PHP - How to count how many months from a specific date - php

Question

How can I count the number of months from the following two dates below using the Procedural style method?
PHP code.
$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date

Answer 1

You're looking for DateTime::diff?
$delete_date = "2000-01-12 08:02:39";
$date_format = 'Y-m-d H:i:s';
$current_date = date($date_format);
$diff = date_diff(date_create_from_format($date_format, $delete_date), date_create());
$months = $diff->m;
Something along the lines of that.

Answer 2

Using DateTime you will get the total months this way:
$d1 = new DateTime("2000-01-12 08:02:39");
$d2 = new DateTime();
$d3 = $d1->diff($d2);
$months = ($d3->y*12)+$d3->m;
You would still need to handle the leftover days $d3->d ... but that depends on your needs.

Answer 3

$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date
$diff = strtotime($current_date) - strtotime($delete_date);
$months = floor(floatval($diff) / (60 * 60 * 24 * 365 / 12));
echo $months . "\n";

Answer 4

is this what you looking for?
$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date
// convert date to int
$delete_date = strtotime($delete_date);
$current_date = strtotime($current_date);
// calculate it
$diff = $delete_date - $current_date;
// convert int to time
$conv_diff = date('format', $diff);

Answer 5

Try this, it is easy, maybe not enogh chick, but very effective.
function calculateMonthsBetweenDates($fMonth, $fDay, $fYear, $tMonth, $tDay, $tYear)
{
//Build datetime vars using month, day and year
$dateFrom = mktime(0, 0, 0, $fMonth, $fDay, $fYear);
$dateTo = mktime(0, 0, 0, $tMonth, $tDay, $tYear);
//Check dateTo is a later date than dateFrom.
if($dateFrom<=$dateTo){
$yearF = date("Y", $dateFrom);
$yearT = date("Y", $dateTo);
$monthF = date("m", $dateFrom);
$monthT = date("m", $dateTo);
//same year
if ($yearF == $yearT)
$months = ($monthT - $monthF);
else{
//different year
$months = (12*($yearT-$yearF)-$monthF) + $monthT;
}
return $months;
}
else
return false; //or -1
}