);
$this->args = $args;
}
function __invoke(&$arg) {
return call_user_func_array($this->callback, array_merge(array($arg),$this->args));
}
}
But the programs aren't being updated, so somewhere along the line it lost the reference to the original object. I'm not sure how to fix this.
The second argument to array_filter must be a callback; which means that array_filter itself will be calling your filter function. There is no way to tell array_filter to call that function in any other way, so you'll need to find a way to get the value of $today into your function some other way.
This is a perfect example of when to use a closure, which will let you bind some data (in this case, the value of $today) into a function / callback. Assuming you are using PHP 5.3 or later:
// Assuming $today has already been set
$object = $this; // PHP 5.4 eliminates the need for this
$programs = array_filter( $programs, function( $x ) use ( $today, $object ){
return $object->ProgramRuleFilter( $x, $today );
});
This defines a closure inline, using the values of $today and $object from the parent scope, and then just calls your existing function ProgramRuleFilter on that $object. (The somewhat unusual $object = $this gets around the fact that otherwise, the closure would not be able to call a method on your object instance. But in PHP 5.4, you can replace $object with $this inside the closure.)
Now, this is a somewhat inelegant way to do it, because all this closure does is hand off the work to the ProgramRuleFilter function. A better way would be to use the closure instead of the function. So:
// Assuming $today has already been set
$filter = function( $x ) use ( $today ){
// Cut and paste the contents of ProgramRuleFilter() here,
// and make it operate on $x and $today
};
$programs = array_filter( $programs, $filter );
Which variation works best for you will depend on the implementation of the rest of your app. Good luck!
I wrote a new method to handle it:
public static function array_filter_args($array, $callback) {
$args = array_slice(func_get_args(),2);
foreach($array as $key=>&$value) {
if(!call_user_func_array($callback, array_merge(array(&$value),$args))) {
unset($array[$key]);
}
}
return $array;
}
Called like this:
$programs = ArrayHelper::array_filter_args($programs, array($this,'ProgramRuleFilter'), $today);
I didn't know you could do this array(&$value), but I thought I'd try it, and it looks like it works. I'm guessing that array_merge is the culprit that dereferences the variable otherwise.

how do I condense this statement?

I have the following function:
<?php
class Test{
function myFunction(){
return array('first','second','third');
}
}
?>
And I can print out the elements of the array:
$var=new Test();
$varr=$var->myFunction();
print($varr[1]);
Is there a way to condense this statement so I don't have to assign $var->myFunction() to a second variable (in this case $varr)?
PHP does not support this very well (as of PHP 5.3) as Tim Cooper already highlighted. So you need to think twice if you really need to have this compacted.
You can do things quite dynamically e.g. by return an ArrayObject instead of an array:
class Test
{
function myFunction()
{
return new ArrayObject(array('first','second','third'), 3);
}
}
$var = new Test();
print($var->myFunction()->{1});
Which will decorate the array data with some additional methods and ways of accessing. Another way would be for functions w/o parameter to fool the PHP parser and offer a property instead of a function dynamically:
class Test
{
function myFunction()
{
return array('first','second','third');
}
public function __get($name)
{
return $this->$name();
}
}
$var = new Test();
print($var->myFunction[1]);
But I don't know if this is really useful in an application.
So check your motivation why you want to compact the code and then decide on your own.
In PHP 5.4 you'll be able to do:
$varr=$var->myFunction()[1];
Until then, using list might help out:
list(,$varr) = $var->myFunction();
Another solution is to modify your method to accept an optional index of the item to return:
function myFunction($index = null){
$arr = array('first','second','third');
return $index == null ? $arr : $arr[$index];
}
$varr = $var->myFunction(1);

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